Class 7 Exam  >  Class 7 Notes  >  Mathematics (Maths) Class 7 (Old NCERT)  >  RD Sharma Solutions: Decimals (Exercise 3.2)

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT) PDF Download

Q.1. Find the product:

(i) 4.74 × 10

(ii) 0.45 × 10

(iii) 0.0215 × 10

(iv) 0.0054 × 10

Ans: 

(i) On dividing by 100, we get:

4.74 ×10 = Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)× 10 = Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)= 47.4

(ii) On dividing by 100, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)×10 = Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)= 4.5

(iii) Because the decimal is after 4 places from the right, we will divide by 10,000. We get: 

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)×10 = Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)= 0.215

(iv) Because the decimal is after 4 places from the right, we will divide by 10,000. We get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)×10 =Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT) = 0.054


Q.2. Find the product:

(i) 35.853 × 100

(ii) 42.5 × 100

(iii) 12.075 × 100

(iv) 100 × 0.005

Ans: 

(i) On dividing by 1,000, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)× 100 = Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)= 3585.3

(ii) On dividing by 10, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)× 100 =425 ×10 = 4250

(iii) On dividing by 1,000, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)× 100 = Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT) = 1207.5

(iv) On dividing by 1,000, we get:

100 ×Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)= 0.5


Q.3. Find the product:

(i) 2.506 × 1000

(ii) 20.708 × 1000

(iii) 0.0529 × 1000

(iv) 1000 × 0.1

Ans: 

(i) On dividing by 1000, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)×1000 = 2506

(ii) On dividing by 1000, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)× 1000 = 20708

(iii) On dividing by 10,000, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)×1000 = Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)= 52.9

(iv) On dividing by 10, we get:

1000 ×Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)= 100


Q.4. Find the product:

(i) 3.4 × 17

(ii) 0.745 × 12

(iii) 28.73 × 47

(iv) 0.0415 × 59

Ans: 

(i) On dividing the decimal by 10 and multiplying the numbers, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT) = 57.8

(ii) On dividing the decimal by 1000 and multiplying the numbers, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT) = 8.94

(iii) On dividing the decimal by 100 and multiplying the numbers, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT) = 1350.31

(iv) On dividing the decimal by 10000 and multiplying the numbers, we get:

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT) = 2.4485


Q.5. Find:

(i) 1.07 × 0.02

(ii) 211.9 × 1.13

(iii) 10.05 × 1.05

(iv) 13.01 × 5.01

Ans: 

(i)Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

= 0.0214

(ii)Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

= 239.447

(iii)Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

= 10.5525

(iv)Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

= 65.1801


Q.6. Find the area of a rectangle whose length is 5.5 m and breadth is 3.4 m.

Ans: Length of the rectangle = 5.5 m

Breadth of the rectangle = 3.4 m

We know:

Area of rectangle = Length × Breadth

= 5.5 × 3.4 =Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)= 18.7 meter square

Thus, area of the rectangle = 18.7 m2


Q.7. If the cost of a book is Rs 25.75, find the cost of 24 such books.

Ans: Cost of one book = Rs. 25.75

∴ Cost of 24 books = Rs. 25.75 × 24

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

= 103 × 6 

= 618


Q.8. A car covers a distance of 14.75 km in one litre of petrol. How much distance will it cover in 15.5 litres of petrol?

Ans: Distance travelled by the car in 1 litre of petrol = 14.75 km

∴ Distance travelled by the car in 15.5 litres of petrol = 14.75 × 15.5

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

= 228.625 km

Thus, the car travelled 228.625 km in 15.5 litres of petrol.


Q.9. One kg of rice costs Rs 42.65. What will be the cost of 18.25 kg of rice?

Ans: Price of 1 kg of rice = Rs. 42.65

Price of 18.25 kg of rice = Rs. 42.65 × 18.25

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

= 778.3625

Thus, 18.25 kg of rice will cost Rs. 778.36.


Q.10. One metre of cloth costs Rs 152.50. What is the cost of 10.75 metres of cloth?

Ans: Cost of 1 m of cloth = Rs. 152.50

∴ Cost of 10.75 m of cloth = Rs. 152.50 × 10.75

Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

=Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT)

= 1639.375

Thus, 10.75 m of cloth will cost Rs. 1639.375.

The document Decimals (Exercise 3.2) RD Sharma Solutions | Mathematics (Maths) Class 7 (Old NCERT) is a part of the Class 7 Course Mathematics (Maths) Class 7 (Old NCERT).
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FAQs on Decimals (Exercise 3.2) RD Sharma Solutions - Mathematics (Maths) Class 7 (Old NCERT)

1. What are decimals?
Ans. Decimals are a way to represent numbers that are not whole or integers. They consist of a decimal point followed by digits that can be greater than or less than one. For example, 0.5, 2.75, and 3.14159 are all decimals.
2. How are decimals different from fractions?
Ans. Decimals and fractions are both ways to represent numbers that are not whole. However, decimals are expressed in base 10 and use a decimal point, while fractions are expressed as a ratio of two numbers. Decimals can be easily converted to fractions and vice versa.
3. How do you compare decimals?
Ans. To compare decimals, start by comparing the digits to the left of the decimal point. If they are equal, move to the next digit to the right and continue until you find a difference. The decimal with the larger digit at that position is greater. If the digits are equal, but one decimal has additional digits, it is greater.
4. How do you add and subtract decimals?
Ans. To add or subtract decimals, align the decimal points and perform the operation as you would with whole numbers. If the decimals have different numbers of digits after the decimal point, add zeros to the shorter decimal to make them equal in length.
5. Can decimals be converted to percentages?
Ans. Yes, decimals can be easily converted to percentages by multiplying them by 100. For example, 0.75 can be converted to 75%. Similarly, percentages can be converted to decimals by dividing them by 100.
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