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Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET PDF Download

Introduction

  • Thermodynamic potentials are important functions in statistical mechanics that connect the behavior of tiny particles to the overall properties of larger systems. 
  • These potentials help us find various thermodynamic quantities and allow us to predict how systems will act under different conditions. 
  • The main types of thermodynamic potentials include Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET
  • Each potential has its own natural variablesand uses, such as: 
    • Finding equilibrium conditions
    • Predicting spontaneous processes
    • Understanding phase transitions

Internal Energy

  • The total energy in a thermodynamic system is represented as U.
  • This energy includes the kinetic and potential energies of all the particles within the system.
  • U is essential for understanding the First Law of Thermodynamics, which is expressed as: dU = δQ - δWThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET
  • The energy Udepends on certain extensive properties, such as:
    • Entropy
    • Volume
    • Number of particles
  • The natural variablesthat relate to this energy are:
    • Entropy (S)
    • Volume (V)

Enthalpy

  • H = U + PV, where P represents pressure and V stands for volume.
  • It measures the total heat content of a system.
  • This concept is especially useful for processes that happen at constant pressure, known as isobaric processes.
  • Changes in enthalpy (ΔH) show the heat that is either absorbed or released during chemical reactions.
  • Two important variables related to enthalpy are entropy (S) and pressure (P).

Helmholtz free energy

  • A is expressed as A = U - TS, where T stands for temperature and S means entropy.
  • This equation shows the useful work that can be obtained from a closed system when the temperature is constant.
  • The value of A is at its lowest point when the system is in equilibrium, especially in situations with a fixed temperature and volume.
  • The equation helps in figuring out the direction of spontaneous processes under conditions of constant temperature and constant volume.
  • The natural variables in this context are temperature (T) and volume (V).

Gibbs free energy

  • G is defined as G = H - TS or G = U + PV - TS
  • G measures the maximum work that can be obtained from a system in a reversible way.
  • G is at its lowest point when a system is in equilibrium at constant temperature and pressure.
  • It is important for understanding chemical equilibrium and whether reactions will occur spontaneously.
  • The key variables that affect G are temperature (T) and pressure (P).

Mathematical formulations

Legendre transformations

  • Mathematical method used to change between different thermodynamic potentials.
  • Facilitates the conversion between conjugate variables, which include both extensive and intensive properties.
  • Maintains the information content while altering the independent variables.
  • General formula:
  • F(x,y) = f(x,y) - y ∂f/∂y
  • This method allows for the derivation of new potentials from existing ones, such as transforming U (internal energy) to H (enthalpy) and A (Helmholtz free energy) to G (Gibbs free energy).

Partial derivatives relationships

Various thermodynamic properties can be linked through mathematical equations. 

  • Fundamental Equation:
    • dU: This represents the change in internal energy. 
    • T: This is the temperature. 
    • dS: This indicates the change in entropy. 
    • P: This refers to pressure. 
    • dV: This signifies the change in volume. 
    • dN: This denotes the change in the number of particles. 
    • The fundamental equation can be expressed as: dU = TdS - PdV + μdN
  • Derived Relationships:
    • (∂U/∂S)V,N = T
    • (∂U/∂V)S,N = -P
    • (∂U/∂N)S,V = μ

These equations allow for the calculation of one thermodynamic quantity based on measurements of other quantities.

Maxwell Relations

F = F ( x , y ) and if it is perfect differential then d F = M dx + NdyThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETthen, M and N will satisfy the condition Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETMaxwell relations are relationship between two derivatives of thermodynamic variables, and energy due to the equivalence of potential second derivative under a change of operation order
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETWhere F is thermodynamic potentialand x and y are two of its natural independent variables.

Maxwell relations are extremely important for two reasons: 

  • First they show us that derivative of thermodynamic parameters are not all independent. This can serve as a consistency check in both experiments and in theoretical analysis.
  • Maxwell relations provide a method for expressing some derivative in other ways. This enables as to connect difficult to measure quantities to those which are readily accessible experimentally.
    The measurement of entropy and chemical potential can not be directly measurable in lab but with the help of Maxwell relation there thermodynamic property can be determine theoretically.
    For Maxwell relation,

Let us Legendre the independent variable as x , and y such that
U = U(x,y), S = S(x, y) V = V(x, y)
So Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETFrom first law of thermodynamic
dU = TdS - PdV
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETHence U,V, and S are perfect differential.
Then
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

SimilarlyThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET
Equating equation (1) and (2),
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

Maxwell first relation:- Put x = T , y = V
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

Maxwell Second Relation:-  Put x = T ,y = P
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETMaxwell Third Relation:- Put x = s , y = vThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

Maxwell Fourth Relation:- Put x = S, y = P
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

Thermodynamic potential is a scalar function used to represent the thermodynamic state of system. The concept of thermodynamic potentials was introduced by Pierre Duhem in 1886.

One main thermodynamic potential that has a physical interpretation is the internal energy.

It is energy of configuration of a given system of conservative forces. Expression for all other thermodynamic energy potentials are drivable via Legendre transformation.

Different Types of Thermodynamic Potential and Maxwell Relation

Thermodynamic potentials are different form of energy which can be used in different thermodynamic process. Thermodynamic potentials are path independent variables so they are perfect differential.
If F is unique thermodynamic potential defined by variables x and y as F = F ( x , y ) and if it is perfect differential then dF = Mdx + Ndy
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETthen M and N will satisfy the condition

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

Internal Energy

U and second from the first laws of thermodynamics dU = TdS - PdVFrom Legendre transformationfrom given relation one can derive Maxwell relation

Enthalpy

(H) the enthalpy is defined as H = U + PV dH = dU + PdV + VdP from Laws of thermodynamics,TdS = dU + PdV & dH = TdS + VdP from Legendre transformation,

The Enthalpy H is Extensive quantity, which can not be measured directly. Thus change in enthalpy is more useful.
△H is positive in endothermic reaction and negative in exothermic reaction.
From above relation one can derive Maxwell relation Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET
△H of a system is equal to sum of non-mechanical work done on it and the heat supplied to it.
Helmholtz Free Energy
(F) the Helmholtz free energy is defined F = U - T S
dF = dU - TdS - SdT 
From laws of thermodynamics, d U = T d S - P d V 
dF = TdS - PdV - TdS - SdT 
dF = - P d V - SdT
From Legendre transformation
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET
From above relation one can derive Maxwell relationThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET
The free Energy F, which is available energy for work in reversible isothermal process.
Gibbs Energy: ‘G’ is defined as G = H - TS .
G = U + P V - T S
dG = dU + PdV - VdP - TdS - SdT 
TdS - PdV + PdV + VdP - TdS - SdT 
dG = VdP - SdT
from Legendre transformation
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET
From above relation one can derive Maxwell relation
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET
Gibbs free energy is popularly as free enthalpy.
  • The Gibbs free energy is Maximum amount of nonexpanding work that can be exacted from a closed system.
  • The maximum will activated when the system is in reversible process.
  • Gibbs free energy is also treated as chemical potential.
  • In thermodynamics, chemical potential, as partial molar free energy, is a form of potential energy that can be absorbed or relived during a chemical reaction.
  • The chemical potential of a species in the minute can be defined the slope of the energy at system with respect to a change in the no of moles.Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

where Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETis chemical potential, G is Gibbs energy and N is no of molecules

Example 1: Prove that internal energy U is given by
Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET
Solution: (a) F = U-TS =U = F + TSThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETG = H-TS

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETApplication of Maxwell Relation

  • First T - dS equation

    Let T, and \/are independent variable S = S (T, V)

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

  • Second T - dS Equation

    Let T and P are independent variable S = S(T, P).

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETFrom Maxwell relation

  • Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETThird T-dS Equation

Let P , V are independent variable S = S (P ,V )

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

The First Energy Equation

Let T and V are independent variable U = U(T, V)

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETFrom first law of thermodynamics,
dU = TdS - PdV

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETUsing Maxwell relationThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

Second Energy Equation

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET

Using Maxwell relation,Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETThis is popularly known as second energy equation.

Application of second energy equation

If U is function of independent variable of T and P.

Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET


Example 2: From relation dU = TdS - P d V
Derive Maxwell relation Thermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET
Solution:dU = TdS - PdVThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETHence U is exact differentialThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NET


Example 3: A real gas which obey van der Waal's equation of state are kept in container which has temperature T0 and volume V0. if volume of container changes to V such that temperature of gas become T what is change in entropy?
Solution: Assume Cv is specific heat of constant volume

For van der Waal's gasThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETFrom first T -dS equationThermodynamic Potentials | Physics for IIT JAM, UGC - NET, CSIR NETwhere S0 is integration constant.

Some important FAQs are as follows:

Q1. Explain the significance of Legendre transformations in deriving Maxwell relations.

Sol.Legendre transformations allow the redefinition of thermodynamic potentials by replacing natural variables (like S and V) with their conjugates (like T and P). For instance: 
dG = −S dT + V dP
This simplifies the derivation of Maxwell relations and enables the conversion of thermodynamic quantities into measurable forms.

Q2. What is the physical significance of chemical potential (μ) in thermodynamics?

Sol.Chemical potential (μ) represents the change in Gibbs free energy (G) with respect to the number of particles (N):
μ = (∂G / ∂N)T,P
It indicates the potential energy available for particle exchange during chemical reactions and phase transitions.

Q3. A system undergoes a reversible isothermal process. What happens to the Helmholtz free energy (A)?

Sol. During a reversible isothermal process (T = constant), the change in Helmholtz free energy (ΔA) represents the maximum work done by the system:
ΔA = −Wmax
At equilibrium, A is minimized.

Q4. Explain the relationship between enthalpy (H) and entropy (S) during an isobaric process.

Sol. During an isobaric process (P=constant), the change in enthalpy (ΔH) is equal to the heat absorbed or released:
ΔH = TΔS
Here, ΔS is the change in entropy. If ΔH > 0, the process is endothermic; if ΔH < 0, it is exothermic.

Q5. Why is Gibbs free energy important in chemical reactions?

Sol. Gibbs free energy G = H − T S indicates the maximum non-expanding work obtainable from a system at constant temperature and pressure. It predicts:

  • Spontaneity: A reaction is spontaneous if ΔG < 0.
  • Equilibrium: At equilibrium, ΔG = 0.
  • Phase Transitions: Helps determine equilibrium conditions during phase changes.
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