Class 8 Exam  >  Class 8 Notes  >  RD Sharma Solutions for Class 8 Mathematics  >  RD Sharma Solutions - Chapter 14 - Compound Interest (Part - 1), Class 8, Maths

Chapter 14 - Compound Interest (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics PDF Download

PAGE NO 14.4:

Question 1:

Find the compound interest when principal = Rs 3000, rate = 5% per annum and time = 2 years.

ANSWER:

Principal for the first year = Rs 3,000

Interest for the first year = RsChapter 14 - Compound Interest (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

= Rs 150

Amount at the end of the first year = Rs 3,000 + Rs 150                                                            

= Rs 3,150

Principal for the second year = Rs 3,150

Interest for the second year = RsChapter 14 - Compound Interest (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

= Rs 157.50

Amount at the end of the second year = Rs 3,150 + Rs 157.50                                                                   

= Rs 3307.50

∴ Compound interest = Rs(3,307.50 − 3,000)                                       

= Rs 307.50

PAGE NO 14.4:

Question 2:

What will be the compound interest on Rs 4000 in two years when rate of interest is 5% per annum?

ANSWER:

We know that amount A at the end of n years at the rate of R% per annum is given by A = P(1 + R/100)n.

Given:P = Rs 4,000

R = 5% p.a.

n = 2 years

Now,A = 4,000(1 + 5/100)²

= 4,000(1.05)²

= Rs 4,410

And,CI = A − P

= Rs 4,410 − Rs 4,000

= Rs 410

PAGE NO 14.4:

Question 3:

Rohit deposited Rs 8000 with a finance company for 3 years at an interest of 15% per annum. What is the compound interest that Rohit gets after 3 years?

ANSWER:

We know that amount A at the end of n years at the rate of R% per annum is given by A = P(1 + R/100)n.

Given:P = Rs 8,000

R = 15% p.a.

n = 3 years

Now,A = 8,000(1 + 15/100)³

= 8,000(1.15)³

= Rs 12,167

And,CI = A − P

= Rs 12,167 − Rs 8,000

= Rs 4,167

PAGE NO 14.4:

Question 4:

Find the compound interest on Rs 1000 at the rate of 8% per annum for 1.5 years when interest is compounded half-yearly.

ANSWER:

Given:P = Rs 1,000

R = 8% p.a.

n = 1.5 years

We know that:A = P(1 + R/200)²n

= 1,000(1 + 8/200)³

= 1,000(1.04)³

= Rs 1,124.86

Now,CI = A − P

= Rs 1,124.86 − Rs 1,000

= Rs 124.86

PAGE NO 14.4:

Question 5:

Find the compound interest on Rs 160000 for one year at the rate of 20% per annum, if the interest is compounded quarterly.

ANSWER:

Given:P = Rs 16,000

R = 20% p.a.

n = 1 year

We know that:A = P(1 + R/400)4n 

= 16,000(1 + 20/400)4

= 16,000(1.05)4

= Rs 19,448.1

Now,CI = A − P

= Rs 19,448.1 − Rs 16,000

= Rs 3,448.1

PAGE NO 14.5:

Question 6:

Swati took a loan of Rs 16000 against her insurance policy at the rate of 12.5% per annum. Calculate the total compound interest payable by Swati after 3 years.

ANSWER:

Given:P = Rs 16,000

R = 12.5% p.a.

n = 3 years

We know that:A = P(1 + R/100)n

= 16,000(1 + 12.5/100)³

= 16,000(1.125)³ = Rs 22,781.25

Now, CI = A − P

= Rs 22,781.25 − Rs 16,000

= Rs 6,781.25

PAGE NO 14.5:

Question 7:

Roma borrowed Rs 64000 from a bank for 1.5 years at the rate of 10% per annum. Compute the total compound interest payable by Roma after 1.5 years, if the interest is compounded half-yearly.

ANSWER:

Given:P = Rs 64,000

R = 10% p.a.

n = 1.5 years

Amount after n years:

A = P(1 + R/200)²

= 64,000(1 + 10/200)³

= 64,000(1.05)³

= Rs 74,088

Now,CI = A − P

= Rs 74,088 − Rs 64,000

= Rs 10,088

PAGE NO 14.5:

Question 8:

Mewa Lal borrowed Rs 20000 from his friend Rooplal at 18% per annum simple interest. He lent it to Rampal at the same rate but compounded annually. Find his gain after 2 years.

ANSWER:

SI for Mewa Lal = PRT/100

Chapter 14 - Compound Interest (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

 = Rs 7,200

Thus, he has to pay Rs 7,200 as interest after borrowing.

CI for Mewa Lal  =  A − P

= 20,000(1 + 18/100)² − 20,000

= 20,000(1.18)² − 20,000

= 27,848 − 20,000

= Rs 7,848

He gained Rs 7,848  as interest after lending.    

His gain in the whole transaction = Rs 7,848 − Rs 7,200                                                          

= Rs 648

PAGE NO 14.5:

Question 9:

Find the compound interest on Rs 8000 for 9 months at 20% per annum compounded quarterly.

ANSWER:

P = Rs 8,000

T = 9 months = 3 quarters

R = 20% per annum = 5% per quarter

A = 8,000(1 + 5/100)³

= 8,000(1.05)³

= 9,261

The required amount is Rs 9,261.

Now,CI = A − P

= Rs 9,261 − Rs 8,000

= Rs 1,261

PAGE NO 14.5:

Question 10:

Find the compound interest at the rate of 10% per annum for two years on that principal which in two years at the rate of 10% per annum gives Rs 200 as simple interest.

ANSWER: 

SI = PRT100

Chapter 14 - Compound Interest (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Rs 1,000

A = P(1 + R/100)

= 1,000(1 + 10/100)²

= 1,000(1.10)² = Rs 1,210

Now,CI = A − P

= Rs 1,210 − Rs 1,000

= Rs 210

PAGE NO 14.5:

Question 11:

Find the compound interest on Rs 64000 for 1 year at the rate of 10% per annum compounded quarterly.

ANSWER:

To calculate the interest compounded quarterly, we have:

A = P(1 + R/400)4n 

= 64,000(1 + 10/400)4×1

= 64,000(1.025)

= 70,644.03

Thus, the required amount is Rs 70,644.03.

Now,CI = A − P

= Rs 70,644.025 − Rs 64,000

= Rs 6,644.03

PAGE NO 14.5:

Question 12:

Ramesh deposited Rs 7500 in a bank which pays him 12% interest per annum compounded quarterly. What is the amount which he receives after 9 months.

ANSWER:

Given:P = Rs 7,500

R = 12% p.a. = 3% quarterly

T = 9 months = 3 quarters

We know that:A = P(1 + R/100)n

A = 7,500(1 + 3/100)³

= 7,500(1.03)³ = 8,195.45

Thus, the required amount is Rs 8,195.45.

PAGE NO 14.5:

Question 13:

Anil borrowed a sum of Rs 9600 to install a handpump in his dairy. If the rate of interest is 5.5% per annum compounded annually, determine the compound interest which Anil will have to pay after 3 years.

ANSWER:

A = P(1 + R/100)

= 9,600(1 + 5.5/100)³

= 9,600(1.055)³ = Rs 11,272.72

Now,CI = A − P

= Rs 11,272.72 − Rs 9,600

= Rs 1,672.72

PAGE NO 14.5:

Question 14:

Surabhi borrowed a sum of Rs 12000 from a finance company to purchase a refrigerator. If the rate of interest is 5% per annum compounded annually, calculate the compound interest that Surabhi has to pay to the company after 3 years.

ANSWER:

A = P(1 + R/100)

= 12,000(1 + 5/100)³

= 12,000(1.05)³ = 13,891.50

Thus, the required amount is Rs 13,891.50.

Now,CI = A − P

= Rs 13,891.50 − Rs 12,000

= Rs 1,891.50

PAGE NO 14.5:

Question 15:

Daljit received a sum of Rs. 40000 as a loan from a finance company. If the rate of interest is 7% per annum compounded annually, calculate the compound interest that Daljit pays after 2 years.

ANSWER:

A = P(1 + R/100)n

= 40,000(1 + 7/100)²

= 40,000(1.07)²

= 45,796

Thus, the required amount is Rs 45,796.

Now,CI = A − P

= Rs 45,796 − Rs 40,000

= Rs 5,796

The document Chapter 14 - Compound Interest (Part - 1), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics is a part of the Class 8 Course RD Sharma Solutions for Class 8 Mathematics.
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FAQs on Chapter 14 - Compound Interest (Part - 1), Class 8, Maths RD Sharma Solutions - RD Sharma Solutions for Class 8 Mathematics

1. What is compound interest and how is it different from simple interest?
Ans. Compound interest is the interest earned not only on the principal amount but also on the accumulated interest from previous periods. It is calculated based on the principal amount, the interest rate, and the time period. On the other hand, simple interest is calculated only on the principal amount. Compound interest generally yields higher returns compared to simple interest.
2. How is compound interest calculated?
Ans. Compound interest is calculated using the formula: A = P(1 + r/n)^(nt), where A is the final amount, P is the principal amount, r is the rate of interest, n is the number of times interest is compounded per year, and t is the time period in years. By substituting the values in this formula, we can calculate the compound interest.
3. Can you provide an example to understand compound interest better?
Ans. Sure! Let's say you invest $1000 in a fixed deposit account that offers a compound interest rate of 5% per annum, compounded annually. After 2 years, the compound interest can be calculated as follows: A = 1000(1 + 0.05/1)^(1*2) = 1000(1.05)^2 = 1102.50 So, the compound interest earned in 2 years would be $102.50.
4. How does the frequency of compounding affect compound interest?
Ans. The frequency of compounding refers to how often the interest is added to the principal amount. The more frequently the interest is compounded, the higher the compound interest. For example, if the interest is compounded annually, the compound interest will be lower compared to compounding semi-annually or quarterly. The formula for compound interest remains the same, but the value of 'n' (number of times interest is compounded per year) will change accordingly.
5. Is compound interest always beneficial?
Ans. Compound interest is generally beneficial for investments or savings as it allows the amount to grow exponentially over time. However, it can also work against you if you have loans or debts that accumulate compound interest. In such cases, the interest can quickly add up, making it harder to repay the debt. It is important to understand the terms and conditions of any financial agreement to determine whether compound interest is beneficial or not.
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