Class 9 Exam  >  Class 9 Notes  >  Mathematics (Maths) Class 9  >  Very Short Answer Type Questions: Circles

Class 9 Maths Question Answers - Circles

Q1. In the figure, if ∠ ACB = 35°, then find the measure of ∠ OAB.

Class 9 Maths Question Answers - Circles

Ans: ∠AOB = 180° -  (∠1 + ∠2)
= 180° - (35° + 35°)                     [∵ AO = OB ∴ ∠1 = ∠2]
= 110°
∠ACB = (1/2)(∠AOB) = (1/2) (110°) = 55°


Q2. If points A, B and C are such that AB ⊥ BC and AB = 12 cm, BC = 16 cm. Find the radius of the circle passing through the points A, B and C.
Ans:
∵ AB ⊥ BC
∴ ∠B = 90°                  [Angle in a semicircle]
⇒ AC is a diameter 

Class 9 Maths Question Answers - Circles

Class 9 Maths Question Answers - Circles

AC = 20

Radius = 10cm


Q3. The angles subtended by a chord at any two points of a circle are equal. Write true or false for the above statement and justify your answer.
Ans:
False. If two points lie in the same segment only, then the angles will be equal otherwise they are not equal.


Q4. Two chords of a circle of length 10 cm and 8 cm are at the distance 8.0 cm and 3.5 cm, respectively from the centre, state true and false for the above statement.
Ans:
False. As the larger chord is at a smaller distance from the centre.


Q5. If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing through the points A, B and C is 

Ans: 

Class 9 Maths Question Answers - Circles

Assuming that AB = 12 cm and BC = 16 cm

If BC and AB are in a circle, then AC will be the circle's diameter.

[circular's diameter forms a right angle to the circle]

Apply the Pythagorean theorem to the ABC right angle.

AC2=AB2+BC2

AC2=(12)2+(16)2

AC2=144+256⇒ AC2=400

⇒ AC2=√400=20 cm

[using the square root of a positive number since the diameter is always positive]

∴ Circle radius = 1/2(AC)=1/220=10 cm

As a result, the circle's radius is 10 cm.


Q6. In Figure, if ∠ABC = 20º, then ∠AOC is equal to:  

Class 9 Maths Question Answers - CirclesAns: Assumed: ABC = 20°...(1)

We are aware that an arc's angle at the circle's center is twice as large as its angle at the rest of the circle.

= ∠AOC = 2(20°) (From (1))

=  ∠AOC = 40°

AOC thus equals 40°


Q7. Two chords AB and AC of a circle with center O are on the opposite sides of OA. Then ∠OAB = ∠OAC. 

Write true or false for the above statement and justify your answer.

Class 9 Maths Question Answers - Circles

Ans:

Two chords are used: AB and AC.

Join us, OB and OC.

Specifically, triangle OAC and OAB

OA (common side) = OA

Triangles OAB and OAC are not congruent, therefore it is impossible to prove that any third side or angle is equivalent. OC = OB (radius of the circle).

<OAC and <OAB

The claim is untrue as a result.


Q8. ABCD is a cyclic quadrilateral such that ∠A = 90°, ∠B = 70°, ∠C = 95° and∠D = 105°.
Write true or false for the above statement and justify your answer.

Ans: Given that ABCD is a cyclic quadrilateral with angles of 90°, 70°, 95°, and 105°,

We are aware that the sum of the opposite angles in a cyclic quadrilateral is 180°.

It can be expressed mathematically as follows: A + C = 90° + 95° = 185° 180°

B + D = 70° + 105° = 175° 

The sum of the opposing angles in this situation is not 180°.

It is therefore not a cyclic quadrilateral.

The claim is false as a result.


Q9. In Fig, if AOB is the diameter of the circle and AC = BC, then ∠CAB is equal to: 

Class 9 Maths Question Answers - Circles

Ans: We are aware that the circle's diameter forms a right angle.

∠BCA = 90 ......(i)

AC = BC, and (ii) <ABC=<CAB (the angle opposite to equal sides is equal)

In △ ABC, ∠CBA+∠ABC+∠BCA=180 [Triangle's angle-sum attribute]]
 ∠CAB+∠CAB+90=180
 2 ∠CAB=90
 ∠CAB=45. 


Q10.  Two chords AB and CD of a circle are each at distances 4 cm from the center. Then AB = CD.

Write true or false for the above statement and justify your answer. 

Class 9 Maths Question Answers - CirclesAns: The right answer is True.

The above assertion is accurate since chords that are equally spaced from a circle's center have equal lengths.

AB=CD 


Q11.  If A, B, C, and D are four points such that ∠BAC = 30° and ∠BDC = 60°, then D is the center of the circle through A, B and C. 

Write true or false for the above statement and justify your answer. 
Ans: False
Because there are numerous places D where ∠BDC=60°, none of which can be the center of the circle formed by points A, B, and C.

The document Class 9 Maths Question Answers - Circles is a part of the Class 9 Course Mathematics (Maths) Class 9.
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FAQs on Class 9 Maths Question Answers - Circles

1. What are the basic properties of a circle?
Ans. The basic properties of a circle include its center, radius, diameter, circumference, and area. The radius is the distance from the center to any point on the circle, while the diameter is twice the radius. The circumference is the distance around the circle, and the area is the space enclosed within the circle.
2. How do you calculate the circumference of a circle?
Ans. The circumference of a circle can be calculated using the formula C = 2πr, where C is the circumference and r is the radius. Alternatively, if the diameter (d) is known, it can be calculated using C = πd.
3. What is the area of a circle and how is it calculated?
Ans. The area of a circle is the amount of space enclosed within it. It is calculated using the formula A = πr², where A is the area and r is the radius of the circle.
4. What is the difference between a chord and a diameter in a circle?
Ans. A chord is a line segment with both endpoints on the circle, whereas a diameter is a specific type of chord that passes through the center of the circle and has its endpoints on the circle itself. The diameter is always the longest chord in a circle.
5. How can a circle be constructed using a compass and straightedge?
Ans. To construct a circle using a compass and straightedge, first place the compass point on the desired center of the circle. Then, adjust the compass to the desired radius. Finally, rotate the compass 360 degrees around the center point to draw the circle.
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