Class 6 Exam > Class 6 Notes > RD Sharma Solutions for Class 6 Mathematics > RD Sharma Solutions -Ex-2.6, Playing With Numbers, Class 6, Maths
Ex-2.6, Playing With Numbers, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics PDF Download
Q. 1.) Find the H.C. F of the following numbers using prime factors using prime factorization method:
Answer: (i) 144 and 198
Prime factorization of 144 = 2 x 2 x 2 x 3 x 3
Prime factorization of 198 = 2 x 3 x 3 x11
Therefore, HCF = 2 x 2 x 3 = 18
(ii) 81 and 117
Prime factorization of 81 = 3 x 3 x 3 x 3
Prime factorization of 117 = 3 x 3 x13
Therefore, HCF = 3 x 3 = 9
(iii) 84 and 98
Prime factorization of 84 = 2 x 2 x 3 x 7
Prime factorization of 98 = 2 x 7 x 7
Therefore, HCF = 2 x 7 = 14
(iv) 225 and 450
Prime factorization of 225 = 3 x 3 x 5 x 5
Prime factorization of 198 = 2 x 3 x 3 x 5 x 5
Therefore, HCF = 3 x 3 x 5 x 5 = 225
(v) 170 and 238
Prime factorization of 170 = 2 x 5 x 17
Prime factorization of 238 = 2 x 7 x 17
Therefore, HCF = 2 x 17 = 34
(vi) 504 and 980
Prime factorization of 504 = 2 x 2 x 2 x 3 x 3 x 7
Prime factorization of 980 = 2 x 2 x 5 x 7 x 7
Therefore, HCF = 2 x 2 x 7 = 28
(vii) 150, 140 and 210
Prime factorization of 150 = 2 x 3 x 5 x 5
Prime factorization of 140 = 2 x 2 x 5 x 7
Prime factorization of 210 = 2 x 3 x 5 x 7
Therefore, HCF = 2 x 5 = 10
(viii) 84, 120 and 138
Prime factorization of 84= 2 x 2 x 3 x 7
Prime factorization of 120 = 2 x 2 x 2 x 3 x 5
Prime factorization of 138 = 2 x 3 x 23
Therefore, HCF = 2 x 3 = 6
(ix) 106, 159 and 265
Prime factorization of 106 = 2 x 53
Prime factorization of 159= 2 x 53
Prime factorization of 265 = 5 x 53
Therefore, HCF = 53
Q. 2.) What is the H.C.F of two consecutive?
Answer: (i) The common factor of two consecutive numbers is always 1.
Therefore, HCF of two consecutive numbers = 1
(ii) The common factors of two consecutive even numbers are 1 and 2.
Therefore, HCF of two consecutive even numbers = 2
(iii) The common factor of two consecutive odd numbers is 1.
Therefore, HCF of two consecutive odd numbers = 1
Q. 3.) H.C.F of co-primes numbers 4 and 15 was found as follows:
4 = 2 x 2 and 15 = 3 x 5
Since there is no common prime factor. So, H.C.F of 4 and 15 is 0. Is the answer correct? If not what is the correct H.C.F?
Answer: No, it is not correct.
We know that HCF of two co-prime number is 1.
4 and 15 are co-prime numbers because the only factor common to them is 1.
Thus, HCF of 4 and 15 is 1.
The document Ex-2.6, Playing With Numbers, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.
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FAQs on Ex-2.6, Playing With Numbers, Class 6, Maths RD Sharma Solutions - RD Sharma Solutions for Class 6 Mathematics
| 1. What are RD Sharma Solutions? |  |
Ans. RD Sharma Solutions are a comprehensive set of solutions for the RD Sharma textbook, which is widely used for mathematics in Class 6. These solutions provide step-by-step explanations and solutions to the exercises and questions present in the textbook, helping students understand the concepts and improve their problem-solving skills.
| 2. How can RD Sharma Solutions help in playing with numbers? | |
Ans. RD Sharma Solutions for the chapter "Playing With Numbers" in Class 6 Mathematics provide detailed explanations and solutions to various concepts and problems related to numbers. These solutions cover topics such as prime numbers, factors, multiples, divisibility, and various number patterns. By using RD Sharma Solutions, students can understand these concepts better and practice solving different types of number-related problems.
| 3. Are RD Sharma Solutions suitable for self-study? | |
Ans. Yes, RD Sharma Solutions are suitable for self-study. These solutions are designed to be easy to understand and follow, providing step-by-step explanations and solutions to the exercises in the textbook. Students can refer to these solutions while studying at home and practice solving problems on their own, improving their understanding and problem-solving skills.
| 4. Can RD Sharma Solutions help in preparing for exams? | |
Ans. Yes, RD Sharma Solutions can be a valuable resource for exam preparation. These solutions cover all the important concepts and problem-solving techniques related to the chapter "Playing With Numbers" in Class 6 Mathematics. By practicing the exercises and questions provided in RD Sharma Solutions, students can strengthen their knowledge and improve their performance in exams.
| 5. Are RD Sharma Solutions available online? | |
Ans. Yes, RD Sharma Solutions are available online. Many educational websites and platforms offer RD Sharma Solutions for Class 6 Mathematics, including the chapter "Playing With Numbers." Students can access these solutions online, either for free or by purchasing them, and use them for self-study, exam preparation, or to clarify any doubts they may have while studying the chapter.
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