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Problems on Trains Tips and Tricks for Government Exams

Theory

  • Similar to the concept of speed, distance and time, train problems are specifically based on evaluating the speed, distance covered and time is taken by a train under different conditions. 
  • There are specific formulas which are to be used to find answers to the train-based questions and candidates must memorise them in order to crack the answer for problems on trains.
    Problems on Trains Tips and Tricks for Government Exams

Formula

  • Speed of the Train = Total distance covered by the train / Time taken
  • If the length of two trains is given, say a and b, and the trains are moving in opposite directions with speeds of x and y respectively, then the time taken by trains to cross each other = {(a+b) / (x+y)}
  • If the length of two trains is given, say a and b, and they are moving in the same direction, with speeds x and y respectively, then the time is taken to cross each other = {(a+b) / (x-y)}
  • When the starting time of two trains is the same from x and y towards each other and after crossing each other, they took t1 and t2 time in reaching  y and x respectively, then the ratio between the speed of two trains = √t2 : √t1
  • If two trains leave x and y stations at time t1 and t2 respectively and travel with speed L and M respectively, then distanced from x, where two trains meet is = (t2 – t1) × {(product of speed) / (difference in speed)}
  • The average speed of a train without any stoppage is x, and with the stoppage, it covers the same distance at an average speed of y, then Rest Time per hour = (Difference in average speed) / (Speed without stoppage) 
  • If two trains of equal lengths and different speeds take t1 and t2 time to cross a pole, then the time taken by them to cross each other if the train is moving in opposite direction = (2×t1×t2) / (t2+t1)
  • If two trains of equal lengths and different speeds take t1 and t2 time to cross a pole, then the time taken by them to cross each other if the train is moving in the same direction = (2×t1×t2) / (t2-t1)

Types 

  • Time Taken by Train to Cross any stationary Body or Platform – Question may be asked where the candidate has to calculate the time taken by a train to cross a stationary body like a pole or a standing man or a platform/ bridge
  • Time Taken by 2 trains to cross each other – Another question that may be asked is the time two trains might take to cross each other
  • Train Problems based on Equations – Two cases may be given in the question and the candidates will have to form equations based on the condition given 

Tips

  • In train based problems, their are two objects. First object is the Train itself and second object is that, which is crossed by the train.
  • So, if a train moving or cross a pole, then the first object is train and the second object is pole.
  • If the train moving or cross the platform then the first object is train and second object is platform which the train is crosses.
  • And, if a train cross or moving a man or woman who is standing on platform then the train is first object and the second object is that man or woman.
  • And also, if a train crossing or moving another train in the same direction or opposite direction then the first object is first train and second object is second train.

Solved Examples

Question for Tips & Tricks: Problems on Trains
Try yourself:A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
View Solution

Question for Tips & Tricks: Problems on Trains
Try yourself:A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
View Solution

Question for Tips & Tricks: Problems on Trains
Try yourself:The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
View Solution

The document Problems on Trains Tips and Tricks for Government Exams is a part of the Bank Exams Course Tips & Tricks for Government Exams.
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