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**Question 1. The critical flow ratios for a three-phase signal are found to be 0.30, 0.25, and 0.25. The total time lost in the cycle is 10 s. Pedestrian crossings at the junction are not significant. The respective Green times (expressed in seconds and rounded off to the nearest integer) for the three phases are [2016 : 2 Marks, Set-II](a) 34, 28 and 28(b) 40, 25, and 25(c) 40, 30 and 30(d) 50, 25, and 25 Answer:** (a)

Solution:

(a) 15

(b) 20

(c) 25

(d) 30

Answer:

Solution:

Let us assume,

q = traffic flow

k = traffic density

V = velocity of test vehicle along the stream

V - velocity of test vehicle against the stream

=> q - KV

=> q - k x 20 = 50 ...(i)

q + kV

=> q + k x 30 = 200 ...(ii)

Solving equation (i) and (ii), we get

k = 3 Veh/km

Consider a ‘L’ km long stretch,

Solution:

= 3.0 sec

Flow of traffic stream

Solution:

q= uk

q= (70-0.7 k)k

= 70k-0.7 k

Maximum possible volume is capacity of road

For maximum volume,

(i) 1.5 times the average number of vehicles (by vehicle type) that would store in turning lane per cycle during the peak hour.

(ii) 2 times the average number of vehicles (by vehicle type) that would store in turning lane per cycle during the peak hour.

(iii) Average number of vehicles (by vehicle type) that would store in the adjacent through lane per cycle during the peak hour.

(iv) Average number number of vehicles (by vehicle type) that would store in all lanes per cycle during the peak hour.

As per the IRC recommendations, the correct choice for design length of storage lanes is [2015 :1 Mark, Set-Il]

(a) Maximum of (ii) and (iii)

(b) Maximum of (i) and (iii)

(c) Average of (i) and (iii)

(d) Only (iv)

(a) u

(b) u

(c) u

(d) u

Solution:

q

q

and q

Saturation flow rate is 1800 veh/hr/lane

Lost time,

L = 4 x 4 = 16 sec

Length of the cycle,

C

(a) 1200

(b) 2400

(c) 4800

(d) 9600

45 vehicles overtook the student when he stopped for 15 minutes.

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