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**Series Resonance Circuit Diagram**

If the resonance occurs in series RLC circuit, then it is called as Series Resonance. Consider the following series RLC circuit, which is represented in phasor domain.

Here, the passive elements such as resistor, inductor and capacitor are connected in series. This entire combination is in series with the input sinusoidal voltage source.

Apply KVL around the loop.

V−V_{R}−V_{L}−V_{C }= 0

⇒ V−IR−I(jX_{L})−I(−jX_{C}) = 0

⇒ V = IR+I(jX_{L})+I(−jX_{C})

⇒ V = I[R+j(X_{L}−X_{C})] Equation 1

The above equation is in the form of V = IZ.

Therefore, the impedance Z of series RLC circuit will be

Z = R+j(X_{L}−X_{C})**Parameters & Electrical Quantities at Resonance**

Now, let us derive the values of parameters and electrical quantities at resonance of series RLC circuit one by one.**Resonant Frequency**

The frequency at which resonance occurs is called as resonant frequency f_{r}. In series RLC circuit resonance occurs, when the imaginary term of impedance Z is zero, i.e., the value of X_{L} − X_{C} should be equal to zero.

⇒ X_{L} = X_{C}

Substitute X_{L} = 2πfL and in the above equation.

Therefore, the resonant frequency f_{r} of series RLC circuit is

Where, L is the inductance of an inductor and C is the capacitance of a capacitor.

The resonant frequency fr of series RLC circuit depends only on the inductance L and capacitance C. But, it is independent of resistance R.**Impedance**

We got the impedance Z of series RLC circuit as

Z = R+j(X_{L} − X_{C})

Substitute X_{L} = X_{C} in the above equation.

Z = R+j(X_{C} − X_{C})

⇒ Z = R+j(0)

⇒ Z = R

At resonance, the impedance Z of series RLC circuit is equal to the value of resistance R, i.e., Z = R.**Current flowing through the Circuit**

Substitute X_{L} − X_{C} = 0 in Equation 1

V = I[R+j(0)]

⇒ V = IR

⇒ I = V/R

Therefore, current flowing through series RLC circuit at resonance is I = V/R

At resonance, the impedance of series RLC circuit reaches to minimum value. Hence, the maximum current flows through this circuit at resonance.**Voltage across Resistor**

The voltage across resistor is

V_{R} = IR

Substitute the value of I in the above equation.

⇒ VR = V

Therefore, the voltage across resistor at resonance is V_{R} = V.**Voltage across Inductor**

The voltage across inductor is

V_{L} = I(jX_{L})

Substitute the value of I in the above equation.

⇒ V_{L} = jQV

Therefore, the voltage across inductor at resonance is V_{L} = jQV.

So, the magnitude of voltage across inductor at resonance will be

|V_{L}| = QV

Where Q is the Quality factor and its value is equal to **Voltage across Capacitor**The voltage across capacitor is

V

Substitute the value of I in the above equation.

⇒ V

Therefore, the voltage across capacitor at resonance is V

So, the magnitude of voltage across capacitor at resonance will be

|V

Where Q is the Quality factor and its value is equal to

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