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Word Problems: Fractions - 3 | Mathematics for Class 5 PDF Download

Q1: Deepa used 5/9 L of milk to prepare kheer. She added 1/2 L more milk to the kheer. How many liters of milk did she use to make the kheer?

Sol: To find the total milk used by Deepa, we add the initial amount to the additional amount.

  • Initial milk used: 5/9 L
  • Additional milk added: 1/2 L

To add these two fractions, we need a common denominator. The least common multiple of 9 and 2 is 18.

  • Convert 5/9 to a denominator of 18: 5/9 × 2/2 = 10/18
  • Convert 1/2 to a denominator of 18: 1/2 × 9/9 = 9/18 

Now, add the two fractions: Word Problems: Fractions - 3 | Mathematics for Class 5
Deepa used 1 1/18 liters of milk for the kheer.

Q2: Babita has 1/3 m of blue ribbon and 1/2 m of red ribbon. How much total ribbon does she have?

Sol: Babita's total ribbon length is the sum of the blue and red ribbons.

  • Blue ribbon: 1/3 m
  • Red ribbon: 1/2 m

To add these, find a common denominator, which is 6.

  • Convert 1/3 to a denominator of 6: 1/3 × 2/2 = 2/6
  • Convert 1/2 to a denominator of 6: 1/2 × 3/3 = 3/6 

Add the two fractions: 2/6 + 3/6 = 5/6
Babita has a total of 5/6 meters of ribbon.

Q3: Neha bought one cabbage weighing 7/9 of a kg and one cauliflower weighing 3/4 of a kg. How many kilograms did the two weigh together?

Sol: To find the total weight of the vegetables, add the weight of the cabbage and the cauliflower.

  • Weight of cabbage: 7/9 kg
  • Weight of cauliflower: 3/4 kg

Find a common denominator, which is 36.

  • Convert 7/9 to a denominator of 36: 7/9 × 4/4 = 28/36
  • Convert 3/4 to a denominator of 36: 3/4 × 9/9 = 27/36

Add the two fractions: Word Problems: Fractions - 3 | Mathematics for Class 5
Neha's vegetables together weigh 1 19/36 kilograms.

Q4: A family eats 11/3 breads at a meal. Will 4 breads be enough for 3 meals?

Sol: To determine if 4 breads are enough for 3 meals, calculate the total bread needed for 3 meals.

  • Bread needed per meal: 11/3
  • Number of meals: 3

Multiply the bread needed per meal by the number of meals: 11/3 ×  3 = 11
Since 11 breads are needed for 3 meals and only 4 breads are available, 4 breads are not enough.

Q5: Deepak spent 3/8 hours studying Hindi and Mathematics. He spent 1/12 of an hour studying Hindi. How long did he spend studying Mathematics?

Sol: Time spent on both subjects (Hindi and Mathematics): 3/8 hour
Time spent on Hindi: 1/12 hour
To find out how much time was spent studying Mathematics, we subtract the time spent on Hindi from the total study time.
Step-by-step calculation:

Convert fractions to have a common denominator.

The Least Common Multiple (LCM) of 8 and 12 is 24.

  • Convert 3/8 to a fraction with a denominator of 24: Word Problems: Fractions - 3 | Mathematics for Class 5
  • Convert 1/12 to a fraction with a denominator of 24: Word Problems: Fractions - 3 | Mathematics for Class 5

Subtract the time spent on Hindi from the total study time: Word Problems: Fractions - 3 | Mathematics for Class 5
Conclusion: Deepak spent 7/24 of an hour studying Mathematics. This fraction represents the difference in time between the total study period and the portion used for Hindi, providing the specific amount dedicated to Mathematics.

Q6: I ate 1/8 of a pizza and my sister ate 3/6 of the pizza. The rest of it was eaten by my brother. How much pizza did my brother eat?

Sol: Pizza eaten by me: 1/8
Pizza eaten by my sister: 3/6
First, we need to convert all fractions to a common denominator to make it easier to add them together. The Least Common Multiple (LCM) of 8 and 6 is 24.
Convert the fractions to have a common denominator (24):

  • Convert 1/8 to a fraction with a denominator of 24: Word Problems: Fractions - 3 | Mathematics for Class 5
  • Convert 3/6 to a fraction with a denominator of 24: Word Problems: Fractions - 3 | Mathematics for Class 5

Add the fractions together to find the total amount of pizza eaten by me and my sister: 3/24 + 12/24 = 15/24
Subtract this total from the whole pizza to find out how much pizza my brother ate: 24/24 - 15/24 = 9/24 
Simplify the fraction (if possible) to find the exact amount my brother ate: Word Problems: Fractions - 3 | Mathematics for Class 5

Conclusion: My brother ate 3/8 of the pizza. This fraction represents the remainder of the pizza after my sister and I had our portions.

Q7: In February 2021 , a school was working only three-fourths of the total number of days in the month and the remaining number of days given as holidays. How many days did the school work in the month of February?

Sol:  The year 2021 is a non-leap year. We know that a non-leap has 28 days in February month. So, the total number of days = 28.
Given, the school was working only three-fourths of the total number of days in the month. The number of days school working in February month = 3/4 of 28.
Word Problems: Fractions - 3 | Mathematics for Class 5
Hence, the school working for 21 days in the month of February for the year 2021.

Q8: An oil container contains Word Problems: Fractions - 3 | Mathematics for Class 5 litres of oil which are poured into Word Problems: Fractions - 3 | Mathematics for Class 5 litres bottles. How many bottles are needed to fill Word Problems: Fractions - 3 | Mathematics for Class 5 litres of oil?

Sol:  Given, a container holds total oil of Word Problems: Fractions - 3 | Mathematics for Class 5 litres, and the total amount held by each bottle is Word Problems: Fractions - 3 | Mathematics for Class 5 litres.
Consider the number of bottles required is x.
From the given question, the total oil in the container is equal to the product of oil in each bottle and the number of bottles required.
Word Problems: Fractions - 3 | Mathematics for Class 5
Therefore, 3 bottles are required to fill the total oil in the container.

Q9: At a party, total 280 ice-creams are prepared. Four-seventh of them is eaten by the children. Find the ice-creams eaten by the children.

Sol: Total ice-creams prepared = 280
Number of ice-creams eaten by children Word Problems: Fractions - 3 | Mathematics for Class 5
Hence, children ate 160 ice-creams.

Q10: Keerthi needs Word Problems: Fractions - 3 | Mathematics for Class 5 cups of sugar for baking a cake. She decided to make 6 cakes for her friends. How many cups of sugar did she need for making the 6 cakes?

Sol:  Given, Keerthi needs Word Problems: Fractions - 3 | Mathematics for Class 5 cup of sugar to make a cake.
The total cups of sugar required to make 6 cakes is calculated by multiplying the sugar needed for one cake with the number of cakes that needs to be prepared by Keerthi and is given by Word Problems: Fractions - 3 | Mathematics for Class 5
Convert the above-mixed fraction to an improper fraction by multiplying the denominator with the whole and add to the numerator keeping the same denominator as
Word Problems: Fractions - 3 | Mathematics for Class 5
The total cups of sugar needed for making 6 cakes Word Problems: Fractions - 3 | Mathematics for Class 5
Hence, Keerthi needs 9 cups of sugar to make 6 cakes.

The document Word Problems: Fractions - 3 | Mathematics for Class 5 is a part of the Class 5 Course Mathematics for Class 5.
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FAQs on Word Problems: Fractions - 3 - Mathematics for Class 5

1. What are some tips for solving word problems involving fractions?
Ans. To solve word problems involving fractions, start by carefully reading the problem to understand what is being asked. Identify the fractions involved and what operations (addition, subtraction, multiplication, division) are needed. It can be helpful to draw diagrams or use visual aids to represent the fractions. Always simplify your fractions where possible and double-check your calculations for accuracy.
2. How can I convert mixed numbers to improper fractions in word problems?
Ans. To convert a mixed number to an improper fraction, first multiply the whole number by the denominator of the fraction part. Then, add the numerator to this product to get the new numerator. The denominator remains the same. For example, to convert 2 3/4 to an improper fraction, calculate (2 × 4) + 3 = 8 + 3 = 11, so it becomes 11/4.
3. What is the best way to add or subtract fractions in word problems?
Ans. When adding or subtracting fractions, first ensure the fractions have a common denominator. If they don't, find the least common denominator (LCD) and convert each fraction accordingly. Once they have the same denominator, you can simply add or subtract the numerators while keeping the denominator the same. Finally, simplify the resulting fraction if possible.
4. How do I handle fractions in multiplication and division word problems?
Ans. In multiplication word problems, simply multiply the numerators together and the denominators together. For example, to multiply 1/2 by 3/4, you would calculate (1 × 3) / (2 × 4) = 3/8. In division, remember to multiply by the reciprocal of the fraction you are dividing by. For example, dividing 1/2 by 3/4 means multiplying 1/2 by 4/3, resulting in (1 × 4) / (2 × 3) = 4/6, which simplifies to 2/3.
5. What should I do if I encounter a complex word problem involving multiple fractions?
Ans. For complex word problems involving multiple fractions, break the problem down into smaller parts. Identify each fraction and the operations required. Work through the problem step by step, addressing one fraction or operation at a time. Keep track of your calculations and simplify fractions as you go. If necessary, write down intermediate steps to avoid confusion. Solving the problem in parts will help clarify the overall solution.
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