Worksheet Solutions: Animal Jumps | Mathematics (Maths Mela) Class 5 - New NCERT PDF Download

Multiple Choice Questions (MCQs)

Q1. Which of the following is a factor of 24?
(a) 5
(b) 6
(c) 7
(d) 9
Ans: (b) 6

• Factors are numbers that divide a number exactly.

• 6 × 4 = 24 → so, 6 is a factor of 24.

Q2. The smallest multiple of any number is:
(a) 0
(b) 1
(c) The number itself
(d) 2
Ans: (c) The number itself

• Multiples are obtained by multiplying the number with whole numbers (0,1,2,3,…).

• The smallest multiple is the number itself (not 0, because 0 is a multiple of all numbers but not considered here in such questions).

Q3. Which of the following is a multiple of 7?
(a) 21
(b) 22
(c) 23
(d) 25
Ans: (a) 21

• Multiples of 7 → 7, 14, 21, 28, …

• 21 is in the list.

Q4. How many factors does 12 have?
(a) 4
(b) 6
(c) 8
(d) 5
Ans: (b) 6

• Factors of 12 → 1, 2, 3, 4, 6, 12

• Total = 6 factors.

Q5. Which of the following numbers is a common factor of 18 and 24?
(a) 3
(b) 4
(c) 5
(d) 7
Ans: (a) 3

• Factors of 18 → 1, 2, 3, 6, 9, 18

• Factors of 24 → 1, 2, 3, 4, 6, 8, 12, 24

• Common factors → 1, 2, 3, 6

• From the options, (a) is correct.

Q6. Which of the following numbers is NOT a multiple of 9?
(a) 18
(b) 27
(c) 35
(d) 36
Ans: (c) 35

• Multiples of 9 → 9, 18, 27, 36, …

• 35 is not in this list.

Q7. A number that has exactly two factors is called a:
(a) Prime number
(b) Composite number
(c) Even number
(d) Odd number
Ans: (a) Prime number

• Prime numbers have exactly 2 factors: 1 and the number itself.

• Composite numbers have more than 2 factors.

Q8. What is the greatest common factor (GCF) of 12 and 16?
(a) 2
(b) 3
(c) 4
(d) 6
Ans: (c) 4

• Factors of 12 → 1, 2, 3, 4, 6, 12

• Factors of 16 → 1, 2, 4, 8, 16

• Common factors → 1, 2, 4

• Greatest = 4

Q9. The least common multiple (LCM) of 4 and 6 is:
(a)12
(b) 24
(c) 10
(d) 8
Ans: (a) 12

• Multiples of 4 → 4, 8, 12, 16, 20, 24…

• Multiples of 6 → 6, 12, 18, 24…

• Smallest common multiple = 12

Q10. Which of the following is a factor of every number?
(a) 0
(b) 1
(c) 2
(d) The number itself
Ans: (b) 1

• 1 divides every number exactly.

• 0 is not a factor of any number.

Fill in the Blanks

Q1. Factors of 20 are ________, ________, ________, ________, ________.
Ans: 1, 2, 4, 5, 10, 20

Q2. Multiples of 5 are ________, ________, ________, ________.
Ans: 5, 10, 15, 20

Q3. The smallest prime number is ________.
Ans: 2

Q4. Common factors of 12 and 18 are ________, ________, ________.
Ans: 1, 2, 3, 6

Q5. LCM of 3 and 4 is ________.
Ans: 12

Q6. 1 is a factor of every ________.
Ans: number

Q7. The number 15 has ________ factors.
Ans: 4 (1, 3, 5, 15)

Q8. Multiples of 7 up to 50 are ________, ________, ________, ________, ________, ________.
Ans: 7, 14, 21, 28, 35, 42, 49

Answer the Following 

Q1: In a sports day event, students are lined up in rows of 6, 9, or 18. What is the smallest number of students that can be arranged in this way?

Sol: To determine the smallest number of students that can be arranged in rows of 6, 9, or 18, we need to calculate the Least Common Multiple (LCM) of the numbers 6, 9, and 18.
Prime factors:

• 6 = 2 × 3
• 9 = 3 × 3
• 18 = 2 × 3 × 3

Common factors and multiplication:

• Common factors = 2, 3 × 3
• Multiply all common factors: 2 × 3 × 3 = 18

Therefore, the smallest number of students is 18.

Q2: A baker has cookies that he wants to pack in boxes of 7, 14, or 21 cookies. What is the least number of cookies he needs to ensure there are no cookies left out?

Sol: To ensure no cookies are left out when packed in boxes of 7, 14, or 21, we find the LCM of these numbers.
Prime factors:

• 7 = 7
• 14 = 2 × 7
• 21 = 3 × 7

Common factors and multiplication:

The LCM takes the highest powers of all prime numbers involved: 2 × 3 × 7 = 42

Therefore, the baker needs at least 42 cookies.

Q3: At a community picnic, the organizers want to divide the attendees into groups of 4, 6, or 8 evenly. What is the minimum number of attendees needed?

Sol: To find the minimum number of attendees that can be divided evenly into groups of 4, 6, or 8, we calculate the LCM of these numbers.
Prime factors:

• 4 = 2 × 2
• 6 = 2 × 3
• 8 = 2 × 2 × 2

Common factors and multiplication:

Use the highest powers: 2³ and 3¹ → LCM = 8 × 3 = 24

Therefore, at least 24 attendees are needed.

Q4: A classroom has students who need to be arranged in rows of 10, 20, or 25 for a group photo. What is the least number of students that should be present?

Sol: To find the least number of students that can be arranged in rows of 10, 20, or 25, we look for the LCM.
Prime factors:

• 10 = 2 × 5
• 20 = 2 × 2 × 5
• 25 = 5 × 5

Common factors and multiplication:

Highest powers: 2² (from 20), 5² (from 25)
 →  LCM = 100

Therefore, at least 100 students should be present.

Q5: A musical concert is organized where the audience must be seated in sections of 15, 30, or 45. How many minimum seats should be available?

Sol: To find the minimum number of seats, calculate the LCM of 15, 30, and 45.
Prime factors:

• 15 = 3 × 5
• 30 = 2 × 3 × 5
• 45 = 3 × 3 × 5

Common factors and multiplication:

Highest powers of all primes: 2¹, 3², 5¹ → LCM = 90

Therefore, at least 90 seats should be available. These solutions use the factorization method to find the LCM, ensuring that students can understand the process through basic multiplication of common prime factors.