Class 7 Exam > Class 7 Notes > Mathematics (Maths) Class 7 > RS Aggarwal Solutions: Lines & Angles
RS Aggarwal Solutions: Lines & Angles | Mathematics (Maths) Class 7 PDF Download
| Download, print and study this document offline |
Please wait while the PDF view is loading
Page 1
Q u e s t i o n : 1
Find the complement of each of the following angles:
i
35°
ii
47°
iii
60°
iv
73°
S o l u t i o n :
i
The given angle measures 35°.
Let the measure of its complement be x.
x + 35° = 90°
or x = 90 -35
° = 55°
Hence, the complement of the given angle will be 55°.
ii
The given angle measures 47°.
Let the measure of its complement be x.
x + 47° = 90°
or x = 90 -47
° = 43°
Hence, the complement of the given angle will be 43°.
iii
The given angle measures 60°.
Let the measure of its complement be x°.
x + 60° = 90°
or x = 90 -60
° = 30°
Hence, the complement of the given angle will be 30°.
iv
The given angle measures 73°.
Let the measure of its complement be x.
x + 73
o
= 90°
or x = 90 -73
° = 17°
Hence, the complement of the given angle will be 17°.
Q u e s t i o n : 2
Find the supplement of each of the following angles:
i
80°
ii
54°
iii
105°
iv
123°
S o l u t i o n :
i
The given angle measures 80°.
Let the measure of its supplement be x.
x + 80° = 180°
or x = 180 -80
° = 100°
Hence, the complement of the given angle will be 100°.
ii
The given angle measures 54°.
Let the measure of its supplement be x.
x + 54° = 180°
or x = 180 -54
° = 126°
Hence, the complement of the given angle will be 126°.
iii
The given angle measures 105°.
Let the measure of its supplement be x.
x + 105° = 180°
or, x = 180 -105
° = 75°
Hence, the complement of the given angle will be 75°.
iv
The given angle measures 123°.
Let the measure of its supplement be x.
Page 2
Q u e s t i o n : 1
Find the complement of each of the following angles:
i
35°
ii
47°
iii
60°
iv
73°
S o l u t i o n :
i
The given angle measures 35°.
Let the measure of its complement be x.
x + 35° = 90°
or x = 90 -35
° = 55°
Hence, the complement of the given angle will be 55°.
ii
The given angle measures 47°.
Let the measure of its complement be x.
x + 47° = 90°
or x = 90 -47
° = 43°
Hence, the complement of the given angle will be 43°.
iii
The given angle measures 60°.
Let the measure of its complement be x°.
x + 60° = 90°
or x = 90 -60
° = 30°
Hence, the complement of the given angle will be 30°.
iv
The given angle measures 73°.
Let the measure of its complement be x.
x + 73
o
= 90°
or x = 90 -73
° = 17°
Hence, the complement of the given angle will be 17°.
Q u e s t i o n : 2
Find the supplement of each of the following angles:
i
80°
ii
54°
iii
105°
iv
123°
S o l u t i o n :
i
The given angle measures 80°.
Let the measure of its supplement be x.
x + 80° = 180°
or x = 180 -80
° = 100°
Hence, the complement of the given angle will be 100°.
ii
The given angle measures 54°.
Let the measure of its supplement be x.
x + 54° = 180°
or x = 180 -54
° = 126°
Hence, the complement of the given angle will be 126°.
iii
The given angle measures 105°.
Let the measure of its supplement be x.
x + 105° = 180°
or, x = 180 -105
° = 75°
Hence, the complement of the given angle will be 75°.
iv
The given angle measures 123°.
Let the measure of its supplement be x.
x + 123° = 180°
or x = 180 -123
° = 57°
Hence, the complement of the given angle will be 57°.
Q u e s t i o n : 3
Among two supplementary angles, the measure of the larger angle is 36° more than the measure of the smaller. Find their measures.
S o l u t i o n :
Let the two supplementary angles be x°
and 180 -x
°.
Since it is given that the measure of the larger angle is 36° more than the smaller angle, let the larger angle be x°.
? 180 -x
°
+ 36° = x°
or 216 = 2x
or 108 = x
Larger angle = 108°
Smaller angle = 108 -36
°
= 72°
Q u e s t i o n : 4
Find the angle which is equal to its supplement.
S o l u t i o n :
Let the measure of the required angle be x.
Since it is its own supplement:
x + x = 180°or 2x = 180°or x = 90°
Therefore, the required angle is 90°.
Q u e s t i o n : 5
Can two angles be supplementary if both of them are:
i
acute?
ii
obtuse?
iii
right?
S o l u t i o n :
i
No. If both the angles are acute, i.e. less than 90°, they cannot be supplementary as their sum will always be less than 180°.
ii
No. If both the angles are obtuse, i.e. more than 90°, they cannot be supplementary as their sum will always be more than 180°.
iii
Yes. If both the angles are right, i.e. they both measure 90°, then they form a supplementary pair.
90°
+ 90° = 180°
Q u e s t i o n : 6
In the given figure, AOB is a straight line and the ray OC stands on it.
If ?AOC = 64° and ?BOC = x°, find the value of x.
S o l u t i o n :
By linear pair property:
?AOC + ?COB = 180°64° + ?COB = 180° ?COB = x° = 180° - 64° = 116°
? x = 116
Q u e s t i o n : 7
In the given figure, AOB is a straight line and the ray OC stands on it.
If ?AOC = (2x - 10)° and ?BOC = (3x + 20)°, find the value of x.
Also, find ?AOC and ?BOC
S o l u t i o n :
° ) 0 2 + x 3 ( = C O B ? , ° ) 0 1 – x 2 ( = C O A ? t i n o s d n a t s C O y a r d n a e n i l t h g i a r t s a s i B O A
° 2 2 1 = ° 0 2 + ° 2 0 1 – ° 0 2 + ° ( 3 x 3 = ° ) 0 2 + x 3 ( = C O B ? ° 8 5 = ° 0 1 – ° 8 ) = 0 1 – ° ( 3 x 2 = ° ) 0 1 – x 2 ( = C O A ? ° ( 3 = x ? ° 0 7 1 = x 5 ? ° 0 8 1 = ° 0 1 + x 5 ? ° 0 8 1 = ° 0 2 + x 3 + ° 0 1 – x 2 ? ) r i a p r a e n i L ( ° 0 8 1 = C O B ? + C O A ?
Page 3
Q u e s t i o n : 1
Find the complement of each of the following angles:
i
35°
ii
47°
iii
60°
iv
73°
S o l u t i o n :
i
The given angle measures 35°.
Let the measure of its complement be x.
x + 35° = 90°
or x = 90 -35
° = 55°
Hence, the complement of the given angle will be 55°.
ii
The given angle measures 47°.
Let the measure of its complement be x.
x + 47° = 90°
or x = 90 -47
° = 43°
Hence, the complement of the given angle will be 43°.
iii
The given angle measures 60°.
Let the measure of its complement be x°.
x + 60° = 90°
or x = 90 -60
° = 30°
Hence, the complement of the given angle will be 30°.
iv
The given angle measures 73°.
Let the measure of its complement be x.
x + 73
o
= 90°
or x = 90 -73
° = 17°
Hence, the complement of the given angle will be 17°.
Q u e s t i o n : 2
Find the supplement of each of the following angles:
i
80°
ii
54°
iii
105°
iv
123°
S o l u t i o n :
i
The given angle measures 80°.
Let the measure of its supplement be x.
x + 80° = 180°
or x = 180 -80
° = 100°
Hence, the complement of the given angle will be 100°.
ii
The given angle measures 54°.
Let the measure of its supplement be x.
x + 54° = 180°
or x = 180 -54
° = 126°
Hence, the complement of the given angle will be 126°.
iii
The given angle measures 105°.
Let the measure of its supplement be x.
x + 105° = 180°
or, x = 180 -105
° = 75°
Hence, the complement of the given angle will be 75°.
iv
The given angle measures 123°.
Let the measure of its supplement be x.
x + 123° = 180°
or x = 180 -123
° = 57°
Hence, the complement of the given angle will be 57°.
Q u e s t i o n : 3
Among two supplementary angles, the measure of the larger angle is 36° more than the measure of the smaller. Find their measures.
S o l u t i o n :
Let the two supplementary angles be x°
and 180 -x
°.
Since it is given that the measure of the larger angle is 36° more than the smaller angle, let the larger angle be x°.
? 180 -x
°
+ 36° = x°
or 216 = 2x
or 108 = x
Larger angle = 108°
Smaller angle = 108 -36
°
= 72°
Q u e s t i o n : 4
Find the angle which is equal to its supplement.
S o l u t i o n :
Let the measure of the required angle be x.
Since it is its own supplement:
x + x = 180°or 2x = 180°or x = 90°
Therefore, the required angle is 90°.
Q u e s t i o n : 5
Can two angles be supplementary if both of them are:
i
acute?
ii
obtuse?
iii
right?
S o l u t i o n :
i
No. If both the angles are acute, i.e. less than 90°, they cannot be supplementary as their sum will always be less than 180°.
ii
No. If both the angles are obtuse, i.e. more than 90°, they cannot be supplementary as their sum will always be more than 180°.
iii
Yes. If both the angles are right, i.e. they both measure 90°, then they form a supplementary pair.
90°
+ 90° = 180°
Q u e s t i o n : 6
In the given figure, AOB is a straight line and the ray OC stands on it.
If ?AOC = 64° and ?BOC = x°, find the value of x.
S o l u t i o n :
By linear pair property:
?AOC + ?COB = 180°64° + ?COB = 180° ?COB = x° = 180° - 64° = 116°
? x = 116
Q u e s t i o n : 7
In the given figure, AOB is a straight line and the ray OC stands on it.
If ?AOC = (2x - 10)° and ?BOC = (3x + 20)°, find the value of x.
Also, find ?AOC and ?BOC
S o l u t i o n :
° ) 0 2 + x 3 ( = C O B ? , ° ) 0 1 – x 2 ( = C O A ? t i n o s d n a t s C O y a r d n a e n i l t h g i a r t s a s i B O A
° 2 2 1 = ° 0 2 + ° 2 0 1 – ° 0 2 + ° ( 3 x 3 = ° ) 0 2 + x 3 ( = C O B ? ° 8 5 = ° 0 1 – ° 8 ) = 0 1 – ° ( 3 x 2 = ° ) 0 1 – x 2 ( = C O A ? ° ( 3 = x ? ° 0 7 1 = x 5 ? ° 0 8 1 = ° 0 1 + x 5 ? ° 0 8 1 = ° 0 2 + x 3 + ° 0 1 – x 2 ? ) r i a p r a e n i L ( ° 0 8 1 = C O B ? + C O A ?
Q u e s t i o n : 8
In the given figure, AOB is a straight line and the rays OC and OD stands on it.
If ?AOC = 65°, ?BOD = 70° and ?COD = x° find the value of x.
S o l u t i o n :
Since AOB is a straight line, we have:
?AOC + ?BOD + ?COD = 180°or 65°+ 70° + x° = 180° (given)or 135° + x° = 180°or x° = 45°Thus, the value of x is 45
Q u e s t i o n : 9
In the given figure, two straight line AB and CD intersect at a point O.
If ?AOC = 42°, find the measure of each of the angles:
i
?AOD
ii
?BOD
iii
?COB
S o l u t i o n :
? OD
Q u e s t i o n : 1 0
In the given figure, two straight line PQ and RS intersect at a O.
If ?POS = 114°, find the measure of each of the angles:
i
?POR
ii
?ROQ
iii
?QOS
S o l u t i o n :
Q u e s t i o n : 1 1
In the given figure, rays OA, OB, OC and OD are such that
Page 4
Q u e s t i o n : 1
Find the complement of each of the following angles:
i
35°
ii
47°
iii
60°
iv
73°
S o l u t i o n :
i
The given angle measures 35°.
Let the measure of its complement be x.
x + 35° = 90°
or x = 90 -35
° = 55°
Hence, the complement of the given angle will be 55°.
ii
The given angle measures 47°.
Let the measure of its complement be x.
x + 47° = 90°
or x = 90 -47
° = 43°
Hence, the complement of the given angle will be 43°.
iii
The given angle measures 60°.
Let the measure of its complement be x°.
x + 60° = 90°
or x = 90 -60
° = 30°
Hence, the complement of the given angle will be 30°.
iv
The given angle measures 73°.
Let the measure of its complement be x.
x + 73
o
= 90°
or x = 90 -73
° = 17°
Hence, the complement of the given angle will be 17°.
Q u e s t i o n : 2
Find the supplement of each of the following angles:
i
80°
ii
54°
iii
105°
iv
123°
S o l u t i o n :
i
The given angle measures 80°.
Let the measure of its supplement be x.
x + 80° = 180°
or x = 180 -80
° = 100°
Hence, the complement of the given angle will be 100°.
ii
The given angle measures 54°.
Let the measure of its supplement be x.
x + 54° = 180°
or x = 180 -54
° = 126°
Hence, the complement of the given angle will be 126°.
iii
The given angle measures 105°.
Let the measure of its supplement be x.
x + 105° = 180°
or, x = 180 -105
° = 75°
Hence, the complement of the given angle will be 75°.
iv
The given angle measures 123°.
Let the measure of its supplement be x.
x + 123° = 180°
or x = 180 -123
° = 57°
Hence, the complement of the given angle will be 57°.
Q u e s t i o n : 3
Among two supplementary angles, the measure of the larger angle is 36° more than the measure of the smaller. Find their measures.
S o l u t i o n :
Let the two supplementary angles be x°
and 180 -x
°.
Since it is given that the measure of the larger angle is 36° more than the smaller angle, let the larger angle be x°.
? 180 -x
°
+ 36° = x°
or 216 = 2x
or 108 = x
Larger angle = 108°
Smaller angle = 108 -36
°
= 72°
Q u e s t i o n : 4
Find the angle which is equal to its supplement.
S o l u t i o n :
Let the measure of the required angle be x.
Since it is its own supplement:
x + x = 180°or 2x = 180°or x = 90°
Therefore, the required angle is 90°.
Q u e s t i o n : 5
Can two angles be supplementary if both of them are:
i
acute?
ii
obtuse?
iii
right?
S o l u t i o n :
i
No. If both the angles are acute, i.e. less than 90°, they cannot be supplementary as their sum will always be less than 180°.
ii
No. If both the angles are obtuse, i.e. more than 90°, they cannot be supplementary as their sum will always be more than 180°.
iii
Yes. If both the angles are right, i.e. they both measure 90°, then they form a supplementary pair.
90°
+ 90° = 180°
Q u e s t i o n : 6
In the given figure, AOB is a straight line and the ray OC stands on it.
If ?AOC = 64° and ?BOC = x°, find the value of x.
S o l u t i o n :
By linear pair property:
?AOC + ?COB = 180°64° + ?COB = 180° ?COB = x° = 180° - 64° = 116°
? x = 116
Q u e s t i o n : 7
In the given figure, AOB is a straight line and the ray OC stands on it.
If ?AOC = (2x - 10)° and ?BOC = (3x + 20)°, find the value of x.
Also, find ?AOC and ?BOC
S o l u t i o n :
° ) 0 2 + x 3 ( = C O B ? , ° ) 0 1 – x 2 ( = C O A ? t i n o s d n a t s C O y a r d n a e n i l t h g i a r t s a s i B O A
° 2 2 1 = ° 0 2 + ° 2 0 1 – ° 0 2 + ° ( 3 x 3 = ° ) 0 2 + x 3 ( = C O B ? ° 8 5 = ° 0 1 – ° 8 ) = 0 1 – ° ( 3 x 2 = ° ) 0 1 – x 2 ( = C O A ? ° ( 3 = x ? ° 0 7 1 = x 5 ? ° 0 8 1 = ° 0 1 + x 5 ? ° 0 8 1 = ° 0 2 + x 3 + ° 0 1 – x 2 ? ) r i a p r a e n i L ( ° 0 8 1 = C O B ? + C O A ?
Q u e s t i o n : 8
In the given figure, AOB is a straight line and the rays OC and OD stands on it.
If ?AOC = 65°, ?BOD = 70° and ?COD = x° find the value of x.
S o l u t i o n :
Since AOB is a straight line, we have:
?AOC + ?BOD + ?COD = 180°or 65°+ 70° + x° = 180° (given)or 135° + x° = 180°or x° = 45°Thus, the value of x is 45
Q u e s t i o n : 9
In the given figure, two straight line AB and CD intersect at a point O.
If ?AOC = 42°, find the measure of each of the angles:
i
?AOD
ii
?BOD
iii
?COB
S o l u t i o n :
? OD
Q u e s t i o n : 1 0
In the given figure, two straight line PQ and RS intersect at a O.
If ?POS = 114°, find the measure of each of the angles:
i
?POR
ii
?ROQ
iii
?QOS
S o l u t i o n :
Q u e s t i o n : 1 1
In the given figure, rays OA, OB, OC and OD are such that
?AOB = 56°, ?BOC = 100°, ?COD = x° and ?DOA = 74°.
Find the value of x.
S o l u t i o n :
Sum of all the angles around a point is 360°.
? ?AOB + ?BOC + ? COD + ?DOA = 360°or 56° + 100° + x° + 74° = 360° (given)or 230° + x° = 360°or x° = 130°or x = 130
Read More
|
76 videos|344 docs|39 tests
|
Related Exams
About this Document
|
4.83/5 Rating |
|
Dec 25, 2024 Last updated |
Document Description: RS Aggarwal Solutions: Lines & Angles for Class 7 2024 is part of Mathematics (Maths) Class 7 preparation.
The notes and questions for RS Aggarwal Solutions: Lines & Angles have been prepared according to the Class 7 exam syllabus. Information about RS Aggarwal Solutions: Lines & Angles covers topics
like and RS Aggarwal Solutions: Lines & Angles Example, for Class 7 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for RS Aggarwal Solutions: Lines & Angles.
Introduction of RS Aggarwal Solutions: Lines & Angles in English is available as part of our Mathematics (Maths) Class 7
for Class 7 & RS Aggarwal Solutions: Lines & Angles in Hindi for Mathematics (Maths) Class 7 course.
Download more important topics related with notes, lectures and mock test series for Class 7
Exam by signing up for free. Class 7: RS Aggarwal Solutions: Lines & Angles | Mathematics (Maths) Class 7
Description
Full syllabus notes, lecture & questions for RS Aggarwal Solutions: Lines & Angles | Mathematics (Maths) Class 7 - Class 7 | Plus excerises question with solution to help you revise complete syllabus for Mathematics (Maths) Class 7 | Best notes, free PDF download
Information about RS Aggarwal Solutions: Lines & Angles
In this doc you can find the meaning of RS Aggarwal Solutions: Lines & Angles defined & explained in the simplest way possible. Besides explaining types of
RS Aggarwal Solutions: Lines & Angles theory, EduRev gives you an ample number of questions to practice RS Aggarwal Solutions: Lines & Angles tests, examples and also practice Class 7
tests
|
Explore Courses for Class 7 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
Related Searches
past year papers
,Free
,ppt
,Extra Questions
,shortcuts and tricks
,RS Aggarwal Solutions: Lines & Angles | Mathematics (Maths) Class 7
,Summary
,Objective type Questions
,Exam
,Semester Notes
,RS Aggarwal Solutions: Lines & Angles | Mathematics (Maths) Class 7
,study material
,Sample Paper
,MCQs
,Viva Questions
,video lectures
,Previous Year Questions with Solutions
,RS Aggarwal Solutions: Lines & Angles | Mathematics (Maths) Class 7
,practice quizzes
,mock tests for examination
,Important questions
;
Additional Information about RS Aggarwal Solutions: Lines & Angles for Class 7 Preparation
RS Aggarwal Solutions: Lines & Angles Free PDF Download
The RS Aggarwal Solutions: Lines & Angles is an invaluable resource that delves deep into the core of the Class 7 exam.
These study notes are curated by experts and cover all the essential topics and concepts, making your preparation more efficient and effective.
With the help of these notes, you can grasp complex subjects quickly, revise important points easily,
and reinforce your understanding of key concepts. The study notes are presented in a concise and easy-to-understand manner,
allowing you to optimize your learning process. Whether you're looking for best-recommended books, sample papers, study material,
or toppers' notes, this PDF has got you covered. Download the RS Aggarwal Solutions: Lines & Angles now and kickstart your journey towards success in the Class 7 exam.
Importance of RS Aggarwal Solutions: Lines & Angles
The importance of RS Aggarwal Solutions: Lines & Angles cannot be overstated, especially for Class 7 aspirants.
This document holds the key to success in the Class 7 exam.
It offers a detailed understanding of the concept, providing invaluable insights into the topic.
By knowing the concepts well in advance, students can plan their preparation effectively.
Utilize this indispensable guide for a well-rounded preparation and achieve your desired results.
RS Aggarwal Solutions: Lines & Angles Notes
RS Aggarwal Solutions: Lines & Angles Notes offer in-depth insights into the specific topic to help you master it with ease.
This comprehensive document covers all aspects related to RS Aggarwal Solutions: Lines & Angles.
It includes detailed information about the exam syllabus, recommended books, and study materials for a well-rounded preparation.
Practice papers and question papers enable you to assess your progress effectively.
Additionally, the paper analysis provides valuable tips for tackling the exam strategically.
Access to Toppers' notes gives you an edge in understanding complex concepts.
Whether you're a beginner or aiming for advanced proficiency, RS Aggarwal Solutions: Lines & Angles Notes on EduRev are your ultimate resource for success.
RS Aggarwal Solutions: Lines & Angles Class 7 Questions
The "RS Aggarwal Solutions: Lines & Angles Class 7 Questions" guide is a valuable resource for all aspiring students preparing for the
Class 7 exam. It focuses on providing a wide range of practice questions to help students gauge
their understanding of the exam topics. These questions cover the entire syllabus, ensuring comprehensive preparation.
The guide includes previous years' question papers for students to familiarize themselves with the exam's format and difficulty level.
Additionally, it offers subject-specific question banks, allowing students to focus on weak areas and improve their performance.
Study RS Aggarwal Solutions: Lines & Angles on the App
Students of Class 7 can study RS Aggarwal Solutions: Lines & Angles alongwith tests & analysis from the EduRev app,
which will help them while preparing for their exam. Apart from the RS Aggarwal Solutions: Lines & Angles,
students can also utilize the EduRev App for other study materials such as previous year question papers, syllabus, important questions, etc.
The EduRev App will make your learning easier as you can access it from anywhere you want.
The content of RS Aggarwal Solutions: Lines & Angles is prepared as per the latest Class 7 syllabus.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup