Class 8 Exam > Class 8 Notes > Mathematics (Maths) Class 8 > RS Aggarwal Solutions: Exercise 8C - Linear Equations
RS Aggarwal Solutions: Exercise 8C - Linear Equations | Mathematics (Maths) Class 8 PDF Download
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Page 1
Question 1.
If 2x - 3 = x + 2, then x = ?
A. 1
B. 3
C. 5
D. 7
Answer:
2x - 3 = x + 2
By transposing x and 3
? 2x - x = 3 + 2
? x = 5
Question 2.
If , then x = ?
A. 5
B. - 5
Page 2
Question 1.
If 2x - 3 = x + 2, then x = ?
A. 1
B. 3
C. 5
D. 7
Answer:
2x - 3 = x + 2
By transposing x and 3
? 2x - x = 3 + 2
? x = 5
Question 2.
If , then x = ?
A. 5
B. - 5
C. 6
D. - 6
Answer:
? 7x = - 35
? x = - 5
Question 3.
If z = (z + 10), then z = ?
A. 40
B. 20
C. 10
D. 60
Answer:
z = (z + 10)
By cross multiplication,
Taking LCM of 1 and 5 = 5
Page 3
Question 1.
If 2x - 3 = x + 2, then x = ?
A. 1
B. 3
C. 5
D. 7
Answer:
2x - 3 = x + 2
By transposing x and 3
? 2x - x = 3 + 2
? x = 5
Question 2.
If , then x = ?
A. 5
B. - 5
C. 6
D. - 6
Answer:
? 7x = - 35
? x = - 5
Question 3.
If z = (z + 10), then z = ?
A. 40
B. 20
C. 10
D. 60
Answer:
z = (z + 10)
By cross multiplication,
Taking LCM of 1 and 5 = 5
? x = 40
Question 4.
If 3m = 5m , then m = ?
A.
B.
C.
D.
Answer:
By cross multiplication, 5m-3m = 8/5
Question 5.
If 5t - 3 = 3t - 5, then t = ?
A. 1
B. - 1
C. 2
D. – 2
Answer:
5t - 3 = 3t - 5 .... (1)
By transposition of -3 on RHS we get,
5t = 3t - 5 + 3
5t = 3t - 2
Page 4
Question 1.
If 2x - 3 = x + 2, then x = ?
A. 1
B. 3
C. 5
D. 7
Answer:
2x - 3 = x + 2
By transposing x and 3
? 2x - x = 3 + 2
? x = 5
Question 2.
If , then x = ?
A. 5
B. - 5
C. 6
D. - 6
Answer:
? 7x = - 35
? x = - 5
Question 3.
If z = (z + 10), then z = ?
A. 40
B. 20
C. 10
D. 60
Answer:
z = (z + 10)
By cross multiplication,
Taking LCM of 1 and 5 = 5
? x = 40
Question 4.
If 3m = 5m , then m = ?
A.
B.
C.
D.
Answer:
By cross multiplication, 5m-3m = 8/5
Question 5.
If 5t - 3 = 3t - 5, then t = ?
A. 1
B. - 1
C. 2
D. – 2
Answer:
5t - 3 = 3t - 5 .... (1)
By transposition of -3 on RHS we get,
5t = 3t - 5 + 3
5t = 3t - 2
By transposition of 3t on LHS we get,
5t - 3t = - 2
? 2t = - 2
? t = - 1
Check:
Put the value of t in (1),
LHS
5(-1) - 3 = -5 -3
= -8
RHS
3t - 5 = 3(-1) - 5
= -3 - 5
= -8
As LHS =RHS
The value t=-1 is correct.
Question 6.
If then y = ?
A. 1
B.
C.
D.
Answer:
By cross multiplication,
? 3y = 7
=
Page 5
Question 1.
If 2x - 3 = x + 2, then x = ?
A. 1
B. 3
C. 5
D. 7
Answer:
2x - 3 = x + 2
By transposing x and 3
? 2x - x = 3 + 2
? x = 5
Question 2.
If , then x = ?
A. 5
B. - 5
C. 6
D. - 6
Answer:
? 7x = - 35
? x = - 5
Question 3.
If z = (z + 10), then z = ?
A. 40
B. 20
C. 10
D. 60
Answer:
z = (z + 10)
By cross multiplication,
Taking LCM of 1 and 5 = 5
? x = 40
Question 4.
If 3m = 5m , then m = ?
A.
B.
C.
D.
Answer:
By cross multiplication, 5m-3m = 8/5
Question 5.
If 5t - 3 = 3t - 5, then t = ?
A. 1
B. - 1
C. 2
D. – 2
Answer:
5t - 3 = 3t - 5 .... (1)
By transposition of -3 on RHS we get,
5t = 3t - 5 + 3
5t = 3t - 2
By transposition of 3t on LHS we get,
5t - 3t = - 2
? 2t = - 2
? t = - 1
Check:
Put the value of t in (1),
LHS
5(-1) - 3 = -5 -3
= -8
RHS
3t - 5 = 3(-1) - 5
= -3 - 5
= -8
As LHS =RHS
The value t=-1 is correct.
Question 6.
If then y = ?
A. 1
B.
C.
D.
Answer:
By cross multiplication,
? 3y = 7
=
Question 7.
If then x = ?
A. 1
B. - 1
C. 3
D. - 3
Answer:
Taking LCM of 1 and 3 = 3,
? 2(6x + 4) = (x - 3)
? 12x - x = - 3 - 8
? x = - 1
Question 8.
If , then n = ?
A. 30
B. 42
C. 36
D. 28
Answer:
Taking LCM of 2, 4, 6 = 12
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Document Description: RS Aggarwal Solutions: Exercise 8C - Linear Equations for Class 8 2024 is part of Mathematics (Maths) Class 8 preparation.
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