Letters For Digits Problems: Addition Video Lecture - Class 8

hello friends this video on playing with
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example calm no more fear from exam let
us look at another interesting this
pattern where you open have dated four
digit so what do we mean by metal for
education
look at this perm see here a cutie
instead of numbers at certain places you
have letters for example a D so these
are the letters and it is a kind of
person then you need to replace these
letters with the appropriate digit now
looks difficult when you see this but we
will actually learn the clicks how to
solve these kind of puzzle
now there are a few rules that need to
be set in in case of a person first rule
is each letter in the puzzle must stand
for just one digit for example if you
talk about a a can stand for any digit a
single digit one three zero five nine
seven anything but it can never stand
for the same digits for which D stands
for
let's say it be dance for to a cannot
stand for to so a and B cannot stand for
the same number taking each digit must
be represented by just one little so if
you are representing one digit so if you
are trying to represent something like -
so you should use only one measure like
a or B if you are representing a number
like 23
then you should represent equals a be
equal to digits so one digits one letter
or one letter one widget so a and O we
cannot represent 10 or 125 or what will
be 0 it can only represent one digit the
first digit of a number cannot be 0 for
example as we all know that two can be
written as zero to let a in an set in
mathematics we can write 2 as below 2
because 2 and 0 to mean the same but but
when you are dealing with these kind of
puzzles you are not supposed to write a
letter
which would represent zero before a
number for example if you have diluted
so let's say for two you are I think be
take the level sign to write B that is
present too but if you write something
like let's see a to where you see a is
zero that is not allowed
basically you should not write video
before a number the first digit of a
knuckle cannot be zero so that is a
simple rule so for example here in this
case you are T 2 so this B cannot be 0 2
has to be written as 2 and not else 0 to
2 in a similarly you can have addition
as well as multiplication puzzles where
some of the numbers sum of the digits
are replaced with letters and you need
to actually find out what what are the
values of each of those letters so let
us fall deal with Eddie hence so we take
this example and you see how to be false
being kind of fun so first we focus on
the digits active units later so these
are the digits from the user space so
let us focus on this particular column
so here is what we have to solve here we
see that 8 plus 5 is equal to 2 so that
is what this particular columns 10 Plus
8 plus 5 is equal to 2 now what should
be the value of a such that a plus 5 is
equal to 2 not exactly - but the sum of
a and Phi should be a number whose unit
digit is 2 that is what our aim is
so let's do some Dipendra so 5 is fixed
what would happen we add 0 to 5 you be
excited we have want to fight we get it
2 to 5 we get pregnant
3 to 5 digit 8 4 to 5 3 8 9 5 Plus 5 is
10 6 plus 5 is 11 7 plus 5 is 12 8 plus
5 is 13 and 9
- in putting these are all possible
values of a technic a can be any digits
from 0 to 9 so if you add these this is
the sum that you get so do you see any
that some that are you with digital -
yes here you can see unit digital - so
that means 7 could be a possibility for
a so the value of 8 could be 7 next to
be at least get what it could be so this
was our first step now in the second
step what we do we put a is equal to 7
in this problem and see what happens
which is T 7 to 5 plus B 2 so this is B
now 7 plus 5 is 12 so you have 1 and
carry forward the 3 plus 2 is 5 plus 1
stand forward that is C so therefore B
has to be C so therefore in this problem
a is equal to 7 and B is equal to 6 so
basically this is the approach that we
follow to solve the addition problems
always focus on the unit's place digit
first so a new tank once you can get
some of the values for the utilities
later then you can move on to those
other measures let us try few more
problems let's look at this one a 1 plus
1 B is equal to B 0 taken as I discussed
we will first focus on the digits at the
unit scale so our state 150 units place
which is 1 plus B is equal to 0 so what
could be the value of B such that 1 plus
B will result in something whose unit
weight is 0 let us quickly know you do
not really need to ready to this you can
just think about it in your mind so 1
plus 0 is 1 1 plus 1 is
one plus three is 1 plus 2 is 3
one plus three is four so in a similar
way you will gradually reach at a point
where the sound would be pain and if
that would happen only then the value P
is nice
so therefore 9 could be a possible value
of B so in next step what do we do we
put B is equal to 9 then what do we get
we get a 1 1 9 bit and if that is right
also this B will also be 9 because b b
they have to represent the strain gauges
- this would be 9 0 so now let's do the
term so 9 plus 1 is 10 0 is here and
final carry forward so one is carry
forward so now you have to do one a plus
one plus the steady forward one so
basically K + 2 should be equal to 9 so
therefore basically a plus 1 plus 1 this
one is the carry forward 1 this should
be equal to 9 so you can take a plus 2
should be equal to 9 therefore a is
equal to 9 9 X to the 7th there
therefore in this problem we can't
really be what is present and B is equal
to 9 let's look at the next line of
figures you have three digit numbers but
our process will still remain the same
so we will first start with a huge place
so our first step would be leading with
regular space which is B plus 1 is equal
to 8 so what do you need to add to 1 so
that you get 8 so if you look at the
same table you can say that you will
come across and after that you wicked 8
and in fact if what are you going to add
2 months you will add 7 so 7 could be a
possibility in this problem so therefore
what we do in step number two we put B
is equal to 7 now when we put B is equal
to 7 we get to a 7
seven one the result is seven one eight
so in this case UT 7 plus 1 is 8 now a
plus 7 should be equal to 1 now let's
move on to the middle column let's focus
on this column so after this one and 8
plus 7 should be equal to 1 so what is
that value which should be added to 7 so
that you get an alert with units latest
one let's try it out 1 plus 7 57 2 plus
7 would be 9 1 plus 7 would be 8 2 plus
7 would be 9 3 plus 7 would be 10 4 plus
7 booty 11 5 plus 7 good defense so you
see here you have one particular case so
that means the value of
es4 could be one possibility right so
therefore in step number three we put a
is equal to four now let's put a equal
to 4 so this will be 2 4 and he was
already 7 2 3 2 4 7 1 let's add 3 2 so
this is 8 this is 1 this is 7 so we see
this absolutely fit here so therefore in
this problem the value of K is 4 and the
value of B is 7
let us now look at the third problem
which is a plus a plus B is equal to B a
now this looks interesting isn't it so
here you have 3a which when added gives
another a so you are continue to find
out the digit which when added to it
went for three times the desired we have
the same rigid in its unity so let us
try it out with different digits
something like 0 plus 0 plus 0 gives you
0 0 actually satisfies this condition
then 1 plus 1 plus 1 gives you 3 so 1
doesn't satisfy the condition 2 plus 2
plus 2 gives you 6 3 plus 3 plus 3 gives
you 9 4 plus 4 plus
this is 12 5 plus 5 plus 5 gives you 16
6 plus 6 plus 6 gives you gives you 18
the beginni then you add the same number
for 3 times you are actually multiplying
that number with 3 so it is an to
delighting the table of 3 3 1 2 3 2 to
the 6 it is an is equal to 12 3 Hydra
sustain please is there anything now
which digit do you think satisfies this
condition so 1 is 0 and the other one
else sighs these are the two digits
which satisfies this condition so we
have two possibilities one possibility
is we can put a is equal to 0 so let us
try that out so let us make some space
here so the first possibility is put a
is equal to 0 so when you put a is equal
to 0 this becomes 0 plus 0 plus 0 which
is 0 here so then what is the point of
having B so we also have a be here so in
this case if a is 0 in fact if there is
no point of having D so that means a is
equal to 0 is not the correct relation a
is equal to 0 is not possible because we
also need to have some value of D which
is not 0 because we know that any number
cannot have 0 as the first digit so this
is not possible
so what are we left with so we are left
with the second possibility that is put
a is equal to 5 now when you put a equal
to 5 it becomes 5 plus 5 plus sign so
what is that it is 15 right so this
means that I know of a is 5 and the
value of D is 1 so therefore a is equal
to 5 and B is equal to 1 now I am
writing all of these just to explain you
because you are learning it for the
first time but in nearly examination or
alienated you are solving it you do not
need to get it all over you
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