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Ex-2.9, Playing With Numbers, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics PDF Download

Q. 1.) Determine the L.C.M of the numbers given below:

Answer: (i) 48 , 60

Prime factorization of 48 = 2 x 2 x 2 x 2 x 3

Prime factorization of 60 = 2 x 2 x 3 x 5

Therefore, Required LCM=2 x 2 x 2 x 2 x 3 x 5 = 240

(ii) 42, 63

Prime factorization of 42 = 2 x 3 x 7

Prime factorization of 63 = 3 x 3 x 7

Therefore, Required LCM = 2 x 3 x 3 x 7 = 126

(iii)18, 17

Prime factorization of 18 = 2 x 3 x 3

Prime factorization of 17 = 17

Therefore, Required LCM = 2 x 3 x 3 x 17 = 306

(iv) 15, 30, 90

Prime factorization of 15 = 3 x 5

Prime factorization of 30 = 2 x 3 x 5

Prime factorization of 90 = 2 x 3 x 3 x 5

Therefore, Required LCM = 2 x 3 x 3 x 5 = 90

(v)56, 65, 85

Prime factorization of 56 = 2 x 2 x 2 x 7

Prime factorization of 65 = 5 x 13

Prime factorization of 85 = 5 x 17

Therefore, Required LCM =2 x 2 x 2 x 5 x 7 x 13 x 17 = 61,880

(vi) 180, 384, 144

Prime factorization of 180 = 2 x 2 x 3 x 3 x 5

Prime factorization of 384 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3

Prime factorization of 144 = 2 x 2 x 2 x 2 x 3 x 3

Therefore,

Therefore, Required LCM=2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 5 = 5,760

(vii) 108, 135, 162

Prime factorization of 108 = 2 x 2 x 3 x 3 x 3

Prime factorization of 135 = 3 x 3 x 3 x 5

Prime factorization of 162 = 2 x 3 x 3 x 3 x 3

Therefore, Required LCM=2 x 2 x 3 x 3 x 3 x 3 x 5 =1,620

(viii) 28, 36, 45, 60

Prime factorization of 28 = 2 x 2 x 7

Prime factorization of 36 = 2 x 2 x 3 x 3

Prime factorization of 45 = 3 x 3 x 5

Prime factorization of 60 = 2 x 2 x 3 x 5

Therefore, Required LCM =2 x 2 x 3 x 3 x 5 x 7= 1,260

The document Ex-2.9, Playing With Numbers, Class 6, Maths RD Sharma Solutions | RD Sharma Solutions for Class 6 Mathematics is a part of the Class 6 Course RD Sharma Solutions for Class 6 Mathematics.
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FAQs on Ex-2.9, Playing With Numbers, Class 6, Maths RD Sharma Solutions - RD Sharma Solutions for Class 6 Mathematics

1. What are RD Sharma Solutions?
Ans. RD Sharma Solutions are comprehensive and step-by-step solutions to the mathematical problems given in the RD Sharma textbook. These solutions are designed to help students understand and solve complex mathematical problems with ease.
2. What is the significance of Ex-2.9 in RD Sharma Solutions?
Ans. Ex-2.9 in RD Sharma Solutions is a chapter that focuses on the topic "Playing With Numbers." It covers various concepts related to numbers, including divisibility, factors, multiples, prime numbers, and composite numbers. This exercise helps students strengthen their understanding of number patterns and properties.
3. How can Class 6 students benefit from RD Sharma Solutions?
Ans. Class 6 students can benefit from RD Sharma Solutions as it provides a comprehensive understanding of mathematical concepts. These solutions offer step-by-step explanations, making it easier for students to grasp complex topics. By practicing with these solutions, students can improve their problem-solving skills and excel in their math exams.
4. How can RD Sharma Solutions for Class 6 Maths be accessed?
Ans. RD Sharma Solutions for Class 6 Maths can be accessed through various mediums. These solutions are available in the form of textbooks, online websites, mobile applications, and PDF formats. Students can choose the medium that suits them best and access the solutions to practice and enhance their mathematical skills.
5. Are RD Sharma Solutions for Class 6 Maths available in the same language as the textbook?
Ans. Yes, RD Sharma Solutions for Class 6 Maths are available in the same language as the textbook. The solutions are written in a language that is easy to understand and comprehend for students of Class 6. This ensures that students can easily follow the explanations and solve the mathematical problems effectively.
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