Class 7 Exam  >  Class 7 Notes  >  RD Sharma Solutions for Class 7 Mathematics  >  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math

RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics PDF Download

Question 1:

Find the simple interest, when:
 (i) Principal = Rs 2000, Rate of Interest = 5% per annum and Time = 5 years.
 (ii) Principal = Rs 500, Rate of Interest = 12.5% per annum and Time = 4 years.
 (iii) Principal = Rs 4500, Rate of Interest = 4% per annum and Time =  months.
 (iv) Principal = Rs 12000, Rate of Interest = 18% per annum and Time = 4 months.
 (v) Principal = Rs 1000, Rate of Interest = 10% per annum and Time = 73 days.

Answer 1:

(i) Principal (P) = Rs 2000
Rate of interest (R) = 5% p.a.
Time (T) = 5 years

Simple interest =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

(ii)  Principal (P) = Rs 500
Rate of interest (R) = 12.5% p.a.
Time (T) = 4 years
Simple interest =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

(iii) Principal (P) = Rs 4500
Rate of interest (R) = 4% p.a.
Time (T) = 6 months 

RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Simple interest =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

 

(iv) Principal (P) = Rs 12000
Rate of interest (R) = 18% p.a.
Time (T) = 4 months RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics (1 year = 12 months)

Simple interest =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

 

(v) Principal (P) = Rs 1000
Rate of interest (R) = 10% p.a.
Time (T) = 73 days =    RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Simple interest =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

 

Question 2:

Find the interest on Rs 500 for a period of 4 years at the rate of 8% per annum. Also, find the amount to be paid at the end of the period.

Answer 2:

Principal amount (P) = Rs 500
Time period (T) = 4 years
Rate of interest (R)  = 8% p.a.

Interest = RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Total amount paid = Principal amount + Interest = Rs 500 + 160
                                                                         = Rs 660

Question 3:

A sum of Rs 400 is lent at the rate of 5% per annum. Find the interest at the end of 2 years.

Answer 3:

Principal amount (P) = Rs 400
Time period (T) = 2 years
Rate of interest (R)  = 5% p.a.

Interest paid after 2 years=RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

 

Question 4:

A sum of Rs 400 is lent for 3 years at the rate of 6% per annum. Find the interest.

Answer 4:

Principal amount (P) = Rs 400
Time period (T) = 3 years
Rate of interest (R)  = 6% p.a.
Interest after 3 years =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

 

Question 5:

A person deposits Rs 25000 in a firm who pays an interest at the rate of 20% per annum. Calculate the income he gets from it annually.

Answer 5:

Principal amount (P) = Rs 25000
Time period (T) = 1 year
Rate of interest (R)  = 20% p.a.
Annual interest =

RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

 

Question 6:

A man borrowed Rs 8000 from a bank at 8% per annum. Find the amount he has to pay after 412412years.

Answer 6:

Principal amount (P) = Rs 8000
Time period (T) =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Rate of interest (R)  = 8% p.a.
Interest =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Total amount paid after  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics = Principal amount + Interest = Rs 8000 + Rs 2880  = Rs 10880

 

Question 7:

Rakesh lent out Rs 8000 for 5 years at 15% per annum and borrowed Rs 6000 for 3 years at 12% per annum. How much did he gain or lose?

Answer 7:

Principal amount lent out by Rakesh (P) = Rs 8000
Time period (T) = 5 years
Rate of interest (R)  = 15% p.a.
Interest =   RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Principal amount borrowed by Rakesh (P) = Rs 6000
Time period (T) = 3 years
Rate of interest (R) = 12% p.a.
 Interest =   RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Amount gained by Rakesh = Rs 6000 − Rs 2160 = Rs 3840

 

Question 8:

Anita deposits Rs 1000 in a savings bank account. The bank pays interest at the rate of 5% per annum. What amount can Anita get after one year?

Answer 8:

Principal amount (P) = Rs 1000
Time period (T) = 1 year
Rate of interest (R) = 5% p.a.

 Interest =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Total amount paid after 1 year = Principal amount + Interest = Rs 1000 + Rs 50  = Rs 1050

 

Question 9:

Nalini borrowed Rs 550 from her friend at 8% per annum. She returned the amount after 6 months. How much did she pay?

Answer 9:

Principal amount (P) = Rs 550
Time period (T)  = 6 months =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics (1 year = 12 months)

Interest =   RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Total amount paid after 6 months = Principal amount + Interest = Rs 550 + Rs 22 = Rs 572

 

Question 10:

Rohit borowed Rs 600000 from a bank at 9% per annum for 2 years. He lent this sum of money to Rohan at 10% per annum for 2 years. How much did Rohit earn from this transaction?

Answer 10:

Principal amount lent out by Rohit (P) = Rs. 60000
Time period (T)        = 2 years
Rate of interest (R)  = 10% p.a.

 Interest = RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Principal amount borrowed by Rohit from the bank (P) = Rs. 60000
Time period (T)                                         = 2 years
Rate of interest (R)                                   = 9% p.a.

Interest =   RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Amount gained by Rohit = Rs. 12000 - 10800 = Rs. 1200

 

Question 11:

Romesh borrowed Rs 2000 at 2% per annum and Rs 1000 at 5% per annum. He cleared his debt after 2 years by giving Rs 2800 and a watch. What is the cost of the watch?

Answer 11:

Principal amount borrowed by Romesh (P) = Rs. 2000
Time period (T)        = 2 years
Rate of interest (R)  = 2% p.a.

Interest = RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Principal amount borrowed by Romesh (P) = Rs. 1000
Time period (T)        = 2 years
Rate of interest (R)  = 5% p.a.

 Interest =  RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics

Total amount that he will have to return  = Rs. 2000 + 1000 + 80 + 100 = Rs. 3180

Amount repaid = Rs. 2800
Value of the watch = Rs. 3180 - 2800 = Rs. 380

The document RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math | RD Sharma Solutions for Class 7 Mathematics is a part of the Class 7 Course RD Sharma Solutions for Class 7 Mathematics.
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FAQs on RD Sharma Solutions (Part - 1) - Ex-13.1, Simple Interest, Class 7, Math - RD Sharma Solutions for Class 7 Mathematics

1. What is the formula for calculating simple interest?
Ans. The formula for calculating simple interest is: Simple Interest (SI) = (Principal × Rate × Time)/100
2. How is simple interest different from compound interest?
Ans. Simple interest is calculated only on the principal amount, while compound interest is calculated on both the principal and the accumulated interest. Compound interest generally yields higher returns compared to simple interest over a longer period of time.
3. How do you find the rate of interest in a simple interest problem?
Ans. To find the rate of interest, you need to rearrange the formula for simple interest: Rate = (Simple Interest × 100)/(Principal × Time)
4. Can the principal amount be negative in a simple interest problem?
Ans. No, the principal amount cannot be negative in a simple interest problem. The principal represents the original amount of money, and it is always considered positive.
5. Is simple interest always calculated annually?
Ans. No, simple interest can be calculated for any time period, such as monthly, quarterly, or annually. The time period needs to be consistent with the rate of interest. For example, if the rate of interest is given as an annual rate, the time period should also be in years.
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