Class 8 Exam > Class 8 Notes > Mathematics (Maths) Class 8 > RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots
Exercise 4.5 - Cubes & Cube Roots RD Sharma Solutions | Mathematics (Maths) Class 8 PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
Question:54
Making use of the cube root table, find the cube roots 7
Solution:
Because 7 lies between 1 and 100, we will look at the row containing 7 in the column of x.
By the cube root table, we have:
3
v 7 = 1. 913
Thus, the answer is 1.913.
Question:55
Making use of the cube root table, find the cube root
70
Solution:
Because 70 lies between 1 and 100, we will look at the row containing 70 in the column of x.
By the cube root table, we have:
3
v 70 = 4. 121
Question:56
Making use of the cube root table, find the cube root
700
Solution:
We have:
700 = 70 ×10
? Cube root of 700 will be in the column of
3
v 10x against 70.
By the cube root table, we have:
3
v 700 = 8. 879
Thus, the answer is 8.879.
Question:57
Making use of the cube root table, find the cube root
7000
Solution:
We have:
7000 = 70 ×100
?
3
v 7000 =
3
v 7 ×1000 =
3
v 7 ×
3
v 1000
By the cube root table, we have:
3
v 7 = 1. 913 and
3
v 1000 = 10
?
3
v 7000 =
3
v 7 ×
3
v 1000 = 1. 913 ×10 = 19. 13
Question:58
Making use of the cube root table, find the cube root
1100
Solution:
We have:
1100 = 11 ×100
?
3
v 1100 =
3
v 11 ×100 =
3
v 11 ×
3
v 100
By the cube root table, we have:
3
v 11 = 2. 224 and
3
v 100 = 4. 642
?
3
v 1100 =
3
v 11 ×
3
v 100 = 2. 224 ×4. 642 = 10. 323 Up to three decimal places
Thus, the answer is 10.323.
Question:59
Making use of the cube root table, find the cube root
780
Solution:
We have:
( )
Page 2
Question:54
Making use of the cube root table, find the cube roots 7
Solution:
Because 7 lies between 1 and 100, we will look at the row containing 7 in the column of x.
By the cube root table, we have:
3
v 7 = 1. 913
Thus, the answer is 1.913.
Question:55
Making use of the cube root table, find the cube root
70
Solution:
Because 70 lies between 1 and 100, we will look at the row containing 70 in the column of x.
By the cube root table, we have:
3
v 70 = 4. 121
Question:56
Making use of the cube root table, find the cube root
700
Solution:
We have:
700 = 70 ×10
? Cube root of 700 will be in the column of
3
v 10x against 70.
By the cube root table, we have:
3
v 700 = 8. 879
Thus, the answer is 8.879.
Question:57
Making use of the cube root table, find the cube root
7000
Solution:
We have:
7000 = 70 ×100
?
3
v 7000 =
3
v 7 ×1000 =
3
v 7 ×
3
v 1000
By the cube root table, we have:
3
v 7 = 1. 913 and
3
v 1000 = 10
?
3
v 7000 =
3
v 7 ×
3
v 1000 = 1. 913 ×10 = 19. 13
Question:58
Making use of the cube root table, find the cube root
1100
Solution:
We have:
1100 = 11 ×100
?
3
v 1100 =
3
v 11 ×100 =
3
v 11 ×
3
v 100
By the cube root table, we have:
3
v 11 = 2. 224 and
3
v 100 = 4. 642
?
3
v 1100 =
3
v 11 ×
3
v 100 = 2. 224 ×4. 642 = 10. 323 Up to three decimal places
Thus, the answer is 10.323.
Question:59
Making use of the cube root table, find the cube root
780
Solution:
We have:
( )
780 = 78 ×10
? Cube root of 780 would be in the column of
3
v 10x against 78.
By the cube root table, we have:
3
v 780 = 9. 205
Thus, the answer is 9.205.
Question:60
Making use of the cube root table, find the cube root
7800
Solution:
We have:
7800 = 78 ×100
?
3
v 7800 =
3
v 78 ×100 =
3
v 78 ×
3
v 100
By the cube root table, we have:
3
v 78 = 4. 273 and
3
v 100 = 4. 642
3
v 7800 =
3
v 78 ×
3
v 100 = 4. 273 ×4. 642 = 19. 835 upto three decimal places
Thus, the answer is 19.835
Question:61
Making use of the cube root table, find the cube root
1346
Solution:
By prime factorisation, we have:
1346 = 2 ×673 ?
3
v 1346 =
3
v 2 ×
3
v 673
Also
670 < 673 < 680 ?
3
v 670 <
3
v 673 <
3
v 680
From the cube root table, we have:
3
v 670 = 8. 750 and
3
v 680 = 8. 794
For the difference (680 -670), i.e., 10, the difference in the values
= 8. 794 -8. 750 = 0. 044
? For the difference of (673 -670), i.e., 3, the difference in the values
=
0.044
10
×3 = 0. 0132 = 0. 013 uptothreedecimalplaces
?
3
v 673 = 8. 750 +0. 013 = 8. 763
Now
3
v 1346 =
3
v 2 ×
3
v 673 = 1. 260 ×8. 763 = 11. 041 uptothreedecimalplaces
Thus, the answer is 11.041.
Question:62
Making use of the cube root table, find the cube root
250
Solution:
We have:
250 = 25 ×100
? Cube root of 250 would be in the column of
3
v 10x against 25.
By the cube root table, we have:
3
v 250 = 6. 3
Thus, the required cube root is 6.3.
Question:63
Making use of the cube root table, find the cube root
5112
Solution:
By prime factorisation, we have:
5112 = 2
3
×3
2
×71 ?
3
v 5112 = 2 ×
3
v 9 ×
3
v 71
( )
Page 3
Question:54
Making use of the cube root table, find the cube roots 7
Solution:
Because 7 lies between 1 and 100, we will look at the row containing 7 in the column of x.
By the cube root table, we have:
3
v 7 = 1. 913
Thus, the answer is 1.913.
Question:55
Making use of the cube root table, find the cube root
70
Solution:
Because 70 lies between 1 and 100, we will look at the row containing 70 in the column of x.
By the cube root table, we have:
3
v 70 = 4. 121
Question:56
Making use of the cube root table, find the cube root
700
Solution:
We have:
700 = 70 ×10
? Cube root of 700 will be in the column of
3
v 10x against 70.
By the cube root table, we have:
3
v 700 = 8. 879
Thus, the answer is 8.879.
Question:57
Making use of the cube root table, find the cube root
7000
Solution:
We have:
7000 = 70 ×100
?
3
v 7000 =
3
v 7 ×1000 =
3
v 7 ×
3
v 1000
By the cube root table, we have:
3
v 7 = 1. 913 and
3
v 1000 = 10
?
3
v 7000 =
3
v 7 ×
3
v 1000 = 1. 913 ×10 = 19. 13
Question:58
Making use of the cube root table, find the cube root
1100
Solution:
We have:
1100 = 11 ×100
?
3
v 1100 =
3
v 11 ×100 =
3
v 11 ×
3
v 100
By the cube root table, we have:
3
v 11 = 2. 224 and
3
v 100 = 4. 642
?
3
v 1100 =
3
v 11 ×
3
v 100 = 2. 224 ×4. 642 = 10. 323 Up to three decimal places
Thus, the answer is 10.323.
Question:59
Making use of the cube root table, find the cube root
780
Solution:
We have:
( )
780 = 78 ×10
? Cube root of 780 would be in the column of
3
v 10x against 78.
By the cube root table, we have:
3
v 780 = 9. 205
Thus, the answer is 9.205.
Question:60
Making use of the cube root table, find the cube root
7800
Solution:
We have:
7800 = 78 ×100
?
3
v 7800 =
3
v 78 ×100 =
3
v 78 ×
3
v 100
By the cube root table, we have:
3
v 78 = 4. 273 and
3
v 100 = 4. 642
3
v 7800 =
3
v 78 ×
3
v 100 = 4. 273 ×4. 642 = 19. 835 upto three decimal places
Thus, the answer is 19.835
Question:61
Making use of the cube root table, find the cube root
1346
Solution:
By prime factorisation, we have:
1346 = 2 ×673 ?
3
v 1346 =
3
v 2 ×
3
v 673
Also
670 < 673 < 680 ?
3
v 670 <
3
v 673 <
3
v 680
From the cube root table, we have:
3
v 670 = 8. 750 and
3
v 680 = 8. 794
For the difference (680 -670), i.e., 10, the difference in the values
= 8. 794 -8. 750 = 0. 044
? For the difference of (673 -670), i.e., 3, the difference in the values
=
0.044
10
×3 = 0. 0132 = 0. 013 uptothreedecimalplaces
?
3
v 673 = 8. 750 +0. 013 = 8. 763
Now
3
v 1346 =
3
v 2 ×
3
v 673 = 1. 260 ×8. 763 = 11. 041 uptothreedecimalplaces
Thus, the answer is 11.041.
Question:62
Making use of the cube root table, find the cube root
250
Solution:
We have:
250 = 25 ×100
? Cube root of 250 would be in the column of
3
v 10x against 25.
By the cube root table, we have:
3
v 250 = 6. 3
Thus, the required cube root is 6.3.
Question:63
Making use of the cube root table, find the cube root
5112
Solution:
By prime factorisation, we have:
5112 = 2
3
×3
2
×71 ?
3
v 5112 = 2 ×
3
v 9 ×
3
v 71
( )
By the cube root table, we have:
3
v 9 = 2. 080 and
3
v 71 = 4. 141
?
3
v 5112 = 2 ×
3
v 9 ×
3
v 71 = 2 ×2. 080 ×4. 141 = 17. 227 uptothreedecimalplaces
Thus, the required cube root is 17.227.
Question:64
Making use of the cube root table, find the cube root
9800
Solution:
We have:
9800 = 98 ×100
?
3
v 9800 =
3
v 98 ×100 =
3
v 98 ×
3
v 100
By cube root table, we have:
3
v 98 = 4. 610 and
3
v 100 = 4. 642
?
3
v 9800 =
3
v 98 ×
3
v 100 = 4. 610 ×4. 642 = 21. 40 uptothreedecimalplaces
Thus, the required cube root is 21.40.
Question:65
Making use of the cube root table, find the cube root
732
Solution:
We have:
730 < 732 < 740 ?
3
v 730 <
3
v 732 <
3
v 740
From cube root table, we have:
3
v 730 = 9. 004 and
3
v 740 = 9. 045
For the difference (740 -730), i.e., 10, the difference in values
= 9. 045 -9. 004 = 0. 041
? For the difference of (732 -730), i.e., 2, the difference in values
=
0.041
10
×2 = 0. 0082
?
3
v 732 = 9. 004 +0. 008 = 9. 012
Question:66
Making use of the cube root table, find the cube root
7342
Solution:
We have:
7300 < 7342 < 7400 ?
3
v 7000 <
3
v 7342 <
3
v 7400
From the cube root table, we have:
3
v 7300 = 19. 39 and
3
v 7400 = 19. 48
For the difference (7400 -7300), i.e., 100, the difference in values
= 19. 48 -19. 39 = 0. 09
? For the difference of (7342 -7300), i.e., 42, the difference in the values
=
0.09
100
×42 = 0. 0378 = 0. 037
?
3
v 7342 = 19. 39 +0. 037 = 19. 427
Question:67
Making use of the cube root table, find the cube root
133100
Solution:
We have:
133100 = 1331 ×100 ?
3
v 133100 =
3
v 1331 ×100 = 11 ×
3
v 100
By cube root table, we have:
3
v 100 = 4. 642
?
3
v 133100 = 11 ×
3
v 100 = 11 ×4. 642 = 51. 062
Page 4
Question:54
Making use of the cube root table, find the cube roots 7
Solution:
Because 7 lies between 1 and 100, we will look at the row containing 7 in the column of x.
By the cube root table, we have:
3
v 7 = 1. 913
Thus, the answer is 1.913.
Question:55
Making use of the cube root table, find the cube root
70
Solution:
Because 70 lies between 1 and 100, we will look at the row containing 70 in the column of x.
By the cube root table, we have:
3
v 70 = 4. 121
Question:56
Making use of the cube root table, find the cube root
700
Solution:
We have:
700 = 70 ×10
? Cube root of 700 will be in the column of
3
v 10x against 70.
By the cube root table, we have:
3
v 700 = 8. 879
Thus, the answer is 8.879.
Question:57
Making use of the cube root table, find the cube root
7000
Solution:
We have:
7000 = 70 ×100
?
3
v 7000 =
3
v 7 ×1000 =
3
v 7 ×
3
v 1000
By the cube root table, we have:
3
v 7 = 1. 913 and
3
v 1000 = 10
?
3
v 7000 =
3
v 7 ×
3
v 1000 = 1. 913 ×10 = 19. 13
Question:58
Making use of the cube root table, find the cube root
1100
Solution:
We have:
1100 = 11 ×100
?
3
v 1100 =
3
v 11 ×100 =
3
v 11 ×
3
v 100
By the cube root table, we have:
3
v 11 = 2. 224 and
3
v 100 = 4. 642
?
3
v 1100 =
3
v 11 ×
3
v 100 = 2. 224 ×4. 642 = 10. 323 Up to three decimal places
Thus, the answer is 10.323.
Question:59
Making use of the cube root table, find the cube root
780
Solution:
We have:
( )
780 = 78 ×10
? Cube root of 780 would be in the column of
3
v 10x against 78.
By the cube root table, we have:
3
v 780 = 9. 205
Thus, the answer is 9.205.
Question:60
Making use of the cube root table, find the cube root
7800
Solution:
We have:
7800 = 78 ×100
?
3
v 7800 =
3
v 78 ×100 =
3
v 78 ×
3
v 100
By the cube root table, we have:
3
v 78 = 4. 273 and
3
v 100 = 4. 642
3
v 7800 =
3
v 78 ×
3
v 100 = 4. 273 ×4. 642 = 19. 835 upto three decimal places
Thus, the answer is 19.835
Question:61
Making use of the cube root table, find the cube root
1346
Solution:
By prime factorisation, we have:
1346 = 2 ×673 ?
3
v 1346 =
3
v 2 ×
3
v 673
Also
670 < 673 < 680 ?
3
v 670 <
3
v 673 <
3
v 680
From the cube root table, we have:
3
v 670 = 8. 750 and
3
v 680 = 8. 794
For the difference (680 -670), i.e., 10, the difference in the values
= 8. 794 -8. 750 = 0. 044
? For the difference of (673 -670), i.e., 3, the difference in the values
=
0.044
10
×3 = 0. 0132 = 0. 013 uptothreedecimalplaces
?
3
v 673 = 8. 750 +0. 013 = 8. 763
Now
3
v 1346 =
3
v 2 ×
3
v 673 = 1. 260 ×8. 763 = 11. 041 uptothreedecimalplaces
Thus, the answer is 11.041.
Question:62
Making use of the cube root table, find the cube root
250
Solution:
We have:
250 = 25 ×100
? Cube root of 250 would be in the column of
3
v 10x against 25.
By the cube root table, we have:
3
v 250 = 6. 3
Thus, the required cube root is 6.3.
Question:63
Making use of the cube root table, find the cube root
5112
Solution:
By prime factorisation, we have:
5112 = 2
3
×3
2
×71 ?
3
v 5112 = 2 ×
3
v 9 ×
3
v 71
( )
By the cube root table, we have:
3
v 9 = 2. 080 and
3
v 71 = 4. 141
?
3
v 5112 = 2 ×
3
v 9 ×
3
v 71 = 2 ×2. 080 ×4. 141 = 17. 227 uptothreedecimalplaces
Thus, the required cube root is 17.227.
Question:64
Making use of the cube root table, find the cube root
9800
Solution:
We have:
9800 = 98 ×100
?
3
v 9800 =
3
v 98 ×100 =
3
v 98 ×
3
v 100
By cube root table, we have:
3
v 98 = 4. 610 and
3
v 100 = 4. 642
?
3
v 9800 =
3
v 98 ×
3
v 100 = 4. 610 ×4. 642 = 21. 40 uptothreedecimalplaces
Thus, the required cube root is 21.40.
Question:65
Making use of the cube root table, find the cube root
732
Solution:
We have:
730 < 732 < 740 ?
3
v 730 <
3
v 732 <
3
v 740
From cube root table, we have:
3
v 730 = 9. 004 and
3
v 740 = 9. 045
For the difference (740 -730), i.e., 10, the difference in values
= 9. 045 -9. 004 = 0. 041
? For the difference of (732 -730), i.e., 2, the difference in values
=
0.041
10
×2 = 0. 0082
?
3
v 732 = 9. 004 +0. 008 = 9. 012
Question:66
Making use of the cube root table, find the cube root
7342
Solution:
We have:
7300 < 7342 < 7400 ?
3
v 7000 <
3
v 7342 <
3
v 7400
From the cube root table, we have:
3
v 7300 = 19. 39 and
3
v 7400 = 19. 48
For the difference (7400 -7300), i.e., 100, the difference in values
= 19. 48 -19. 39 = 0. 09
? For the difference of (7342 -7300), i.e., 42, the difference in the values
=
0.09
100
×42 = 0. 0378 = 0. 037
?
3
v 7342 = 19. 39 +0. 037 = 19. 427
Question:67
Making use of the cube root table, find the cube root
133100
Solution:
We have:
133100 = 1331 ×100 ?
3
v 133100 =
3
v 1331 ×100 = 11 ×
3
v 100
By cube root table, we have:
3
v 100 = 4. 642
?
3
v 133100 = 11 ×
3
v 100 = 11 ×4. 642 = 51. 062
Question:68
Making use of the cube root table, find the cube root
37800
Solution:
We have:
37800 = 2
3
×3
3
×175 ?
3
v 37800 =
3
v
2
3
×3
3
×175 = 6 ×
3
v 175
Also
170 < 175 < 180 ?
3
v 170 <
3
v 175 <
3
v 180
From cube root table, we have:
3
v 170 = 5. 540 and
3
v 180 = 5. 646
For the difference (180 -170), i.e., 10, the difference in values
= 5. 646 -5. 540 = 0. 106
? For the difference of (175 -170), i.e., 5, the difference in values
=
0.106
10
×5 = 0. 053
?
3
v 175 = 5. 540 +0. 053 = 5. 593
Now
37800 = 6 ×
3
v 175 = 6 ×5. 593 = 33. 558
Thus, the required cube root is 33.558.
Question:69
Making use of the cube root table, find the cube root
0.27
Solution:
The number 0.27 can be written as
27
100
.
Now
3
v 0. 27 =
3 27
100
=
3
v
27
3
v
100
=
3
3
v
100
By cube root table, we have:
3
v 100 = 4. 642
?
3
v 0. 27 =
3
3
v
100
=
3
4.642
= 0. 646
Thus, the required cube root is 0.646.
Question:70
Making use of the cube root table, find the cube root
8.6
Solution:
The number 8.6 can be written as
86
10
.
Now
3
v 8. 6 =
3 86
10
=
3
v
86
3
v
10
By cube root table, we have:
3
v 86 = 4. 414 and
3
v 10 = 2. 154
?
3
v 8. 6 =
3
v
86
3
v
10
=
4.414
2.154
= 2. 049
Thus, the required cube root is 2.049.
Question:71
Making use of the cube root table, find the cube root
0.86
Solution:
The number 0.86 could be written as
86
100
.
Now
3
v 0. 86 =
3 86
100
=
3
v
86
3
v
100
v
v
v
Page 5
Question:54
Making use of the cube root table, find the cube roots 7
Solution:
Because 7 lies between 1 and 100, we will look at the row containing 7 in the column of x.
By the cube root table, we have:
3
v 7 = 1. 913
Thus, the answer is 1.913.
Question:55
Making use of the cube root table, find the cube root
70
Solution:
Because 70 lies between 1 and 100, we will look at the row containing 70 in the column of x.
By the cube root table, we have:
3
v 70 = 4. 121
Question:56
Making use of the cube root table, find the cube root
700
Solution:
We have:
700 = 70 ×10
? Cube root of 700 will be in the column of
3
v 10x against 70.
By the cube root table, we have:
3
v 700 = 8. 879
Thus, the answer is 8.879.
Question:57
Making use of the cube root table, find the cube root
7000
Solution:
We have:
7000 = 70 ×100
?
3
v 7000 =
3
v 7 ×1000 =
3
v 7 ×
3
v 1000
By the cube root table, we have:
3
v 7 = 1. 913 and
3
v 1000 = 10
?
3
v 7000 =
3
v 7 ×
3
v 1000 = 1. 913 ×10 = 19. 13
Question:58
Making use of the cube root table, find the cube root
1100
Solution:
We have:
1100 = 11 ×100
?
3
v 1100 =
3
v 11 ×100 =
3
v 11 ×
3
v 100
By the cube root table, we have:
3
v 11 = 2. 224 and
3
v 100 = 4. 642
?
3
v 1100 =
3
v 11 ×
3
v 100 = 2. 224 ×4. 642 = 10. 323 Up to three decimal places
Thus, the answer is 10.323.
Question:59
Making use of the cube root table, find the cube root
780
Solution:
We have:
( )
780 = 78 ×10
? Cube root of 780 would be in the column of
3
v 10x against 78.
By the cube root table, we have:
3
v 780 = 9. 205
Thus, the answer is 9.205.
Question:60
Making use of the cube root table, find the cube root
7800
Solution:
We have:
7800 = 78 ×100
?
3
v 7800 =
3
v 78 ×100 =
3
v 78 ×
3
v 100
By the cube root table, we have:
3
v 78 = 4. 273 and
3
v 100 = 4. 642
3
v 7800 =
3
v 78 ×
3
v 100 = 4. 273 ×4. 642 = 19. 835 upto three decimal places
Thus, the answer is 19.835
Question:61
Making use of the cube root table, find the cube root
1346
Solution:
By prime factorisation, we have:
1346 = 2 ×673 ?
3
v 1346 =
3
v 2 ×
3
v 673
Also
670 < 673 < 680 ?
3
v 670 <
3
v 673 <
3
v 680
From the cube root table, we have:
3
v 670 = 8. 750 and
3
v 680 = 8. 794
For the difference (680 -670), i.e., 10, the difference in the values
= 8. 794 -8. 750 = 0. 044
? For the difference of (673 -670), i.e., 3, the difference in the values
=
0.044
10
×3 = 0. 0132 = 0. 013 uptothreedecimalplaces
?
3
v 673 = 8. 750 +0. 013 = 8. 763
Now
3
v 1346 =
3
v 2 ×
3
v 673 = 1. 260 ×8. 763 = 11. 041 uptothreedecimalplaces
Thus, the answer is 11.041.
Question:62
Making use of the cube root table, find the cube root
250
Solution:
We have:
250 = 25 ×100
? Cube root of 250 would be in the column of
3
v 10x against 25.
By the cube root table, we have:
3
v 250 = 6. 3
Thus, the required cube root is 6.3.
Question:63
Making use of the cube root table, find the cube root
5112
Solution:
By prime factorisation, we have:
5112 = 2
3
×3
2
×71 ?
3
v 5112 = 2 ×
3
v 9 ×
3
v 71
( )
By the cube root table, we have:
3
v 9 = 2. 080 and
3
v 71 = 4. 141
?
3
v 5112 = 2 ×
3
v 9 ×
3
v 71 = 2 ×2. 080 ×4. 141 = 17. 227 uptothreedecimalplaces
Thus, the required cube root is 17.227.
Question:64
Making use of the cube root table, find the cube root
9800
Solution:
We have:
9800 = 98 ×100
?
3
v 9800 =
3
v 98 ×100 =
3
v 98 ×
3
v 100
By cube root table, we have:
3
v 98 = 4. 610 and
3
v 100 = 4. 642
?
3
v 9800 =
3
v 98 ×
3
v 100 = 4. 610 ×4. 642 = 21. 40 uptothreedecimalplaces
Thus, the required cube root is 21.40.
Question:65
Making use of the cube root table, find the cube root
732
Solution:
We have:
730 < 732 < 740 ?
3
v 730 <
3
v 732 <
3
v 740
From cube root table, we have:
3
v 730 = 9. 004 and
3
v 740 = 9. 045
For the difference (740 -730), i.e., 10, the difference in values
= 9. 045 -9. 004 = 0. 041
? For the difference of (732 -730), i.e., 2, the difference in values
=
0.041
10
×2 = 0. 0082
?
3
v 732 = 9. 004 +0. 008 = 9. 012
Question:66
Making use of the cube root table, find the cube root
7342
Solution:
We have:
7300 < 7342 < 7400 ?
3
v 7000 <
3
v 7342 <
3
v 7400
From the cube root table, we have:
3
v 7300 = 19. 39 and
3
v 7400 = 19. 48
For the difference (7400 -7300), i.e., 100, the difference in values
= 19. 48 -19. 39 = 0. 09
? For the difference of (7342 -7300), i.e., 42, the difference in the values
=
0.09
100
×42 = 0. 0378 = 0. 037
?
3
v 7342 = 19. 39 +0. 037 = 19. 427
Question:67
Making use of the cube root table, find the cube root
133100
Solution:
We have:
133100 = 1331 ×100 ?
3
v 133100 =
3
v 1331 ×100 = 11 ×
3
v 100
By cube root table, we have:
3
v 100 = 4. 642
?
3
v 133100 = 11 ×
3
v 100 = 11 ×4. 642 = 51. 062
Question:68
Making use of the cube root table, find the cube root
37800
Solution:
We have:
37800 = 2
3
×3
3
×175 ?
3
v 37800 =
3
v
2
3
×3
3
×175 = 6 ×
3
v 175
Also
170 < 175 < 180 ?
3
v 170 <
3
v 175 <
3
v 180
From cube root table, we have:
3
v 170 = 5. 540 and
3
v 180 = 5. 646
For the difference (180 -170), i.e., 10, the difference in values
= 5. 646 -5. 540 = 0. 106
? For the difference of (175 -170), i.e., 5, the difference in values
=
0.106
10
×5 = 0. 053
?
3
v 175 = 5. 540 +0. 053 = 5. 593
Now
37800 = 6 ×
3
v 175 = 6 ×5. 593 = 33. 558
Thus, the required cube root is 33.558.
Question:69
Making use of the cube root table, find the cube root
0.27
Solution:
The number 0.27 can be written as
27
100
.
Now
3
v 0. 27 =
3 27
100
=
3
v
27
3
v
100
=
3
3
v
100
By cube root table, we have:
3
v 100 = 4. 642
?
3
v 0. 27 =
3
3
v
100
=
3
4.642
= 0. 646
Thus, the required cube root is 0.646.
Question:70
Making use of the cube root table, find the cube root
8.6
Solution:
The number 8.6 can be written as
86
10
.
Now
3
v 8. 6 =
3 86
10
=
3
v
86
3
v
10
By cube root table, we have:
3
v 86 = 4. 414 and
3
v 10 = 2. 154
?
3
v 8. 6 =
3
v
86
3
v
10
=
4.414
2.154
= 2. 049
Thus, the required cube root is 2.049.
Question:71
Making use of the cube root table, find the cube root
0.86
Solution:
The number 0.86 could be written as
86
100
.
Now
3
v 0. 86 =
3 86
100
=
3
v
86
3
v
100
v
v
v
By cube root table, we have:
3
v 86 = 4. 414 and
3
v 100 = 4. 642
?
3
v 0. 86 =
3
v
86
3
v
100
=
4.414
4.642
= 0. 951 uptothreedecimalplaces
Thus, the required cube root is 0.951.
Question:72
Making use of the cube root table, find the cube root
8.65
Solution:
The number 8.65 could be written as
865
100
.
Now
3
v 8. 65 =
3 865
100
=
3
v
865
3
v
100
Also
860 < 865 < 870 ?
3
v 860 <
3
v 865 <
3
v 870
From the cube root table, we have:
3
v 860 = 9. 510 and
3
v 870 = 9. 546
For the difference (870 -860), i.e., 10, the difference in values
= 9. 546 -9. 510 = 0. 036
? For the difference of (865 -860), i.e., 5, the difference in values
=
0.036
10
×5 = 0. 018 uptothreedecimalplaces
?
3
v 865 = 9. 510 +0. 018 = 9. 528 uptothreedecimalplaces
From the cube root table, we also have:
3
v 100 = 4. 642
?
3
v 8. 65 =
3
v
865
3
v
100
=
9.528
4.642
= 2. 053 uptothreedecimalplaces
Thus, the required cube root is 2.053.
Question:73
Making use of the cube root table, find the cube root
7532
Solution:
We have:
7500 < 7532 < 7600 ?
3
v 7500 <
3
v 7532 <
3
v 7600
From the cube root table, we have:
3
v 7500 = 19. 57 and
3
v 7600 = 19. 66
For the difference (7600 -7500), i.e., 100, the difference in values
= 19. 66 -19. 57 = 0. 09
? For the difference of (7532 -7500), i.e., 32, the difference in values
=
0.09
100
×32 = 0. 0288 = 0. 029 uptothreedecimalplaces
?
3
v 7532 = 19. 57 +0. 029 = 19. 599
Question:74
Making use of the cube root table, find the cube root
833
Solution:
We have:
830 < 833 < 840 ?
3
v 830 <
3
v 833 <
3
v 840
From the cube root table, we have:
3
v 830 = 9. 398 and
3
v 840 = 9. 435
For the difference (840 -830), i.e., 10, the difference in values
= 9. 435 -9. 398 = 0. 037
v
Read More
|
79 videos|408 docs|31 tests
|
Related Exams
About this Document
|
4.73/5 Rating |
|
Dec 24, 2024 Last updated |
Document Description: RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots for Class 8 2024 is part of Mathematics (Maths) Class 8 preparation.
The notes and questions for RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots have been prepared according to the Class 8 exam syllabus. Information about RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots covers topics
like and RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots Example, for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots.
Introduction of RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots in English is available as part of our Mathematics (Maths) Class 8
for Class 8 & RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots in Hindi for Mathematics (Maths) Class 8 course.
Download more important topics related with notes, lectures and mock test series for Class 8
Exam by signing up for free. Class 8: Exercise 4.5 - Cubes & Cube Roots RD Sharma Solutions | Mathematics (Maths) Class 8
Description
Full syllabus notes, lecture & questions for Exercise 4.5 - Cubes & Cube Roots RD Sharma Solutions | Mathematics (Maths) Class 8 - Class 8 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 8 | Best notes, free PDF download
Information about RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots
In this doc you can find the meaning of RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots defined & explained in the simplest way possible. Besides explaining types of
RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots theory, EduRev gives you an ample number of questions to practice RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots tests, examples and also practice Class 8
tests
|
Explore Courses for Class 8 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
Important questions
,Previous Year Questions with Solutions
,MCQs
,video lectures
,Exam
,Extra Questions
,ppt
,Sample Paper
,Semester Notes
,mock tests for examination
,study material
,practice quizzes
,Viva Questions
,Summary
,Objective type Questions
,Exercise 4.5 - Cubes & Cube Roots RD Sharma Solutions | Mathematics (Maths) Class 8
,past year papers
,Exercise 4.5 - Cubes & Cube Roots RD Sharma Solutions | Mathematics (Maths) Class 8
,Exercise 4.5 - Cubes & Cube Roots RD Sharma Solutions | Mathematics (Maths) Class 8
,shortcuts and tricks
,Free
;
Additional Information about RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots for Class 8 Preparation
RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots Free PDF Download
The RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots is an invaluable resource that delves deep into the core of the Class 8 exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots now and kickstart your journey towards success in the Class 8 exam.
Importance of RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots
The importance of RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots cannot be overstated, especially for Class 8 aspirants.
This document holds the key to success in the Class 8 exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots Notes
RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots Notes on EduRev are your ultimate resource for success.
RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots Class 8 Questions
The "RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots Class 8 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 8 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots on the App
Students of Class 8 can study RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of RD Sharma Solutions: Exercise 4.5 - Cubes & Cube Roots is prepared as per the latest Class 8 syllabus.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup