Wave-Particle Duality
- Wave Particle Duality postulates that matter as well as light exhibits both wave and particle nature.
- This phenomenon is proven not only for elementary particles but for compound particles as well like atoms and molecules.
- In order to explain different phenomena, different assumptions were made about the nature of light. For example, the photoelectric effect of light assumed that light was made up of particles, whereas interference and diffraction assumed that light was made up of waves.
- Wave-particle duality can be used to describe all phenomena. As light was composed of particles or waves, wave-particle dual nature soon was found to be characteristic of electrons as well.
- The particle properties of electrons was well documented when the DeBroglie hypothesis and the subsequent experiments by Davisson and Germer established the wave nature of the electron.
In this document we will discuss how we will discuss how photoelectric effect proved that particle nature of light.
Key Points of Photoelectric Effect
- Based on the wave model of light, physicists predicted that increasing light amplitude would increase the kinetic energy of emitted photoelectrons, while increasing the frequency would increase measured current.
- Contrary to the predictions, experiments showed that increasing the light frequency increased the kinetic energy of the photoelectrons, and increasing the light amplitude increased the current.
- Based on these findings, Einstein proposed that light behaved like a stream of particles called photons with an energy E = hv.
- The work function,Φ, is the minimum amount of energy required to induce photoemission of electrons from a metal surface, and the value of Φ depends on the metal.
- The energy of the incident photon must be equal to the sum of the metal's work function and the photoelectron kinetic energy: Ephoton = KEelectron + Φ.
Question for Wave-Particle Duality - Quantum Mechanics
Try yourself:The minimum energy required to remove an electron is called
Explanation
Work function is the minimum quantity of energy which is required to remove an electron to infinity from the surface of a given solid, usually a metal.
Report a problem
What is the Photoelectric Effect?
When light shines on a metal, electrons can be ejected from the surface of the metal in a phenomenon known as the photoelectric effect. This process is also often referred to as photoemission, and the electrons that are ejected from the metal are called photoelectrons. In terms of their behavior and their properties, photoelectrons are no different from other electrons. The prefix, photo-, simply tells us that the electrons have been ejected from a metal surface by incident light.
In the photoelectric effect, light waves (red wavy lines) hitting a metal surface cause electrons to be ejected from the metal.
In this document, we will discuss how 19th century physicists attempted (but failed!) to explain the photoelectric effect using classical physics. This ultimately led to the development of the modern description of electromagnetic radiation, which has both wave-like and particle-like properties.
Predictions based on Light as a Wave
To explain the photoelectric effect, 19th-century physicists theorized that the oscillating electric field of the incoming light wave was heating the electrons and causing them to vibrate, eventually freeing them from the metal surface.
This hypothesis was based on the assumption that light traveled purely as a wave through space.
Scientists also believed that the energy of the light wave was proportional to its brightness, which is related to the wave's amplitude.
In order to test their hypotheses, they performed experiments to look at the effect of light amplitude and frequency on the rate of electron ejection, as well as the kinetic energy of the photoelectrons.
Based on the classical description of light as a wave, they made the following predictions:
The kinetic energy of emitted photoelectrons should increase with the light amplitude.
The rate of electron emission, which is proportional to the measured electric current, should increase as the light frequency is increased.
To help us understand why they made these predictions, we can compare a light wave to a water wave. Imagine some beach balls sitting on a dock that extends out into the ocean. The dock represents a metal surface, the beach balls represent electrons, and the ocean waves represent light waves.
If a single large wave were to shake the dock, we would expect the energy from the big wave would send the beach balls flying off the dock with much more kinetic energy compared to a single, small wave. This is also what physicists believed would happen if the light intensity was increased.
Light amplitude was expected to be proportional to the light energy, so higher amplitude light was predicted to result in photoelectrons with more kinetic energy.
Classical physicists also predicted that increasing the frequency of light waves (at a constant amplitude) would increase the rate of electrons being ejected, and thus increase the measured electric current.
Using our beach ball analogy, we would expect waves hitting the dock more frequently would result in more beach balls being knocked off the dock compared to the same sized waves hitting the dock less often.
Now that we know what physicists thought would happen, let's look at what they actually observed experimentally!
When Intuition Fails: Photons to the Rescue!
When experiments were performed to look at the effect of light amplitude and frequency, the following results were observed:
The kinetic energy of photoelectrons increases with light frequency.
Electric current remains constant as light frequency increases.
Electric current increases with light amplitude.
The kinetic energy of photoelectrons remains constant as light amplitude increases.
These results were completely at odds with the predictions based on the classical description of light as a wave! In order to explain what was happening, it turned out that an entirely new model of light was needed. That model was developed by Albert Einstein, who proposed that light sometimes behaved as particles of electromagnetic energy which we now call photons. The energy of a photon could be calculated using Planck's equation:
Ephoton=hν
where \text{E}_{\text{photon}}Ephotonstart text, E, end text, start subscript, start text, p, h, o, t, o, n, end text, end subscript is the energy of a photon in joules (\text{J}Jstart text, J, end text), hhh is Planck's constant (6.626\times10^{-34}\text{ J}\cdot\text{s})(6.626×10-34J⋅s)left parenthesis, 6, point, 626, times, 10, start superscript, minus, 34, end superscript, start text, space, J, end text, dot, start text, s, end text, right parenthesis, and \nuν\nu is the frequency of the light in \text{Hz}Hzstart text, H, z, end text. According to Planck's equation, the energy of a photon is proportional to the frequency of the light, \nuν\nu. The amplitude of the light is then proportional to the number of photons with a given frequency.
Light Frequency and the Threshold Frequency
We can think of the incident light as a stream of photons with an energy determined by the light frequency. When a photon hits the metal surface, the photon's energy is absorbed by an electron in the metal. The graphic below illustrates the relationship between light frequency and the kinetic energy of ejected electrons.
The frequency of red light (left) is less than the threshold frequency of this metal (
νred < νo ) so no electrons are ejected. The green (middle) and blue light (right) have (
ν > νo ) , so both cause photoemission. The higher energy blue light ejects electrons with higher kinetic energy compared to the green light.
The scientists observed that if the incident light had a frequency less than a minimum frequency v0, then no electrons were ejected regardless of the light amplitude. This minimum frequency is also called the threshold frequency, and the value of v0 depends on the metal. For frequencies greater than v0, electrons would be ejected from the metal. Furthermore, the kinetic energy of the photoelectrons was proportional to the light frequency. The relationship between photoelectron kinetic energy and light frequency is shown in graph (a) below.
Isn't there more Math somewhere?
We can analyze the frequency relationship using the law of conservation of energy. The total energy of the incoming photon, Ephoton, must be equal to the kinetic energy of the ejected electron, KEelectron, plus the energy required to eject the electron from the metal. The energy required to free the electron from a particular metal is also called the metal's work function, which is represented by the symbol Φ (in the units of J):
Ephoton = KEphoton + Φ
Like the threshold frequency v0, the value of Φ also changes depending on the metal. We can now write the energy of the photon in terms of the light frequency using Planck's equation:
Ephoton = hv = KEphoton + Φ
Rearranging this equation in terms of the electron's kinetic energy, we get:
We can see that kinetic energy of the photoelectron increases linearly with v as long as the photon energy is greater than the work function Φ , which is exactly the relationship shown in graph (a) above. We can also use this equation to find the photoelectron velocity v, which is related KEelectron as follows:
KEelectron = hv - Φ = 1/2 mev2
where me is the rest mass of an electron, 9.1094 x 10-31 kg.
Question for Wave-Particle Duality - Quantum Mechanics
Try yourself:What is the kinetic energy of the photoelectrons ejected from the copper by the light with a frequency of 3.0 x 1016 Hz?
Explanation
We can calculate the kinetic energy of the photoelectron using the equation that relates kinetic energy to the energy of the photon, and the work function.
Ephoton = KEphoton + Φ
Since we want to know kinetic energy, we can start by rearranging the equation so that we will be solving for the kinetic energy of the electron:
KEphoton = Ephoton - Φ
Now inserting values
KEphoton = (2.0 x 10-17 J) - (7.53 x 10-19 J) = 1.9 x 10-17 J
Therefore, each photoelectron has a kinetic energy of 1.9 x 10-17 J
Report a problem
Exploring the Wave Amplitude trends
In terms of photons, higher amplitude light means more photons hitting the metal surface. This results in more electrons ejected over a given time period. As long as the light frequency is greater than vo, increasing the light amplitude will cause the electron current to increase proportionally as shown in graph (a) below.
Since increasing the light amplitude has no effect on the energy of the incoming photon, the photoelectron kinetic energy remains constant as the light amplitude is increased (see graph (b) above).
If we try to explain this result using our dock-and-beach-balls analogy, the relationship in graph (b) indicates that no matter the height of the wave hitting the dock-−minuswhether it's a tiny swell, or a huge tsunami-−minusthe individual beach balls would be launched off the dock with the exact same speed! Thus, our intuition and analogy don't do a very good job of explaining these particular experiments.
Question for Wave-Particle Duality - Quantum Mechanics
Try yourself:The work function of a substance is 4.0 eV. The longest wavelength of light that can cause photoelectron emission from this substance is approximately
Explanation
Let λm = Longest wavelength of light
(hc/λm) = Φ (work function)
λm= hc/Φ = (6.63 x 10-34) x (3 x108)/(4.0 x1.6 x10-19) = 310 nm
Report a problem
We are going to discuss how interference provides the proof of wave nature of light in this document.
Questions on Photoelectric Effect
Question: The work function of copper metal is Φ = 7.53 x 10-19 J. If we shine light with a frequency of 3.0 x 1016 on copper metal, will the photoelectric effect be observed?
Ans. In order to eject electrons, we need the energy of the photons to be greater than the work function of copper. We can use Planck's equation to calculate the energy of the photon, Ephoton:
Ephoton = hv
= (6.626 x 10-34 J.s) (3.0 x 1016 Hz) plug in values of h = 2.0 x 10-17 J
If we compare our calculated photon energy to copper's work function, we see that the photon energy is greater than Φ.Thus, we would expect to see photoelectrons ejected from the copper.
Question: According to Einstein’s photoelectric equation, the plot of the kinetic energy of the emitted photoelectrons from a metal vs the frequency of the incident radiation gives a straight line whose slope
(a) depends on the nature of the metal used
(b) depends on the intensity of the radiation
(c) depends both on the intensity of the radiation and the metal used
(d) is the same for all metals and independent of the intensity of the radiation.
Ans.
According to Einstein’s equation, Kinetic energy = hv – Φ where kinetic energy and f (frequency) are variables, compare it with the equation, y = mx + c
Therefore, the slope of line = h, h is Planck’s constant.Hence, the slope is the same for all metals and independent of the intensity of radiation.