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9. Simple and Compound Interest 
EXERCISE 9(A) 
Question 1. 
Find the interest and the amount on: 
(i) Rs. 750 in 3 years 4 months at 10% per annum. 
(ii) Rs. 5,000 at 8% per year from 23rd December 2011 to 29th July 2012. 
(iii) Rs. 2,600 in 2 years 3 months at 1% per month. 
(iv) Rs. 4,000 in 1 years at 2 paise per rupee per month. 
Solution: 
Page 2


9. Simple and Compound Interest 
EXERCISE 9(A) 
Question 1. 
Find the interest and the amount on: 
(i) Rs. 750 in 3 years 4 months at 10% per annum. 
(ii) Rs. 5,000 at 8% per year from 23rd December 2011 to 29th July 2012. 
(iii) Rs. 2,600 in 2 years 3 months at 1% per month. 
(iv) Rs. 4,000 in 1 years at 2 paise per rupee per month. 
Solution: 
 
Question 2. 
Rohit borrowed Rs. 24,000 at 7.5 percent per year. How much money will he pay at the 
end of 4th years to clear his debt ? 
Solution: 
 
Page 3


9. Simple and Compound Interest 
EXERCISE 9(A) 
Question 1. 
Find the interest and the amount on: 
(i) Rs. 750 in 3 years 4 months at 10% per annum. 
(ii) Rs. 5,000 at 8% per year from 23rd December 2011 to 29th July 2012. 
(iii) Rs. 2,600 in 2 years 3 months at 1% per month. 
(iv) Rs. 4,000 in 1 years at 2 paise per rupee per month. 
Solution: 
 
Question 2. 
Rohit borrowed Rs. 24,000 at 7.5 percent per year. How much money will he pay at the 
end of 4th years to clear his debt ? 
Solution: 
 
Question 3. 
The interest on a certain sum of money is Rs. 1,480 in 2 years and at 10 per cent per 
year. Find the sum of money. 
Solution: 
Let P = Rs. x 
Time (T) = 2 years 
Rate (R) = 0% 
 
Question 4. 
On what principal will the simple interest be Rs. 7,008 in 6 years 3 months at 5% per 
year ? 
Solution: 
 
Page 4


9. Simple and Compound Interest 
EXERCISE 9(A) 
Question 1. 
Find the interest and the amount on: 
(i) Rs. 750 in 3 years 4 months at 10% per annum. 
(ii) Rs. 5,000 at 8% per year from 23rd December 2011 to 29th July 2012. 
(iii) Rs. 2,600 in 2 years 3 months at 1% per month. 
(iv) Rs. 4,000 in 1 years at 2 paise per rupee per month. 
Solution: 
 
Question 2. 
Rohit borrowed Rs. 24,000 at 7.5 percent per year. How much money will he pay at the 
end of 4th years to clear his debt ? 
Solution: 
 
Question 3. 
The interest on a certain sum of money is Rs. 1,480 in 2 years and at 10 per cent per 
year. Find the sum of money. 
Solution: 
Let P = Rs. x 
Time (T) = 2 years 
Rate (R) = 0% 
 
Question 4. 
On what principal will the simple interest be Rs. 7,008 in 6 years 3 months at 5% per 
year ? 
Solution: 
 
Question 5. 
Find the principal which will amount to Rs. 4,000 in 4 years at 6.25% Per annum. 
Solution: 
 
 
Question 6. 
(i) At what rate per cent per annum will Rs. 630 produce an interest of Rs. 126 in 4 
years ? 
(ii) At what rate per cent per year will a sum double itself in 6 years ? 
Solution: 
Page 5


9. Simple and Compound Interest 
EXERCISE 9(A) 
Question 1. 
Find the interest and the amount on: 
(i) Rs. 750 in 3 years 4 months at 10% per annum. 
(ii) Rs. 5,000 at 8% per year from 23rd December 2011 to 29th July 2012. 
(iii) Rs. 2,600 in 2 years 3 months at 1% per month. 
(iv) Rs. 4,000 in 1 years at 2 paise per rupee per month. 
Solution: 
 
Question 2. 
Rohit borrowed Rs. 24,000 at 7.5 percent per year. How much money will he pay at the 
end of 4th years to clear his debt ? 
Solution: 
 
Question 3. 
The interest on a certain sum of money is Rs. 1,480 in 2 years and at 10 per cent per 
year. Find the sum of money. 
Solution: 
Let P = Rs. x 
Time (T) = 2 years 
Rate (R) = 0% 
 
Question 4. 
On what principal will the simple interest be Rs. 7,008 in 6 years 3 months at 5% per 
year ? 
Solution: 
 
Question 5. 
Find the principal which will amount to Rs. 4,000 in 4 years at 6.25% Per annum. 
Solution: 
 
 
Question 6. 
(i) At what rate per cent per annum will Rs. 630 produce an interest of Rs. 126 in 4 
years ? 
(ii) At what rate per cent per year will a sum double itself in 6 years ? 
Solution: 
 
Question 7. 
(i) In how many years will Rs.950 produce Rs.399 as simple interest at 7% ? 
(ii) Find the time in which Rs.1200 will amount to Rs.1536 at 3.5% per year. 
Solution: 
 
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