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Page 1
56/1/2/D 1 [P.T.O.
¸üÖê»Ö ®ÖÓ.
Roll No.
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú)
CHEMISTRY (Theory)
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70
Time allowed : 3 hours ] [ Maximum Marks : 70
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö :
(i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …
(ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …
(iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …
(vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà
Æîü …
Series : SSO/1
ÛúÖê›ü ®ÖÓ.
Code No.
56/1/2/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …
• Please check that this question paper contains 12 printed pages.
• Code number given on the right hand side of the question paper should be written on the
title page of the answer-book by the candidate.
• Please check that this question paper contains 26 questions.
• Please write down the Serial Number of the question before attempting it.
• 15 minutes time has been allotted to read this question paper. The question paper will be
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the
question paper and will not write any answer on the answer-book during this period.
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë …
Candidates must write the Code on
the title page of the answer-book.
SET – 2
Page 2
56/1/2/D 1 [P.T.O.
¸üÖê»Ö ®ÖÓ.
Roll No.
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú)
CHEMISTRY (Theory)
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70
Time allowed : 3 hours ] [ Maximum Marks : 70
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö :
(i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …
(ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …
(iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …
(vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà
Æîü …
Series : SSO/1
ÛúÖê›ü ®ÖÓ.
Code No.
56/1/2/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …
• Please check that this question paper contains 12 printed pages.
• Code number given on the right hand side of the question paper should be written on the
title page of the answer-book by the candidate.
• Please check that this question paper contains 26 questions.
• Please write down the Serial Number of the question before attempting it.
• 15 minutes time has been allotted to read this question paper. The question paper will be
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the
question paper and will not write any answer on the answer-book during this period.
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë …
Candidates must write the Code on
the title page of the answer-book.
SET – 2
56/1/2/D 2
General Instructions :
(i) All questions are compulsory.
(ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each.
(iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each.
(iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each.
(v) Q. no. 23 is a value based question and carry 4 marks.
(vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each.
(vii) Use log tables if necessary, use of calculators is not allowed.
1. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1
CH
3
– CH
2
– Br ŸÖ£ÖÖ CH
3
–
C
|
C
|
B
H
3
–
r
CH
3
Which would undergo S
N
2 reaction faster in the following pair and why ?
CH
3
– CH
2
– Br and CH
3
–
C
|
C
|
B
H
3
–
r
CH
3
2. BaCl
2
†Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1
Out of BaCl
2
and KCl, which one is more effective in causing coagulation of a
negatively charged colloidal Sol ? Give reason.
3. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü ? 1
What is the formula of a compound in which the element Y forms ccp lattice and
atoms of X occupy 1/3
rd
of tetrahedral voids ?
Page 3
56/1/2/D 1 [P.T.O.
¸üÖê»Ö ®ÖÓ.
Roll No.
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú)
CHEMISTRY (Theory)
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70
Time allowed : 3 hours ] [ Maximum Marks : 70
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö :
(i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …
(ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …
(iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …
(vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà
Æîü …
Series : SSO/1
ÛúÖê›ü ®ÖÓ.
Code No.
56/1/2/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …
• Please check that this question paper contains 12 printed pages.
• Code number given on the right hand side of the question paper should be written on the
title page of the answer-book by the candidate.
• Please check that this question paper contains 26 questions.
• Please write down the Serial Number of the question before attempting it.
• 15 minutes time has been allotted to read this question paper. The question paper will be
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the
question paper and will not write any answer on the answer-book during this period.
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë …
Candidates must write the Code on
the title page of the answer-book.
SET – 2
56/1/2/D 2
General Instructions :
(i) All questions are compulsory.
(ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each.
(iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each.
(iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each.
(v) Q. no. 23 is a value based question and carry 4 marks.
(vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each.
(vii) Use log tables if necessary, use of calculators is not allowed.
1. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1
CH
3
– CH
2
– Br ŸÖ£ÖÖ CH
3
–
C
|
C
|
B
H
3
–
r
CH
3
Which would undergo S
N
2 reaction faster in the following pair and why ?
CH
3
– CH
2
– Br and CH
3
–
C
|
C
|
B
H
3
–
r
CH
3
2. BaCl
2
†Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1
Out of BaCl
2
and KCl, which one is more effective in causing coagulation of a
negatively charged colloidal Sol ? Give reason.
3. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü ? 1
What is the formula of a compound in which the element Y forms ccp lattice and
atoms of X occupy 1/3
rd
of tetrahedral voids ?
56/1/2/D 3 [P.T.O.
4. H
3
PO
4
Ûúß õÖÖ¸üÛúŸÖÖ ŒµÖÖ Æîü ? 1
What is the basicity of H
3
PO
4
?
5. פüµÖê ÝÖµÖê µÖÖî×ÝÖÛú ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö ×»Ö×ÜÖ‹ : 1
Write the IUPAC name of the given compound :
6. ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ†Öë ´Öë ¯ÖϵÖãŒŸÖ †×³ÖÛúÖ¸üÛúÖë Ûêú ®ÖÖ´Ö ¤üßו֋ : 2
Name the reagents used in the following reactions :
(i) CH
3
– CO – CH
3
?
??? CH
3
– C
|
O
H
H
– CH
3
(ii) C
6
H
5
– CH
2
– CH
3
?
??? C
6
H
5
– COO
–
K
+
7. ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ŒµÖÖ ŸÖÖŸ¯ÖµÖÔ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö Ûêú ×»ÖµÖê
?
mix
H ÛúÖ ×“ÖÅ®Öü ŒµÖÖ Æîü ? 2
What is meant by positive deviations from Raoult’s law ? Give an example. What is
the sign of ?
mix
H for positive deviation ?
†£Ö¾ÖÖ/OR
7. ‹×•ÖµÖÖê™ÒüÖê¯ÃÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ¯ÖÏÖ¯ŸÖ ‹×•ÖµÖÖê™ÒüÖê¯Ö ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ÛúÖ
ÆüÖêŸÖÖ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … 2
Define azeotropes. What type of azeotrope is formed by positive deviation from
Raoult’s law ? Give an example.
Page 4
56/1/2/D 1 [P.T.O.
¸üÖê»Ö ®ÖÓ.
Roll No.
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú)
CHEMISTRY (Theory)
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70
Time allowed : 3 hours ] [ Maximum Marks : 70
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö :
(i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …
(ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …
(iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …
(vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà
Æîü …
Series : SSO/1
ÛúÖê›ü ®ÖÓ.
Code No.
56/1/2/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …
• Please check that this question paper contains 12 printed pages.
• Code number given on the right hand side of the question paper should be written on the
title page of the answer-book by the candidate.
• Please check that this question paper contains 26 questions.
• Please write down the Serial Number of the question before attempting it.
• 15 minutes time has been allotted to read this question paper. The question paper will be
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the
question paper and will not write any answer on the answer-book during this period.
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë …
Candidates must write the Code on
the title page of the answer-book.
SET – 2
56/1/2/D 2
General Instructions :
(i) All questions are compulsory.
(ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each.
(iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each.
(iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each.
(v) Q. no. 23 is a value based question and carry 4 marks.
(vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each.
(vii) Use log tables if necessary, use of calculators is not allowed.
1. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1
CH
3
– CH
2
– Br ŸÖ£ÖÖ CH
3
–
C
|
C
|
B
H
3
–
r
CH
3
Which would undergo S
N
2 reaction faster in the following pair and why ?
CH
3
– CH
2
– Br and CH
3
–
C
|
C
|
B
H
3
–
r
CH
3
2. BaCl
2
†Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1
Out of BaCl
2
and KCl, which one is more effective in causing coagulation of a
negatively charged colloidal Sol ? Give reason.
3. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü ? 1
What is the formula of a compound in which the element Y forms ccp lattice and
atoms of X occupy 1/3
rd
of tetrahedral voids ?
56/1/2/D 3 [P.T.O.
4. H
3
PO
4
Ûúß õÖÖ¸üÛúŸÖÖ ŒµÖÖ Æîü ? 1
What is the basicity of H
3
PO
4
?
5. פüµÖê ÝÖµÖê µÖÖî×ÝÖÛú ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö ×»Ö×ÜÖ‹ : 1
Write the IUPAC name of the given compound :
6. ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ†Öë ´Öë ¯ÖϵÖãŒŸÖ †×³ÖÛúÖ¸üÛúÖë Ûêú ®ÖÖ´Ö ¤üßו֋ : 2
Name the reagents used in the following reactions :
(i) CH
3
– CO – CH
3
?
??? CH
3
– C
|
O
H
H
– CH
3
(ii) C
6
H
5
– CH
2
– CH
3
?
??? C
6
H
5
– COO
–
K
+
7. ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ŒµÖÖ ŸÖÖŸ¯ÖµÖÔ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö Ûêú ×»ÖµÖê
?
mix
H ÛúÖ ×“ÖÅ®Öü ŒµÖÖ Æîü ? 2
What is meant by positive deviations from Raoult’s law ? Give an example. What is
the sign of ?
mix
H for positive deviation ?
†£Ö¾ÖÖ/OR
7. ‹×•ÖµÖÖê™ÒüÖê¯ÃÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ¯ÖÏÖ¯ŸÖ ‹×•ÖµÖÖê™ÒüÖê¯Ö ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ÛúÖ
ÆüÖêŸÖÖ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … 2
Define azeotropes. What type of azeotrope is formed by positive deviation from
Raoult’s law ? Give an example.
56/1/2/D 4
8. (a) ×ÃÖ»¾Ö¸ü Œ»ÖÖê¸üÖ‡›ü Ûêú •Ö»ÖßµÖ ×¾Ö»ÖµÖ®Ö Ûêú ×¾ÖªãŸÖ †¯Ö‘Ö™ü®Ö ´Öë Ûîú£ÖÖê›ü ¯Ö¸ü ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ‹Ñ ÆüÖêŸÖß Æïü :
Ag
+
(aq) + e
–
?? Ag(s) E° = +0.80 V
H
+
(aq) + e
–
??
1
2
H
2
(g) E° = 0.00 V
ˆ®ÖÛêú ´ÖÖ®ÖÛú †¯Ö“ÖµÖ®Ö ‡»ÖꌙÒüÖê›ü ×¾Ö³Ö¾Ö (E°) Ûêú ´ÖÖ®ÖÖë Ûêú †Ö¬ÖÖ¸ü ¯Ö¸ü Ûîú£ÖÖê›ü ¯Ö¸ü ×ÛúÃÖ †×³Ö×ÛÎúµÖÖ Ûúß
ÃÖÓ³ÖÖ¾Ö®ÖÖ Æîü †Öî¸ü ŒµÖÖë ?
(b) ÃÖß´ÖÖÓŸÖ ´ÖÖê»Ö¸ü “ÖÖ»ÖÛúŸÖÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ×¾ÖªãŸÖË †¯Ö‘Ö™ËüµÖ Ûúß “ÖÖ»ÖÛúŸÖÖ ÃÖÖÓ¦üÞÖ Ûêú ‘Ö™ü®Öê Ûêú ÃÖÖ£Ö
ŒµÖÖë Ûú´Ö ÆüÖê®Öê »ÖÝÖŸÖß Æîü ? 2
(a) Following reactions occur at cathode during the electrolysis of aqueous silver
chloride solution :
Ag
+
(aq) + e
–
?? Ag(s) E° = +0.80 V
H
+
(aq) + e
–
??
1
2
H
2
(g) E° = 0.00 V
On the basis of their standard reduction electrode potential (E°) values, which
reaction is feasible at the cathode and why ?
(b) Define limiting molar conductivity. Why conductivity of an electrolyte solution
decreases with the decrease in concentration ?
9. ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾Ö ŒµÖÖ Æïü ? ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾ÖÖë Ûúß ¤üÖê ×¾Ö¿ÖêÂÖŸÖÖ†Öë ÛúÖê ×»Ö×ÜÖ‹ … 2
What are the transition elements ? Write two characteristics of the transition elements.
10. (i) ÛúÖò´¯»ÖêŒÃÖ [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö
×»Ö×ÜÖµÖê …
(ii) ×®Ö´®Ö ÛúÖò´¯»ÖêŒÃÖ ÛúÖ ÃÖæ¡Ö ×»Ö×ÜÖ‹ :
¯Öê®™üÖ‹ê´ÖÖ‡®Ö®ÖÖ‡™ÒüÖ‡™üÖê-o-ÛúÖê²ÖÖ»™ü (III). 2
(i) Write down the IUPAC name of the following complex :
[Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine)
(ii) Write the formula for the following complex :
Pentaamminenitrito-o-Cobalt (III).
Page 5
56/1/2/D 1 [P.T.O.
¸üÖê»Ö ®ÖÓ.
Roll No.
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú)
CHEMISTRY (Theory)
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70
Time allowed : 3 hours ] [ Maximum Marks : 70
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö :
(i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …
(ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …
(iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …
(vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …
(vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà
Æîü …
Series : SSO/1
ÛúÖê›ü ®ÖÓ.
Code No.
56/1/2/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …
• Please check that this question paper contains 12 printed pages.
• Code number given on the right hand side of the question paper should be written on the
title page of the answer-book by the candidate.
• Please check that this question paper contains 26 questions.
• Please write down the Serial Number of the question before attempting it.
• 15 minutes time has been allotted to read this question paper. The question paper will be
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the
question paper and will not write any answer on the answer-book during this period.
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë …
Candidates must write the Code on
the title page of the answer-book.
SET – 2
56/1/2/D 2
General Instructions :
(i) All questions are compulsory.
(ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each.
(iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each.
(iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each.
(v) Q. no. 23 is a value based question and carry 4 marks.
(vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each.
(vii) Use log tables if necessary, use of calculators is not allowed.
1. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1
CH
3
– CH
2
– Br ŸÖ£ÖÖ CH
3
–
C
|
C
|
B
H
3
–
r
CH
3
Which would undergo S
N
2 reaction faster in the following pair and why ?
CH
3
– CH
2
– Br and CH
3
–
C
|
C
|
B
H
3
–
r
CH
3
2. BaCl
2
†Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1
Out of BaCl
2
and KCl, which one is more effective in causing coagulation of a
negatively charged colloidal Sol ? Give reason.
3. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü ? 1
What is the formula of a compound in which the element Y forms ccp lattice and
atoms of X occupy 1/3
rd
of tetrahedral voids ?
56/1/2/D 3 [P.T.O.
4. H
3
PO
4
Ûúß õÖÖ¸üÛúŸÖÖ ŒµÖÖ Æîü ? 1
What is the basicity of H
3
PO
4
?
5. פüµÖê ÝÖµÖê µÖÖî×ÝÖÛú ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö ×»Ö×ÜÖ‹ : 1
Write the IUPAC name of the given compound :
6. ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ†Öë ´Öë ¯ÖϵÖãŒŸÖ †×³ÖÛúÖ¸üÛúÖë Ûêú ®ÖÖ´Ö ¤üßו֋ : 2
Name the reagents used in the following reactions :
(i) CH
3
– CO – CH
3
?
??? CH
3
– C
|
O
H
H
– CH
3
(ii) C
6
H
5
– CH
2
– CH
3
?
??? C
6
H
5
– COO
–
K
+
7. ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ŒµÖÖ ŸÖÖŸ¯ÖµÖÔ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö Ûêú ×»ÖµÖê
?
mix
H ÛúÖ ×“ÖÅ®Öü ŒµÖÖ Æîü ? 2
What is meant by positive deviations from Raoult’s law ? Give an example. What is
the sign of ?
mix
H for positive deviation ?
†£Ö¾ÖÖ/OR
7. ‹×•ÖµÖÖê™ÒüÖê¯ÃÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ¯ÖÏÖ¯ŸÖ ‹×•ÖµÖÖê™ÒüÖê¯Ö ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ÛúÖ
ÆüÖêŸÖÖ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … 2
Define azeotropes. What type of azeotrope is formed by positive deviation from
Raoult’s law ? Give an example.
56/1/2/D 4
8. (a) ×ÃÖ»¾Ö¸ü Œ»ÖÖê¸üÖ‡›ü Ûêú •Ö»ÖßµÖ ×¾Ö»ÖµÖ®Ö Ûêú ×¾ÖªãŸÖ †¯Ö‘Ö™ü®Ö ´Öë Ûîú£ÖÖê›ü ¯Ö¸ü ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ‹Ñ ÆüÖêŸÖß Æïü :
Ag
+
(aq) + e
–
?? Ag(s) E° = +0.80 V
H
+
(aq) + e
–
??
1
2
H
2
(g) E° = 0.00 V
ˆ®ÖÛêú ´ÖÖ®ÖÛú †¯Ö“ÖµÖ®Ö ‡»ÖꌙÒüÖê›ü ×¾Ö³Ö¾Ö (E°) Ûêú ´ÖÖ®ÖÖë Ûêú †Ö¬ÖÖ¸ü ¯Ö¸ü Ûîú£ÖÖê›ü ¯Ö¸ü ×ÛúÃÖ †×³Ö×ÛÎúµÖÖ Ûúß
ÃÖÓ³ÖÖ¾Ö®ÖÖ Æîü †Öî¸ü ŒµÖÖë ?
(b) ÃÖß´ÖÖÓŸÖ ´ÖÖê»Ö¸ü “ÖÖ»ÖÛúŸÖÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ×¾ÖªãŸÖË †¯Ö‘Ö™ËüµÖ Ûúß “ÖÖ»ÖÛúŸÖÖ ÃÖÖÓ¦üÞÖ Ûêú ‘Ö™ü®Öê Ûêú ÃÖÖ£Ö
ŒµÖÖë Ûú´Ö ÆüÖê®Öê »ÖÝÖŸÖß Æîü ? 2
(a) Following reactions occur at cathode during the electrolysis of aqueous silver
chloride solution :
Ag
+
(aq) + e
–
?? Ag(s) E° = +0.80 V
H
+
(aq) + e
–
??
1
2
H
2
(g) E° = 0.00 V
On the basis of their standard reduction electrode potential (E°) values, which
reaction is feasible at the cathode and why ?
(b) Define limiting molar conductivity. Why conductivity of an electrolyte solution
decreases with the decrease in concentration ?
9. ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾Ö ŒµÖÖ Æïü ? ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾ÖÖë Ûúß ¤üÖê ×¾Ö¿ÖêÂÖŸÖÖ†Öë ÛúÖê ×»Ö×ÜÖ‹ … 2
What are the transition elements ? Write two characteristics of the transition elements.
10. (i) ÛúÖò´¯»ÖêŒÃÖ [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö
×»Ö×ÜÖµÖê …
(ii) ×®Ö´®Ö ÛúÖò´¯»ÖêŒÃÖ ÛúÖ ÃÖæ¡Ö ×»Ö×ÜÖ‹ :
¯Öê®™üÖ‹ê´ÖÖ‡®Ö®ÖÖ‡™ÒüÖ‡™üÖê-o-ÛúÖê²ÖÖ»™ü (III). 2
(i) Write down the IUPAC name of the following complex :
[Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine)
(ii) Write the formula for the following complex :
Pentaamminenitrito-o-Cobalt (III).
56/1/2/D 5 [P.T.O.
11. (i) ÛúÖò´¯»ÖêŒÃÖ [Pt(NH
3
)
2
Cl
2
] Ûêú •µÖÖ×´ÖŸÖßµÖ ÃÖ´ÖÖ¾ÖµÖ¾Ö ÛúÖê †Ö¸êü×ÜÖŸÖ Ûúßו֋ …
(ii) ×ÛÎúÙü»Ö ±úß»›ü ×ÃÖ¨üÖ®ŸÖ Ûêú †Ö¬ÖÖ¸ü ¯Ö¸ü µÖפü ?
o
< P ÆüÖê ŸÖÖê d
4
ÛúÖ ‡»ÖꌙÒüÖò®Ö ×¾Ö®µÖÖÃÖ ×»Ö×ÜÖ‹ …
(iii) ÛúÖò´¯»ÖêŒÃÖ [Ni(CO)
4
] ÛúÖ ÃÖÓÛú¸üÞÖ †Öî¸ü “Öã´²ÖÛúßµÖ ¯ÖÏÛéú×ŸÖ ×»Ö×ÜÖ‹ … (¯Ö.ÃÖÓ. Ni = 28) 3
(i) Draw the geometrical isomers of complex [Pt(NH
3
)
2
Cl
2
].
(ii) On the basis of crystal field theory, write the electronic configuration for d
4
ion
if ?
o
< P.
(iii) Write the hybridization and magnetic behaviour of the complex [Ni(CO)
4
].
(At.no. of Ni = 28)
12. ×®Ö´®Ö ÃÖê»Ö Ûúß 25 °C ¯Ö¸ü emf ¯Ö׸üÛú×»ÖŸÖ Ûúßו֋ :
Fe | Fe
2+
(0.001 M) || H
+
(0.01 M) | H
2
(g) (1 bar) | Pt(s)
E°(Fe
2+
| Fe) = –0.44 V E°(H
+
| H
2
) = 0.00 V 3
Calculate emf of the following cell at 25 °C :
Fe | Fe
2+
(0.001 M) || H
+
(0.01 M) | H
2
(g) (1 bar) | Pt(s)
E°(Fe
2+
| Fe) = –0.44 V E°(H
+
| H
2
) = 0.00 V
13. ×®Ö´®Ö †¾Ö»ÖÖêÛú®ÖÖë Ûêú ×»ÖµÖê ÛúÖ¸üÞÖ ¤üßו֋ :
(i) “Ö´ÖÔ¿ÖÖê¬Ö®Ö Ûêú ²ÖÖ¤ü “Ö´Ö›ÌüÖ ÃÖÜŸÖ ÆüÖê •ÖÖŸÖÖ Æîü …
(ii) ¦ü¾Ö ×¾Ö¸üÖê¬Öß ÃÖÖò»Ö Ûúß †¯ÖêõÖÖ ¦ü¾ÖîÖêÆüß ÃÖÖò»Ö †×¬ÖÛú ãÖÖµÖß ÆüÖêŸÖÖ Æîü …
(iii) •Ö²Ö Æîü²Ö¸ü ¯ÖÏÛÎú´Ö «üÖ¸üÖ †´ÖÖê×®ÖµÖÖ ²Ö®ÖÖµÖÖ •ÖÖŸÖÖ Æîü ŸÖ²Ö CO ÛúÖê ¤æü¸ü ¸üÜÖ®ÖÖ †Ö¾Ö¿µÖÛú ÆüÖêŸÖÖ Æîü … 3
Give reasons for the following observations :
(i) Leather gets hardened after tanning.
(ii) Lyophilic sol is more stable than lyophobic sol.
(iii) It is necessary to remove CO when ammonia is prepared by Haber’s process.
14. ×®Ö´®Ö ²ÖÆãü»ÖÛúÖë Ûêú ‹Ûú»ÖÛúÖë Ûêú ®ÖÖ´Ö ¾Ö ˆ®ÖÛúß ÃÖÓ¸ü“Ö®ÖÖµÖë ×»Ö×ÜÖ‹ :
(i) ®ÖÖµÖ»ÖÖò®Ö-6, 6
(ii) PHBV
(iii) ®Ö߆Öê¯ÖÏß®Ö 3
Write the names and structures of the monomers of the following polymers :
(i) Nylon-6, 6
(ii) PHBV
(iii) Neoprene
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FAQs on Past Year Paper, Chemistry (Set - 1 ), Delhi, 2015, Class 12, Chemistry - Additional Study Material for Class 12
| 1. What is the importance of studying past year papers for the Class 12 Chemistry exam in Delhi? |  |
Ans. Studying past year papers for the Class 12 Chemistry exam in Delhi is important as it helps students understand the pattern of questions asked in the exam. By going through these papers, students can identify the important topics and concepts that are frequently asked. It also gives them an idea of the level of difficulty of the questions and helps them prepare accordingly.
| 2. How can studying past year papers in Chemistry help improve my exam performance? | |
Ans. Studying past year papers in Chemistry can help improve exam performance in several ways. Firstly, it familiarizes students with the format and structure of the question paper, enabling them to manage their time effectively during the exam. Secondly, it helps students identify their weak areas and focus on improving them. By practicing questions from previous years, students can gain confidence and develop a better understanding of the subject. Additionally, studying past year papers allows students to assess their level of preparation and make necessary adjustments to their study plan.
| 3. Are there any specific topics that are frequently asked in the Class 12 Chemistry exam in Delhi? | |
Ans. Yes, there are certain topics that are frequently asked in the Class 12 Chemistry exam in Delhi. Some of these topics include chemical bonding, coordination compounds, biomolecules, electrochemistry, and organic chemistry. It is important for students to pay special attention to these topics and ensure they have a thorough understanding of the concepts and principles associated with them.
| 4. How can I make the best use of past year papers for the Class 12 Chemistry exam in Delhi? | |
Ans. To make the best use of past year papers for the Class 12 Chemistry exam in Delhi, students can follow these steps:
1. Start by going through the entire question paper to understand the pattern and types of questions asked.
2. Identify the topics that have been frequently asked in previous years and focus on revising them.
3. Attempt the questions from past year papers under exam-like conditions to improve time management and familiarity with the exam format.
4. Analyze your performance in these practice tests and identify areas where you need improvement.
5. Use the past year papers as a tool for self-assessment and practice regularly to build confidence and improve your understanding of the subject.
| 5. Can studying past year papers alone guarantee success in the Class 12 Chemistry exam in Delhi? | |
Ans. Studying past year papers alone cannot guarantee success in the Class 12 Chemistry exam in Delhi. While they are a valuable resource for exam preparation, it is important to have a comprehensive understanding of the subject. Students should also refer to their textbooks, class notes, and other study materials to ensure they have covered all the necessary topics and concepts. Additionally, practicing numerical problems, solving sample papers, and seeking guidance from teachers can further enhance exam performance.
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