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Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10 PDF Download

1. Cube


Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10For a Cube of  side a   we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = (a3) cu. units.
(ii) Lateral surface area = [4a2] sq. units.
(iii) Total surface area = [6a2] sq. units.

2. Cuboid

 For a Cuboid of length = l, breadth = b and height = h, we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = (l × b × h) cu. units.
(ii) Lateral surface area = [2 (l + b) × h] sq. units.
(iii) Total surface area = [2 (lb + bh + hl] sq. units.

3. Cylinder


For a Cylinder of base radius = r and height (or length) = h, we have:

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Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = πr2h cu. units.
(ii) Curved surface area = 2πrh sq. units.
(iii) Total surface area = 2πr (h + r) sq. units.

4. Hollow Cylinder


For a Hollow Cylinder having external radius = R, internal radius = r and height = h, we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume= [External volume] − [Internal volume]
=(πR2h − πr2h) cu. units = π(R2 − r2) cu. units.
(ii) Curved surface area= [External S.A.] + [Internal S.A.]
=[2πRh + 2πrh] sq. units = 2πh (R + r) sq. units
(iii) Total surface area= (curved S.A.) + (area of the base-ring)
= [(2πRh + 2πrh) + 2 (πR2 − πr2)] sq. units
= [(2πh (R + r) + 2π (R2 − r2)] sq. units

5. Cone


For a Cone of base radius = r, height = h and slant height l =√h2+r2we have:

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Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = 1/3 πr2h cu. units.
(ii) Curved surface area = πrl sq. units.
(iii) Total surface area = [Curved surface area] + [Area of base]
= [πrl + πr2] sq. units = πr (l + r) sq. units.

6. Sphere


For a Sphere of radius r, we have:

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Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = 4/3 πr3 cu. units.
(ii) Curved surface area = 4πr2 sq. units.
(iii) Total surface area =4πr2sq. units.     

7. Hemisphere


For a Hemisphere of radius r, we have:

Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10(i) Volume = 2/3 πr3 cu. units.
(ii) Surface area = 2πr2 sq. units.
(iii) Total surface area = 3πr2 sq. units.

The document Facts that Matter: Surface Areas & Volumes | Mathematics (Maths) Class 10 is a part of the Class 10 Course Mathematics (Maths) Class 10.
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FAQs on Facts that Matter: Surface Areas & Volumes - Mathematics (Maths) Class 10

1. What is the formula for calculating the surface area of a sphere?
Ans. The formula for calculating the surface area of a sphere is \( 4\pi r^2 \), where \( r \) is the radius of the sphere.
2. How do you find the volume of a cylinder?
Ans. The volume of a cylinder can be calculated using the formula \( V = \pi r^2 h \), where \( r \) is the radius of the base and \( h \) is the height of the cylinder.
3. What is the difference between surface area and volume?
Ans. Surface area refers to the total area that the surface of a three-dimensional object occupies, while volume measures the amount of space inside that object.
4. How is the volume of a cone calculated?
Ans. The volume of a cone is calculated using the formula \( V = \frac{1}{3}\pi r^2 h \), where \( r \) is the radius of the base and \( h \) is the height of the cone.
5. Can you explain how to find the surface area of a rectangular prism?
Ans. To find the surface area of a rectangular prism, use the formula \( SA = 2(lw + lh + wh) \), where \( l \) is the length, \( w \) is the width, and \( h \) is the height of the prism.
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