Question for Practice Questions: Structure of Atom
Try yourself:Isotopes contain
Explanation
Isotopes contain the same number of protons.
Question for Practice Questions: Structure of Atom
Try yourself:The number of angular nodes in an orbital of hydrogen-like species is
Explanation
The number of angular node is equal to the value of l (azimuthal quantum number).
Question for Practice Questions: Structure of Atom
Try yourself:Which of the following orbitals is not permitted in an atom?
Explanation
The value of m cannot be greater than the value of l.
Question for Practice Questions: Structure of Atom
Try yourself:In the absence of electric and magnetic fields which of the following orbitals of multi-electron atom will have the
same energy?
(i) n = 2, l = 1, m = 0
(ii) n = 3, l = 1, m = 1
(iii) n = 4, l = 0, m = 0
(iv) n = 3, l = 1, m = 0
Explanation
Orbitals having the same value of n + l will have the same energy irrespective of the value of m.
Question for Practice Questions: Structure of Atom
Try yourself:The other orbitals filled in 47Ag is
Explanation
The outer filled orbital in 47Ag is 4d. Its electronic configuration is [Kr](4d)10(5s)1.
Question for Practice Questions: Structure of Atom
Try yourself:Which of the following spectral series of hydrogen atom lies in the ultraviolet region of electromagnetic radiation?
Question for Practice Questions: Structure of Atom
Try yourself:The splitting of spectral lines of hydrogen atom in the presence of magnetic field is known as
Question for Practice Questions: Structure of Atom
Try yourself:The shape of an orbital is governed by the
Question for Practice Questions: Structure of Atom
Try yourself:How many unpaired electrons are present in Ni2+ (Z = 28)?
Explanation
The electronic configuration of 28Ni2+ (electron = 26) is (1s)2(2s)2(2p)6(3s)2(3p)6(3d)8.
Question for Practice Questions: Structure of Atom
Try yourself:The energy of an orbital in a multielectron atom depends on the
Explanation
The energy of a single electron species such as H, He+, and Li2+ depends only on the principal quantum number whereas for a multielectron species, it depends on the principal as well as azimuthal quantum number.
Question for Practice Questions: Structure of Atom
Try yourself:A dx2 – y2 orbital has
Question for Practice Questions: Structure of Atom
Try yourself:Which of the following statements on the atomic wave function ψ is not correct?
Explanation
It is ψ2 and not ψ is proportional to the probability of finding an electron.
Question for Practice Questions: Structure of Atom
Try yourself:The binding energy of electrons in a metal is 193 kJ mol–1. The threshold frequency of the metal is
Explanation
Binding energy of electron per atom of the metal

Question for Practice Questions: Structure of Atom
Try yourself:The outer electronic configuration of cerium (Z = 58) is
Explanation
The expected outer electronic configuration of 58Ce is (4f)1(5d)1(6s)2. But due to very similar energies of 4f and 5d orbitals in all the lanthanides excepting Gd (4f75d16s2) and 71Lu (4f14, 5d1, 6s2), (5d)1 electron is shifted to (4f) orbital and hence 5d orbital remains unoccupied. Thus, the observed configuration of 58Ce is (4f)2(5d)0(6s)2.
Question for Practice Questions: Structure of Atom
Try yourself:If the radius of Bohr’s first orbit of H atom is r, then the radius of Bohr’s first orbit of Li2+ ion will be
Explanation
The expression of radius is

where K is constant.

Question for Practice Questions: Structure of Atom
Try yourself:Which of the following electronic transitions in the line spectrum of He+ will have the same wavelength as that
Explanation
First line in the Lyman series of hydrogen atom corresponds to

For He+, the spectral line occurs at

Question for Practice Questions: Structure of Atom
Try yourself:The ionization energy of one mole of hydrogen atoms is about
Explanation
IE = NAR∞ hc = (6.022 x 1023 mol–1) (1.09678 x 107 m–1) (6.626 x 10–34 J s) (3 x 108 m s–1)
= 1.313 x 106 J mol–1 = 1313 kJ mol–1
Question for Practice Questions: Structure of Atom
Try yourself:Which of the following statements is not true?
Explanation
Paschen spectral series lies in the near infrared region of electromagnetic radiation.
Question for Practice Questions: Structure of Atom
Try yourself:The ionization energy of a hydrogen atom in the ground state is 2.17 x 10–11 erg. The ionization energy of Li2+ in the ground state will be
Explanation
ELi = Z2EH = (32) (2.17 x 10–11 erg) = 1.953 x 10–10 erg = 1.953 x 10–17 J
Question for Practice Questions: Structure of Atom
Try yourself:Naturally occurring copper is assigned atomic mass equal to 63.546 u. If it consists of two isotopes 63Cu (atomic mass = 62.930 u) and 65Cu (atomic mass = 64.928 u), then mass percentage of isotope 65Cu in the naturally occurring copper is
Explanation
We have
63.546 u = x (62.930 u) + (1 – x) (64.928 u)
Hence

Mass percent of 65Cu = 0.31 x 100 = 31%
Question for Practice Questions: Structure of Atom
Try yourself:In Bohr theory of He+, the energy difference between two successive energy levels
Explanation
The expression of energy is


For n = 1 ΔE = 3K/4 = 0.75 K
n = 2 ΔE = 5K/36 = 0.14 K
n = 3 ΔE = 7K/144 = 0.049 K
Question for Practice Questions: Structure of Atom
Try yourself:If θ is the angle made by orbital angular momentum with the z-axis, then the quantum number l and m of an atom are related to each other through the expression
Explanation

Lz = m(h/2π) and Lz = L cos θ. Hence,

Question for Practice Questions: Structure of Atom
Try yourself:The angular dependence of an orbital is decided by the
Explanation

The terms within the brackets represents angular dependence.
Question for Practice Questions: Structure of Atom
Try yourself:Which of the following symbols correctly represents an orbitals in an atom?
Explanation
The function R depends on the quantum numbers n and l, the function Θ depends on l and | m | and the function Ф depends on m.
Question for Practice Questions: Structure of Atom
Try yourself:Hydrogen atom in its ground state is excited by a radiation of wavelength 97.26 nm. The longest wavelength it emits is
Explanation




The transition n2 = 4 → n1 = 3 will emit the longest wavelength. Hence


= 1.875 x 10–6 m = 1875 nm