Class 7 Exam  >  Class 7 Notes  >  Mathematics (Maths) Class 7  >  RS Aggarwal Solutions: Integers (Exercise 1A)

RS Aggarwal Solutions: Integers (Exercise 1A) | Mathematics (Maths) Class 7 PDF Download

Q.1. Evaluate:
(i) 15 + (−8)

(ii) (−16) + 9
(iii) (−7) + (−23)
(iv) (−32) + 47
(v) 53 + (−26)
(vi) (−48) + (−36)
Ans.
(i) 15 + (−8) = 7
(ii) (−16) + 9 = −7
(iii) (−7) + (−23) = −30
(iv) (−32) + 47 = 15
(v) 53 + (−26) = 27
(vi) (−48) + (−36) = −84

Q.2. Find the sum of:
(i) 153 and − 302

(ii) 1005 and − 277
(iii) − 2035 and 297
(iv) − 489 and − 324
(v) − 1000 and 438
(vi) − 238 and 500
Ans.
(i) 153 + (−302) = −149
(ii)  1005 + (−277) = 728
(iii) (−2035) + 297 = −1738
(iv)  (−489) + (−324) = −813
(v)  (−1000) + 438 = −562
(vi) (−238) + 500 = 262

Q.3. Find the additive inverse of:
(i) − 83
(ii) 256
(iii) 0

(iv) − 2001
Ans. 
(i) Additive inverse of −83 = −(−83) = 83
(ii) Additive inverse of 256 = −(256) = −256
(iii) Additive inverse of 0 = −(0) = 0
(iv) Additive inverse of 2001 = −(−2001) = 2001

Q.4. Subtract:
(i) 28 from − 42

(ii) − 36 from 42
(iii) − 37 from − 53
(iv) − 66 from − 34
(v) 318 from 0
(vi) − 153 from − 240
(vii) − 64 from 0
(viii) − 56 from 144
Ans.
(i) −42 − 28 = (−42) + (−28) = −70
(ii) 42 −(−36) = 42 + 36 = 78
(iii) -53 - (-37) = (-53) - (-37) = -16
(iv)  -34 - (-66) = -34 + 66 = 32
(v) 0 - 318 = -318
(vi)  (-240) - (-153) = -87
(vii)  0 - (-64) = 0 + 64 = 64
(viii) 144 - (-56) = 144 + 56 = 200

Q.5. Subtract the sum of − 1032 and 878 from − 34.
Ans.
Sum of −1032 and 878
= −1032 + 878
= -154
Subtracting the sum from −34, we get
−34 − (−154)
= (−34)+ 154
= 120

Q.6. Subtract − 134 from the sum of 38 and − 87.
Ans. 
First, we will calculate the sum of 38 and −87.
38 + (−87) = −49
Now, subtracting −134 from the sum, we get:
−49 − (−134)
=(−49) + 134
= 85

Q.7. Fill in the blanks:
(i) {(−13) + 27} + (−41) = (−13) + {27 + (......)}

(ii) (−26) + {(−49) + (−83)} = {(−26) + (−49)} + (......)
(iii) 53 + (−37) = (−37) + (......)
(iv) (−68) + (−76) = (......) + (−68)
(v) (−72) + (......) = −72
(vi) − (−83) = ......
(vii) (−60) − (......) = − 59
(viii) (−31) + (......) = − 40
Ans. (i) −41   (∵ Associative property)
(ii) −83   (∵ Associative property)
(iii)  53  (∵ Commutative property)
(iv)  −76  (∵ Commutative property)
(v) 0  (∵ Additive identity)
(vi)  83  (∵ Additive inverse)
(vii)  (−60) − (−59) = −1
(viii)  (−40) − (−31) = −9

Q.8. Simplify: {−13−(−27)} + {−25−(−40)}.
Ans.
{−13 − (−27)} + {−25 − (−40)}
= {−13 + 27} + {−25 + 40}
=14 + 15
= 29

Q.9. Find 36 − (−64) and (−64) − 36. Are they equal?
Ans.
36 − (−64) = 36 + 64 = 100
Now, (−64) − 36 = (−64) + (−36) = −100
Here, 100 ≠≠ −100
Thus, they are not equal.

Q.10. If a = − 8, b = − 7, c = 6, verify that (a+b) + c = a + (b+c).
Ans. 
(a + b) + c = (−8 + (−7)) + 6 = −15 + 6 = −9
a + (b + c) = −8 + (−7 + 6) = −8 + (−1) = −9
Hence, (a + b) + c = a + (b + c)   [i.e., Property of Associativity]

Q.11. If a = − 9 and b = − 6, show that (a−b) ≠ (b−a).
Ans.
Here, (a − b) = −9 − (−6) = −3
Similarly, (b − a) = −6 − (−9) = 3
∴ (a−b) ≠ (b−a)

Q.12. The sum of two integers is − 16. If one of them is 53, find the other.
Ans. 
Let the other integer be a. Then, we have: 53 + a = −16
⇒ a = −16 − 53 = −69
∴ The other integer is −69.

Q.13. Ths sum of two integers is 65. If one of them is − 31, find the other.
Ans.
Let the other integer be a.
Then, −31 + a = 65
⇒ a = 65 − (−31) = 96
∴ The other integer is 96.

Q.14. The difference of an integer a and (−6) is 4. Find the value of a.
Ans. 
We have: a − (−6) = 4
⇒ a = 4 + (−6) = −2
∴ a = −2

Q.15. Write a pair of integers whose sum gives
(i) zero;

(ii) a negative integer;
(iii) an integer smaller than both the integers;
(iv) an integer greater than both the integers;
(v) an integer smaller than  only one of the integers.
Ans.
(i)  Consider the integers 8 and −8. Then, we have:
8 + (−8) = 0
(ii) Consider the integers 2 and (−9). Then, we have:
2 + (−9)= −7, which is a negative integer.
(iii)  Consider the integers −4 and −5. Then, we have:
(−4) + (−5) = −9, which is smaller than −4 and −5.
(iv) Consider the integers 2 and 6. Then, we have:
2 + 6 = 8, which is greater than both 2 and 6.
(v)  Consider the integers 7 and −4. Then, we have:
7 + (−4) = 3, which is smaller than 7 only.

Q.16. For each of the following statements, write (T) for true and (F) for false:
(i) The smallest integer is zero.
(ii) − 10 is greater than − 7

(iii) Zero is larger than every negative integer.
(iv) The sum of two negative integers is a negative integer.
(v) The sum of a negative integer and a positive integer is always a positive integer.
Ans.
(i)  F (false). −3, −90 and −100 are also integers. We cannot determine the smallest integer, since they are infinite.
(ii)  F (false). −10 is less than −7.
(iii)  T (true). All negative integers are less than zero.
(iv)  T (true).
(v)  F (false). Example: −9 + 2 = −7

The document RS Aggarwal Solutions: Integers (Exercise 1A) | Mathematics (Maths) Class 7 is a part of the Class 7 Course Mathematics (Maths) Class 7.
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FAQs on RS Aggarwal Solutions: Integers (Exercise 1A) - Mathematics (Maths) Class 7

1. What are RS Aggarwal Solutions and why are they important for Class 7 students studying integers?
Ans. RS Aggarwal Solutions are a series of comprehensive and step-by-step solutions provided for the textbook questions in the RS Aggarwal Mathematics book. They are important for Class 7 students studying integers as they help in understanding and solving the questions effectively. These solutions provide a clear explanation of concepts, various methods of solving problems, and can be used as a reference for exam preparation.
2. How can RS Aggarwal Solutions for Integers help in improving my performance in exams?
Ans. RS Aggarwal Solutions for Integers can help in improving your performance in exams by providing a thorough understanding of concepts and problem-solving techniques. These solutions offer detailed explanations, step-by-step solutions, and practice questions that can enhance your problem-solving skills. Regular practice with these solutions can also help in developing speed and accuracy, which are essential for scoring well in exams.
3. Are RS Aggarwal Solutions for Integers available online?
Ans. Yes, RS Aggarwal Solutions for Integers are available online. They can be accessed through various educational websites and platforms. These online solutions provide convenience and accessibility, allowing students to study and practice anytime and anywhere. Additionally, online solutions often offer interactive features, such as quizzes and tests, to further enhance the learning experience.
4. Can RS Aggarwal Solutions for Integers be used as a self-study tool?
Ans. Yes, RS Aggarwal Solutions for Integers can be used as a self-study tool. These solutions provide a comprehensive and detailed explanation of concepts, making it easier for students to understand and learn independently. The step-by-step solutions and practice questions provided in these solutions allow students to practice and reinforce their understanding of the topics covered. However, it is always recommended to seek guidance from a teacher or mentor when needed.
5. Are RS Aggarwal Solutions for Integers aligned with the Class 7 curriculum?
Ans. Yes, RS Aggarwal Solutions for Integers are aligned with the Class 7 curriculum. These solutions cover all the topics and concepts prescribed in the textbook, ensuring comprehensive coverage of the curriculum. The solutions follow the same sequence as the textbook, making it easy for students to navigate and refer to the relevant chapters. By using these solutions, students can be confident that they are studying the required topics and preparing effectively for their exams.
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