Class 9 Exam  >  Class 9 Notes  >  Chemistry Class 9 ICSE  >  Selina Textbook Solutions: Language of Chemistry

Selina Textbook Solutions: Language of Chemistry | Chemistry Class 9 ICSE PDF Download

Download, print and study this document offline
Please wait while the PDF view is loading
 Page 1


Chapter 4. The Language of Chemistry
Exercise 4
Solution 1.
Solution 2.
Solution 3.
Page 2


Chapter 4. The Language of Chemistry
Exercise 4
Solution 1.
Solution 2.
Solution 3.
 
(d) This equation satisfies the “Law of Conservation of Mass.” 
Law of Conservation of mass: “Matter is neither created nor destroyed in course of a 
chemical reaction.”
Solution 4.
(a)
Zn + H
2
SO
4
 ? ZnSO
4
 + H
2
This equation conveys following information:
1. The actual result of chemical change.
2. The substances take part in a chemical reaction and substances formed as a result 
of reaction.
3. Here one molecule of zinc, one molecule ofSulphuric acid react to give one molecule 
of zinc sulphate and one molecule of Hydrogen.
4. Composition of respective molecules i.e. one molecule ofsulphuric acid contains two 
atoms of hydrogen, one atom of sulphur and four atoms of oxygen.
5. Relativemoleculer masses of different substances i.e. molecular mass of 
Zn= 65, H
2
SO
4
 (2+32+64) = 98 
ZnSO
4
 (65+32+64) = 161 
H
2
 = 2
6. 22.4 litres of hydrogen are formed at S.T.P.
(b)
Mg + 2HCl
2
 ? MgCl
2
 + H
2
This equation conveys following information:
1. Magnesium reacts with of Hydrochloric acid to form Magnesium chloride and 
Hydrogen gas.
2. 24g of Magnesium react with 2(1 + 35.5) = 73g of Hydrochloric acid to produce (24 
+ 71) i.e. 95g of Magnesium chloride
3. That Hydrogen produced out at S.T.P. is 22.4 liters.
Page 3


Chapter 4. The Language of Chemistry
Exercise 4
Solution 1.
Solution 2.
Solution 3.
 
(d) This equation satisfies the “Law of Conservation of Mass.” 
Law of Conservation of mass: “Matter is neither created nor destroyed in course of a 
chemical reaction.”
Solution 4.
(a)
Zn + H
2
SO
4
 ? ZnSO
4
 + H
2
This equation conveys following information:
1. The actual result of chemical change.
2. The substances take part in a chemical reaction and substances formed as a result 
of reaction.
3. Here one molecule of zinc, one molecule ofSulphuric acid react to give one molecule 
of zinc sulphate and one molecule of Hydrogen.
4. Composition of respective molecules i.e. one molecule ofsulphuric acid contains two 
atoms of hydrogen, one atom of sulphur and four atoms of oxygen.
5. Relativemoleculer masses of different substances i.e. molecular mass of 
Zn= 65, H
2
SO
4
 (2+32+64) = 98 
ZnSO
4
 (65+32+64) = 161 
H
2
 = 2
6. 22.4 litres of hydrogen are formed at S.T.P.
(b)
Mg + 2HCl
2
 ? MgCl
2
 + H
2
This equation conveys following information:
1. Magnesium reacts with of Hydrochloric acid to form Magnesium chloride and 
Hydrogen gas.
2. 24g of Magnesium react with 2(1 + 35.5) = 73g of Hydrochloric acid to produce (24 
+ 71) i.e. 95g of Magnesium chloride
3. That Hydrogen produced out at S.T.P. is 22.4 liters.
Solution 5.
(a) A poly-atomic ion is a charged ion composed of two or more atoms covalently 
bounded that can be carbonate (CO
3
2-) 
and sulphate (SO
4
2-
)
(b) The fundamental laws which are involved in every equation are:
1. A chemical equation consists of formulae of reactants connected by plus sign (+) 
and arrow ( ?) followed by the formulae of products connected by plus sign (+).
2. The sign of an arrow ( ?) is to read ‘to form’. It also shows the direction in which 
reaction is predominant.
Solution 6.
(a) two 
(b) six 
(c) three 
(d) four 
(e) (i) three (ii) five (iii) four (iv) two
Solution 7.
According to law of conservation of mass, “matter can neither be created nor be 
destroyed in a chemical reaction”. This is possible only, if total number of atoms on the 
reactants side is equals to total number of atoms on products side. Thus, a chemical 
reaction should be always balanced.
Let us consider an example, 
Fe + H
2
O ? Fe
3
O
4
 + H
2 
In this equation number of atoms on both sides is not the same, the equation is not 
balanced. 
The balanced form of this equation is given by, 
3Fe + 4H
2
O  ? Fe
3
O
4
 + 4H
2
Solution 8.
Page 4


Chapter 4. The Language of Chemistry
Exercise 4
Solution 1.
Solution 2.
Solution 3.
 
(d) This equation satisfies the “Law of Conservation of Mass.” 
Law of Conservation of mass: “Matter is neither created nor destroyed in course of a 
chemical reaction.”
Solution 4.
(a)
Zn + H
2
SO
4
 ? ZnSO
4
 + H
2
This equation conveys following information:
1. The actual result of chemical change.
2. The substances take part in a chemical reaction and substances formed as a result 
of reaction.
3. Here one molecule of zinc, one molecule ofSulphuric acid react to give one molecule 
of zinc sulphate and one molecule of Hydrogen.
4. Composition of respective molecules i.e. one molecule ofsulphuric acid contains two 
atoms of hydrogen, one atom of sulphur and four atoms of oxygen.
5. Relativemoleculer masses of different substances i.e. molecular mass of 
Zn= 65, H
2
SO
4
 (2+32+64) = 98 
ZnSO
4
 (65+32+64) = 161 
H
2
 = 2
6. 22.4 litres of hydrogen are formed at S.T.P.
(b)
Mg + 2HCl
2
 ? MgCl
2
 + H
2
This equation conveys following information:
1. Magnesium reacts with of Hydrochloric acid to form Magnesium chloride and 
Hydrogen gas.
2. 24g of Magnesium react with 2(1 + 35.5) = 73g of Hydrochloric acid to produce (24 
+ 71) i.e. 95g of Magnesium chloride
3. That Hydrogen produced out at S.T.P. is 22.4 liters.
Solution 5.
(a) A poly-atomic ion is a charged ion composed of two or more atoms covalently 
bounded that can be carbonate (CO
3
2-) 
and sulphate (SO
4
2-
)
(b) The fundamental laws which are involved in every equation are:
1. A chemical equation consists of formulae of reactants connected by plus sign (+) 
and arrow ( ?) followed by the formulae of products connected by plus sign (+).
2. The sign of an arrow ( ?) is to read ‘to form’. It also shows the direction in which 
reaction is predominant.
Solution 6.
(a) two 
(b) six 
(c) three 
(d) four 
(e) (i) three (ii) five (iii) four (iv) two
Solution 7.
According to law of conservation of mass, “matter can neither be created nor be 
destroyed in a chemical reaction”. This is possible only, if total number of atoms on the 
reactants side is equals to total number of atoms on products side. Thus, a chemical 
reaction should be always balanced.
Let us consider an example, 
Fe + H
2
O ? Fe
3
O
4
 + H
2 
In this equation number of atoms on both sides is not the same, the equation is not 
balanced. 
The balanced form of this equation is given by, 
3Fe + 4H
2
O  ? Fe
3
O
4
 + 4H
2
Solution 8.
Solution 9.
Page 5


Chapter 4. The Language of Chemistry
Exercise 4
Solution 1.
Solution 2.
Solution 3.
 
(d) This equation satisfies the “Law of Conservation of Mass.” 
Law of Conservation of mass: “Matter is neither created nor destroyed in course of a 
chemical reaction.”
Solution 4.
(a)
Zn + H
2
SO
4
 ? ZnSO
4
 + H
2
This equation conveys following information:
1. The actual result of chemical change.
2. The substances take part in a chemical reaction and substances formed as a result 
of reaction.
3. Here one molecule of zinc, one molecule ofSulphuric acid react to give one molecule 
of zinc sulphate and one molecule of Hydrogen.
4. Composition of respective molecules i.e. one molecule ofsulphuric acid contains two 
atoms of hydrogen, one atom of sulphur and four atoms of oxygen.
5. Relativemoleculer masses of different substances i.e. molecular mass of 
Zn= 65, H
2
SO
4
 (2+32+64) = 98 
ZnSO
4
 (65+32+64) = 161 
H
2
 = 2
6. 22.4 litres of hydrogen are formed at S.T.P.
(b)
Mg + 2HCl
2
 ? MgCl
2
 + H
2
This equation conveys following information:
1. Magnesium reacts with of Hydrochloric acid to form Magnesium chloride and 
Hydrogen gas.
2. 24g of Magnesium react with 2(1 + 35.5) = 73g of Hydrochloric acid to produce (24 
+ 71) i.e. 95g of Magnesium chloride
3. That Hydrogen produced out at S.T.P. is 22.4 liters.
Solution 5.
(a) A poly-atomic ion is a charged ion composed of two or more atoms covalently 
bounded that can be carbonate (CO
3
2-) 
and sulphate (SO
4
2-
)
(b) The fundamental laws which are involved in every equation are:
1. A chemical equation consists of formulae of reactants connected by plus sign (+) 
and arrow ( ?) followed by the formulae of products connected by plus sign (+).
2. The sign of an arrow ( ?) is to read ‘to form’. It also shows the direction in which 
reaction is predominant.
Solution 6.
(a) two 
(b) six 
(c) three 
(d) four 
(e) (i) three (ii) five (iii) four (iv) two
Solution 7.
According to law of conservation of mass, “matter can neither be created nor be 
destroyed in a chemical reaction”. This is possible only, if total number of atoms on the 
reactants side is equals to total number of atoms on products side. Thus, a chemical 
reaction should be always balanced.
Let us consider an example, 
Fe + H
2
O ? Fe
3
O
4
 + H
2 
In this equation number of atoms on both sides is not the same, the equation is not 
balanced. 
The balanced form of this equation is given by, 
3Fe + 4H
2
O  ? Fe
3
O
4
 + 4H
2
Solution 8.
Solution 9.
Solution 10.
(a) The atomic mass unit (amu) is defined as 1/12
th
 of the mass of an atom of carbon.
1 a.m.u. = 1.67 x 10
-24
 gm = 1.67 x 10
-27
 kg 
1 gm mass = 6.02 x 10
23
 a.m.u. and 1 kg mass = 6.02 x 10
26
 a.m.u. (b)
(i) The relative molecular mass of = CuSO
4
5H
2
O 
= 63.5 + 32 + (16 x 4) + 5 (2 + 16) 
= 159.5 + 90 = 249.5
(ii) The relative molecular mass of = (NH
4
)
2
CO
3
 = N
2
H
8
CO
3 
= 14 x 2 + 1 x 8 + 12 + 3 x 16 
= 28 + 8 + 12 + 48 = 96
(iii) The relative molecular mass of = (NH
2
)
2
CO = N
2
H
4
CO 
= 2 x 14 + 1 x 4 + 12 + 16 
= 28 + 4 + 12 + 16 = 60 
(iv) The relative molecular mass of = Mg
3
N
2
 = 3 x 24 + 2 x 14 = 72 + 28 = 100
Solution 11.
Read More
10 videos|47 docs|9 tests

FAQs on Selina Textbook Solutions: Language of Chemistry - Chemistry Class 9 ICSE

1. What are the basic concepts covered in the Language of Chemistry for Class 9?
Ans. The Language of Chemistry for Class 9 covers fundamental concepts such as the structure of atoms, symbols of elements, molecular formulas, chemical equations, and the significance of the periodic table. It emphasizes the importance of understanding chemical symbols and formulas to communicate chemical information effectively.
2. How can I improve my understanding of chemical symbols and formulas in Class 9 Chemistry?
Ans. To improve your understanding of chemical symbols and formulas, practice writing and recognizing the symbols of common elements, learn the rules for creating chemical formulas (like using subscripts for the number of atoms), and solve problems involving the conversion of word equations into chemical equations. Engaging in group studies and using flashcards can also be helpful.
3. What are the common types of chemical reactions studied in Class 9?
Ans. Common types of chemical reactions studied in Class 9 include combination reactions, decomposition reactions, displacement reactions, and redox reactions. Understanding these types helps students predict the products of chemical reactions and grasp the concept of reactants transforming into products.
4. Why is the periodic table important in the study of chemistry for Class 9 students?
Ans. The periodic table is essential because it organizes elements based on their atomic number and properties, allowing students to understand trends such as electronegativity, atomic size, and reactivity. It serves as a vital reference for learning about element relationships and predicting chemical behavior.
5. What strategies can I use to prepare for the Language of Chemistry exam effectively?
Ans. Effective strategies for preparing for the Language of Chemistry exam include reviewing class notes regularly, practicing previous years' question papers, forming study groups for collaborative learning, and utilizing online resources or tutorials. Additionally, creating summary charts for chemical reactions and formulas can enhance retention and understanding.
Related Searches

ppt

,

MCQs

,

practice quizzes

,

Exam

,

Extra Questions

,

Free

,

Previous Year Questions with Solutions

,

video lectures

,

Sample Paper

,

Viva Questions

,

mock tests for examination

,

Important questions

,

Objective type Questions

,

Semester Notes

,

past year papers

,

Selina Textbook Solutions: Language of Chemistry | Chemistry Class 9 ICSE

,

Summary

,

shortcuts and tricks

,

Selina Textbook Solutions: Language of Chemistry | Chemistry Class 9 ICSE

,

study material

,

Selina Textbook Solutions: Language of Chemistry | Chemistry Class 9 ICSE

,

pdf

;