Unit Test (Solutions): Far and Near | Mathematics (Maths Mela) Class 5 - New NCERT PDF Download

Time: 1 hour

M.M. 30

Attempt all questions.

• Question numbers 1 to 5 carry 1 mark each.
• Question numbers 6 to 8 carry 2 marks each.
• Question numbers 9 to 11 carry 3 marks each.
• Question number 12 & 13 carry 5 marks each

Q1: 7 km = ? m (1 Mark)
(a) 700
(b) 7000
(c) 70
(d) 70,000
Sol: (b) 7000

• Conversion: 1 km = 1000 m

• 7 km = 7 × 1000 = 7000 m

Q2: A rope is 900 cm long. If cut into 15 equal pieces, the length of each piece is: (1 Mark)
(a) 90 m
(b) 60 cm
(c) 6 m
(d) 600 m
Sol: (b) 60 cm

• Total length = 900 cm

• Number of pieces = 15

• Length of each piece = 900 ÷ 15 = 60 cm

Q3: A bamboo pole is 420 cm long. What is its length in metres? (1 Mark)
(a) 42 m
(b) 4.2 m
(c) 0.42 m
(d) 4200 m
Sol: (b) 4.2 m 

• Conversion: 1 m = 100 cm

• Length in metres = 420 ÷ 100 = 4.2 m

Q4: A train is 480 m long. What is its length in kilometers? (1 Mark)
(a) 0.048 km
(b) 4.8 km
(c) 0.48 km
(d) 48 km
Sol: (c) 0.48 km

• Conversion: 1 km = 1000 m

• Length in km = 480 ÷ 1000 = 0.48 km

Q5: A ribbon is 54 m long. If each piece is 6 m long, how many pieces can be cut? (1 Mark)
(a) 7
(b) 8
(c) 9
(d) 10
Sol: (c) 9

• Total length = 54 m

• Length of each piece = 6 m

• Number of pieces = 54 ÷ 6 = 9

Q6: A ribbon is 144 m long. It is cut into 12 equal pieces. What is the length of each piece? (2 Marks)

Sol:
144 ÷ 12 = 12 m
Each piece = 12 m

Q7: A man walks 4 km every day. How many kilometers will he walk in 20 days? (2 Marks)​​​

Sol:
4 × 20 = 80 km
= 80 km

Q8: A road between two villages is 9 km 600 m long. Out of this, workers have repaired 7 km 200 m. How much road is still left to repair?  (2 Marks)

Sol:
9 km 600 m = 9600 m
7 km 200 m = 7200 m
Remaining = 9600 – 7200 = 2400 m = 2 km 400 m

Road left = 2 km 400 m

Q9: A cloth merchant bought a roll of cloth 60 m long. He sold 18 m 50 cm to one customer and 21 m 25 cm to another. How much cloth is left with him?  (3 Marks)​​​​

Sol:
Total = 60 m
Sold = 18.50 + 21.25 = 39.75 m
Remaining = 60 – 39.75 = 20.25 m

= 20 m 25 cm left

Q10: The distance from a school to the bus stand is 3 km 750 m. The bus travels this distance in the morning and returns in the afternoon. What is the total distance covered by the bus in a day?   (3 Marks)

Sol:
3 km 750 m = 3750 m
Twice = 3750 × 2 = 7500 m = 7 km 500 m

= 7 km 500 m

Q11: The distance from a playground to the library is 2 km 600 m. A boy goes to the library and returns back to the playground twice in a day. What is the total distance he covers?   (3 Marks)

Sol:
2 km 600 m = 2600 m
One round trip = 2600 × 2 = 5200 m
Two trips = 5200 × 2 = 10,400 m = 10 km 400 m

= 10 km 400 m

Q12: Compare the following using >, < or = sign:   (5 Marks)

(i) 809 cm … 901 cm
(ii) 12 m … 8 m
(iii) 1200 cm … 15 m
(iv) 640 cm … 8 m
(v) 6 km … 5800 m
(vi) 720 cm … 8 m
(vii) 15 m … 140 cm
(viii) 500 m … 1 km
(ix) 300 cm … 25 m
(x) 2 km … 1500 m

Sol:
(i) 809 cm < 901 cm
(ii) 12 m > 8 m
(iii) 1200 cm = 12 m < 15 m
(iv) 640 cm = 6.4 m < 8 m
(v) 6 km = 6000 m > 5800 m
(vi) 720 cm = 7.2 m < 8 m
(vii) 15 m = 1500 cm > 140 cm
(viii) 500 m < 1 km
(ix) 300 cm = 3 m < 25 m
(x) 2 km = 2000 m > 1500 m

Q13: Convert the following into centimeters.   (5 Marks)

(i) 85 mm to cm
(ii) 45 dm to cm
(iii) 7 cm 6 mm to cm
(iv) 25 km to cm
(v) 28 m to cm
(vi) 35 m to km
(vii) 72 hm to km
(viii) 250 dam to km
(ix) 405 dam to km
(x) 9600 cm to km

Sol:

(i) 85 mm = 85 ÷ 10 = 8.5 cm
(ii) 45 dm = 45 × 10 = 450 cm
(iii) 7 cm + (6 ÷ 10) cm = 7.6 cm
(iv) 25 km = 25 × 100,000 = 2,500,000 cm
(v) 28 m = 28 × 100 = 2800 cm
(vi) 35 ÷ 1000 = 0.035 km
(vii) 72 hm = 72 × 100 = 7200 m = 7.2 km
(viii) 250 dam = 250 × 10 = 2500 m = 2.5 km
(ix) 405 dam = 405 × 10 = 4050 m = 4.05 km
(x) 9600 ÷ 100 = 96 m → 96 ÷ 1000 = 0.096 km