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Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET PDF Download

 Multiple Choice Test 

1. The coefficient of the x5 term in the Maclaurin polynomial for sin (2 x ) is

(A) 0
(B) 0.0083333
(C) 0.016667
(D) 0.26667

Solution. The correct answer is (D).
The Maclaurin series for sin(2 x ) is

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

Hence, the coefficient of the x5 term is 0.26667.

2. Given f (3) = 6 , f ′(3) = 8 , f ′′(3) = 11 , and all other higher order derivatives of f (x ) are zero at x = 3 , and assuming the function and all its derivatives exist and are continuous between x = 3 and x = 7 , the value of f (7 ) is

(A) 38.000
(B) 79.500
(C) 126.00
(D) 331.50

Solution: The correct answer is (C).
The Taylor series is given by

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

Since all the derivatives higher than second are zero,

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

3. Given that y(x ) is the solution toQuestions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET y (0) = 3 the value of y(0.2) from a second order Taylor polynomial around x=0 is

(A) 4.400
(B) 8.800
(C) 24.46
(D) 29.00

Solution: The correct answer is (C).
The second order Taylor polynomial is

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

4. The seriesQuestions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET is a Maclaurin series for the following function

(A) cos(x)
(B) cos(2 x)
(C) sin (x)
(D) sin (2 x)

Solution: The correct answer is (B).

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

5.   The functionQuestions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET dt is called the error function.  It is used in the field of probability and cannot be calculated exactly.  However, one can expand the integrand as a Taylor polynomial and conduct integration.  The approximate value of erf (2.0) using the first three terms of the Taylor series around t = 0 is

(A) -0.75225
(B) 0.99532
(C) 1.5330
(D) 2.8586

Solution: The correct answer is (A).
Rewrite the integral as

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

The first three terms of the Taylor series for  Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NETaround t = 0 are

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

The first three terms of the Taylor series are

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

Hence

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET


6.  Using the remainder of Maclaurin polynomial of nth order for f (x ) defined as

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET, the order of the Maclaurin polynomial at least required to get an absolute true error of at most 10 −6 in the calculation of sin (0.1) is (do not use the exact value of sin (0.1) or cos(0.1) to find the answer, but the knowledge that |sin( x)| ≤ 1 and | cos( x) |≤ 1 ).
(A) 3
(B) 5
(C) 7
(D) 9

Solution : The correct answer is (B).

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

So when is 

Questions: Taylor Series | Physics for IIT JAM, UGC - NET, CSIR NET

But since the Maclaurin series for sin (x ) only includes odd terms, n ≥ 5 .

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FAQs on Questions: Taylor Series - Physics for IIT JAM, UGC - NET, CSIR NET

1. What is a Taylor series and how is it used in mathematical methods of physics?
A Taylor series is a representation of a function as an infinite sum of terms that are calculated from the values of the function's derivatives at a single point. It is used in mathematical methods of physics to approximate functions that may be difficult to evaluate directly. By using a Taylor series expansion, physicists can simplify complex functions and make them more manageable for further analysis.
2. How is the Taylor series derived and what are its key components?
The Taylor series is derived by expressing a function as an infinite sum of terms, where each term is the value of a derivative of the function evaluated at a particular point. The key components of a Taylor series include the function itself, the point of expansion, and the derivatives of the function at that point. The derivatives are used to calculate the coefficients of the terms in the series, which determine the contributions of each term to the overall approximation of the function.
3. What are the applications of Taylor series in physics?
Taylor series have various applications in physics. They are used to approximate functions in mathematical models of physical systems, allowing for easier analysis and computation. Taylor series expansions are particularly useful in solving differential equations, as they can transform a complex equation into a series of simpler equations. They are also used in numerical methods for solving physics problems, such as finding roots of equations or integrating functions.
4. Can the Taylor series be used to approximate any arbitrary function?
No, the Taylor series can only approximate functions that are analytic, meaning they can be expressed as a power series. Functions that have singularities, such as poles or branch cuts, cannot be accurately approximated using a Taylor series. In such cases, other mathematical techniques, such as Laurent series or Fourier series, may be more appropriate.
5. How does the accuracy of a Taylor series approximation depend on the number of terms used?
The accuracy of a Taylor series approximation improves as more terms are included in the series. Each additional term in the series adds more detail to the approximation, allowing it to better match the behavior of the original function. However, it is important to note that the accuracy is only guaranteed within a certain radius of convergence, which is determined by the properties of the function being approximated. Beyond this radius, the series may diverge or fail to accurately represent the function.
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