Sample Solution Paper 1 - Chemistry, Class 11 NEET Notes | EduRev

Chemistry Class 11

NEET : Sample Solution Paper 1 - Chemistry, Class 11 NEET Notes | EduRev

 Page 1


  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
CBSE 
Class XI Chemistry 
Sample Paper – 1 Solution 
 
  Section A 
1. This is because o – nitro phenol has intramolecular hydrogen bonding whereas p- nitro 
phenol has intermolecular hydrogen bonding. 
 
OR 
 
-
2 2 2
O NCH CH O will be more stable because 
2
-NO group has electron withdrawing inductive 
effect or – I effect. 
 
2. CO2 has a larger bond angle than
3
BF . This is because 
2
CO has a linear shape and the 
bond angle is 180
o
, 
3
BF on the other hand has a trigonal planar geometry and hence the 
bond angle is 120
o
. 
OR 
 
Bond order of N2 is greater than that of O2. Higher is the bond order greater is the 
stability. Therefore N2 is more stable than O2. 
 
3. The eclipsed conformation of propane is less stable and has more energy than the 
eclipsed conformation of ethane. This is because in propane there are additional 
interactions between C-H and C-C bond of methyl group.  
 
4.  In Antarctica, ozone depletion is due to the formation of chlorine nitrate. 
 
5. Alkali metals have low ionization energies. They can lose electrons when light falls on 
them, and hence are used in photo electric cells. 
 
  Section B 
  
6. Statement ‘a’ is correct and b is incorrect. 
Statement ‘b’ is incorrect because d sub shell can have a maximum of 10 electrons. 
Therefore it has 10 columns and not 8. 
 
7. Elements in which transition of electrons to higher energy d-orbital cannot take place 
are not transition elements. Thus, elements like Zn, Cd and Hg in which all the d-orbitals 
are completely filled are not transition elements although they have been grouped with 
d-block. 
 
Page 2


  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
CBSE 
Class XI Chemistry 
Sample Paper – 1 Solution 
 
  Section A 
1. This is because o – nitro phenol has intramolecular hydrogen bonding whereas p- nitro 
phenol has intermolecular hydrogen bonding. 
 
OR 
 
-
2 2 2
O NCH CH O will be more stable because 
2
-NO group has electron withdrawing inductive 
effect or – I effect. 
 
2. CO2 has a larger bond angle than
3
BF . This is because 
2
CO has a linear shape and the 
bond angle is 180
o
, 
3
BF on the other hand has a trigonal planar geometry and hence the 
bond angle is 120
o
. 
OR 
 
Bond order of N2 is greater than that of O2. Higher is the bond order greater is the 
stability. Therefore N2 is more stable than O2. 
 
3. The eclipsed conformation of propane is less stable and has more energy than the 
eclipsed conformation of ethane. This is because in propane there are additional 
interactions between C-H and C-C bond of methyl group.  
 
4.  In Antarctica, ozone depletion is due to the formation of chlorine nitrate. 
 
5. Alkali metals have low ionization energies. They can lose electrons when light falls on 
them, and hence are used in photo electric cells. 
 
  Section B 
  
6. Statement ‘a’ is correct and b is incorrect. 
Statement ‘b’ is incorrect because d sub shell can have a maximum of 10 electrons. 
Therefore it has 10 columns and not 8. 
 
7. Elements in which transition of electrons to higher energy d-orbital cannot take place 
are not transition elements. Thus, elements like Zn, Cd and Hg in which all the d-orbitals 
are completely filled are not transition elements although they have been grouped with 
d-block. 
 
  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
8. Given: 
9
8
8
9
14 1
14
456nm
456 10 m
c 3 10 m / s
Wehave,
c
3 10
456 10
6.5 10 s
6.5 10 Hz
?
?
?
??
??
??
??
?
?
?
?
? ? ?
? ? ?
 
Frequency is 6.5×10
14
 Hz 
 
9. Oxidation number of Pb in PbO is +2 while in PbO2 it is +4. This causes the compounds to 
differ in their reactivity. While PbO reacts with HCl to give acid-base reaction, and PbO2 
reacts with HCl to give redox reaction. 
 
   2PbO + 4HCl ? 2PbCl2 + 2H2O       (acid-base reaction) 
    PbO2 + 4HCl ? PbCl2 + Cl2 + 2H2O  (redox reaction) 
 
10.  
? ? ? ?
2 2 2
2H O+ 2 F 4HF +O
  
 F2 is the oxidizing agent and H2O is reducing agent.                           
H2O is getting oxidized to O2 whereas F2 is getting reduced to F
-
 ion.  
 
OR 
 
(a) PbS(g) + H2O2(aq)   ? PbSO4(s) + 4H2O(l)  
(b) CO(g) + 2 H2(g) 
Cobalt
catalyst
? ? ? ? CH3OH 
 
11. The energy required to excite outer electrons in the atoms of Be and Mg does not lie in 
the visible range of radiation. Therefore, no absorption of radiation takes place and 
hence no colour is imparted to the flame in the flame test.  
Page 3


  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
CBSE 
Class XI Chemistry 
Sample Paper – 1 Solution 
 
  Section A 
1. This is because o – nitro phenol has intramolecular hydrogen bonding whereas p- nitro 
phenol has intermolecular hydrogen bonding. 
 
OR 
 
-
2 2 2
O NCH CH O will be more stable because 
2
-NO group has electron withdrawing inductive 
effect or – I effect. 
 
2. CO2 has a larger bond angle than
3
BF . This is because 
2
CO has a linear shape and the 
bond angle is 180
o
, 
3
BF on the other hand has a trigonal planar geometry and hence the 
bond angle is 120
o
. 
OR 
 
Bond order of N2 is greater than that of O2. Higher is the bond order greater is the 
stability. Therefore N2 is more stable than O2. 
 
3. The eclipsed conformation of propane is less stable and has more energy than the 
eclipsed conformation of ethane. This is because in propane there are additional 
interactions between C-H and C-C bond of methyl group.  
 
4.  In Antarctica, ozone depletion is due to the formation of chlorine nitrate. 
 
5. Alkali metals have low ionization energies. They can lose electrons when light falls on 
them, and hence are used in photo electric cells. 
 
  Section B 
  
6. Statement ‘a’ is correct and b is incorrect. 
Statement ‘b’ is incorrect because d sub shell can have a maximum of 10 electrons. 
Therefore it has 10 columns and not 8. 
 
7. Elements in which transition of electrons to higher energy d-orbital cannot take place 
are not transition elements. Thus, elements like Zn, Cd and Hg in which all the d-orbitals 
are completely filled are not transition elements although they have been grouped with 
d-block. 
 
  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
8. Given: 
9
8
8
9
14 1
14
456nm
456 10 m
c 3 10 m / s
Wehave,
c
3 10
456 10
6.5 10 s
6.5 10 Hz
?
?
?
??
??
??
??
?
?
?
?
? ? ?
? ? ?
 
Frequency is 6.5×10
14
 Hz 
 
9. Oxidation number of Pb in PbO is +2 while in PbO2 it is +4. This causes the compounds to 
differ in their reactivity. While PbO reacts with HCl to give acid-base reaction, and PbO2 
reacts with HCl to give redox reaction. 
 
   2PbO + 4HCl ? 2PbCl2 + 2H2O       (acid-base reaction) 
    PbO2 + 4HCl ? PbCl2 + Cl2 + 2H2O  (redox reaction) 
 
10.  
? ? ? ?
2 2 2
2H O+ 2 F 4HF +O
  
 F2 is the oxidizing agent and H2O is reducing agent.                           
H2O is getting oxidized to O2 whereas F2 is getting reduced to F
-
 ion.  
 
OR 
 
(a) PbS(g) + H2O2(aq)   ? PbSO4(s) + 4H2O(l)  
(b) CO(g) + 2 H2(g) 
Cobalt
catalyst
? ? ? ? CH3OH 
 
11. The energy required to excite outer electrons in the atoms of Be and Mg does not lie in 
the visible range of radiation. Therefore, no absorption of radiation takes place and 
hence no colour is imparted to the flame in the flame test.  
  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
12.  
? ? ? ?
24
Massof element in that compound
Mass % of anelement 100
Molarmassof thecompound
Molarmassof Na SO 2 23 32 4 16
142g / mol
46
Mass % of Na 100
142
32.39%
32
Mass % of S 100
142
22.54%
64
Mass % of O 100
142
45.07%
??
? ? ?
?
??
?
??
?
??
?
 
 
OR 
Given: 
Weight of CuSO4 =100 g 
Atomic mass of Cu – 63.5 amu 
 
1 mole of CuSO4 contains 1 mole of Cu 
Molar mass of CuSO4 = 63.5 + 32+ (4×16) 
                                         = 159.5 g/mol 
 
So, Cu that can be obtained from 159.5 g of CuSO4 = 63.5 g 
 
Therefore, Cu that can be obtained from 100 g of CuSO4  
 
63.5
100
159.5
39.81g
??
?
 
 
 
Page 4


  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
CBSE 
Class XI Chemistry 
Sample Paper – 1 Solution 
 
  Section A 
1. This is because o – nitro phenol has intramolecular hydrogen bonding whereas p- nitro 
phenol has intermolecular hydrogen bonding. 
 
OR 
 
-
2 2 2
O NCH CH O will be more stable because 
2
-NO group has electron withdrawing inductive 
effect or – I effect. 
 
2. CO2 has a larger bond angle than
3
BF . This is because 
2
CO has a linear shape and the 
bond angle is 180
o
, 
3
BF on the other hand has a trigonal planar geometry and hence the 
bond angle is 120
o
. 
OR 
 
Bond order of N2 is greater than that of O2. Higher is the bond order greater is the 
stability. Therefore N2 is more stable than O2. 
 
3. The eclipsed conformation of propane is less stable and has more energy than the 
eclipsed conformation of ethane. This is because in propane there are additional 
interactions between C-H and C-C bond of methyl group.  
 
4.  In Antarctica, ozone depletion is due to the formation of chlorine nitrate. 
 
5. Alkali metals have low ionization energies. They can lose electrons when light falls on 
them, and hence are used in photo electric cells. 
 
  Section B 
  
6. Statement ‘a’ is correct and b is incorrect. 
Statement ‘b’ is incorrect because d sub shell can have a maximum of 10 electrons. 
Therefore it has 10 columns and not 8. 
 
7. Elements in which transition of electrons to higher energy d-orbital cannot take place 
are not transition elements. Thus, elements like Zn, Cd and Hg in which all the d-orbitals 
are completely filled are not transition elements although they have been grouped with 
d-block. 
 
  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
8. Given: 
9
8
8
9
14 1
14
456nm
456 10 m
c 3 10 m / s
Wehave,
c
3 10
456 10
6.5 10 s
6.5 10 Hz
?
?
?
??
??
??
??
?
?
?
?
? ? ?
? ? ?
 
Frequency is 6.5×10
14
 Hz 
 
9. Oxidation number of Pb in PbO is +2 while in PbO2 it is +4. This causes the compounds to 
differ in their reactivity. While PbO reacts with HCl to give acid-base reaction, and PbO2 
reacts with HCl to give redox reaction. 
 
   2PbO + 4HCl ? 2PbCl2 + 2H2O       (acid-base reaction) 
    PbO2 + 4HCl ? PbCl2 + Cl2 + 2H2O  (redox reaction) 
 
10.  
? ? ? ?
2 2 2
2H O+ 2 F 4HF +O
  
 F2 is the oxidizing agent and H2O is reducing agent.                           
H2O is getting oxidized to O2 whereas F2 is getting reduced to F
-
 ion.  
 
OR 
 
(a) PbS(g) + H2O2(aq)   ? PbSO4(s) + 4H2O(l)  
(b) CO(g) + 2 H2(g) 
Cobalt
catalyst
? ? ? ? CH3OH 
 
11. The energy required to excite outer electrons in the atoms of Be and Mg does not lie in 
the visible range of radiation. Therefore, no absorption of radiation takes place and 
hence no colour is imparted to the flame in the flame test.  
  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
12.  
? ? ? ?
24
Massof element in that compound
Mass % of anelement 100
Molarmassof thecompound
Molarmassof Na SO 2 23 32 4 16
142g / mol
46
Mass % of Na 100
142
32.39%
32
Mass % of S 100
142
22.54%
64
Mass % of O 100
142
45.07%
??
? ? ?
?
??
?
??
?
??
?
 
 
OR 
Given: 
Weight of CuSO4 =100 g 
Atomic mass of Cu – 63.5 amu 
 
1 mole of CuSO4 contains 1 mole of Cu 
Molar mass of CuSO4 = 63.5 + 32+ (4×16) 
                                         = 159.5 g/mol 
 
So, Cu that can be obtained from 159.5 g of CuSO4 = 63.5 g 
 
Therefore, Cu that can be obtained from 100 g of CuSO4  
 
63.5
100
159.5
39.81g
??
?
 
 
 
  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
13.  
(a) The 4f sub shell of an atom contains 12 electrons 
4f
12  
?? ??
 
??
 
??
 
??
 
?
 
?
 
  
So maximum 7 electrons will have same spin. 
 
(b) Six electrons are filled in three orbitals of 4p subshell. 
 
4p
6
  
?? ??
 
??
 
 
 
(c) Z =29 
  Electronic configuration 
2 2 6 2 6 10 1
1s 2s 2p 3s 3p 3d 4s  
 
OR 
 
(a) Number of electrons in 1 molecule of methane = 6 + 4 =10 electrons 
 
              Number of molecules in 1 mole of methane 
               
23
= 6.022 × 10 molecules of methane                
                                                                              
              Number of electrons in 1 mole of methane  
 
              
23
24
 = 6.022×10 10
= 6.0 electr 22×10 ons  
?
  
 
(b) n = 3 
? ? 0 -1
0,1,2
?
?
l to n
 
 For 0 ?   l , 
      0 ?
l
m 
   For 1 ? l 
        1, 0, 1 ? ? ?
l
m 
  For 2 l ? 
2, 1, 0, 1, 2 ? ? ? ? ?
l
m 
Page 5


  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
CBSE 
Class XI Chemistry 
Sample Paper – 1 Solution 
 
  Section A 
1. This is because o – nitro phenol has intramolecular hydrogen bonding whereas p- nitro 
phenol has intermolecular hydrogen bonding. 
 
OR 
 
-
2 2 2
O NCH CH O will be more stable because 
2
-NO group has electron withdrawing inductive 
effect or – I effect. 
 
2. CO2 has a larger bond angle than
3
BF . This is because 
2
CO has a linear shape and the 
bond angle is 180
o
, 
3
BF on the other hand has a trigonal planar geometry and hence the 
bond angle is 120
o
. 
OR 
 
Bond order of N2 is greater than that of O2. Higher is the bond order greater is the 
stability. Therefore N2 is more stable than O2. 
 
3. The eclipsed conformation of propane is less stable and has more energy than the 
eclipsed conformation of ethane. This is because in propane there are additional 
interactions between C-H and C-C bond of methyl group.  
 
4.  In Antarctica, ozone depletion is due to the formation of chlorine nitrate. 
 
5. Alkali metals have low ionization energies. They can lose electrons when light falls on 
them, and hence are used in photo electric cells. 
 
  Section B 
  
6. Statement ‘a’ is correct and b is incorrect. 
Statement ‘b’ is incorrect because d sub shell can have a maximum of 10 electrons. 
Therefore it has 10 columns and not 8. 
 
7. Elements in which transition of electrons to higher energy d-orbital cannot take place 
are not transition elements. Thus, elements like Zn, Cd and Hg in which all the d-orbitals 
are completely filled are not transition elements although they have been grouped with 
d-block. 
 
  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
8. Given: 
9
8
8
9
14 1
14
456nm
456 10 m
c 3 10 m / s
Wehave,
c
3 10
456 10
6.5 10 s
6.5 10 Hz
?
?
?
??
??
??
??
?
?
?
?
? ? ?
? ? ?
 
Frequency is 6.5×10
14
 Hz 
 
9. Oxidation number of Pb in PbO is +2 while in PbO2 it is +4. This causes the compounds to 
differ in their reactivity. While PbO reacts with HCl to give acid-base reaction, and PbO2 
reacts with HCl to give redox reaction. 
 
   2PbO + 4HCl ? 2PbCl2 + 2H2O       (acid-base reaction) 
    PbO2 + 4HCl ? PbCl2 + Cl2 + 2H2O  (redox reaction) 
 
10.  
? ? ? ?
2 2 2
2H O+ 2 F 4HF +O
  
 F2 is the oxidizing agent and H2O is reducing agent.                           
H2O is getting oxidized to O2 whereas F2 is getting reduced to F
-
 ion.  
 
OR 
 
(a) PbS(g) + H2O2(aq)   ? PbSO4(s) + 4H2O(l)  
(b) CO(g) + 2 H2(g) 
Cobalt
catalyst
? ? ? ? CH3OH 
 
11. The energy required to excite outer electrons in the atoms of Be and Mg does not lie in 
the visible range of radiation. Therefore, no absorption of radiation takes place and 
hence no colour is imparted to the flame in the flame test.  
  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
12.  
? ? ? ?
24
Massof element in that compound
Mass % of anelement 100
Molarmassof thecompound
Molarmassof Na SO 2 23 32 4 16
142g / mol
46
Mass % of Na 100
142
32.39%
32
Mass % of S 100
142
22.54%
64
Mass % of O 100
142
45.07%
??
? ? ?
?
??
?
??
?
??
?
 
 
OR 
Given: 
Weight of CuSO4 =100 g 
Atomic mass of Cu – 63.5 amu 
 
1 mole of CuSO4 contains 1 mole of Cu 
Molar mass of CuSO4 = 63.5 + 32+ (4×16) 
                                         = 159.5 g/mol 
 
So, Cu that can be obtained from 159.5 g of CuSO4 = 63.5 g 
 
Therefore, Cu that can be obtained from 100 g of CuSO4  
 
63.5
100
159.5
39.81g
??
?
 
 
 
  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
13.  
(a) The 4f sub shell of an atom contains 12 electrons 
4f
12  
?? ??
 
??
 
??
 
??
 
?
 
?
 
  
So maximum 7 electrons will have same spin. 
 
(b) Six electrons are filled in three orbitals of 4p subshell. 
 
4p
6
  
?? ??
 
??
 
 
 
(c) Z =29 
  Electronic configuration 
2 2 6 2 6 10 1
1s 2s 2p 3s 3p 3d 4s  
 
OR 
 
(a) Number of electrons in 1 molecule of methane = 6 + 4 =10 electrons 
 
              Number of molecules in 1 mole of methane 
               
23
= 6.022 × 10 molecules of methane                
                                                                              
              Number of electrons in 1 mole of methane  
 
              
23
24
 = 6.022×10 10
= 6.0 electr 22×10 ons  
?
  
 
(b) n = 3 
? ? 0 -1
0,1,2
?
?
l to n
 
 For 0 ?   l , 
      0 ?
l
m 
   For 1 ? l 
        1, 0, 1 ? ? ?
l
m 
  For 2 l ? 
2, 1, 0, 1, 2 ? ? ? ? ?
l
m 
  
 
CBSE XI | Chemistry 
Sample Paper – 1 Solution 
 
    
14. The electronic configuration of   
2 2 6 2 4
S=1s 2s 2p 3s 3p 
                                    1s             2s                       2p                 3s                    3p 
Ground state  
 
 
                                    1s             2s                2p                         3s                3p                                3d 
Excited State  
 
                                                                                                       
                                                                                                                        Sp
3
     hybridisation 
 
                                       1s             2s                2p                    sp
3
d  sp
3
d sp
3
d sp
3
d sp
3
d               3d 
 
Hybridise State  
 
 
  Sulphur undergoes sp
3
d hybridisation. 
 
OR 
 
(a) In CO2 there are two C=O bond. Each C=O bond is polar bond. The net dipole moment 
of CO2 molecule is zero. This is possible only if CO2 is a linear molecule (O=C=O). The 
bond dipoles of two C=O bond cancel with each other. 
Whereas H2O molecule has a net dipole moment (1.84 D) H2O molecule has a bent 
structure because here the O-H bonds are oriented at an angle of 104.5
°
 and do not 
cancel the bond moments of each other. 
 
(b) Significance/applications of dipole moment- 
i) In predicting the nature of the molecules: Molecules with specific dipole moments 
are polar in nature and those of zero dipole moments are non-polar in nature. 
ii) In the determination of shapes of molecules. 
iii) In calculating the percentage ionic character. 
  
??
 
??
 ??
 
?? ?? 
??
 
?? ?? ??
 
??
 
??
 
??
 
?? ?? ??
 
?? ?? ??
 ?
 
    
??
 ??
 
??
 
? ? ? ? ??
 
?? ?? 
     
Read More
Offer running on EduRev: Apply code STAYHOME200 to get INR 200 off on our premium plan EduRev Infinity!

Related Searches

Free

,

Previous Year Questions with Solutions

,

Extra Questions

,

Exam

,

Class 11 NEET Notes | EduRev

,

video lectures

,

shortcuts and tricks

,

MCQs

,

Class 11 NEET Notes | EduRev

,

pdf

,

Sample Solution Paper 1 - Chemistry

,

Semester Notes

,

Viva Questions

,

Objective type Questions

,

mock tests for examination

,

Sample Paper

,

Class 11 NEET Notes | EduRev

,

study material

,

Sample Solution Paper 1 - Chemistry

,

ppt

,

Important questions

,

practice quizzes

,

Summary

,

past year papers

,

Sample Solution Paper 1 - Chemistry

;