JEE Exam > JEE Notes > Additional Study Material for JEE > Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths
Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths | Additional Study Material for JEE PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
CBSE Board
Class XII Mathematics
Board Paper – 2015 Solution
All India Set – 1
SECTION – A
1. ? ? ? ? ? ? Given that a 2i j 3k and b 3i 5j 2k
? ? ? ? ? ?
?
??
?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
2 2 2
We need to find a b
i j k
a b 2 1 3
3 5 2
i 2 15 j 4 9 k 10 3
17i 13j 7k
Hence, a b 17 13 7
a b 507
2. ? ? ? ? Let a i j; b j k
? ? ? ?
? ? ? ?
? ?
? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ?
? ? ?
? ? ?
? ? ?
?
? ? ? ?
? ? ? ?
2
22
2
22
a b i j j k 1 0 1 1 0 1 1
a 1 1 0 2
b 0 1 1 2
We know that a b a b cos
a b 1 1
Thus, cos =
2
22 ab
cos cos120
120
Page 2
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
CBSE Board
Class XII Mathematics
Board Paper – 2015 Solution
All India Set – 1
SECTION – A
1. ? ? ? ? ? ? Given that a 2i j 3k and b 3i 5j 2k
? ? ? ? ? ?
?
??
?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
2 2 2
We need to find a b
i j k
a b 2 1 3
3 5 2
i 2 15 j 4 9 k 10 3
17i 13j 7k
Hence, a b 17 13 7
a b 507
2. ? ? ? ? Let a i j; b j k
? ? ? ?
? ? ? ?
? ?
? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ?
? ? ?
? ? ?
? ? ?
?
? ? ? ?
? ? ? ?
2
22
2
22
a b i j j k 1 0 1 1 0 1 1
a 1 1 0 2
b 0 1 1 2
We know that a b a b cos
a b 1 1
Thus, cos =
2
22 ab
cos cos120
120
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
3. Consider the vector equation of the plane.
? ?
? ? ? ?
? ?
? ? ? ?
? ? ? ? ? ? ?
? ? ? ?
? ? ? ? ?
? ? ? ?
?
? ? ?
1 1 1
r 6i 3j 2k 4
xi yj zk 6i 3j 2k 4
6x 3y 2z 4
6x 3y 2z 4 0
Thus the Cartesian equation of the plane is
6x 3y 2z 4 0
Let d be the distance between the point 2, 5, 3
to the plane.
ax by cz d
Thus, d=
a
? ?
? ?
??
? ? ? ? ? ? ?
??
? ? ?
? ? ?
??
??
?
??
??
2 2 2
2
22
bc
6 2 3 5 2 3 4
d
6 3 2
12 15 6 4
d
36 9 4
13
d
49
13
d units
7
4. Given that of a ij = e
2ix
sin(jx)
? ? ? ?
??
? ? ?
2 1 x 2x
12
Substitute i = 1 and j = 2
Thus, a e sin 2 x e sin 2x
Page 3
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
CBSE Board
Class XII Mathematics
Board Paper – 2015 Solution
All India Set – 1
SECTION – A
1. ? ? ? ? ? ? Given that a 2i j 3k and b 3i 5j 2k
? ? ? ? ? ?
?
??
?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
2 2 2
We need to find a b
i j k
a b 2 1 3
3 5 2
i 2 15 j 4 9 k 10 3
17i 13j 7k
Hence, a b 17 13 7
a b 507
2. ? ? ? ? Let a i j; b j k
? ? ? ?
? ? ? ?
? ?
? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ?
? ? ?
? ? ?
? ? ?
?
? ? ? ?
? ? ? ?
2
22
2
22
a b i j j k 1 0 1 1 0 1 1
a 1 1 0 2
b 0 1 1 2
We know that a b a b cos
a b 1 1
Thus, cos =
2
22 ab
cos cos120
120
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
3. Consider the vector equation of the plane.
? ?
? ? ? ?
? ?
? ? ? ?
? ? ? ? ? ? ?
? ? ? ?
? ? ? ? ?
? ? ? ?
?
? ? ?
1 1 1
r 6i 3j 2k 4
xi yj zk 6i 3j 2k 4
6x 3y 2z 4
6x 3y 2z 4 0
Thus the Cartesian equation of the plane is
6x 3y 2z 4 0
Let d be the distance between the point 2, 5, 3
to the plane.
ax by cz d
Thus, d=
a
? ?
? ?
??
? ? ? ? ? ? ?
??
? ? ?
? ? ?
??
??
?
??
??
2 2 2
2
22
bc
6 2 3 5 2 3 4
d
6 3 2
12 15 6 4
d
36 9 4
13
d
49
13
d units
7
4. Given that of a ij = e
2ix
sin(jx)
? ? ? ?
??
? ? ?
2 1 x 2x
12
Substitute i = 1 and j = 2
Thus, a e sin 2 x e sin 2x
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
5. Consider the equation, y = mx, where m is the parameter.
Thus, the above equation represents the family of lines which pass through the origin.
y mx....(1)
y
m....(2)
x
?
??
Differentiating the above equation (1) with respect to x,
? ?
?
??
??
??
? ? ?
??
y mx
dy
m1
dx
dy
m
dx
dy y
from equation (2)
dx x
dy y
0
dx x
Thus we have eliminated the constant, m.
The required differential equation is
dy y
0
dx x
6. Consider the given differential equation:
dy
xlog x y 2log x
dx
Dividing the above equation by xlogx, we have,
xlog x dy y 2log x
xlog x dx xlog x xlog x
dy y 2
....(1)
dx xlog x x
Consider the general linear differential equation,
dy
Py Q,where P and Q are funct
dx
??
??
? ? ?
?? ions of x
? ? ? ?
Pdx
dx
Pdx
x log x
Comparing equation (1) and the general equation, we have,
12
P x and Q x
xlog x x
The integrating factor is given by the formula e
Thus,I.F. e e
??
?
?
?
??
Page 4
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
CBSE Board
Class XII Mathematics
Board Paper – 2015 Solution
All India Set – 1
SECTION – A
1. ? ? ? ? ? ? Given that a 2i j 3k and b 3i 5j 2k
? ? ? ? ? ?
?
??
?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
2 2 2
We need to find a b
i j k
a b 2 1 3
3 5 2
i 2 15 j 4 9 k 10 3
17i 13j 7k
Hence, a b 17 13 7
a b 507
2. ? ? ? ? Let a i j; b j k
? ? ? ?
? ? ? ?
? ?
? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ?
? ? ?
? ? ?
? ? ?
?
? ? ? ?
? ? ? ?
2
22
2
22
a b i j j k 1 0 1 1 0 1 1
a 1 1 0 2
b 0 1 1 2
We know that a b a b cos
a b 1 1
Thus, cos =
2
22 ab
cos cos120
120
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
3. Consider the vector equation of the plane.
? ?
? ? ? ?
? ?
? ? ? ?
? ? ? ? ? ? ?
? ? ? ?
? ? ? ? ?
? ? ? ?
?
? ? ?
1 1 1
r 6i 3j 2k 4
xi yj zk 6i 3j 2k 4
6x 3y 2z 4
6x 3y 2z 4 0
Thus the Cartesian equation of the plane is
6x 3y 2z 4 0
Let d be the distance between the point 2, 5, 3
to the plane.
ax by cz d
Thus, d=
a
? ?
? ?
??
? ? ? ? ? ? ?
??
? ? ?
? ? ?
??
??
?
??
??
2 2 2
2
22
bc
6 2 3 5 2 3 4
d
6 3 2
12 15 6 4
d
36 9 4
13
d
49
13
d units
7
4. Given that of a ij = e
2ix
sin(jx)
? ? ? ?
??
? ? ?
2 1 x 2x
12
Substitute i = 1 and j = 2
Thus, a e sin 2 x e sin 2x
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
5. Consider the equation, y = mx, where m is the parameter.
Thus, the above equation represents the family of lines which pass through the origin.
y mx....(1)
y
m....(2)
x
?
??
Differentiating the above equation (1) with respect to x,
? ?
?
??
??
??
? ? ?
??
y mx
dy
m1
dx
dy
m
dx
dy y
from equation (2)
dx x
dy y
0
dx x
Thus we have eliminated the constant, m.
The required differential equation is
dy y
0
dx x
6. Consider the given differential equation:
dy
xlog x y 2log x
dx
Dividing the above equation by xlogx, we have,
xlog x dy y 2log x
xlog x dx xlog x xlog x
dy y 2
....(1)
dx xlog x x
Consider the general linear differential equation,
dy
Py Q,where P and Q are funct
dx
??
??
? ? ?
?? ions of x
? ? ? ?
Pdx
dx
Pdx
x log x
Comparing equation (1) and the general equation, we have,
12
P x and Q x
xlog x x
The integrating factor is given by the formula e
Thus,I.F. e e
??
?
?
?
??
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
4
? ? ? ?
? ?
?
??
?
? ? ?
?
?
dx
log log x
x log x
dx
Consider I=
xlog x
dx
Substituting logx=t; dt
x
dt
Thus I= log t log log x
t
Hence,I.F. e e log x
SECTION – B
7.
2
1 2 2
A 2 1 2
2 2 1
1 2 2 1 2 2
A 2 1 2 2 1 2
2 2 1 2 2 1
1 1 2 2 2 2 1 2 2 1 2 2 1 2 2 2 2 1
2 1 1 2 2 2 2 2 1 1 2 2 2 2 1 2 2 1
2 1 2 2 1 2 2 2 2 1 1 2 2 2 2 2 1 1
1 4 4 2 2 4 2 4 2
2 2 4 4 1 4 4 2 2
2 4 2 4 2 2 4 4 1
9 8 8
8 9 8
8 8 9
2
Consider A 4A 5I
9 8 8 1 2 2 1 0 0
8 9 8 4 2 1 2 5 0 1 0
8 8 9 2 2 1 0 0 1
9 8 8 4 8 8 5 0 0
8 9 8 8 4 8 0 5 0
8 8 9 8 8 4 0 0 5
9 9 8 8 8 8
8 8 9 9 8 8
8 8 8 8 9 9
Page 5
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
CBSE Board
Class XII Mathematics
Board Paper – 2015 Solution
All India Set – 1
SECTION – A
1. ? ? ? ? ? ? Given that a 2i j 3k and b 3i 5j 2k
? ? ? ? ? ?
?
??
?
? ? ? ? ? ? ? ?
? ? ? ?
? ? ? ?
? ? ?
2 2 2
We need to find a b
i j k
a b 2 1 3
3 5 2
i 2 15 j 4 9 k 10 3
17i 13j 7k
Hence, a b 17 13 7
a b 507
2. ? ? ? ? Let a i j; b j k
? ? ? ?
? ? ? ?
? ?
? ?
? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
? ? ? ? ?
? ? ? ? ?
? ? ?
? ? ?
? ? ?
?
? ? ? ?
? ? ? ?
2
22
2
22
a b i j j k 1 0 1 1 0 1 1
a 1 1 0 2
b 0 1 1 2
We know that a b a b cos
a b 1 1
Thus, cos =
2
22 ab
cos cos120
120
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
3. Consider the vector equation of the plane.
? ?
? ? ? ?
? ?
? ? ? ?
? ? ? ? ? ? ?
? ? ? ?
? ? ? ? ?
? ? ? ?
?
? ? ?
1 1 1
r 6i 3j 2k 4
xi yj zk 6i 3j 2k 4
6x 3y 2z 4
6x 3y 2z 4 0
Thus the Cartesian equation of the plane is
6x 3y 2z 4 0
Let d be the distance between the point 2, 5, 3
to the plane.
ax by cz d
Thus, d=
a
? ?
? ?
??
? ? ? ? ? ? ?
??
? ? ?
? ? ?
??
??
?
??
??
2 2 2
2
22
bc
6 2 3 5 2 3 4
d
6 3 2
12 15 6 4
d
36 9 4
13
d
49
13
d units
7
4. Given that of a ij = e
2ix
sin(jx)
? ? ? ?
??
? ? ?
2 1 x 2x
12
Substitute i = 1 and j = 2
Thus, a e sin 2 x e sin 2x
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
5. Consider the equation, y = mx, where m is the parameter.
Thus, the above equation represents the family of lines which pass through the origin.
y mx....(1)
y
m....(2)
x
?
??
Differentiating the above equation (1) with respect to x,
? ?
?
??
??
??
? ? ?
??
y mx
dy
m1
dx
dy
m
dx
dy y
from equation (2)
dx x
dy y
0
dx x
Thus we have eliminated the constant, m.
The required differential equation is
dy y
0
dx x
6. Consider the given differential equation:
dy
xlog x y 2log x
dx
Dividing the above equation by xlogx, we have,
xlog x dy y 2log x
xlog x dx xlog x xlog x
dy y 2
....(1)
dx xlog x x
Consider the general linear differential equation,
dy
Py Q,where P and Q are funct
dx
??
??
? ? ?
?? ions of x
? ? ? ?
Pdx
dx
Pdx
x log x
Comparing equation (1) and the general equation, we have,
12
P x and Q x
xlog x x
The integrating factor is given by the formula e
Thus,I.F. e e
??
?
?
?
??
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
4
? ? ? ?
? ?
?
??
?
? ? ?
?
?
dx
log log x
x log x
dx
Consider I=
xlog x
dx
Substituting logx=t; dt
x
dt
Thus I= log t log log x
t
Hence,I.F. e e log x
SECTION – B
7.
2
1 2 2
A 2 1 2
2 2 1
1 2 2 1 2 2
A 2 1 2 2 1 2
2 2 1 2 2 1
1 1 2 2 2 2 1 2 2 1 2 2 1 2 2 2 2 1
2 1 1 2 2 2 2 2 1 1 2 2 2 2 1 2 2 1
2 1 2 2 1 2 2 2 2 1 1 2 2 2 2 2 1 1
1 4 4 2 2 4 2 4 2
2 2 4 4 1 4 4 2 2
2 4 2 4 2 2 4 4 1
9 8 8
8 9 8
8 8 9
2
Consider A 4A 5I
9 8 8 1 2 2 1 0 0
8 9 8 4 2 1 2 5 0 1 0
8 8 9 2 2 1 0 0 1
9 8 8 4 8 8 5 0 0
8 9 8 8 4 8 0 5 0
8 8 9 8 8 4 0 0 5
9 9 8 8 8 8
8 8 9 9 8 8
8 8 8 8 9 9
CBSE XII | Mathematics
Board Paper 2015 – All India Set – 1 Solution
000
000
000
2
2
2 1 1 1 1
1
1
Now
A 4A 5I 0
A 4A 5I
A A 4AA 5IA Postmultiply by A
A 4I 5A
1 2 2 4 0 0
2 1 2 0 4 0 5A
2 2 1 0 0 4
1
1
3 2 2
2 3 2 5A
2 2 3
3 2 2
555
2 3 2
A
555
2 2 3
555
OR
1
1
1
2 0 1
A 5 1 0
0 1 3
2 3 0 0 15 0 1 5 0
6 0 5
1
0
Hence A exists.
A A I
2 0 1 1 0 0
A 5 1 0 0 1 0
0 1 3 0 0 1
Read More
|
22 videos|162 docs|17 tests
|
FAQs on Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths - Additional Study Material for JEE
| 1. What is the format of the Mathematics JEE exam for Class 12? |  |
Ans. The Mathematics JEE exam for Class 12 typically follows a multiple-choice question format. Students are required to choose the correct option from the given choices.
| 2. How many questions are there in the Mathematics JEE exam for Class 12? | |
Ans. The number of questions in the Mathematics JEE exam for Class 12 can vary from year to year. However, on average, there are around 25-30 questions in the exam.
| 3. What topics are covered in the Mathematics JEE exam for Class 12? | |
Ans. The Mathematics JEE exam for Class 12 covers a wide range of topics including algebra, calculus, trigonometry, coordinate geometry, and statistics. It is important for students to have a thorough understanding of these topics to perform well in the exam.
| 4. Are calculators allowed in the Mathematics JEE exam for Class 12? | |
Ans. No, calculators are not allowed in the Mathematics JEE exam for Class 12. Students are expected to solve the problems using their mathematical skills and knowledge.
| 5. How can I prepare effectively for the Mathematics JEE exam for Class 12? | |
Ans. To prepare effectively for the Mathematics JEE exam for Class 12, it is important to practice solving a variety of problems from different topics. Additionally, referring to past year papers and solving sample papers can help in understanding the exam pattern and identifying areas that need improvement. Seeking guidance from teachers or joining coaching classes can also be beneficial in preparing for the exam.
Related Exams
About this Document
|
4.90/5 Rating |
|
Nov 24, 2024 Last updated |
Document Description: Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths for JEE 2024 is part of Additional Study Material for JEE preparation.
The notes and questions for Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths have been prepared according to the JEE exam syllabus. Information about Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths covers topics
like and Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths Example, for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths.
Introduction of Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths in English is available as part of our Additional Study Material for JEE
for JEE & Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths in Hindi for Additional Study Material for JEE course.
Download more important topics related with notes, lectures and mock test series for JEE
Exam by signing up for free. JEE: Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths | Additional Study Material for JEE
Description
Full syllabus notes, lecture & questions for Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths | Additional Study Material for JEE - JEE | Plus excerises question with solution to help you revise complete syllabus for Additional Study Material for JEE | Best notes, free PDF download
Information about Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths
In this doc you can find the meaning of Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths defined & explained in the simplest way possible. Besides explaining types of
Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths theory, EduRev gives you an ample number of questions to practice Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths tests, examples and also practice JEE
tests
|
Explore Courses for JEE exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Maths | Additional Study Material for JEE
,Exam
,Objective type Questions
,2015
,Free
,Class 12
,practice quizzes
,Class 12
,Past Year Paper - Solutions
,Previous Year Questions with Solutions
,Important questions
,study material
,2015
,Mathematics (Set - 1)
,past year papers
,MCQs
,Mathematics (Set - 1)
,2015
,mock tests for examination
,Semester Notes
,shortcuts and tricks
,Mathematics (Set - 1)
,Extra Questions
,video lectures
,Class 12
,Summary
,Sample Paper
,Maths | Additional Study Material for JEE
,Past Year Paper - Solutions
,Past Year Paper - Solutions
,Viva Questions
,ppt
,Maths | Additional Study Material for JEE
;
Additional Information about Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths for JEE Preparation
Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths Free PDF Download
The Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths is an invaluable resource that delves deep into the core of the JEE exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths now and kickstart your journey towards success in the JEE exam.
Importance of Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths
The importance of Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths cannot be overstated, especially for JEE aspirants.
This document holds the key to success in the JEE exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths Notes
Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths Notes on EduRev are your ultimate resource for success.
Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths JEE Questions
The "Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths JEE Questions" guide is a valuable resource for all aspiring students preparing for the
JEE exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths on the App
Students of JEE can study Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of Past Year Paper - Solutions, Mathematics (Set - 1), 2015, Class 12, Maths is prepared as per the latest JEE syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup