Class 9 Exam  >  Class 9 Notes  >  Extra Documents & Tests for Class 9  >  Procedure - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math

Procedure - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math | Extra Documents & Tests for Class 9 PDF Download

As performed in the real lab:

Materials Required:

Glazed paper, pencil, a pair of scissors, gum.

Procedure:

1. Make a parallelogram by paper folding. Call it ABCD.
2. Cut out the parallelogram with the help of a pair of scissors.
3. Obtain a perpendicular from D to AB meeting AB at E. [Fig A]
4. Cut and remove the triangle AED and align AD with BC. Call the displaced segment AE as BE'. [Fig B]
5. Verify using a scale that EBE' are collinear.
6. Verify that CE' is perpendicular to EBE and EE' = CD
7. Observe that the figure obtained is a rectangle.[Fig B]

Procedure - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math | Extra Documents & Tests for Class 9

As performed in the simulator:

  1. Create a parallelogram ABCD with length L and breadth B.[Fig C]

  2. Draw perpendicular from A to DC meeting at point E.

    1.     Click on "Set Square" in Tools to use it.

    2.     Drag and place Set Square such that point A and line DC is perpendicular.

  3. Click on ▲ AED to separate it from parallelogram.

  4. Drag ▲ AED and place it such a way that AD is overlapped with BC.

  5. Please see the observation

Procedure - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math | Extra Documents & Tests for Class 9

Observation:

1. E is Co-linear with base.
2. Line DE is perpendicular to base.
3. Therefore it will forms rectangle ABE'E.
4. Thus the area of parallelogram = area of rectangle ABE'E
                                                      = breadth X height

Note:

In some input cases, perpendicular of parallelogram may fall outside the base [E.g. Fig D]. In such cases click on parallelogram to rotate it and follow the same procedure as mentioned above.

Procedure - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math | Extra Documents & Tests for Class 9

Result:

Area of parallelogram is the product of its base and height.

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FAQs on Procedure - To show that the Area of Parallelogram is Product of its Base and Height, Class 9 Math - Extra Documents & Tests for Class 9

1. What is the formula to find the area of a parallelogram?
Ans. The formula to find the area of a parallelogram is to multiply the base of the parallelogram by its height. This can be expressed as: Area = Base x Height.
2. How do you determine the base and height of a parallelogram?
Ans. The base of a parallelogram is any one of its sides, and the height is the perpendicular distance between the base and the opposite side. To determine the base and height, you can measure the length of the sides and use the concept of perpendicularity to find the height.
3. Can the base and height of a parallelogram be the same length?
Ans. No, the base and height of a parallelogram cannot have the same length. The height is the perpendicular distance between the base and the opposite side, so it must be different from the length of the base. If the base and height were the same length, the parallelogram would become a rectangle.
4. Is the formula for finding the area of a parallelogram the same as that for a rectangle?
Ans. Yes, the formula for finding the area of a parallelogram (Area = Base x Height) is the same as that for a rectangle. This is because a rectangle is a special type of parallelogram where all angles are right angles.
5. Can the area of a parallelogram be negative?
Ans. No, the area of a parallelogram cannot be negative. The area is a measure of the region enclosed by the parallelogram, and it is always a positive value. If the calculation results in a negative value, it indicates an error in the measurement or calculation process.
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