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56/1/2/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No. 
 
 
 
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
CHEMISTRY (Theory) 
    
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö : 
 (i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …  
 (iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …  
 (vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà    
Æîü …  
 Series : SSO/1 
ÛúÖê›ü ®ÖÓ. 
Code No.  
    
56/1/2/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …  
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 12 printed pages.  
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the 
question paper and will not write any answer on the answer-book during this period. 
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 2 
Page 2


56/1/2/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No. 
 
 
 
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
CHEMISTRY (Theory) 
    
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö : 
 (i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …  
 (iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …  
 (vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà    
Æîü …  
 Series : SSO/1 
ÛúÖê›ü ®ÖÓ. 
Code No.  
    
56/1/2/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …  
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 12 printed pages.  
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the 
question paper and will not write any answer on the answer-book during this period. 
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 2 
56/1/2/D 2  
General Instructions : 
 (i) All questions are compulsory. 
 (ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each. 
 (iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each. 
 (iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each. 
 (v) Q. no. 23 is a value based question and carry 4 marks. 
 (vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each. 
 (vii) Use log tables if necessary, use of calculators is not allowed. 
 
1. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1 
  CH
3
 – CH
2
 – Br ŸÖ£ÖÖ CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 Which would undergo S
N
2 reaction faster in the following pair and why ? 
  CH
3
 – CH
2
 – Br and CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 
2. BaCl
2
 †Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê 
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1 
 Out of BaCl
2
 and KCl, which one is more effective in causing coagulation of a 
negatively charged colloidal Sol ? Give reason. 
 
3. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ 
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü  ?  1 
 What is the formula of a compound in which the element Y forms ccp lattice and 
atoms of X occupy 1/3
rd
 of tetrahedral voids ? 
Page 3


56/1/2/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No. 
 
 
 
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
CHEMISTRY (Theory) 
    
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö : 
 (i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …  
 (iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …  
 (vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà    
Æîü …  
 Series : SSO/1 
ÛúÖê›ü ®ÖÓ. 
Code No.  
    
56/1/2/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …  
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 12 printed pages.  
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the 
question paper and will not write any answer on the answer-book during this period. 
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 2 
56/1/2/D 2  
General Instructions : 
 (i) All questions are compulsory. 
 (ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each. 
 (iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each. 
 (iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each. 
 (v) Q. no. 23 is a value based question and carry 4 marks. 
 (vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each. 
 (vii) Use log tables if necessary, use of calculators is not allowed. 
 
1. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1 
  CH
3
 – CH
2
 – Br ŸÖ£ÖÖ CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 Which would undergo S
N
2 reaction faster in the following pair and why ? 
  CH
3
 – CH
2
 – Br and CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 
2. BaCl
2
 †Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê 
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1 
 Out of BaCl
2
 and KCl, which one is more effective in causing coagulation of a 
negatively charged colloidal Sol ? Give reason. 
 
3. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ 
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü  ?  1 
 What is the formula of a compound in which the element Y forms ccp lattice and 
atoms of X occupy 1/3
rd
 of tetrahedral voids ? 
56/1/2/D 3 [P.T.O. 
4. H
3
PO
4
 Ûúß õÖÖ¸üÛúŸÖÖ ŒµÖÖ Æîü ? 1 
 What is the basicity of H
3
PO
4
 ? 
 
5. פüµÖê ÝÖµÖê µÖÖî×ÝÖÛú ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö ×»Ö×ÜÖ‹ : 1 
    
 Write the IUPAC name of the given compound : 
    
  
 
6. ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ†Öë ´Öë ¯ÖϵÖãŒŸÖ †×³ÖÛúÖ¸üÛúÖë Ûêú ®ÖÖ´Ö ¤üßו֋ : 2 
 Name the reagents used in the following reactions : 
 (i) CH
3
 – CO – CH
3
 
?
??? CH
3
 – C
|
O
H
H
 – CH
3
 
 (ii) C
6
H
5
 – CH
2
 – CH
3 
?
??? C
6
H
5
 – COO
–
K
+ 
 
7. ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ŒµÖÖ ŸÖÖŸ¯ÖµÖÔ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö Ûêú ×»ÖµÖê  
?
mix
H ÛúÖ ×“ÖÅ®Öü ŒµÖÖ Æîü ? 2 
 What is meant by positive deviations from Raoult’s law ? Give an example. What is 
the sign of ?
mix
H for positive deviation ? 
†£Ö¾ÖÖ/OR 
7. ‹×•ÖµÖÖê™ÒüÖê¯ÃÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ¯ÖÏÖ¯ŸÖ ‹×•ÖµÖÖê™ÒüÖê¯Ö ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ÛúÖ 
ÆüÖêŸÖÖ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ …  2 
 Define azeotropes. What type of azeotrope is formed by positive deviation from 
Raoult’s law ? Give an example. 
Page 4


56/1/2/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No. 
 
 
 
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
CHEMISTRY (Theory) 
    
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö : 
 (i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …  
 (iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …  
 (vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà    
Æîü …  
 Series : SSO/1 
ÛúÖê›ü ®ÖÓ. 
Code No.  
    
56/1/2/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …  
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 12 printed pages.  
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the 
question paper and will not write any answer on the answer-book during this period. 
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 2 
56/1/2/D 2  
General Instructions : 
 (i) All questions are compulsory. 
 (ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each. 
 (iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each. 
 (iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each. 
 (v) Q. no. 23 is a value based question and carry 4 marks. 
 (vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each. 
 (vii) Use log tables if necessary, use of calculators is not allowed. 
 
1. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1 
  CH
3
 – CH
2
 – Br ŸÖ£ÖÖ CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 Which would undergo S
N
2 reaction faster in the following pair and why ? 
  CH
3
 – CH
2
 – Br and CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 
2. BaCl
2
 †Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê 
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1 
 Out of BaCl
2
 and KCl, which one is more effective in causing coagulation of a 
negatively charged colloidal Sol ? Give reason. 
 
3. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ 
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü  ?  1 
 What is the formula of a compound in which the element Y forms ccp lattice and 
atoms of X occupy 1/3
rd
 of tetrahedral voids ? 
56/1/2/D 3 [P.T.O. 
4. H
3
PO
4
 Ûúß õÖÖ¸üÛúŸÖÖ ŒµÖÖ Æîü ? 1 
 What is the basicity of H
3
PO
4
 ? 
 
5. פüµÖê ÝÖµÖê µÖÖî×ÝÖÛú ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö ×»Ö×ÜÖ‹ : 1 
    
 Write the IUPAC name of the given compound : 
    
  
 
6. ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ†Öë ´Öë ¯ÖϵÖãŒŸÖ †×³ÖÛúÖ¸üÛúÖë Ûêú ®ÖÖ´Ö ¤üßו֋ : 2 
 Name the reagents used in the following reactions : 
 (i) CH
3
 – CO – CH
3
 
?
??? CH
3
 – C
|
O
H
H
 – CH
3
 
 (ii) C
6
H
5
 – CH
2
 – CH
3 
?
??? C
6
H
5
 – COO
–
K
+ 
 
7. ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ŒµÖÖ ŸÖÖŸ¯ÖµÖÔ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö Ûêú ×»ÖµÖê  
?
mix
H ÛúÖ ×“ÖÅ®Öü ŒµÖÖ Æîü ? 2 
 What is meant by positive deviations from Raoult’s law ? Give an example. What is 
the sign of ?
mix
H for positive deviation ? 
†£Ö¾ÖÖ/OR 
7. ‹×•ÖµÖÖê™ÒüÖê¯ÃÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ¯ÖÏÖ¯ŸÖ ‹×•ÖµÖÖê™ÒüÖê¯Ö ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ÛúÖ 
ÆüÖêŸÖÖ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ …  2 
 Define azeotropes. What type of azeotrope is formed by positive deviation from 
Raoult’s law ? Give an example. 
56/1/2/D 4  
8. (a) ×ÃÖ»¾Ö¸ü Œ»ÖÖê¸üÖ‡›ü Ûêú •Ö»ÖßµÖ ×¾Ö»ÖµÖ®Ö Ûêú ×¾ÖªãŸÖ †¯Ö‘Ö™ü®Ö ´Öë Ûîú£ÖÖê›ü ¯Ö¸ü ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ‹Ñ ÆüÖêŸÖß Æïü :   
   Ag
+
(aq) + e
–
 ?? Ag(s) E° = +0.80 V 
   H
+
(aq) + e
–
 ?? 
1
2
H
2
(g) E° = 0.00 V 
  ˆ®ÖÛêú ´ÖÖ®ÖÛú †¯Ö“ÖµÖ®Ö ‡»ÖꌙÒüÖê›ü ×¾Ö³Ö¾Ö (E°) Ûêú ´ÖÖ®ÖÖë Ûêú †Ö¬ÖÖ¸ü ¯Ö¸ü Ûîú£ÖÖê›ü ¯Ö¸ü ×ÛúÃÖ †×³Ö×ÛÎúµÖÖ Ûúß 
ÃÖÓ³ÖÖ¾Ö®ÖÖ Æîü †Öî¸ü ŒµÖÖë ? 
 (b) ÃÖß´ÖÖÓŸÖ ´ÖÖê»Ö¸ü “ÖÖ»ÖÛúŸÖÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ×¾ÖªãŸÖË †¯Ö‘Ö™ËüµÖ Ûúß “ÖÖ»ÖÛúŸÖÖ ÃÖÖÓ¦üÞÖ Ûêú ‘Ö™ü®Öê Ûêú ÃÖÖ£Ö 
ŒµÖÖë Ûú´Ö ÆüÖê®Öê »ÖÝÖŸÖß Æîü ?  2 
 (a) Following reactions occur at cathode during the electrolysis of aqueous silver 
chloride solution : 
   Ag
+
(aq) + e
–
 ?? Ag(s) E° = +0.80 V 
   H
+
(aq) + e
–
 ?? 
1
2
H
2
(g) E° = 0.00 V 
  On the basis of their standard reduction electrode potential (E°) values, which 
reaction is feasible at the cathode and why ? 
 (b) Define limiting molar conductivity. Why conductivity of an electrolyte solution 
decreases with the decrease in concentration ? 
 
9. ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾Ö ŒµÖÖ Æïü ? ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾ÖÖë Ûúß ¤üÖê ×¾Ö¿ÖêÂÖŸÖÖ†Öë ÛúÖê ×»Ö×ÜÖ‹ …  2 
 What are the transition elements ? Write two characteristics of the transition elements. 
 
10. (i) ÛúÖò´¯»ÖêŒÃÖ [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö    
×»Ö×ÜÖµÖê …  
 (ii) ×®Ö´®Ö ÛúÖò´¯»ÖêŒÃÖ ÛúÖ ÃÖæ¡Ö ×»Ö×ÜÖ‹ :  
  ¯Öê®™üÖ‹ê´ÖÖ‡®Ö®ÖÖ‡™ÒüÖ‡™üÖê-o-ÛúÖê²ÖÖ»™ü (III). 2 
 (i) Write down the IUPAC name of the following complex :  
  [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) 
 (ii) Write the formula for the following complex :  
  Pentaamminenitrito-o-Cobalt (III). 
Page 5


56/1/2/D 1 [P.T.O. 
 
 
 
 
¸üÖê»Ö ®ÖÓ. 
Roll No. 
 
 
 
¸üÃÖÖµÖ®Ö ×¾Ö–ÖÖ®Ö (ÃÖî¨üÖ×®ŸÖÛú) 
CHEMISTRY (Theory) 
    
×®Ö¬ÖÖÔ׸üŸÖ ÃÖ´ÖµÖ : 3 ‘ÖÞ™êüü] [†×¬ÖÛúŸÖ´Ö †ÓÛúú : 70 
Time allowed : 3 hours ] [ Maximum Marks : 70 
 
ÃÖÖ´ÖÖ®µÖ ×®Ö¤ìü¿Ö : 
 (i) ÃÖ³Öß ¯ÖÏ¿®Ö †×®Ö¾ÖÖµÖÔ Æïü …  
 (ii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 1 ÃÖê 5 ŸÖÛú †×ŸÖ »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 1 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æîü …  
 (iii) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 6 ÃÖê 10 ŸÖÛú »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 2 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (iv) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 11 ÃÖê 22 ŸÖÛú ³Öß »Ö‘Öã-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 3 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (v) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 23 ´Ö滵ÖÖ¬ÖÖ׸üŸÖ ¯ÖÏ¿®Ö Æîü †Öî¸ü ‡ÃÖÛêú ×»Ö‹ 4 †ÓÛú ×®Ö¬ÖÖÔ׸üŸÖ Æïü …  
 (vi) ¯ÖÏ¿®Ö-ÃÖÓܵÖÖ 24 ÃÖê 26 ¤üß‘ÖÔ-ˆ¢Ö¸üßµÖ ¯ÖÏ¿®Ö Æïü … ¯ÖÏŸµÖêÛú ¯ÖÏ¿®Ö Ûêú ×»Ö‹ 5 †ÓÛú Æïü …  
 (vii) µÖפü †Ö¾Ö¿µÖÛú ÆüÖê ŸÖÖê »ÖÖòÝÖ ™êü²Ö»Ö ÛúÖ ˆ¯ÖµÖÖêÝÖ Ûú¸ü ÃÖÛúŸÖê Æïü … Ûîú»ÖÛãú»Öê™ü¸ü Ûêú ˆ¯ÖµÖÖêÝÖ Ûúß †®Öã´Ö×ŸÖ ®ÖÆüà    
Æîü …  
 Series : SSO/1 
ÛúÖê›ü ®ÖÓ. 
Code No.  
    
56/1/2/D
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ´ÖãצüŸÖ ¯Öéšü 12 Æïü …  
• ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë ¤üÖ×Æü®Öê ÆüÖ£Ö Ûúß †Öê¸ü פü‹ ÝÖ‹ ÛúÖê›ü ®Ö´²Ö¸ü ÛúÖê ”ûÖ¡Ö ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü ¯Ö¸ü ×»ÖÜÖë …  
• Ûéú¯ÖµÖÖ •ÖÖÑ“Ö Ûú¸ü »Öë ×Ûú ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ´Öë 26 ¯ÖÏ¿®Ö Æïü …  
• Ûéú¯ÖµÖÖ ¯ÖÏ¿®Ö ÛúÖ ˆ¢Ö¸ü ×»ÖÜÖ®ÖÖ ¿Öãºþ Ûú¸ü®Öê ÃÖê ¯ÖÆü»Öê, ¯ÖÏ¿®Ö ÛúÖ ÛÎú´ÖÖÓÛú †¾Ö¿µÖ ×»ÖÜÖë …  
• ‡ÃÖ ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖê ¯ÖœÌü®Öê Ûêú ×»Ö‹ 15 ×´Ö®Ö™ü ÛúÖ ÃÖ´ÖµÖ ×¤üµÖÖ ÝÖµÖÖ Æîü … ¯ÖÏ¿®Ö-¯Ö¡Ö ÛúÖ ×¾ÖŸÖ¸üÞÖ ¯Öæ¾ÖÖÔÆËü®Ö ´Öë 10.15 ²Ö•Öê 
×ÛúµÖÖ •ÖÖµÖêÝÖÖ … 10.15 ²Ö•Öê ÃÖê 10.30 ²Ö•Öê ŸÖÛú ”ûÖ¡Ö Ûêú¾Ö»Ö ¯ÖÏ¿®Ö-¯Ö¡Ö ¯ÖœÌëüÝÖê †Öî¸ü ‡ÃÖ †¾Ö×¬Ö Ûêú ¤üÖî¸üÖ®Ö ¾Öê ˆ¢Ö¸ü-
¯Öã×ßÖÛúÖ ¯Ö¸ü ÛúÖê‡Ô ˆ¢Ö¸ü ®ÖÆüà ×»ÖÜÖëÝÖê …  
• Please check that this question paper contains 12 printed pages.  
• Code number given on the right hand side of the question paper should be written on the 
title page of the answer-book by the candidate. 
• Please check that this question paper contains 26 questions. 
• Please write down the Serial Number of the question before attempting it. 
• 15 minutes time has been allotted to read this question paper. The question paper will be 
distributed at 10.15 a.m. From 10.15 a.m. to 10.30 a.m., the students will only read the 
question paper and will not write any answer on the answer-book during this period. 
¯Ö¸üßõÖÖ£Öá ÛúÖê›ü ÛúÖê ˆ¢Ö¸ü-¯Öã×ßÖÛúÖ Ûêú ´ÖãÜÖ-¯Öéšü 
¯Ö¸ü †¾Ö¿µÖ ×»ÖÜÖë … 
Candidates must write the Code on 
the title page of the answer-book. 
 
SET – 2 
56/1/2/D 2  
General Instructions : 
 (i) All questions are compulsory. 
 (ii) Q. no. 1 to 5 are very short answer questions and carry 1 mark each. 
 (iii) Q. no. 6 to 10 are short answer questions and carry 2 marks each. 
 (iv) Q. no. 11 to 22 are also short answer questions and carry 3 marks each. 
 (v) Q. no. 23 is a value based question and carry 4 marks. 
 (vi) Q. no. 24 to 26 are long answer questions and carry 5 marks each. 
 (vii) Use log tables if necessary, use of calculators is not allowed. 
 
1. ×®Ö´®Ö µÖãÝ´Ö ´Öë ÛúÖî®Ö S
N
2 †×³Ö×ÛÎúµÖÖ †×¬ÖÛú ŸÖß¾ÖΟÖÖ ÃÖê Ûú¸êüÝÖÖ †Öî¸ü ŒµÖÖë ? 1 
  CH
3
 – CH
2
 – Br ŸÖ£ÖÖ CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 Which would undergo S
N
2 reaction faster in the following pair and why ? 
  CH
3
 – CH
2
 – Br and CH
3
 – 
C
|
C
|
B
H
3
 –
r
CH
3 
 
2. BaCl
2
 †Öî¸ü KCl ´Öë ÃÖê ÛúÖî®Ö ŠúÞÖÖŸ´ÖÛú “ÖÖ•ÖÔ ¾ÖÖ»Öê ÛúÖê»ÖÖ‡›üß ÃÖÖò»Ö ÛúÖ ÃÛÓú¤ü®Ö †×¬ÖÛú ¯ÖϳÖÖ¾Ö¿ÖÖ»Öß œÓüÝÖ ÃÖê 
Ûú¸êüÝÖÖ ? ÛúÖ¸üÞÖ ¤üßו֋ … 1 
 Out of BaCl
2
 and KCl, which one is more effective in causing coagulation of a 
negatively charged colloidal Sol ? Give reason. 
 
3. ˆÃÖ µÖÖî×ÝÖÛú ÛúÖ ÃÖæ¡Ö ŒµÖÖ ÆüÖêÝÖÖ ×•ÖÃÖ´Öë Y ŸÖ¢¾Ö ccp •ÖÖ»ÖÛú ²Ö®ÖÖŸÖÖ Æîü †Öî¸ü X “ÖŸÖã±ú»ÖÛúßµÖ ×¸ü׌ŸÖ ÛúÖ 1/3¾ÖÖÑ 
³ÖÖÝÖ ‘Öê¸üŸÖÖ Æîü  ?  1 
 What is the formula of a compound in which the element Y forms ccp lattice and 
atoms of X occupy 1/3
rd
 of tetrahedral voids ? 
56/1/2/D 3 [P.T.O. 
4. H
3
PO
4
 Ûúß õÖÖ¸üÛúŸÖÖ ŒµÖÖ Æîü ? 1 
 What is the basicity of H
3
PO
4
 ? 
 
5. פüµÖê ÝÖµÖê µÖÖî×ÝÖÛú ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö ×»Ö×ÜÖ‹ : 1 
    
 Write the IUPAC name of the given compound : 
    
  
 
6. ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ†Öë ´Öë ¯ÖϵÖãŒŸÖ †×³ÖÛúÖ¸üÛúÖë Ûêú ®ÖÖ´Ö ¤üßו֋ : 2 
 Name the reagents used in the following reactions : 
 (i) CH
3
 – CO – CH
3
 
?
??? CH
3
 – C
|
O
H
H
 – CH
3
 
 (ii) C
6
H
5
 – CH
2
 – CH
3 
?
??? C
6
H
5
 – COO
–
K
+ 
 
7. ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ŒµÖÖ ŸÖÖŸ¯ÖµÖÔ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ … ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö Ûêú ×»ÖµÖê  
?
mix
H ÛúÖ ×“ÖÅ®Öü ŒµÖÖ Æîü ? 2 
 What is meant by positive deviations from Raoult’s law ? Give an example. What is 
the sign of ?
mix
H for positive deviation ? 
†£Ö¾ÖÖ/OR 
7. ‹×•ÖµÖÖê™ÒüÖê¯ÃÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ¸üÖˆ»™ü ×®ÖµÖ´Ö ÃÖê ¬Ö®ÖÖŸ´ÖÛú ×¾Ö“Ö»Ö®Ö ÃÖê ¯ÖÏÖ¯ŸÖ ‹×•ÖµÖÖê™ÒüÖê¯Ö ×ÛúÃÖ ¯ÖÏÛúÖ¸ü ÛúÖ 
ÆüÖêŸÖÖ Æîü ? ‹Ûú ˆ¤üÖÆü¸üÞÖ ¤üßו֋ …  2 
 Define azeotropes. What type of azeotrope is formed by positive deviation from 
Raoult’s law ? Give an example. 
56/1/2/D 4  
8. (a) ×ÃÖ»¾Ö¸ü Œ»ÖÖê¸üÖ‡›ü Ûêú •Ö»ÖßµÖ ×¾Ö»ÖµÖ®Ö Ûêú ×¾ÖªãŸÖ †¯Ö‘Ö™ü®Ö ´Öë Ûîú£ÖÖê›ü ¯Ö¸ü ×®Ö´®Ö †×³Ö×ÛÎúµÖÖ‹Ñ ÆüÖêŸÖß Æïü :   
   Ag
+
(aq) + e
–
 ?? Ag(s) E° = +0.80 V 
   H
+
(aq) + e
–
 ?? 
1
2
H
2
(g) E° = 0.00 V 
  ˆ®ÖÛêú ´ÖÖ®ÖÛú †¯Ö“ÖµÖ®Ö ‡»ÖꌙÒüÖê›ü ×¾Ö³Ö¾Ö (E°) Ûêú ´ÖÖ®ÖÖë Ûêú †Ö¬ÖÖ¸ü ¯Ö¸ü Ûîú£ÖÖê›ü ¯Ö¸ü ×ÛúÃÖ †×³Ö×ÛÎúµÖÖ Ûúß 
ÃÖÓ³ÖÖ¾Ö®ÖÖ Æîü †Öî¸ü ŒµÖÖë ? 
 (b) ÃÖß´ÖÖÓŸÖ ´ÖÖê»Ö¸ü “ÖÖ»ÖÛúŸÖÖ ÛúÖê ¯Ö׸ü³ÖÖ×ÂÖŸÖ Ûúßו֋ … ×¾ÖªãŸÖË †¯Ö‘Ö™ËüµÖ Ûúß “ÖÖ»ÖÛúŸÖÖ ÃÖÖÓ¦üÞÖ Ûêú ‘Ö™ü®Öê Ûêú ÃÖÖ£Ö 
ŒµÖÖë Ûú´Ö ÆüÖê®Öê »ÖÝÖŸÖß Æîü ?  2 
 (a) Following reactions occur at cathode during the electrolysis of aqueous silver 
chloride solution : 
   Ag
+
(aq) + e
–
 ?? Ag(s) E° = +0.80 V 
   H
+
(aq) + e
–
 ?? 
1
2
H
2
(g) E° = 0.00 V 
  On the basis of their standard reduction electrode potential (E°) values, which 
reaction is feasible at the cathode and why ? 
 (b) Define limiting molar conductivity. Why conductivity of an electrolyte solution 
decreases with the decrease in concentration ? 
 
9. ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾Ö ŒµÖÖ Æïü ? ÃÖÓÛÎú´ÖÞÖ ŸÖŸ¾ÖÖë Ûúß ¤üÖê ×¾Ö¿ÖêÂÖŸÖÖ†Öë ÛúÖê ×»Ö×ÜÖ‹ …  2 
 What are the transition elements ? Write two characteristics of the transition elements. 
 
10. (i) ÛúÖò´¯»ÖêŒÃÖ [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) ÛúÖ †Ö‡Ô.µÖæ.¯Öß.‹.ÃÖß. ®ÖÖ´Ö    
×»Ö×ÜÖµÖê …  
 (ii) ×®Ö´®Ö ÛúÖò´¯»ÖêŒÃÖ ÛúÖ ÃÖæ¡Ö ×»Ö×ÜÖ‹ :  
  ¯Öê®™üÖ‹ê´ÖÖ‡®Ö®ÖÖ‡™ÒüÖ‡™üÖê-o-ÛúÖê²ÖÖ»™ü (III). 2 
 (i) Write down the IUPAC name of the following complex :  
  [Cr(NH
3
)
2
Cl
2
(en)]Cl (en = ethylenediamine) 
 (ii) Write the formula for the following complex :  
  Pentaamminenitrito-o-Cobalt (III). 
56/1/2/D 5 [P.T.O. 
11. (i) ÛúÖò´¯»ÖêŒÃÖ [Pt(NH
3
)
2
Cl
2
] Ûêú •µÖÖ×´ÖŸÖßµÖ ÃÖ´ÖÖ¾ÖµÖ¾Ö ÛúÖê †Ö¸êü×ÜÖŸÖ Ûúßו֋ …  
 (ii) ×ÛÎúÙü»Ö ±úß»›ü ×ÃÖ¨üÖ®ŸÖ Ûêú †Ö¬ÖÖ¸ü ¯Ö¸ü µÖפü ?
o
 < P ÆüÖê ŸÖÖê d
4
 ÛúÖ ‡»ÖꌙÒüÖò®Ö ×¾Ö®µÖÖÃÖ ×»Ö×ÜÖ‹ …  
 (iii) ÛúÖò´¯»ÖêŒÃÖ [Ni(CO)
4
] ÛúÖ ÃÖÓÛú¸üÞÖ †Öî¸ü “Öã´²ÖÛúßµÖ ¯ÖÏÛéú×ŸÖ ×»Ö×ÜÖ‹ … (¯Ö.ÃÖÓ. Ni = 28) 3 
 (i) Draw the geometrical isomers of complex [Pt(NH
3
)
2
Cl
2
]. 
 (ii) On the basis of crystal field theory, write the electronic configuration for d
4
 ion 
if ?
o
 < P. 
 (iii) Write the hybridization and magnetic behaviour of the complex [Ni(CO)
4
]. 
  (At.no. of Ni = 28) 
 
12. ×®Ö´®Ö ÃÖê»Ö Ûúß 25 °C ¯Ö¸ü emf ¯Ö׸üÛú×»ÖŸÖ Ûúßו֋ : 
 Fe | Fe
2+
(0.001 M) || H
+
(0.01 M) | H
2
(g) (1 bar) | Pt(s) 
 E°(Fe
2+
 | Fe) = –0.44 V   E°(H
+ 
| H
2
) = 0.00 V 3 
 Calculate emf of the following cell at 25 °C : 
 Fe | Fe
2+
(0.001 M) || H
+
(0.01 M) | H
2
(g) (1 bar) | Pt(s) 
 E°(Fe
2+
 | Fe) = –0.44 V   E°(H
+ 
| H
2
) = 0.00 V 
 
13. ×®Ö´®Ö †¾Ö»ÖÖêÛú®ÖÖë Ûêú ×»ÖµÖê ÛúÖ¸üÞÖ ¤üßו֋ : 
 (i) “Ö´ÖÔ¿ÖÖê¬Ö®Ö Ûêú ²ÖÖ¤ü “Ö´Ö›ÌüÖ ÃÖÜŸÖ ÆüÖê •ÖÖŸÖÖ Æîü …  
 (ii) ¦ü¾Ö ×¾Ö¸üÖê¬Öß ÃÖÖò»Ö Ûúß †¯ÖêõÖÖ ¦ü¾ÖîÖêÆüß ÃÖÖò»Ö †×¬ÖÛú ãÖÖµÖß ÆüÖêŸÖÖ Æîü …  
 (iii) •Ö²Ö Æîü²Ö¸ü ¯ÖÏÛÎú´Ö «üÖ¸üÖ †´ÖÖê×®ÖµÖÖ ²Ö®ÖÖµÖÖ •ÖÖŸÖÖ Æîü ŸÖ²Ö CO ÛúÖê ¤æü¸ü ¸üÜÖ®ÖÖ †Ö¾Ö¿µÖÛú ÆüÖêŸÖÖ Æîü …  3 
 Give reasons for the following observations : 
 (i) Leather gets hardened after tanning. 
 (ii) Lyophilic sol is more stable than lyophobic sol. 
 (iii) It is necessary to remove CO when ammonia is prepared by Haber’s process. 
 
14. ×®Ö´®Ö ²ÖÆãü»ÖÛúÖë Ûêú ‹Ûú»ÖÛúÖë Ûêú ®ÖÖ´Ö ¾Ö ˆ®ÖÛúß ÃÖÓ¸ü“Ö®ÖÖµÖë ×»Ö×ÜÖ‹  : 
 (i) ®ÖÖµÖ»ÖÖò®Ö-6, 6 
 (ii) PHBV 
 (iii) ®Ö߆Öê¯ÖÏß®Ö    3 
 Write the names and structures of the monomers of the following polymers : 
 (i) Nylon-6, 6 
 (ii) PHBV 
 (iii) Neoprene 
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FAQs on Past Year Paper, Chemistry (Set - 2), Delhi, 2015, Class 12, Chemistry - Additional Study Material for Class 12

1. What is the significance of the Past Year Paper in the Chemistry Class 12 exam?
Ans. The Past Year Paper is significant in the Chemistry Class 12 exam as it allows students to understand the exam pattern, marking scheme, and types of questions that may be asked. It helps students in their exam preparation by providing them with an idea of the expected questions and allows them to practice solving them within the given time frame.
2. How can solving the Past Year Paper in Chemistry Class 12 help in improving exam performance?
Ans. Solving the Past Year Paper in Chemistry Class 12 can help improve exam performance by familiarizing students with the format and style of questions typically asked in the exam. It allows students to identify their weak areas and focus on them for further preparation. Additionally, solving the paper under timed conditions helps improve time management skills, enabling students to complete the actual exam within the given time limit.
3. What are the benefits of practicing with the Chemistry Class 12 Past Year Paper from Delhi Board?
Ans. Practicing with the Chemistry Class 12 Past Year Paper from Delhi Board offers several benefits. Firstly, it provides students with a clear understanding of the exam pattern and the type of questions that are frequently asked. Secondly, it helps students gauge their preparation level and identify areas where they need improvement. Lastly, it familiarizes students with the marking scheme, allowing them to strategize their answers accordingly for maximum marks.
4. Are the Chemistry Class 12 Past Year Papers from Delhi the same every year?
Ans. No, the Chemistry Class 12 Past Year Papers from Delhi are not the same every year. The questions may vary from year to year, although certain topics and concepts may be repeated. It is essential for students to solve multiple past year papers from different years to get a comprehensive understanding of the subject and be prepared for any type of question that may be asked in the actual exam.
5. How can one effectively utilize the Chemistry Class 12 Past Year Paper for exam preparation?
Ans. To effectively utilize the Chemistry Class 12 Past Year Paper for exam preparation, students should follow these steps: 1. Start by solving the paper under timed conditions to simulate the actual exam environment. 2. After completing the paper, thoroughly analyze the answers and compare them with the provided solutions or marking scheme. 3. Identify the areas where mistakes were made and revise those topics. 4. Pay attention to the types of questions that are frequently asked and practice similar questions from other sources. 5. Repeat the process with multiple past year papers to gain more exposure to different question patterns and improve overall understanding and performance.
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