IIT JAM Exam > IIT JAM Notes > IIT JAM Past Year Papers and Model Test Paper (All Branches) > Physics - 2022 Past Year Paper
Physics - 2022 Past Year Paper | IIT JAM Past Year Papers and Model Test Paper (All Branches) PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
IIT-JAM 2022
Section A
22
4 zz + =
Multiple Choice Questions
Q.1-Q.10 Carry ONE marks each.
Q1. The equation in the complex plane (where z is the complex conjugate of z )
represents
(a) Ellipse (b) Hyperbola (c) Circle of radius 2 (d) Circle of radius 4
Ans.1: (b)
Solution: & z x iy z x iy =+ =-
( ) ( )
22
2 2
4 4 z z x iy x iy
-
+ =? + + - =
22
2 xy ?- = Equation of Hyperbola
Q2. A rocket ( ) ' S moves at a speed /
2
c
ms along the positive x -axis, where c is the speed of
light. When it crosses the origin, the clocks attached to the rocket and the one with a
stationary observer ( ) S located at 0 x = are both set to zero. If S observes an event at
( ) , xt the same event occurs in the ' S frame at
(a)
2
'
2 3
ct
x x
??
= -
??
??
and
2
'
2 3
x
t t
c
??
= -
??
??
(b)
2
'
2 3
ct
x x
? ?
= +
? ?
? ?
and
2
'
2 3
x
t t
c
??
= -
??
??
(c)
2
'
2 3
ct
x x
??
= -
??
??
and
2
'
2 3
x
t t
c
? ?
= +
? ?
? ?
(d)
2
'
2 3
ct
x x
? ?
= +
? ?
? ?
and
2
'
2 3
x
t t
c
? ?
= +
? ?
? ?
Ans. 2: (a)
Solution: From the question one Rocket ' S moving with speed of /2 C and one observer
is standing 0 x = . For point P the coordinate at S frame is ( ) , xy and the coordinate at
' S frame is ( ) ', ' x y
Page 2
IIT-JAM 2022
Section A
22
4 zz + =
Multiple Choice Questions
Q.1-Q.10 Carry ONE marks each.
Q1. The equation in the complex plane (where z is the complex conjugate of z )
represents
(a) Ellipse (b) Hyperbola (c) Circle of radius 2 (d) Circle of radius 4
Ans.1: (b)
Solution: & z x iy z x iy =+ =-
( ) ( )
22
2 2
4 4 z z x iy x iy
-
+ =? + + - =
22
2 xy ?- = Equation of Hyperbola
Q2. A rocket ( ) ' S moves at a speed /
2
c
ms along the positive x -axis, where c is the speed of
light. When it crosses the origin, the clocks attached to the rocket and the one with a
stationary observer ( ) S located at 0 x = are both set to zero. If S observes an event at
( ) , xt the same event occurs in the ' S frame at
(a)
2
'
2 3
ct
x x
??
= -
??
??
and
2
'
2 3
x
t t
c
??
= -
??
??
(b)
2
'
2 3
ct
x x
? ?
= +
? ?
? ?
and
2
'
2 3
x
t t
c
??
= -
??
??
(c)
2
'
2 3
ct
x x
??
= -
??
??
and
2
'
2 3
x
t t
c
? ?
= +
? ?
? ?
(d)
2
'
2 3
ct
x x
? ?
= +
? ?
? ?
and
2
'
2 3
x
t t
c
? ?
= +
? ?
? ?
Ans. 2: (a)
Solution: From the question one Rocket ' S moving with speed of /2 C and one observer
is standing 0 x = . For point P the coordinate at S frame is ( ) , xy and the coordinate at
' S frame is ( ) ', ' x y
22
22
2
'
1 1
4
c
xt
x vt
x
vc
cc
-
-
= =
- -
;
1
'1
24
c
x xt
??
=--
??
??
;
[ ]
2
' / 2
3
x x ct = -
2
2
22 2 2
/
/
2
'
1/ 1/ 4
c
t xc
t xv c
t
vc c c
-
-
= =
--
;
1
'1
24
x
tt
c
? ?
=--
? ?
? ?
;
2
'
2 3
x
t t
c
? ?
= -
? ?
? ?
[ ]
2
' /2
3
x x ct = - ;
2
'
2 3
x
t t
c
? ?
= -
? ?
? ?
So option (a) is correct.
Q3. Consider a classical ideal gas of N molecules equilibrium at temperature T . Each
molecule has two energy levels - ? and ?. The mean energy of the gas is
(a) 0 (b) tanh
B
N
kT
?? ?
?
??
??
(c) tanh
B
N
kT
?? ?
-?
??
??
(d)
2
?
Ans. 3: (c)
Solution: The partition function for a single gas molecule is
1
Ze e
ße ße -
= +
Mean energy per particle,
( )
1
ln
ln
ee
Z
E
ße ße
ßß
-
??
-? +
?
??
=-=-
??
( ) ( ) ( )
1
e e
ee
ße ße
ße ße
e e
-
-
? ?
=- -+
? ?
+
ee
ee
ße ße
ße ße
e
-
-
-
= -
+
? for a classical system of N -molecules,
the mean energy is
1
tanh
ee
U NE N N
e e kT
ße ße
ße ße
ß
e
ee
-
-
??
+
= =-=-
??
??
+
??
x
Observer
S Frame
0 x =
0
t t =
Frame
Frame
S S '
/2 c
p
( ) ,: xt s
( ) ,: xt s '' '
Rocket S '
/ 2, 0 Ct =
Page 3
IIT-JAM 2022
Section A
22
4 zz + =
Multiple Choice Questions
Q.1-Q.10 Carry ONE marks each.
Q1. The equation in the complex plane (where z is the complex conjugate of z )
represents
(a) Ellipse (b) Hyperbola (c) Circle of radius 2 (d) Circle of radius 4
Ans.1: (b)
Solution: & z x iy z x iy =+ =-
( ) ( )
22
2 2
4 4 z z x iy x iy
-
+ =? + + - =
22
2 xy ?- = Equation of Hyperbola
Q2. A rocket ( ) ' S moves at a speed /
2
c
ms along the positive x -axis, where c is the speed of
light. When it crosses the origin, the clocks attached to the rocket and the one with a
stationary observer ( ) S located at 0 x = are both set to zero. If S observes an event at
( ) , xt the same event occurs in the ' S frame at
(a)
2
'
2 3
ct
x x
??
= -
??
??
and
2
'
2 3
x
t t
c
??
= -
??
??
(b)
2
'
2 3
ct
x x
? ?
= +
? ?
? ?
and
2
'
2 3
x
t t
c
??
= -
??
??
(c)
2
'
2 3
ct
x x
??
= -
??
??
and
2
'
2 3
x
t t
c
? ?
= +
? ?
? ?
(d)
2
'
2 3
ct
x x
? ?
= +
? ?
? ?
and
2
'
2 3
x
t t
c
? ?
= +
? ?
? ?
Ans. 2: (a)
Solution: From the question one Rocket ' S moving with speed of /2 C and one observer
is standing 0 x = . For point P the coordinate at S frame is ( ) , xy and the coordinate at
' S frame is ( ) ', ' x y
22
22
2
'
1 1
4
c
xt
x vt
x
vc
cc
-
-
= =
- -
;
1
'1
24
c
x xt
??
=--
??
??
;
[ ]
2
' / 2
3
x x ct = -
2
2
22 2 2
/
/
2
'
1/ 1/ 4
c
t xc
t xv c
t
vc c c
-
-
= =
--
;
1
'1
24
x
tt
c
? ?
=--
? ?
? ?
;
2
'
2 3
x
t t
c
? ?
= -
? ?
? ?
[ ]
2
' /2
3
x x ct = - ;
2
'
2 3
x
t t
c
? ?
= -
? ?
? ?
So option (a) is correct.
Q3. Consider a classical ideal gas of N molecules equilibrium at temperature T . Each
molecule has two energy levels - ? and ?. The mean energy of the gas is
(a) 0 (b) tanh
B
N
kT
?? ?
?
??
??
(c) tanh
B
N
kT
?? ?
-?
??
??
(d)
2
?
Ans. 3: (c)
Solution: The partition function for a single gas molecule is
1
Ze e
ße ße -
= +
Mean energy per particle,
( )
1
ln
ln
ee
Z
E
ße ße
ßß
-
??
-? +
?
??
=-=-
??
( ) ( ) ( )
1
e e
ee
ße ße
ße ße
e e
-
-
? ?
=- -+
? ?
+
ee
ee
ße ße
ße ße
e
-
-
-
= -
+
? for a classical system of N -molecules,
the mean energy is
1
tanh
ee
U NE N N
e e kT
ße ße
ße ße
ß
e
ee
-
-
??
+
= =-=-
??
??
+
??
x
Observer
S Frame
0 x =
0
t t =
Frame
Frame
S S '
/2 c
p
( ) ,: xt s
( ) ,: xt s '' '
Rocket S '
/ 2, 0 Ct =
Q4. At a temperature T, let ß and k denote the volume expansively and isothermal
compressibility of a gas, respectively. Then
k
ß
is equal to
(a)
V
P
T
? ??
??
?
??
(b)
T
P
V
? ??
??
?
??
(c)
V
T
P
? ??
??
?
??
(d)
P
T
V
? ??
??
?
??
Ans. 4: (a)
Solution: given
1 V
VT
ß
? ??
=
??
?
??
and
1
T
V
k
VP
- ? ??
=
??
?
??
1
1
P
T
V
VT
V k
VP
ß
? ??
??
?
??
=
- ? ??
??
?
??
1
PT
VV
V
VT P
?? ?? ??
= -
?? ??
??
?? ??
TP V
PV P
VT T
?? ? ???? ? ?
=-=
???? ? ?
?? ?
???? ? ?
Here, in the last step we made use of reciprocity theorem i.e
xx
yy
y
zx
z
z
? ? ?? ? ?? ??
= -
? ? ?? ??
? ??
??
? ? ??
Q5. The resultant of the binary subtraction 1110101 0011110 - is
(a) 1001111 (b) 1010111 (c) 1010011 (d) 1010001
Ans. 5: (b)
Solution: 2s compliment of 0011110 ?
1100001
1
1100010
+
Thus 1110101 0011110 - is
1110101
1100010
11010111
Q6. Consider a particle trapped in a three-dimensional potential well such that
( ) , , 0 U x yz = for 0 ,0 ,0 xa y a z a = = = = = = and ( ) , , U x yz = 8 everywhere else. The
degeneracy of the
th
5 excited state is
(a) 1 (b) 3 (c) 6 (d) 9
Page 4
IIT-JAM 2022
Section A
22
4 zz + =
Multiple Choice Questions
Q.1-Q.10 Carry ONE marks each.
Q1. The equation in the complex plane (where z is the complex conjugate of z )
represents
(a) Ellipse (b) Hyperbola (c) Circle of radius 2 (d) Circle of radius 4
Ans.1: (b)
Solution: & z x iy z x iy =+ =-
( ) ( )
22
2 2
4 4 z z x iy x iy
-
+ =? + + - =
22
2 xy ?- = Equation of Hyperbola
Q2. A rocket ( ) ' S moves at a speed /
2
c
ms along the positive x -axis, where c is the speed of
light. When it crosses the origin, the clocks attached to the rocket and the one with a
stationary observer ( ) S located at 0 x = are both set to zero. If S observes an event at
( ) , xt the same event occurs in the ' S frame at
(a)
2
'
2 3
ct
x x
??
= -
??
??
and
2
'
2 3
x
t t
c
??
= -
??
??
(b)
2
'
2 3
ct
x x
? ?
= +
? ?
? ?
and
2
'
2 3
x
t t
c
??
= -
??
??
(c)
2
'
2 3
ct
x x
??
= -
??
??
and
2
'
2 3
x
t t
c
? ?
= +
? ?
? ?
(d)
2
'
2 3
ct
x x
? ?
= +
? ?
? ?
and
2
'
2 3
x
t t
c
? ?
= +
? ?
? ?
Ans. 2: (a)
Solution: From the question one Rocket ' S moving with speed of /2 C and one observer
is standing 0 x = . For point P the coordinate at S frame is ( ) , xy and the coordinate at
' S frame is ( ) ', ' x y
22
22
2
'
1 1
4
c
xt
x vt
x
vc
cc
-
-
= =
- -
;
1
'1
24
c
x xt
??
=--
??
??
;
[ ]
2
' / 2
3
x x ct = -
2
2
22 2 2
/
/
2
'
1/ 1/ 4
c
t xc
t xv c
t
vc c c
-
-
= =
--
;
1
'1
24
x
tt
c
? ?
=--
? ?
? ?
;
2
'
2 3
x
t t
c
? ?
= -
? ?
? ?
[ ]
2
' /2
3
x x ct = - ;
2
'
2 3
x
t t
c
? ?
= -
? ?
? ?
So option (a) is correct.
Q3. Consider a classical ideal gas of N molecules equilibrium at temperature T . Each
molecule has two energy levels - ? and ?. The mean energy of the gas is
(a) 0 (b) tanh
B
N
kT
?? ?
?
??
??
(c) tanh
B
N
kT
?? ?
-?
??
??
(d)
2
?
Ans. 3: (c)
Solution: The partition function for a single gas molecule is
1
Ze e
ße ße -
= +
Mean energy per particle,
( )
1
ln
ln
ee
Z
E
ße ße
ßß
-
??
-? +
?
??
=-=-
??
( ) ( ) ( )
1
e e
ee
ße ße
ße ße
e e
-
-
? ?
=- -+
? ?
+
ee
ee
ße ße
ße ße
e
-
-
-
= -
+
? for a classical system of N -molecules,
the mean energy is
1
tanh
ee
U NE N N
e e kT
ße ße
ße ße
ß
e
ee
-
-
??
+
= =-=-
??
??
+
??
x
Observer
S Frame
0 x =
0
t t =
Frame
Frame
S S '
/2 c
p
( ) ,: xt s
( ) ,: xt s '' '
Rocket S '
/ 2, 0 Ct =
Q4. At a temperature T, let ß and k denote the volume expansively and isothermal
compressibility of a gas, respectively. Then
k
ß
is equal to
(a)
V
P
T
? ??
??
?
??
(b)
T
P
V
? ??
??
?
??
(c)
V
T
P
? ??
??
?
??
(d)
P
T
V
? ??
??
?
??
Ans. 4: (a)
Solution: given
1 V
VT
ß
? ??
=
??
?
??
and
1
T
V
k
VP
- ? ??
=
??
?
??
1
1
P
T
V
VT
V k
VP
ß
? ??
??
?
??
=
- ? ??
??
?
??
1
PT
VV
V
VT P
?? ?? ??
= -
?? ??
??
?? ??
TP V
PV P
VT T
?? ? ???? ? ?
=-=
???? ? ?
?? ?
???? ? ?
Here, in the last step we made use of reciprocity theorem i.e
xx
yy
y
zx
z
z
? ? ?? ? ?? ??
= -
? ? ?? ??
? ??
??
? ? ??
Q5. The resultant of the binary subtraction 1110101 0011110 - is
(a) 1001111 (b) 1010111 (c) 1010011 (d) 1010001
Ans. 5: (b)
Solution: 2s compliment of 0011110 ?
1100001
1
1100010
+
Thus 1110101 0011110 - is
1110101
1100010
11010111
Q6. Consider a particle trapped in a three-dimensional potential well such that
( ) , , 0 U x yz = for 0 ,0 ,0 xa y a z a = = = = = = and ( ) , , U x yz = 8 everywhere else. The
degeneracy of the
th
5 excited state is
(a) 1 (b) 3 (c) 6 (d) 9
Ans. 6: (c)
Solution: Energy for 3d Potential well is
2
2 2 22
222
2
y
x z
n
n n
E
ma b c
p
? ?
= ++
? ?
? ?
? ?
?
From question abc a = = = so,
22
222
2
2
x yz
E nnn
ma
p
?? = ++
??
?
Energy State ( , ,
xy z
nn n ) Energy Degeneracy
Ground State (1,1,1)
22 2
32ma p ?
1
1
st
Excited State (1,1,2), (1,2,1), (2,1,1)
22 2
62ma p ?
3
2
nd
Excited State (1,2,2), (2,1,2), (2,2,1)
22 2
92ma p ?
3
3
rd
Excited State (1,1,3), (1,3,1), (3,1,1)
22 2
11 2ma p ?
3
4
th
Excited State (2,2,2)
22 2
12 2ma p ?
1
5
th
Excited State (1,2,3), (2,1,3), (2,3,1),
(3,1,2), (3,2,1), (1,3,2)
22 2
14 2ma p ?
6
Q7. A particle of mass mand angular momentum L moves in space where its potential
energy is ( ) ( )
2
0 U r kr k = > and r is the radial coordinate. If the particle moves in a
circular orbit, then the radius of the orbit is
(a)
1
2
4
L
mk
? ?
? ?
? ?
(b)
1
2
4
2
L
mk
??
??
??
(c)
1
2
4
2L
mk
? ?
? ?
? ?
(d)
1
2
4
4L
mk
? ?
? ?
? ?
Ans. 7: (b)
Solution: Let the velocity of the particle is v and angular momentum L .
Method 1:-
( )
2
U r kr =
We have
Force
( )
() 2
U r
F kr
r
?
=- =-
?
We know that centripetal force
2
mv
F
r
= -
2
2
mv
kr
r
- =- ;
2
2
2kr
v
m
= ;
2
2kr
v
m
=
Page 5
IIT-JAM 2022
Section A
22
4 zz + =
Multiple Choice Questions
Q.1-Q.10 Carry ONE marks each.
Q1. The equation in the complex plane (where z is the complex conjugate of z )
represents
(a) Ellipse (b) Hyperbola (c) Circle of radius 2 (d) Circle of radius 4
Ans.1: (b)
Solution: & z x iy z x iy =+ =-
( ) ( )
22
2 2
4 4 z z x iy x iy
-
+ =? + + - =
22
2 xy ?- = Equation of Hyperbola
Q2. A rocket ( ) ' S moves at a speed /
2
c
ms along the positive x -axis, where c is the speed of
light. When it crosses the origin, the clocks attached to the rocket and the one with a
stationary observer ( ) S located at 0 x = are both set to zero. If S observes an event at
( ) , xt the same event occurs in the ' S frame at
(a)
2
'
2 3
ct
x x
??
= -
??
??
and
2
'
2 3
x
t t
c
??
= -
??
??
(b)
2
'
2 3
ct
x x
? ?
= +
? ?
? ?
and
2
'
2 3
x
t t
c
??
= -
??
??
(c)
2
'
2 3
ct
x x
??
= -
??
??
and
2
'
2 3
x
t t
c
? ?
= +
? ?
? ?
(d)
2
'
2 3
ct
x x
? ?
= +
? ?
? ?
and
2
'
2 3
x
t t
c
? ?
= +
? ?
? ?
Ans. 2: (a)
Solution: From the question one Rocket ' S moving with speed of /2 C and one observer
is standing 0 x = . For point P the coordinate at S frame is ( ) , xy and the coordinate at
' S frame is ( ) ', ' x y
22
22
2
'
1 1
4
c
xt
x vt
x
vc
cc
-
-
= =
- -
;
1
'1
24
c
x xt
??
=--
??
??
;
[ ]
2
' / 2
3
x x ct = -
2
2
22 2 2
/
/
2
'
1/ 1/ 4
c
t xc
t xv c
t
vc c c
-
-
= =
--
;
1
'1
24
x
tt
c
? ?
=--
? ?
? ?
;
2
'
2 3
x
t t
c
? ?
= -
? ?
? ?
[ ]
2
' /2
3
x x ct = - ;
2
'
2 3
x
t t
c
? ?
= -
? ?
? ?
So option (a) is correct.
Q3. Consider a classical ideal gas of N molecules equilibrium at temperature T . Each
molecule has two energy levels - ? and ?. The mean energy of the gas is
(a) 0 (b) tanh
B
N
kT
?? ?
?
??
??
(c) tanh
B
N
kT
?? ?
-?
??
??
(d)
2
?
Ans. 3: (c)
Solution: The partition function for a single gas molecule is
1
Ze e
ße ße -
= +
Mean energy per particle,
( )
1
ln
ln
ee
Z
E
ße ße
ßß
-
??
-? +
?
??
=-=-
??
( ) ( ) ( )
1
e e
ee
ße ße
ße ße
e e
-
-
? ?
=- -+
? ?
+
ee
ee
ße ße
ße ße
e
-
-
-
= -
+
? for a classical system of N -molecules,
the mean energy is
1
tanh
ee
U NE N N
e e kT
ße ße
ße ße
ß
e
ee
-
-
??
+
= =-=-
??
??
+
??
x
Observer
S Frame
0 x =
0
t t =
Frame
Frame
S S '
/2 c
p
( ) ,: xt s
( ) ,: xt s '' '
Rocket S '
/ 2, 0 Ct =
Q4. At a temperature T, let ß and k denote the volume expansively and isothermal
compressibility of a gas, respectively. Then
k
ß
is equal to
(a)
V
P
T
? ??
??
?
??
(b)
T
P
V
? ??
??
?
??
(c)
V
T
P
? ??
??
?
??
(d)
P
T
V
? ??
??
?
??
Ans. 4: (a)
Solution: given
1 V
VT
ß
? ??
=
??
?
??
and
1
T
V
k
VP
- ? ??
=
??
?
??
1
1
P
T
V
VT
V k
VP
ß
? ??
??
?
??
=
- ? ??
??
?
??
1
PT
VV
V
VT P
?? ?? ??
= -
?? ??
??
?? ??
TP V
PV P
VT T
?? ? ???? ? ?
=-=
???? ? ?
?? ?
???? ? ?
Here, in the last step we made use of reciprocity theorem i.e
xx
yy
y
zx
z
z
? ? ?? ? ?? ??
= -
? ? ?? ??
? ??
??
? ? ??
Q5. The resultant of the binary subtraction 1110101 0011110 - is
(a) 1001111 (b) 1010111 (c) 1010011 (d) 1010001
Ans. 5: (b)
Solution: 2s compliment of 0011110 ?
1100001
1
1100010
+
Thus 1110101 0011110 - is
1110101
1100010
11010111
Q6. Consider a particle trapped in a three-dimensional potential well such that
( ) , , 0 U x yz = for 0 ,0 ,0 xa y a z a = = = = = = and ( ) , , U x yz = 8 everywhere else. The
degeneracy of the
th
5 excited state is
(a) 1 (b) 3 (c) 6 (d) 9
Ans. 6: (c)
Solution: Energy for 3d Potential well is
2
2 2 22
222
2
y
x z
n
n n
E
ma b c
p
? ?
= ++
? ?
? ?
? ?
?
From question abc a = = = so,
22
222
2
2
x yz
E nnn
ma
p
?? = ++
??
?
Energy State ( , ,
xy z
nn n ) Energy Degeneracy
Ground State (1,1,1)
22 2
32ma p ?
1
1
st
Excited State (1,1,2), (1,2,1), (2,1,1)
22 2
62ma p ?
3
2
nd
Excited State (1,2,2), (2,1,2), (2,2,1)
22 2
92ma p ?
3
3
rd
Excited State (1,1,3), (1,3,1), (3,1,1)
22 2
11 2ma p ?
3
4
th
Excited State (2,2,2)
22 2
12 2ma p ?
1
5
th
Excited State (1,2,3), (2,1,3), (2,3,1),
(3,1,2), (3,2,1), (1,3,2)
22 2
14 2ma p ?
6
Q7. A particle of mass mand angular momentum L moves in space where its potential
energy is ( ) ( )
2
0 U r kr k = > and r is the radial coordinate. If the particle moves in a
circular orbit, then the radius of the orbit is
(a)
1
2
4
L
mk
? ?
? ?
? ?
(b)
1
2
4
2
L
mk
??
??
??
(c)
1
2
4
2L
mk
? ?
? ?
? ?
(d)
1
2
4
4L
mk
? ?
? ?
? ?
Ans. 7: (b)
Solution: Let the velocity of the particle is v and angular momentum L .
Method 1:-
( )
2
U r kr =
We have
Force
( )
() 2
U r
F kr
r
?
=- =-
?
We know that centripetal force
2
mv
F
r
= -
2
2
mv
kr
r
- =- ;
2
2
2kr
v
m
= ;
2
2kr
v
m
=
2
2kr
Lm r
m
= · ;
2
22 2
2kr
Lm r
m
??
=
??
??
;
24
2 L km e =
2
4
2
L
r
km
= ;
1
2 2
2
L
r
km
??
=
??
??
So option (b) is right.
2
2
2
2
eff
L
V kr
mr
= +
Method:- 2
We know that the effective potential of the system is
;
2
3
2
eff
dV
L
kr
d mr e
-
= +
at
0
,0
eff
dV
rr
dr
= =
2
0 3
0
2
2
L
kr
mr
= ;
1/4
22
4
00
22
LL
rr
mk mk
??
= ?=
??
??
Q8. Consider a two-dimensional force field
( ) ( ) ( )
22 2 2
ˆˆ , 5 44 F x y x ay bxy x x xy y y = ++ + + +
?
If the force field is conservative, then the values of a and b are
(a) 2 a = and 4 b = (b) 2 a = and 8 b =
(c) 4 a = and 2 b = (d) 8 a = and 2 b =
Ans. 8: (b)
Solution:
22 2 2
ˆ ˆ ˆ
00
5 44 0
x y z
F
x yz
x ay bxy x xy y
? ??
?× = ? =
? ??
++ + +
??
( ) ( ) ( )
ˆˆ ˆ 00 00 8 4 2 0 x y z x y ay bx ? -- -+ + - - = 84 2 x y ay bx ?+ = +
( ) ( ) 8 42 0 bx a y ?- + - = 8, 2 b a ?= =
Q9. Consider an electrostatic field E
?
in a region of space. Identify the INCORRECT
statement.
(a) The work done in moving a charge in a closed path inside the region is zero
(b) The curl of E
?
is zero
(c) The field can be expressed as the gradient of a scalar potential
(d) The potential difference between any two points in the region is always zero
Ans. 9: (d)
Read More
FAQs on Physics - 2022 Past Year Paper - IIT JAM Past Year Papers and Model Test Paper (All Branches)
| 1. What is the concept of angular momentum in physics? |  |
Ans. Angular momentum is a fundamental concept in physics that deals with the rotational motion of objects. It is a vector quantity that depends on an object's moment of inertia and its angular velocity. The angular momentum of an object is conserved if there are no external torques acting on it.
| 2. How is angular momentum related to an object's moment of inertia? | |
Ans. Angular momentum is directly proportional to an object's moment of inertia. The moment of inertia represents an object's resistance to changes in its rotational motion. Therefore, objects with larger moments of inertia will have larger angular momenta for the same angular velocity.
| 3. What is the relationship between torque and angular momentum? | |
Ans. Torque is the rotational equivalent of force and is responsible for changes in an object's angular momentum. According to Newton's second law for rotational motion, the torque exerted on an object is equal to the rate of change of its angular momentum. This relationship is given by the equation: Torque = (change in angular momentum)/(change in time).
| 4. Can angular momentum be negative? | |
Ans. Yes, angular momentum can be negative. The sign of angular momentum depends on the direction of rotation. If an object rotates in a counterclockwise direction, its angular momentum is positive. Conversely, if the rotation is in a clockwise direction, the angular momentum is negative.
| 5. How does conservation of angular momentum apply to real-life situations? | |
Ans. Conservation of angular momentum has several real-life applications. For example, figure skaters can increase their rotational speed by pulling their arms closer to their bodies, reducing their moment of inertia and conserving angular momentum. Similarly, divers can perform somersaults or twists by manipulating their body position to change their moment of inertia and maintain angular momentum.
About this Document
|
2.4K Views |
|
4.66/5 Rating |
|
Nov 22, 2024 Last updated |
Document Description: Physics - 2022 Past Year Paper for IIT JAM 2024 is part of IIT JAM Past Year Papers and Model Test Paper (All Branches) preparation.
The notes and questions for Physics - 2022 Past Year Paper have been prepared according to the IIT JAM exam syllabus. Information about Physics - 2022 Past Year Paper covers topics
like and Physics - 2022 Past Year Paper Example, for IIT JAM 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Physics - 2022 Past Year Paper.
Introduction of Physics - 2022 Past Year Paper in English is available as part of our IIT JAM Past Year Papers and Model Test Paper (All Branches)
for IIT JAM & Physics - 2022 Past Year Paper in Hindi for IIT JAM Past Year Papers and Model Test Paper (All Branches) course.
Download more important topics related with notes, lectures and mock test series for IIT JAM
Exam by signing up for free. IIT JAM: Physics - 2022 Past Year Paper | IIT JAM Past Year Papers and Model Test Paper (All Branches)
Description
Full syllabus notes, lecture & questions for Physics - 2022 Past Year Paper | IIT JAM Past Year Papers and Model Test Paper (All Branches) - IIT JAM | Plus excerises question with solution to help you revise complete syllabus for IIT JAM Past Year Papers and Model Test Paper (All Branches) | Best notes, free PDF download
Information about Physics - 2022 Past Year Paper
In this doc you can find the meaning of Physics - 2022 Past Year Paper defined & explained in the simplest way possible. Besides explaining types of
Physics - 2022 Past Year Paper theory, EduRev gives you an ample number of questions to practice Physics - 2022 Past Year Paper tests, examples and also practice IIT JAM
tests
|
29 docs|48 tests
|
Download as PDF
|
Explore Courses for IIT JAM exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Physics - 2022 Past Year Paper | IIT JAM Past Year Papers and Model Test Paper (All Branches)
,ppt
,past year papers
,Sample Paper
,MCQs
,study material
,video lectures
,Exam
,Previous Year Questions with Solutions
,shortcuts and tricks
,Semester Notes
,Physics - 2022 Past Year Paper | IIT JAM Past Year Papers and Model Test Paper (All Branches)
,Extra Questions
,Viva Questions
,Physics - 2022 Past Year Paper | IIT JAM Past Year Papers and Model Test Paper (All Branches)
,mock tests for examination
,Free
,practice quizzes
,Summary
,Objective type Questions
,Important questions
;
Additional Information about Physics - 2022 Past Year Paper for IIT JAM Preparation
Physics - 2022 Past Year Paper Free PDF Download
The Physics - 2022 Past Year Paper is an invaluable resource that delves deep into the core of the IIT JAM exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the Physics - 2022 Past Year Paper now and kickstart your journey towards success in the IIT JAM exam.
Importance of Physics - 2022 Past Year Paper
The importance of Physics - 2022 Past Year Paper cannot be overstated, especially for IIT JAM aspirants.
This document holds the key to success in the IIT JAM exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
Physics - 2022 Past Year Paper Notes
Physics - 2022 Past Year Paper Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to Physics - 2022 Past Year Paper.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, Physics - 2022 Past Year Paper Notes on EduRev are your ultimate resource for success.
Physics - 2022 Past Year Paper IIT JAM Questions
The "Physics - 2022 Past Year Paper IIT JAM Questions" guide is a valuable resource for all aspiring students preparing for the
IIT JAM exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study Physics - 2022 Past Year Paper on the App
Students of IIT JAM can study Physics - 2022 Past Year Paper alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the Physics - 2022 Past Year Paper,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of Physics - 2022 Past Year Paper is prepared as per the latest IIT JAM syllabus.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup