Class 9 Exam  >  Class 9 Notes  >  Mathematics (Maths) Class 9  >  Worksheet Solutions: Heron’s Formula

Heron’s Formula Class 9 Worksheet Maths Chapter 10

Multiple Choice Questions

Q1: The difference between sides at right angles in a right angled triangle is 14 cm. The area of the triangle is 120 cm2. The perimeter of the triangle is
(a) 80
(b) 45
(c) 60
(d) 64
Ans: 
(c)

Let y be one of the at right angle ,then another side will be y-14
Now we know that
A = (1/2)BH
120 = (1/2)y(y - 14)
y- 14y - 240
(y - 24)(y + 10) = 0
y = 24
So other side is 10
From pythogrous theorem
Heron’s Formula Class 9 Worksheet Maths Chapter 10
So perimeter will be =10+24+26=60 cm

Q2: ABCD is a trapezium with AB  = 10cm, AD = 5 cm, BC = 4 cm and DC = 7 cm?
Heron’s Formula Class 9 Worksheet Maths Chapter 10Find the area of the ABCD
(a) 34 cm2
(b) 28cm2
(c) 20 cm2
(d) None of these
Ans:
(a)

BC is the altitude between the two parallel sides AB and DC
So Area of trapezium will be given by
Heron’s Formula Class 9 Worksheet Maths Chapter 10

Q3: Find the area and perimeter of the right angle triangle whose hypotenuse is 5 cm and Base is 4 cm
(a) 6 cm2 ,12 cm
(b) 12 cm2 ,14 cm
(c) 4 cm2, 6 cm
(d) 12 cm2 ,6 cm
Ans:
(a)

By pythogorous theorem
Heron’s Formula Class 9 Worksheet Maths Chapter 10
So Area =(1/2) XBase X height = 6 cm2
Perimeter = 5 + 4 + 3 = 12 cm

Q4: In an isosceles triangle ?ABC with AB = AC = 13 cm. D is mid point on BC. Also BC=10 cm
Which of the following is true?
(a) Area of Triangle ABD and ADC are equal
(b) Area of triangle ABD is 30 cm2
(c) Area of triangle ABC is 60 cm2
(d) All the above
Ans: 
(d)

ABD an ADC are congruent triangle, So Area of Triangle ABD and ADC are equal
Also From pythogorous theorem, AD will be given as
Heron’s Formula Class 9 Worksheet Maths Chapter 10
So Area of triangle ABC = (1/2)X base X height = 60 cm2

Q5: A triangle and a parallelogram have the same base and the same area. The sides of the triangle are 26 cm and 30 cm and parallelogram stands on the base 28 cm. calculate the height of the parallelogram
(a) 12 cm
(b) 14 cm
(c) 10cm
(d) 13 cm
Ans:
(a)

For triangle, all the sides are given, calculating the area using Heron formula
A = 336 cm2
Now for parallelogram, Area is given by
A = Base X Altitude
336 = 28 X H
Or H = 12 cm

True / False

Q1: Heron formula for area of triangle is not valid of all triangles
Ans: 
False

Q2: If each side of the triangles is tripled, the area will becomes 9 times.
Ans: 
True

Q3: Base and corresponding altitude of the parallelogram are 8 and 5 cm respectively. Area of parallelogram is 40 cm2.
Ans: 
True

Q4: If each side of triangle is doubled, the perimeter will become 4 times.
Ans: False

Q5: If p is the perimeter of the triangle of sides a,b,c ,the area of triangle is.
Heron’s Formula Class 9 Worksheet Maths Chapter 10
Ans: 
True

Q6: When two triangles are congruent, there areas are same.
Ans
True

Q7: Heron’s belongs to America.
Ans:
False

Q8:  If the side of the equilateral triangle is a rational number, the area would always be irrational number.
Ans:
 True

Concepts Questions

Q1: Find the area of a triangle having sides as a=5 cm ,b=4 cm,c=3 cm.
Ans: Heron’s Formula Class 9 Worksheet Maths Chapter 10
Area Heron’s Formula Class 9 Worksheet Maths Chapter 10

Q2: Find the area of an quilateral triangle having side a=2 cm
Ans: Area of equilateral
Heron’s Formula Class 9 Worksheet Maths Chapter 10

Q3: Find the area of a right angle triangle have base=4 cm and Height =3 cm
Ans: Area of triangle
A = (1/2)BH = 6cm2

Q4: Find the area of a Parallelogram whose two sides are 10 cm and 16 cm and diagonal is 14 cm.
Ans: In parallelogram whose two sides and diagonal are given, Area is given by
Heron’s Formula Class 9 Worksheet Maths Chapter 10
Where Heron’s Formula Class 9 Worksheet Maths Chapter 10
So s=20cm
So A=80(3)1/2cm2

Q5: Rhombus of diagonals to 10 and 24 cm. Find its area.
Ans: Area is given by
A=(1/2)d1d= 120cm2

The document Heron’s Formula Class 9 Worksheet Maths Chapter 10 is a part of the Class 9 Course Mathematics (Maths) Class 9.
All you need of Class 9 at this link: Class 9
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FAQs on Heron’s Formula Class 9 Worksheet Maths Chapter 10

1. What is Heron's Formula and how is it used to calculate the area of a triangle?
Ans.Heron's Formula is a mathematical formula used to find the area of a triangle when the lengths of all three sides are known. The formula is given by: Area = √(s(s-a)(s-b)(s-c)), where s is the semi-perimeter of the triangle, calculated as s = (a + b + c) / 2, and a, b, and c are the lengths of the triangle's sides.
2. Can Heron's Formula be applied to any type of triangle?
Ans.Yes, Heron's Formula can be applied to any type of triangle, whether it is scalene, isosceles, or equilateral, as long as the lengths of all three sides are known.
3. How do you derive the semi-perimeter in Heron's Formula?
Ans.The semi-perimeter (s) in Heron's Formula is derived by adding the lengths of the three sides of the triangle and then dividing by 2. The formula is: s = (a + b + c) / 2, where a, b, and c are the lengths of the triangle's sides.
4. What are some practical applications of Heron's Formula?
Ans.Heron's Formula is used in various practical applications, including land surveying, architecture, and construction, where it is necessary to calculate the area of triangular plots of land or building foundations without measuring the height.
5. Are there any limitations or restrictions when using Heron's Formula?
Ans.The main limitation of Heron's Formula is that it requires the lengths of all three sides of the triangle to be known. Additionally, the triangle must satisfy the triangle inequality theorem, meaning the sum of the lengths of any two sides must be greater than the length of the third side.
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