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Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE PDF Download

Q.1. A train is moving along a straight line with a constant acceleration ‘a’. A boy standing in the train throws a ball forward with a speed of 10 m/s, at an angle of 60° to the horizontal. The boy has to move forward by 1.15 m inside the train to catch the ball back at the initial height. The acceleration of the train, in m/s2, is

Ans. 5

Solution. From t h e perspective of observer A, consider in g vertical motion of the ball from the point of throw till it reaches back at the initial height.

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Considering horizontal motion from the perspective of observer B. Let u be the speed of train at the time of throw.

The horizontal distance travelled by the ball = (u + 5) √3 .

The horizonal distance travelled by the boy

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

As the boy catches the ball therefore

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

∴   a ≈5 m/s2

Q.2. Airplanes A and B are flying with constant velocity in the same vertical plane at angles 30° and 60° with respect to the horizontal respectively as shown in figure. The speed of A is 100 √3 m/s. At time t = 0 s, an observer in A finds B at a distance of 500 m. The observer sees B moving with a constant velocity perpendicular to the line of motion of A. If at t = t0, A just escapes being hit by B, t0 in seconds is         (JEE Adv. 2014)

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Ans. 5

Solution. Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Here 

vA = vB cos 30°

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

∴vB = 200 ms–1

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Q.3. A rocket is moving in a gravity free space with a constant acceleration of 2 m/s2 along +x direction (see figure). The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the chamber in +x direction with a speed of 0.3 m/s relative to the rocket. At the same time, another ball is thrown in –x direction with a speed of 0.2 m/s from its right end relative to the rocket. The time in seconds when the two balls hit each other is      (JEE Adv. 2014)

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Ans. 8

Solution. Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

For ball A

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE    ...(1)           

For ball B

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

Integer Answer Type Questions: Motion | JEE Advanced | 35 Years Chapter wise Previous Year Solved Papers for JEE

4 – x = 0.2 t + t2 ...(2)

From (1) and (2) t = 8 sec

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FAQs on Integer Answer Type Questions: Motion - JEE Advanced - 35 Years Chapter wise Previous Year Solved Papers for JEE

1. What is motion in physics?
Ans. Motion refers to the change in position of an object with respect to time. It is a fundamental concept in physics that studies the movement of objects and the factors that affect their motion.
2. What are the different types of motion?
Ans. There are several types of motion, including linear motion, circular motion, oscillatory motion, and projectile motion. Linear motion occurs when an object moves along a straight line, while circular motion occurs when an object moves in a circular path. Oscillatory motion refers to the back and forth movement of an object, and projectile motion is the motion of an object under the influence of gravity.
3. What is the difference between speed and velocity?
Ans. Speed and velocity are both measures of how fast an object is moving, but they have different meanings. Speed is a scalar quantity that only considers the magnitude of the movement, while velocity is a vector quantity that takes into account the magnitude and direction of the movement. In other words, velocity includes both speed and the direction of motion.
4. What is acceleration?
Ans. Acceleration is the rate at which an object changes its velocity over time. It is a vector quantity and is defined as the change in velocity divided by the change in time. Acceleration can be positive, negative, or zero, depending on whether the object is speeding up, slowing down, or maintaining a constant velocity.
5. What are the equations of motion?
Ans. The equations of motion are mathematical formulas that describe the relationship between an object's displacement, velocity, acceleration, and time. The main equations of motion are: - v = u + at (final velocity = initial velocity + acceleration × time) - s = ut + 0.5at^2 (displacement = initial velocity × time + 0.5 × acceleration × time^2) - v^2 = u^2 + 2as (final velocity^2 = initial velocity^2 + 2 × acceleration × displacement) where v is the final velocity, u is the initial velocity, a is the acceleration, s is the displacement, and t is the time.
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