RD Sharma Solutions -Page No.5.12, Negative Numbers And Integers, Class 6, Maths Class 6 Notes | EduRev

RD Sharma Solutions for Class 6 Mathematics

Created by: Abhishek Kapoor

Class 6 : RD Sharma Solutions -Page No.5.12, Negative Numbers And Integers, Class 6, Maths Class 6 Notes | EduRev

The document RD Sharma Solutions -Page No.5.12, Negative Numbers And Integers, Class 6, Maths Class 6 Notes | EduRev is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.
All you need of Class 6 at this link: Class 6

Question 7: Complete the following table:

 

  + −6 −4 −2  0  2  4  6
  6      10 
  4       
  2        8
  0 −6      
 −2       
 −4       0 
 −6    −6   

From the above table
(i) 
Write all the pairs of integers whose sum is 0.
(ii) is (−4) + (−2) = (−2) + (−4)?
(iii) is 0 + (−6) = −6? 

ANSWER:

(i) (6, −6), (4, −4), (2, −2), (0, 0), (−2, 2), (−4, 4) and (−6,6).

(ii) (−4) + (−2) = −6 = (−2) + (−4); Yes

(iii) 0 + (−6) = −6; Yes

 

   +   −6  −4  −2    0    2    4    6
   6    0   2   4    6    8   10   12
   4   −2   0   2    4      6    8   10
   2   −4  −2   0    2    4    6    8
   0   −6  −4  −2    0    2    4    6
  −2   −8  −6  −4   −2    0    2    4
  −4  −10  −8  −6   −4   −2    0    2
  −6  −12  −10  −8   −6   −4   −2    0


Question 8:

Find an integer x such that
(i) x + 1 = 0
(ii) x + 5 = 0
(iii) −3 + x = 0
(iv) x + (−8) = 0
(v) 7 + x = 0
(vi) x + 0 = 0

ANSWER:

(i) x +  1 = 0 ⇒ x = −1
(ii) x + 5 = 0 ⇒ x = −5
(iii) −3 + x = 0 ⇒ x = 3
(iv) x + (−8) = 0 ⇒ x = 8
(v) 7 + x = 0 ⇒ x = −7
(vi) x + 0 = 0  ⇒ x = 0

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