Class 4 Maths - Addition and Subtraction - CBSE Worksheets Solutions

Q1: Arrange in columns and add:
(a) 215, 340 and 100
(b) 321, 436 and 157

Sol: (a) 215, 340 and 100
= 215 + 340 + 100 = 650
(b) 321, 436 and 157
= 321 + 436 + 157 = 914

Q2:  Add:
(a) 

(b)  

(c)

Sol: (a) 2572 + 4325 = 6897
(b) 1635 + 2146 + 5214 = 8989

(c) 1361 + 4527 + 3010 = 8904
Q3: Fill in thewith the correct digits:

(a) 

(b) 

Sol: (a) = The missing numbers are 8724, 0142, 1013.
(b) The missing numbers are 3057, 5610, 1202.

Q4: Monika had Rs 2,183 in her bank account. She again deposited Rs 1,345. What is the amount in Monika's bank account now?
Sol: Amount of money Monika had in the bank = Rs 2,183
Amount Monika deposited in the bank again = Rs 1,345.
Total amount submitted by Monika = Rs. (2183 + 1345) = Rs. 3528

Q5: Arrange in columns and find the sum:
(a) 2,751 + 3,201 + 536
(b) 205 + 6,879 + 2,752
(c) 5196 + 2,861 + 1,674

Sol: (a) 2,751 + 3,201 + 536 = 6488
(b) 205 + 6,879 + 2,752 = 9836

(c) 5196 + 2,861 + 1,674 = 9731

Q6: 
Sol:


Q7: 
Sol:

Q8: Fill in the blanks:
(a) ______+ 2,432 = 2,432 + ______= 2,432
(b) 1,937 + 3,132 = 3,132 + ______.
Sol:
(a) 0 + 2,432 = 2,432 + 0 = 2,432 (Since zero added to any number is the number itself)
(b) 1,937 + 3,132 = 3,132 + 1937  (By using the commutative property of addition which  is a fundamental property in maths that states that the order in which you add two numbers does not affect the sum.)

Q9: In an examination, 6,381 boys and 2,954 girls appeared. How many students in all appeared for the examination?
Sol: Number of boys who appeared for exam = 6381
Number of girls who appeared for exam = 2954
Total number of students = 9335

Q10: At a meeting addressed by a political leader, there were 2,649 men 3,259 women and 837 children. How many people were present at the meeting?
Sol: Number of men = 2649
Number of women = 3259
Number of children = 837
Total number of people at the meeting = 2649  + 3259 + 837

Therefore, total number of people present in the meeting = 6745
Q11: Subtract:

(a)
(b)
Sol: (a)  400 - 321 = 79

(b) 591 - 360 = 231

Q12: Find the difference between :
(a) 153 and 256
(b) 781 and 651
Sol:
(a) 153 and 256 = 256 - 153 = 103
(b) 781 and 651 = 781 - 651 = 130

Q13: Fill in the boxes:
(a)

(b)
Sol: (a) The missing numbers are 8617, 4223.
(b) The missing numbers are 6328, 2725, 3603.

Q14: Fill in the blanks:
(a) 6,821 - 10 = ______.
(b) 491 - 10 = ______.
(c) 9,386- 100  ______.
Sol:
(a) 6,821 - 10 = 6811.
(b) 491 - 10 = 481.
(c) 9,386- 100  = 9286.

Q15: In the year 2010, a poultry farm produced 6,134 eggs. In 2011, it produced 1,785 eggs less than that in 2010. How many eggs were produced in 2011?
Sol: Number of eggs produced by poultry farm in 2010 = 6134
Number of eggs produced in 2011 = Number of eggs produced in 2010 = 6134 - 1785
Therefore, Eggs produced in 2011 = 4349

Q16: What must be added to 2,176 to get 5, 158?
Sol: To know which number should be added to 2176 to get 5158, we have to subtract the two numbers = 5158 - 2176 = 2982 should be added to 2176 to get 5158
Q17: In an examination, 8380 candidates appeared. Out of these, 4,090 candidates failed. How many candidates passed?
Sol: Number of candidates appeared = 8380
Number of candidates failed = 4090
Number of candidates passed = 8380 - 4090 = 4290

Q18: Last year, a cycle factory produced 8,319 cycles. This year the production came down by 5, 761 cycles. What is the production this year?


Sol: Last year, a cycle factory produced = 8319
This year a cycle factory produced less by = 5761
The production this year = 2558 cycles

Q19: To find the difference between two numbers, we always subtract the ______ number from the ______ number.

Sol: To find the difference between two numbers, we always subtract the greater number from the smaller number.

Q20: I am a 5 digit number. My tens digit is 2. My ones and hundreds digit is twice the tens digit. My thousands digit is one subtracted from the product of the ones and tens digit. My ten thousands digit is the difference between the thousands and the tens digit. What number am 'I'?

Sol: 

Tens digit = 2

∴

Ones digit = 2×2=4

Hundreds digit = 2×2=4

Thousands digit = (2×4) - 1= 7

Ten thousands digit = 7-2 = 5

Step 2:

∴

The number is

TTh Th H T O

5 7 4 2 4