Table of contents | |
Resolution of Vectors | |
Addition of Vectors | |
Special Cases in Vector Addition | |
Vector Subtraction | |
Properties of Vector Addition |
Representing Vector on X-Y Plane
Components of a Vector
Ex. A ball is thrown with an initial velocity of 70 feet per second., at an angle of 35° with the horizontal. Find the vertical and horizontal components of the velocity.
Ans. Let v represent the velocity and use the given information to write v in unit vector form:
v =70(cos(35°))i+70(sin(35°))j
Simplify the scalars, we get:
v ≈57.34i+40.15j
Since the scalars are the horizontal and vertical components of v,
Therefore, the horizontal component is 57.34 feet per second and the vertical component is 40.15 feet per second.
In vectors, both magnitude and direction matter, therefore the process of addition differs from simple algebraic addition.
Here are some crucial points regarding vector addition:
Ex. Find the addition of vectors PQ and QR, where PQ = (3, 4) and QR = (2, 6)
Solution.
We will perform the vector addition by adding their corresponding components
PQ + QR = (3, 4) + (2, 6)
= (3 + 2, 4 + 6)
= (5, 10).
To visualize the sum of vectors a and b (i.e., a + b), one can shift vector b so that its initial point coincides with the terminal point of vector a. The resulting vector, starting from the initial point of a to the terminal point of b, represents the sum a + b.
Graphical Representation of Vector Addition
The Triangle’s Law states that if two vectors A and B are represented by two sides of a triangle, taken in the same order, then their resultant is represented by the third side of the triangle, taken in the opposite order. Mathematically, this is expressed as A + B = -C.
Triangle Law of Vector Addition
The Law of Parallelogram addition of Vectors offers an alternative perspective. If two vectors P and Q are represented by two adjacent sides of a parallelogram, both pointing outwards, then their resultant is given by the diagonal drawn through the intersection of the two vectors. The magnitude and direction of the resultant can be calculated using specific formulas.
Parallelogram Addition of Vectors
When combining two vectors using the parallelogram method, the magnitude of the resulting vector (R) is determined by the formula:
(AC)2 = (AE)2 + (EC)2
or R2 = (P + Q cos θ)2 + (Q sin θ)2
or R = √(P2+ Q2 )+ 2PQcos θ
This formula essentially relates the lengths of the vectors involved (P and Q) and the angle (θ) between them.
The direction of the resulting vector, relative to vector P, is given by:
tan θ = CE/AE = Qsinθ/(P+Qcosθ)
θ = tan-1 [Qsinθ/(P+Qcosθ)]
(a) When θ = 0°, cos θ = 1, sin θ = 0°
Substituting for cos θ in equation R = √(P2+ Q2 )+ 2PQcos θ, we get,
R = √(P2+ Q2 )+ 2PQcos θ
= √(P+ Q)2
or R = P+Q (maximum)
Substituting for sin θ and cos θ in equation θ = tan-1 [Qsinθ/(P+Qcosθ)], we get,
θ = tan-1 [Qsinθ/(P+Qcosθ)]
= tan-1 [(Q×0)/(P+(Q×1))]
= tan-1(0)
= 0°
The resultant of two vectors acting in the same direction is equal to the sum of the two. The direction of the resultant coincides with those of the two vectors.
(b) When θ = 180°, cos θ = -1, sin θ = 0°
Substituting for cos θ in equation R = √(P2+ Q2 )+ 2PQcos θ, we get,
R = √(P2+ Q2 )+ 2PQ(-1)
=√P2+ Q2 – 2PQ
= √(P – Q)2 (minimum)
or R = P – Q (minimum)
Substituting for sin θ and cos θ in equation θ = tan-1 [Qsinθ/(P+Qcosθ)], we get,
θ = tan-1 [Qsinθ/(P+Qcosθ)]
= tan-1 [(Q×0)/(P+(Q×(-1)))]
= tan-1(0)
= 0°
This magnitude of the resultant of two vectors acting in opposite directions is equal to the difference in magnitudes of the two and represents the minimum value. The direction of the resultant is in the direction of the bigger one.
(c) When θ = 90°, cos θ = 0 , sin θ = 1
Substituting for cos θ in equation R = √(P2+ Q2 )+ 2PQcos θ, we get,
R = √(P2+ Q2 )+ (2PQ×0)
= √P2+ Q2
Substituting for sin θ and cos θ in equation θ = tan-1 [Qsinθ/(P+Qcosθ)], we get,
θ = tan-1 [Qsinθ/(P+Qcosθ)]
= tan-1 [(Q×1)/(P+(Q×(0)))]
= tan-1(Q/P)
The resultant of two vectors acting at right angles to each other is equal to the square root of the sum of the squares of the magnitudes of the two vectors. The direction of the resultant depends upon their relative magnitudes.
Ex. Two vectors are given along with their components: A = (2,3) and B = (2,-2). Calculate the magnitude and the angle of the sum C using their components.
Solution.Let us represent the components of the given vectors as: In the vector A, Ax = 2 and Ay = 3
In the vector B, Bx = 2 and By = -2
Now, adding the two vectors,
A + B = (2, 3) + (2, -2) = (4, 1)
It can also be written as:
C = (4, 1)
Here in C, Cx = 4 and Cy = 1
The magnitude of the resultant vector C can be calculated as:
|C| = √ ((Cx)2+(Cy)2)
|C| = √ ((4)2 + (1)2)
= √ (16 + 1)
|C| = √ 17 = 4.123 units (Approximately)
The angle can be calculated as follows:
Φ = tan-1 (Cy/ Cx)
Φ = tan-1 (1/4)
Φ ≈ 14.04 degrees
Vector subtraction is a process equivalent to adding the negative of the vector to be subtracted. For instance, if subtracting vector B from vector A, it is essentially the same as adding B to -A.
Vector Subtraction
The properties of vector addition further enhance its utility:
These properties make vector addition a versatile and powerful operation, applicable in various mathematical and physical scenarios.
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1. What is vector resolution and how is it calculated? |
2. How is vector addition performed and what are the properties of vector addition? |
3. What are some special cases in vector addition? |
4. How is vector subtraction different from vector addition? |
5. How are vectors added graphically and algebraically? |
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