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CBSE Class 7  >  Class 7 Notes  >  RD Sharma Solutions Mathematics  >  RD Sharma Solutions - Ex-1.3 Integers, Class 7, Math

RD Sharma Solutions - Ex-1.3 Integers, Class 7, Math

Question 1:

Find the value of
36 ÷ 6 + 3

Answer 1:

On applying the BODMAS rule, we get:
36 ÷ 6 + 3
= 6 + 3 (division first)
= 9

Question 2:

Find the value of
24 + 15 ÷ 3

Answer 2:

On applying the BODMAS rule, we get:
24 + 15 ÷ 3
= 24 + 5 (division first)
= 29

Question 3:

Find the value of
120 - 20 ÷ 4

Answer 3:

On applying the BODMAS rule, we get:
120 - 20 ÷ 4
= 120 - 5 (division first)
= 115

Question 4:

Find the value of
32 - (3 × 5) + 4

Answer 4:

On applying the BODMAS rule, we get:
32 - (3 × 5) + 4
= 32 - 15 + 4 (multiply inside brackets first)
= 32 - 11 (add 15 and 4 is not correct here; perform addition/subtraction from left to right: 32 - 15 = 17, then 17 + 4 = 21)
= 21

Question 5:

Find the value of
3 - (5 - 6 ÷ 3)

Answer 5:

On applying the BODMAS rule, we get:
3 - (5 - 6 ÷ 3)
= 3 - (5 - 2) (division inside brackets first)
= 3 - 3 (simplify inside brackets: 5 - 2 = 3)
= 0

Question 6:

Find the value of
21 - 12 ÷ 3 × 2

Answer 6:

On applying the BODMAS rule, we get:
21 - 12 ÷ 3 × 2
= 21 - 4 × 2 (division first: 12 ÷ 3 = 4)
= 21 - 8 (then multiplication: 4 × 2 = 8)
= 13

Question 7:

Find the value of
16 + 8 ÷ 4 - 2 × 3

Answer 7:

On applying the BODMAS rule, we get:
16 + 8 ÷ 4 - 2 × 3
= 16 + 2 - 6 (division and multiplication first: 8 ÷ 4 = 2, 2 × 3 = 6)
= 18 - 6 (then perform addition: 16 + 2 = 18)
= 12

Question 8:

Find the value of
28 - 5 × 6 + 2

Answer 8:

On applying the BODMAS rule, we get:
28 - 5 × 6 + 2
= 28 - 30 + 2 (multiplication first: 5 × 6 = 30)
= -2 + 2 (then subtraction: 28 - 30 = -2)
= 0

Question 9:

Find the value of
(-20) × (-1) + (-28) ÷ 7

Answer 9:

On applying the BODMAS rule, we get:
(-20) × (-1) + (-28) ÷ 7
= 20 + (-4) (multiplication and division first: (-20)×(-1)=20, (-28)÷7=-4)
= 20 - 4
= 16

Question 10:

Find the value of
(-2) + (-8) ÷ (-4)

Answer 10:

On applying the BODMAS rule, we get:
(-2) + (-8) ÷ (-4)
= (-2) + 2 (division first: (-8) ÷ (-4) = 2)
= 0

Question 11:

Find the value of
(-15) + 4 ÷ (5 - 3)

Answer 11:

On applying the BODMAS rule, we get:
(-15) + 4 ÷ (5 - 3)
= (-15) + 4 ÷ 2 (brackets first: 5 - 3 = 2)
= (-15) + 2 (then division: 4 ÷ 2 = 2)
= -13

Question 12:

Find the value of
(-40) × (-1) + (-28) ÷ 7

Answer 12:

On applying the BODMAS rule, we get:
(-40) × (-1) + (-28) ÷ 7
= 40 + (-4) (multiplication and division first: (-40)×(-1)=40, (-28)÷7=-4)
= 36

Question 13:

Find the value of
(-3) + (-8) ÷ (-4) - 2 × (-2)

Answer 13:

On applying the BODMAS rule, we get:
(-3) + (-8) ÷ (-4) - 2 × (-2)
= (-3) + 2 + 4 (division and multiplication first: (-8)÷(-4)=2, -2×(-2)=4)
= (-3) + 6 (then addition: 2 + 4 = 6)
= 3

Question 14:

Find the value of
(-3) × (-4) ÷ (-2) + (-1).

Answer 14:

On applying the BODMAS rule, we get:
(-3) × (-4) ÷ (-2) + (-1)
= (-3) × 2 + (-1) (division first: (-4) ÷ (-2) = 2)
= -6 - 1 (then multiplication: (-3) × 2 = -6)
= -7

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FAQs on RD Sharma Solutions - Ex-1.3 Integers, Class 7, Math

1. What are RD Sharma Solutions?
Ans. RD Sharma Solutions are a comprehensive set of solutions for the RD Sharma textbook, which is widely used by students studying mathematics in Class 7. These solutions provide step-by-step explanations for all the questions and problems given in the textbook, helping students understand the concepts and solve the problems effectively.
2. How can RD Sharma Solutions help in preparing for the Class 7 Math exam?
Ans. RD Sharma Solutions can be extremely helpful in preparing for the Class 7 Math exam. These solutions provide detailed explanations for each question, making it easier for students to understand the concepts and solve similar problems. By practicing with these solutions, students can improve their problem-solving skills and gain confidence in their math abilities, which can ultimately lead to better performance in the exam.
3. Are the RD Sharma Solutions for Class 7 Math available online?
Ans. Yes, the RD Sharma Solutions for Class 7 Math are available online. There are various websites and educational platforms that provide these solutions for free or for a nominal fee. Students can easily access these solutions online and use them as a valuable resource for their exam preparation.
4. Can RD Sharma Solutions be used as a standalone study material for Class 7 Math?
Ans. While RD Sharma Solutions provide detailed explanations and solutions to the textbook questions, it is recommended to use them as a supplement to the textbook rather than a standalone study material. The textbook itself contains important concepts, examples, and exercises that are crucial for understanding the subject. Therefore, it is advisable to use the RD Sharma Solutions in conjunction with the textbook to get a comprehensive understanding of the topics.
5. Are RD Sharma Solutions suitable for self-study?
Ans. Yes, RD Sharma Solutions are suitable for self-study. The solutions provide step-by-step explanations, allowing students to learn at their own pace and independently solve the problems. However, it is always beneficial to seek guidance from a teacher or mentor if any difficulties or doubts arise during the self-study process. Having someone to clarify concepts and provide additional explanations can enhance the effectiveness of using RD Sharma Solutions for self-study.
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