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Question: A conducting rod of length 2l is rotating with constant angular speed w about its perpendicular bisector. A uniform magnetic field exist parallel to the axis of rotation.The emf induced between two ends of the rod is:
A) Bwl^2
B) 1/2Bωl^2
C) 1/8Bωl^2
D) Zero
Solution:
Potential difference between O and A is:
V0 − VA = 1/2 Bl^2ω
Potential difference between O and B is:
V0 − VB=1/2 Bl^2 ω
so,
So, emf induced = VA − VB = 0
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FAQs on MCQ: Electromagnetic Induction - EmSAT Achieve
| 1. What is electromagnetic induction? |  |
| 2. How does electromagnetic induction work? | |
Ans. Electromagnetic induction works based on Faraday's law of electromagnetic induction, which states that a changing magnetic field induces an electromotive force (EMF) in a conductor, leading to the generation of an electric current.
| 3. What are the applications of electromagnetic induction? | |
Ans. Electromagnetic induction has various practical applications, including power generation in electrical generators, induction heating, transformers, electric motors, and magnetic levitation systems.
| 4. What factors affect the magnitude of induced current in electromagnetic induction? | |
Ans. The magnitude of induced current in electromagnetic induction depends on factors such as the rate of change of magnetic field, the number of turns in the conductor, the strength of the magnetic field, and the resistance of the conductor.
| 5. How is electromagnetic induction related to the EmSAT Achieve exam? | |
Ans. Electromagnetic induction is a topic covered in the EmSAT Achieve exam's Physics section. It is essential for students to understand the principles and applications of electromagnetic induction to perform well in this exam.
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