Find the value of
36 ÷ 6 + 3
On applying the BODMAS rule, we get:
36 ÷ 6 + 3
= 6 + 3 (On performing division)
= 9
Find the value of
24 + 15 ÷ 3
On applying the BODMAS rule, we get:
24 + 15 ÷ 3
= 24 + 5 (On performing division)
= 29
Find the value of
120 − 20 ÷ 4
On applying the DMAS rule, we get:
120 − 20 ÷ 4
= 120 − 5 (On performing division)
= 115
Find the value of
32 − (3 × 5) + 4
On applying the DMAS rule, we get:
32 − ( 3 × 5 ) + 4
= 32 − 15 + 4 (On performing multiplication)
= 36 − 15 (On performing addition)
= 21 (On performing subtraction)
Find the value of
3 − (5 − 6 ÷ 3)
On applying the DMAS rule, we get:
3 −- ( 5 −- 6 ÷ 3)
= 3 −- ( 5 − 2) (On performing division)
= 3 −- 3 (On performing subtraction)
= 0
Find the value of
21 − 12 ÷ 3 × 2
On applying the DMAS rule, we get:
21 − 12 ÷ 3 × 2
= 21 − 4 × 2 (On performing division)
= 21 − 8 (On performing multiplication)
= 13 (On performing subtraction)
Find the value of
16 + 8 ÷ 4 − 2 × 3
On applying the DMAS rule, we get:
16 + 8 ÷ 4 − 2 × 3
= 16 + 2 − 6 (On performing division and multiplication)
= 18 − 6
= 12
Find the value of
28 − 5 × 6 + 2
On applying the DMAS rule, we get:
28 −- 5 × 6 + 2
= 28 −- 30 + 2 (On performing multiplication)
= 30 −- 30 (On performing addition)
= 0 (On performing subtraction)
Find the value of
(−20) × (−1) + (−28) ÷ 7
On applying the DMAS rule, we get:
(− 20) × (− 1) + (−28) ÷ 7
= 20 + (− 4) (On performing division and multiplication)
= 20 − 4
= 16
Find the value of
(−2) + (−8) ÷ (−4)
On applying the DMAS rule, we get:
(− 2) + (− 8) ÷ (− 4)
= (− 2) + 2 (On performing division)
= 0 (On performing addition)
Find the value of
(−15) + 4 ÷ (5 − 3)
On applying the BODMAS rule, we get:
(− 15) + 4 ÷ (5 − 3)
= (− 15) + 4 ÷ 2 (On simplifying brackets)
= (− 15) + 2 (On performing division)
= − 13
Find the value of
(−40) × (−1) + (−28) ÷ 7
On applying the BODMAS rule, we get:
(− 40) × (− 1) + (− 28) ÷ 7
= 40 + (− 4) (On performing division and multiplication)
= 36
Find the value of
(−3) + (−8) ÷ (−4) −2 × (−2)
On applying the BODMAS rule, we get:
(− 3) + (− 8) ÷ (− 4) − 2 × (− 2)
= (− 3) + 2 + 4 (On performing division and multiplication)
= (− 3) + 6 (On performing addition)
= 3 (On performing subtraction)
Find the value of
(−3) × (−4) ÷ (−2) + (−1).
On applying the BODMAS rule, we get:
(−3) × (−4) ÷ (−2) + (−1)
= (−3) × 2 + (−1) (On performing division)
= −6 − 1 (On performing multiplication)
= −7 (On performing addition)
1. What are RD Sharma Solutions? |
2. How can RD Sharma Solutions help in preparing for the Class 7 Math exam? |
3. Are the RD Sharma Solutions for Class 7 Math available online? |
4. Can RD Sharma Solutions be used as a standalone study material for Class 7 Math? |
5. Are RD Sharma Solutions suitable for self-study? |
|
Explore Courses for Class 7 exam
|