JEE  >  All Types of Questions for JEE  >  Single Correct MCQs: Motion

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Document Description: Single Correct MCQs: Motion for JEE 2022 is part of All Types of Questions for JEE preparation. The notes and questions for Single Correct MCQs: Motion have been prepared according to the JEE exam syllabus. Information about Single Correct MCQs: Motion covers topics like and Single Correct MCQs: Motion Example, for JEE 2022 Exam. Find important definitions, questions, notes, meanings, examples, exercises and tests below for Single Correct MCQs: Motion.

Introduction of Single Correct MCQs: Motion in English is available as part of our All Types of Questions for JEE for JEE & Single Correct MCQs: Motion in Hindi for All Types of Questions for JEE course. Download more important topics related with notes, lectures and mock test series for JEE Exam by signing up for free. JEE: Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
1 Crore+ students have signed up on EduRev. Have you?

Q.1. A particle is projected upward with an initial speed u making an angle θ with the horizontal. The radius of curvature of the curve at the instant when the particle strikes the ground is
(a)  Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(b) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(c)  u2/gsinθ
(d)  u2/gcosθ

Correct Answer is option (d)

Radius of curvature R = v2/an = v2gcosθ

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.2. The co-ordinates of a moving particle at any time t are given by x = ct2 and y = bt2. The speed of the particle is given by
(a) 2t (c + b)
(b) 2t Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(c) tSingle Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(d) 2t Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Correct Answer is option (d)
X = ct2 and  y = bt2
⇒ dx/dt = 2ct & dy/dt =  2bt
Since v = Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.3. A bus is moving with a constant velocity v1 along a horizontal road. A man standing inside the bus throws a ball upward with velocity v0 and catches the ball.  The magnitude of displacement of the ball with respect to ground is
(a) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(B) zero
(c) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE 
(d) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Correct Answer is option (c)

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.4. A particle is projected vertically upwards and it attains maximum height H.  If the ratio of times to attain height h (<H) is 1/3, then h equals 
(a) (2/3)  H
(b) (3/4) H
(c) (4/3)  H
(d) (3/2) H

Correct Answer is option (b)
Let the particle be projected vertically upward  with velocity u. Further, let t be the  time when projectile be at height h.  Then
h = ut- 1/2 gt2 or 1/2 gt2 – ut + h = 0

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE . . . (1) 

From equation (1),
Sum of roots, t1 + t2 = - b/a = 2u/g . .. (2)

Product of roots, t1t2 = c/a = 2h/g = . ..  (3) 

Given that t1/tor t2 = 3t1 ..  . (4)
From equations (2) and (4), we get
4t1 = 2u/g or t1 = u/2g = . . . (5)
From equations (3) and (4), we get

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
or u2/2g = 4h/3 = . .. . (6)

Also, maximum height, H = u2/2g . . . (7) 

From Eqs. (6) and (7), we obtain
H = 4h/3 ⇒ h = 3H/4

Q.5. A body A is thrown vertically upward with initial velocity v1. Another body B is dropped from a height h at time t = 0. Which equation represents correct relationship between distance of separation between the two particles (x) and time t (before they collide with ground)?
(a) X = |h - v1t |
(b) X = |h + v1t |
(c) X = Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(d) X = |1/2 g2 - v1t|

Correct Answer is option (a)

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
X = |h - v1t |

 Q.6. A man can swim at a speed of 5 km/h w.r.t. water. He wants to cross a 1.5 km wide river flowing at 3 km/h. He keeps himself always at an angle of 60o with the flow direction while swimming. The time taken by him to cross the river will be
(a) 0.25 hr
(b) 0.35 hr
(c) 0.45 hr
(d) 0.55 hr

Correct Answer is option (b) 
The angle betweenSingle Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEEand Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE is θ (say).
⇒ The required time for crossing,
Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.7. A disc of radius R is rotating inside a room. A boy standing near the rim of the disc, finds that water droplets falling from the ceiling always hit on his head. As one drop hits his head, the next one starts from the ceiling.  If height of the roof above his head is H, angular velocity of the disc is
(a) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(b) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(c) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(d) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Correct Answer is option (c)
The time period of revolution of the disc is equal to the time of motion of water drop in air.  
⇒ 2πR /ω = Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEEor ω = 2πRSingle Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.8. A body is moving in a circle at a uniform speed v. The magnitude of the change in velocity when the radius vector describes an angle of 60° is
(a) v
(b) v/2
(c) √3/2 v
(d) v

Correct Answer is option (d)
Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
⇒ Δv = v

Q.9. A projectile is thrown with a velocity u0 at an angle θ with the horizontal. The ratio of the rate of change of speed w.r.t. time at the highest point to that at the point of projection is
(a) g sin θ
(b) -g sin θ
(c) zero
(d) g

Correct Answer is option (c)
dv/dt (at the top) = 0
As tangential acceleration at the top = 0
dv/dt (at the starting point) = -g sin θ
So, required ratio = zero.

Q.10. A particle starts sliding down a frictionless inclined plane. If Sn is the distance travelled by it from time  t = (n - 1) sec to t = n sec, then the ratio Sn/Sn+1 is
(a) 2n - 1/2n + 1
(b) 2n + 1/2n
(c) 2n/2n + 1
(d) 2n + 1/2n - 1

Correct Answer is option (a)
sn = u + (a/2)(2n - 1)
Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.11. A particle starts moving from rest along a circle of radius 4 m with a constant tangential acceleration of 3 m/sec2. The total acceleration of the particle at t = 2 seconds makes an angle q with the tangential acceleration, where θ is equal to
(a) tan-1(1/3)
(b) tan-1(3)
(c)Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(d) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Correct Answer is option (b)

At t = 2 seconds,
 Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
v = 6 m/sec and a = 3 m/sec2 2

v2/r = 36/4 = 9m/sec2
α = tan-1(3)

Q.12. A particle starts moving with constant acceleration and covers a distance x in first t seconds. The distance travelled by it in the next 2t seconds is
(a) 8x
(b) 3x
(c) x
(d) none of these

Correct Answer is option (a)

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.13. A particle moves in the x-y plane with a velocity vx = 8t - 2 and vy = 2. If it passes through the point x = 14 and y = 4 at t = 2 s, the equation of the path is
(a) x = y2- y + 2
(b) x = y + 2
(c) x = y2 + 2
(d) x = y2 + y + 2

Correct Answer is option (a)

dx/dt =  8t - 2 ⇒ ∫ dx = ∫(8t - 2) dt
⇒ x = 4t2- 2t + c
At t = 2, x = 14 ⇒ C = 2
x = 4t2- 2t + 2 …(1)
dy/dt = 2 ⇒ ∫ dy = ∫ 2dt

⇒ y = 2t + c'
At t = 2, y = 4 ⇒ c' = 0
⇒ y = 2t …(2)
From (1) and (2), eliminating t
x = y2- y + 2

Q.14. A rocket is fired upwards and its fuel is exhausted in 10 sec. The figure shows its v–t graph, where v is in m/s and t is in sec. What is the maximum height reached?
Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(a) 1000 x 5 m
(b) 1000 x 10 m
(c) 1000 x 50 m
(d) 1000 x 100 m

Correct Answer is option (c)
Maximum height reached = area of v–t graph = 1/2 x 100 x 1000 m.

Q.15. If the range of a gun which fires a shell with muzzle speed v is R, then the angle of elevation of the gun is
(a)
 Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(b) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(c) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(d) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Correct Answer is option (d)

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.16. A man starts running with constant speed along a circular path of radius 2 m. He completes two rounds in 16 seconds. The magnitude of the average velocity in first 2 seconds is

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE(a) 2 m/s
(b) 1 m/s
(c) 3 m/s
(d) 6 m/s

Correct Answer is option (b)

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.17. A particle is moving on a circle of radius R such that at every instant the tangential and radial accelerations are equal in magnitude. If the velocity of the particle be v0 at t = 0, the time for the completion of half of first revolution will be
(a) R/v0
(b)Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(c) Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE
(d)Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Correct Answer is option (b)

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.18. A boy throws a ball in a train, moving at a speed of 18 kmph, with a velocity of 15√2 m/s at an angle of 45° to the horizontal in the direction of motion of the train. The angle with which it strikes the plane of projection w.r.t. an observer watching from the road nearby to the train is
(a) 45°
(b) 60°

(c) 37°
(d) none of these

Correct Answer is option (c)

Time of flight t = 2usin θ/g  = 3 sec
Final velocities w.r.t. ground are
vy = u sin θ - gt = 15√2 sin 45° - 10(3) = -15m / s

vx = u cos θ + utrain = 15√2 cos 45° + 18 x  5/18 = 20 m / s
Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE⇒ θ = 37°

Q.19. If position vector of a particle at time t isSingle Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE, then
(a) Particle is moving with constant velocity in straight line
(b) Particle is moving with variable velocity in straight line
(c) Particle moving is in parabolic path
(d) Particle is in rest

Correct Answer is option (a)

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

Q.20. The velocity vector of a particle moving over a horizontal plane is given by Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE The ratio of the magnitude of instantaneous acceleration of the particle at t = 2 sec to the magnitude of displacement of the particle during the interval of first 2 sec is
(a) 3/4
(b) 4/3
(c) 5/4
(d) cannot be determined

Correct Answer is option (a)

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

The document Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE is a part of the JEE Course All Types of Questions for JEE.
All you need of JEE at this link: JEE

Related Searches

Exam

,

study material

,

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

,

mock tests for examination

,

video lectures

,

Sample Paper

,

Objective type Questions

,

Free

,

MCQs

,

ppt

,

practice quizzes

,

Previous Year Questions with Solutions

,

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

,

Viva Questions

,

Important questions

,

Summary

,

past year papers

,

Extra Questions

,

Single Correct MCQs: Motion Notes | Study All Types of Questions for JEE - JEE

,

pdf

,

Semester Notes

,

shortcuts and tricks

;