Physics Past Year Paper Outside Delhi Anskey (Central Zone All Set) - 2016, Class 12 Class 12 Notes | EduRev

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Class 12 : Physics Past Year Paper Outside Delhi Anskey (Central Zone All Set) - 2016, Class 12 Class 12 Notes | EduRev

 Page 1


1     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
MARKING SCHEME  55/1/C 
Q. No. Expected Answer / Value Points Marks Total 
Marks 
SECTION-A 
SET1,Q1 
SET2,Q4 
SET3,Q5 
No work is done /
W = qV
AB 
= q x 0 = 0 
1 1 
SET1,Q2 
SET2,Q1 
SET3,Q3 
A diamagnetic specimen would move towards the weaker region of the field 
while a paramagnetic specimen would move towards the stronger region./ 
A diamagnetic specimen is repelled by a magnet while a paramagnetic 
specimen moves towards the magnet./
The paramagnetic get aligned along B and the diagrammatic perpendicular 
to the field. 
1 
1 
SET1,Q3 
SET2,Q5 
SET3,Q2 
Transmitter, Medium or Channel and Receiver. 1 1 
SET1,Q4 
SET2,Q3 
SET3,Q1 . 
It is due to least scattering of red light as it has the longest wavelength/
As per Rayleigh’s scattering, the amount of light scattered 
1 1 
SET1,Q5 
SET2,Q2 
SET3,Q4 
E = 2V ½ 
½ 1 
SECTION B 
SET1,Q6 
SET2,Q9 
SET3,Q8. 
Modulation index is the ratio of the amplitude of modulating signal to that of carrier 
wave 
Alternatively
c
m
A
A
 Reason- 
 To avoid distortion. 
Role- 
 A bandpass filter rejects low and high frequencies and allows a band of frequencies 
to pass through. 
1 
½ 
½ 2 
Definition-      1 
Reason-      ½ 
Role of bandpass filter-  ½ 
Page 2


1     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
MARKING SCHEME  55/1/C 
Q. No. Expected Answer / Value Points Marks Total 
Marks 
SECTION-A 
SET1,Q1 
SET2,Q4 
SET3,Q5 
No work is done /
W = qV
AB 
= q x 0 = 0 
1 1 
SET1,Q2 
SET2,Q1 
SET3,Q3 
A diamagnetic specimen would move towards the weaker region of the field 
while a paramagnetic specimen would move towards the stronger region./ 
A diamagnetic specimen is repelled by a magnet while a paramagnetic 
specimen moves towards the magnet./
The paramagnetic get aligned along B and the diagrammatic perpendicular 
to the field. 
1 
1 
SET1,Q3 
SET2,Q5 
SET3,Q2 
Transmitter, Medium or Channel and Receiver. 1 1 
SET1,Q4 
SET2,Q3 
SET3,Q1 . 
It is due to least scattering of red light as it has the longest wavelength/
As per Rayleigh’s scattering, the amount of light scattered 
1 1 
SET1,Q5 
SET2,Q2 
SET3,Q4 
E = 2V ½ 
½ 1 
SECTION B 
SET1,Q6 
SET2,Q9 
SET3,Q8. 
Modulation index is the ratio of the amplitude of modulating signal to that of carrier 
wave 
Alternatively
c
m
A
A
 Reason- 
 To avoid distortion. 
Role- 
 A bandpass filter rejects low and high frequencies and allows a band of frequencies 
to pass through. 
1 
½ 
½ 2 
Definition-      1 
Reason-      ½ 
Role of bandpass filter-  ½ 
2     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
SET1,Q7 
SET2,Q10 
SET3,Q6 
Face-AC 
Here ) 
     = 
on face AC is 30º which is less than .Hence the ray get replaced here. 
1 
½ 
½ 
2 
SET1,Q8 
SET2,Q6 
SET3,Q7 
Kinetic Energy for the second state- 
E
k
=  = =3.4X1.6X10
-19
J 
De Broglies wavelength ?= 
 = 0.067nm 
½ 
½ 
½ 
½ 2 
SET1,Q9 
SET2,Q8 
SET3,Q10 
The minimum energy, required to free the electron from the ground state of 
the hydrogen atom, is known as Ionization Energy. 
1 
Path of emergent ray  1 
Naming the face      ½ 
Justification      ½ 
Formulae of Kinetic energy and deBrogliea wavelength  ½ +½ 
Calculation and Result      ½+½ 
Definition      1 
Formula     ½ 
Calculation and Result ½ 
Page 3


1     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
MARKING SCHEME  55/1/C 
Q. No. Expected Answer / Value Points Marks Total 
Marks 
SECTION-A 
SET1,Q1 
SET2,Q4 
SET3,Q5 
No work is done /
W = qV
AB 
= q x 0 = 0 
1 1 
SET1,Q2 
SET2,Q1 
SET3,Q3 
A diamagnetic specimen would move towards the weaker region of the field 
while a paramagnetic specimen would move towards the stronger region./ 
A diamagnetic specimen is repelled by a magnet while a paramagnetic 
specimen moves towards the magnet./
The paramagnetic get aligned along B and the diagrammatic perpendicular 
to the field. 
1 
1 
SET1,Q3 
SET2,Q5 
SET3,Q2 
Transmitter, Medium or Channel and Receiver. 1 1 
SET1,Q4 
SET2,Q3 
SET3,Q1 . 
It is due to least scattering of red light as it has the longest wavelength/
As per Rayleigh’s scattering, the amount of light scattered 
1 1 
SET1,Q5 
SET2,Q2 
SET3,Q4 
E = 2V ½ 
½ 1 
SECTION B 
SET1,Q6 
SET2,Q9 
SET3,Q8. 
Modulation index is the ratio of the amplitude of modulating signal to that of carrier 
wave 
Alternatively
c
m
A
A
 Reason- 
 To avoid distortion. 
Role- 
 A bandpass filter rejects low and high frequencies and allows a band of frequencies 
to pass through. 
1 
½ 
½ 2 
Definition-      1 
Reason-      ½ 
Role of bandpass filter-  ½ 
2     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
SET1,Q7 
SET2,Q10 
SET3,Q6 
Face-AC 
Here ) 
     = 
on face AC is 30º which is less than .Hence the ray get replaced here. 
1 
½ 
½ 
2 
SET1,Q8 
SET2,Q6 
SET3,Q7 
Kinetic Energy for the second state- 
E
k
=  = =3.4X1.6X10
-19
J 
De Broglies wavelength ?= 
 = 0.067nm 
½ 
½ 
½ 
½ 2 
SET1,Q9 
SET2,Q8 
SET3,Q10 
The minimum energy, required to free the electron from the ground state of 
the hydrogen atom, is known as Ionization Energy. 
1 
Path of emergent ray  1 
Naming the face      ½ 
Justification      ½ 
Formulae of Kinetic energy and deBrogliea wavelength  ½ +½ 
Calculation and Result      ½+½ 
Definition      1 
Formula     ½ 
Calculation and Result ½ 
3     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
m E e i
h
me
E
o
o
o
,. .
8
2 2
4
Therefore, Ionization Energy will become 200 times 
 OR 
2 2
1
2
1 1
R
For shortest wavelength, n = a 
Therefore, = => ?= =4x10
-7
m
½ 
½ 
1 
½ 
½ 
2 
2 
SET1,Q10 
SET2,Q7 
SET3,Q9 
a) Effective resistance of the circuit R
E
= 6?
Terminal potential difference across the cell, V=E-ir 
Also p.d. across 4? resistor =4X2V= 8V 
 Hence the volmeter gives the same reading in the two cases. 
b) In series -current same
In parallel – potential same
½ 
½ 
½ 
½ 2 
SECTION C 
SET1,Q11 
SET2,Q15 
SET3,Q22 
Surface with a constant value of potential at all points on the surface. ½ 
Formula      1 
Calculation and Result  ½+½ 
½
a) Relation for terminal potential ½ 
b) Justification ½ 
c) Explanation (parallel and series) ½ + ½ 
Definition-  ½ 
i.Diagram of Equipotential Surface ½ 
ii.Diagram and reason ½ +½ 
iii.Answer and Reason ½+½ 
Page 4


1     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
MARKING SCHEME  55/1/C 
Q. No. Expected Answer / Value Points Marks Total 
Marks 
SECTION-A 
SET1,Q1 
SET2,Q4 
SET3,Q5 
No work is done /
W = qV
AB 
= q x 0 = 0 
1 1 
SET1,Q2 
SET2,Q1 
SET3,Q3 
A diamagnetic specimen would move towards the weaker region of the field 
while a paramagnetic specimen would move towards the stronger region./ 
A diamagnetic specimen is repelled by a magnet while a paramagnetic 
specimen moves towards the magnet./
The paramagnetic get aligned along B and the diagrammatic perpendicular 
to the field. 
1 
1 
SET1,Q3 
SET2,Q5 
SET3,Q2 
Transmitter, Medium or Channel and Receiver. 1 1 
SET1,Q4 
SET2,Q3 
SET3,Q1 . 
It is due to least scattering of red light as it has the longest wavelength/
As per Rayleigh’s scattering, the amount of light scattered 
1 1 
SET1,Q5 
SET2,Q2 
SET3,Q4 
E = 2V ½ 
½ 1 
SECTION B 
SET1,Q6 
SET2,Q9 
SET3,Q8. 
Modulation index is the ratio of the amplitude of modulating signal to that of carrier 
wave 
Alternatively
c
m
A
A
 Reason- 
 To avoid distortion. 
Role- 
 A bandpass filter rejects low and high frequencies and allows a band of frequencies 
to pass through. 
1 
½ 
½ 2 
Definition-      1 
Reason-      ½ 
Role of bandpass filter-  ½ 
2     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
SET1,Q7 
SET2,Q10 
SET3,Q6 
Face-AC 
Here ) 
     = 
on face AC is 30º which is less than .Hence the ray get replaced here. 
1 
½ 
½ 
2 
SET1,Q8 
SET2,Q6 
SET3,Q7 
Kinetic Energy for the second state- 
E
k
=  = =3.4X1.6X10
-19
J 
De Broglies wavelength ?= 
 = 0.067nm 
½ 
½ 
½ 
½ 2 
SET1,Q9 
SET2,Q8 
SET3,Q10 
The minimum energy, required to free the electron from the ground state of 
the hydrogen atom, is known as Ionization Energy. 
1 
Path of emergent ray  1 
Naming the face      ½ 
Justification      ½ 
Formulae of Kinetic energy and deBrogliea wavelength  ½ +½ 
Calculation and Result      ½+½ 
Definition      1 
Formula     ½ 
Calculation and Result ½ 
3     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
m E e i
h
me
E
o
o
o
,. .
8
2 2
4
Therefore, Ionization Energy will become 200 times 
 OR 
2 2
1
2
1 1
R
For shortest wavelength, n = a 
Therefore, = => ?= =4x10
-7
m
½ 
½ 
1 
½ 
½ 
2 
2 
SET1,Q10 
SET2,Q7 
SET3,Q9 
a) Effective resistance of the circuit R
E
= 6?
Terminal potential difference across the cell, V=E-ir 
Also p.d. across 4? resistor =4X2V= 8V 
 Hence the volmeter gives the same reading in the two cases. 
b) In series -current same
In parallel – potential same
½ 
½ 
½ 
½ 2 
SECTION C 
SET1,Q11 
SET2,Q15 
SET3,Q22 
Surface with a constant value of potential at all points on the surface. ½ 
Formula      1 
Calculation and Result  ½+½ 
½
a) Relation for terminal potential ½ 
b) Justification ½ 
c) Explanation (parallel and series) ½ + ½ 
Definition-  ½ 
i.Diagram of Equipotential Surface ½ 
ii.Diagram and reason ½ +½ 
iii.Answer and Reason ½+½ 
4     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
i. 
ii. 
 V / 
iii.No
If the field lines are tangential, work will be done in moving a charge on the 
surface which goes against the definition of equipotential surface. 
½ 
½ 
½ 
½ 
½ 3 
SET1,Q12 
SET2,Q14 
SET3,Q12 
i.When the pass axis of a  poloroid makes an angle  with the plane of
polarisation of polorised light of intensity I
o
  incident on it, then the intensity 
of the tramsmitted emergent light is given by I=
Note: If the student writes the formula I= and draws the 
1 
Statement      1 
Plotting the graph      1 
Calculating value of ( refractive index  1 
Page 5


1     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
MARKING SCHEME  55/1/C 
Q. No. Expected Answer / Value Points Marks Total 
Marks 
SECTION-A 
SET1,Q1 
SET2,Q4 
SET3,Q5 
No work is done /
W = qV
AB 
= q x 0 = 0 
1 1 
SET1,Q2 
SET2,Q1 
SET3,Q3 
A diamagnetic specimen would move towards the weaker region of the field 
while a paramagnetic specimen would move towards the stronger region./ 
A diamagnetic specimen is repelled by a magnet while a paramagnetic 
specimen moves towards the magnet./
The paramagnetic get aligned along B and the diagrammatic perpendicular 
to the field. 
1 
1 
SET1,Q3 
SET2,Q5 
SET3,Q2 
Transmitter, Medium or Channel and Receiver. 1 1 
SET1,Q4 
SET2,Q3 
SET3,Q1 . 
It is due to least scattering of red light as it has the longest wavelength/
As per Rayleigh’s scattering, the amount of light scattered 
1 1 
SET1,Q5 
SET2,Q2 
SET3,Q4 
E = 2V ½ 
½ 1 
SECTION B 
SET1,Q6 
SET2,Q9 
SET3,Q8. 
Modulation index is the ratio of the amplitude of modulating signal to that of carrier 
wave 
Alternatively
c
m
A
A
 Reason- 
 To avoid distortion. 
Role- 
 A bandpass filter rejects low and high frequencies and allows a band of frequencies 
to pass through. 
1 
½ 
½ 2 
Definition-      1 
Reason-      ½ 
Role of bandpass filter-  ½ 
2     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
SET1,Q7 
SET2,Q10 
SET3,Q6 
Face-AC 
Here ) 
     = 
on face AC is 30º which is less than .Hence the ray get replaced here. 
1 
½ 
½ 
2 
SET1,Q8 
SET2,Q6 
SET3,Q7 
Kinetic Energy for the second state- 
E
k
=  = =3.4X1.6X10
-19
J 
De Broglies wavelength ?= 
 = 0.067nm 
½ 
½ 
½ 
½ 2 
SET1,Q9 
SET2,Q8 
SET3,Q10 
The minimum energy, required to free the electron from the ground state of 
the hydrogen atom, is known as Ionization Energy. 
1 
Path of emergent ray  1 
Naming the face      ½ 
Justification      ½ 
Formulae of Kinetic energy and deBrogliea wavelength  ½ +½ 
Calculation and Result      ½+½ 
Definition      1 
Formula     ½ 
Calculation and Result ½ 
3     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
m E e i
h
me
E
o
o
o
,. .
8
2 2
4
Therefore, Ionization Energy will become 200 times 
 OR 
2 2
1
2
1 1
R
For shortest wavelength, n = a 
Therefore, = => ?= =4x10
-7
m
½ 
½ 
1 
½ 
½ 
2 
2 
SET1,Q10 
SET2,Q7 
SET3,Q9 
a) Effective resistance of the circuit R
E
= 6?
Terminal potential difference across the cell, V=E-ir 
Also p.d. across 4? resistor =4X2V= 8V 
 Hence the volmeter gives the same reading in the two cases. 
b) In series -current same
In parallel – potential same
½ 
½ 
½ 
½ 2 
SECTION C 
SET1,Q11 
SET2,Q15 
SET3,Q22 
Surface with a constant value of potential at all points on the surface. ½ 
Formula      1 
Calculation and Result  ½+½ 
½
a) Relation for terminal potential ½ 
b) Justification ½ 
c) Explanation (parallel and series) ½ + ½ 
Definition-  ½ 
i.Diagram of Equipotential Surface ½ 
ii.Diagram and reason ½ +½ 
iii.Answer and Reason ½+½ 
4     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
i. 
ii. 
 V / 
iii.No
If the field lines are tangential, work will be done in moving a charge on the 
surface which goes against the definition of equipotential surface. 
½ 
½ 
½ 
½ 
½ 3 
SET1,Q12 
SET2,Q14 
SET3,Q12 
i.When the pass axis of a  poloroid makes an angle  with the plane of
polarisation of polorised light of intensity I
o
  incident on it, then the intensity 
of the tramsmitted emergent light is given by I=
Note: If the student writes the formula I= and draws the 
1 
Statement      1 
Plotting the graph      1 
Calculating value of ( refractive index  1 
5     FOURTH  DRAFT     1O
th 
March/2016 4:00 PM 
diagram give 1mark. 
i. 
iii.
 =  = 
1 
½ 
½ 3 
SET1,Q13 
SET2,Q13 
SET3,Q14 
(i) For material B 
From the graph for the same value of ‘ ‘, stopping potential is more for material ‘B’/
is higher for lower value of ] 
(ii) No 
As slope is given by  which is constant. 
1 
½ 
½ 
½ 
½ 3 
  Sketch of the Graph      1 
(i) Stopping Potential and Reason  ½+ ½ 
(ii) Dependence of Slope and Explanation   ½+ ½ 
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