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| Application in engineering mechanics: Moment of a force | |
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The cross product of two vectors a and b is defined only in three-dimensional space and is denoted by a × b. In some physics texts the notation a ∧ b is used; this is avoided in much of mathematics to prevent confusion with the exterior product. The result of a cross product is a vector that carries both magnitude and direction and is widely used in engineering mechanics for quantities such as moments and angular momentum.
The cross product a × b is defined as a vector c that is perpendicular to both a and b. Its direction is given by the right-hand rule and its magnitude equals the area of the parallelogram spanned by a and b.
The magnitude and direction are given by the formula
In this expression:
If a and b are parallel (θ = 0° or 180°), then ‖a‖‖b‖ sin θ = 0 and therefore a × b = 0 (the zero vector).
To determine the direction of a × b use the right-hand rule: point the right-hand index finger in the direction of a, the middle finger in the direction of b, and the thumb then points in the direction of the cross product. This convention implies the cross product is anti-commutative:
If a left-handed coordinate system is used, the corresponding left-hand rule would give the opposite direction. This dependence on orientation leads to the notion that the cross product is not a true (polar) vector but a pseudovector - its sign can change under improper coordinate transformations such as reflection. For further detail see cross product and handedness discussions in mechanics texts.
When vectors are expressed in standard Cartesian coordinates, the cross product can be computed by a determinant-like expression. For
a = (a₁, a₂, a₃) and b = (b₁, b₂, b₃),
the cross product components are
a × b = (a₂b₃ - a₃b₂, a₃b₁ - a₁b₃, a₁b₂ - a₂b₁).
Equivalently, using unit vectors i, j, k:
a × b = det
| i j k |
| a₁ a₂ a₃ |
| b₁ b₂ b₃ |
Standard basis cross products are
Let a = (2, -1, 3) and b = (0, 4, -2).
Compute a × b.
Evaluate components on separate lines for clarity.
First component: a₂b₃ - a₃b₂ = (-1)(-2) - (3)(4) = 2 - 12 = -10.
Second component: a₃b₁ - a₁b₃ = (3)(0) - (2)(-2) = 0 + 4 = 4.
Third component: a₁b₂ - a₂b₁ = (2)(4) - (-1)(0) = 8 - 0 = 8.
Therefore a × b = (-10, 4, 8).
In many two- and three-dimensional engineering problems it is convenient to use vectors when computing moments. The moment of a force F about a point A can be written compactly as the cross product
Here r is the position vector from the reference point A to any point on the line of action of the force F.
The magnitude of the moment is
This agrees with the scalar expression for moment given elsewhere (see Eq. 2/5). The perpendicular distance (moment arm) d = r sin α is independent of which point on the line of action of F is chosen for the vector r. The sense (direction) of the moment is established by applying the right-hand rule to the sequence r × F. If the fingers of the right hand curl from the positive sense of r to the positive sense of F, then the thumb points in the positive sense of the moment M. The order r × F must be preserved because reversing the order would reverse the sense of the resulting moment vector.
The moment may be interpreted as the moment about the point A or as the moment about the line O-O that passes through A and is perpendicular to the plane containing r and F. When the perpendicular distance between the line of action of the force and the moment centre is easily known, the scalar approach (M = Fd) is generally simpler. When vectors r and F are available in component form and are not perpendicular, the cross-product expression is often preferable.
Summary: The cross product a × b produces a vector orthogonal to both operands, with magnitude equal to the parallelogram area and direction fixed by the right-hand rule. It is a central tool in mechanics for moments and rotational quantities and is computed by determinant or component formulas in Cartesian coordinates.
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| 1. What is the cross product of vectors? | ![]() |
| 2. How is the magnitude of the cross product calculated? | ![]() |
| 3. What is the significance of the cross product in physics? | ![]() |
| 4. Can the cross product of two vectors be zero? | ![]() |
| 5. How is the cross product different from the dot product? | ![]() |