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Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry PDF Download

When two groups or atoms from adjacent carbons are eliminated with the formation of unsaturated compounds (alkene or alkyne), the reaction is called elimination reaction. Most commonly a nucleophile (from the α-carbon)  and a proton from the β-carbon are eliminated. Hence, the reaction is known as 1, 2- or -elimination αβ or simply -elimination.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

Some familar elimination reactions are:

(i) Dehydrohalogenation of alkyl halides by base.
Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

(ii) Dehydration of alcohols by acids.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

(iii) Hofmann’s degradation of quarterney bases by heat.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

The presence of at least one hydrogen on the β-carbon  is necessary for elimination. The driving forces for elimination are (a) stability of the olefin formed and (b) the relief from steric strain due to crowding in the substrate.

Branching at the β-carbon  (as also at the α-carbon ) of the substrate produces substituted olefins stabilized by hypyperconjugation and hence favours elimination. Thus, Me3CCl gives only 16% olefin while Me2CH—CMe2Cl gives 62% olefin.

Strain in the substrate due to crowding the substituents can be relieved on the formation of olefin since the bond angles increase from 109.5° in the substrate (sp3-hydridized) to 120° inthe product (sp2-hybridized). Hence 3° halides favour elimination most and 1° halides the least, i.e., the order of elimination in halides is 3° > 2° > 1°.

The elimination reactions like SN reactions may proceed by either unimolacular These elimination reactions have been designated E1 and E2 on their resemblance to SN1 mechanism and SN2 mechanism respectively.


(a) Mechanism: The elimination reaction in which the rate of reaction is dependent on the concentration of the substrate only, i.e., kinetically of the first order, is designated E1. Since the rate of reaction is independent of the concentration of the reagent, it is interpreted, as in SN1, that the first step of the reaction is the slowest step involving ionization of the substrate. This is followed by the rapid removal of a proton from the β-carbon  by the reagent in the second step. This is illustrated below. (i) Dehydrahalogenation of alkyl halides: The rate of elimination of a halacid from t-butyl bromide in basic medium is found to be proportional to [Me3CBr]. Therefore, the halide undergoes slow ionization in the first step. This is followed by a rapid extraction of a proton from the carbocation by the base or solvent in the second step.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

it is seen that a carbocation is formed in the first step in both E1 and SN1 reactions. Hence, the reagent can attack the carbon to given substitution product and also can accept a proton to give elimination product. In practice both alcohol (substitution product) and alkene (elimination product) are obtained on hydrolysis of Me3CBr.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

When more than one alkene can be formed, that alkene will predominate which has larger number of alkyl groups on the double-bonded carbons-this is Saytzev’s rule. This is understandable since the substituted alkyl group will stabilize the alkene by hyperconjugation.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

(ii) Dehydration of alcohols—Acid-catalysed dehydration of alcohols follows E1 mechanism. The dehydration is carried out at elevated temperature with sulphuric acid.              Alcohol  is first protonated which weakens the C—O bond. Hence, water is eliminated from the protonated alcohol with generation of a carbocation. The latter then expels a proton to form a stable alkene.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

The concentration of acid depends upon how fast the carbocation is formed, i.e., on the stability of the carbocation. primary alcohols generate unstable carbocations and hence require high temperature and high concentration of acid while 3° alcohols require lower temperature and lower concentration of acid for dehydration. Thus,


Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

E1 reaction is facilitated by 

(i) Branching at the α and β -carbons of the substate-for stability of the olefin. 

(ii) Strong polar solvent-to aid ionisationi,

 (iii) Low concentration of base-the greater stability of the alkene over the carbocation makes the extraction of proton easy.

(b) E2 Mechanism: When the rate of elimination reaction is dependent on both the substrate and the reagent, i.e., rate ∝[Substrate][reagent], the reaction is kinetically of the second order or bimolecular. Such bimolecular elimination reaction is designated E2 on its similarity with SN2. 

Since the reaction involves both the reactants in the rate-determining step, it is interpreted as in SN2, that the reaction occurs in one step in which both the groups (proton and the leaving group) depart simultaneously through the intermediate transition state. It is visualized that as the base abstracts a proton from the β-carbon, simultaneous departure of the nucleophile takes place from the α-carbon.  In the transition state the βC — H and αC — X  bonds are stretched on the attack of the reagent with the incipient π-bond formation.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

The energy of the transition state will be least when the two leaving groups, the α-and  β-carbons  and the attacking base are coplanar in the transition state. Also, the two leaving groups (H and X) should be trans to each other to effect π bond.

The two leaving groups orient themselves in the trans position when a σ bond exists between the α-and β-carbons . When, however, free rotation is not allowed as in the case of double bond, elimination is difficult when the leaving groups are cis to each other. Thus, acetylene dicarboxylic acid is more easily formed from chlorofumaric acid (25) than from chloromaleic acid (26).

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

E2 reaction is facilitated by


(i) Branching at α-and β-carbons —since more stable olefin is formed.

(ii) Strong base of high concentration—since a strong C—H bond has to break,

(iii) Solvant of low polarity—polar solvents form a strong solvent wall around the base restricting the attack. Hence DMF or DMSO are usually used as solvents.

(c) E1 cB Mechanism:   It may be argued that a second-order elimination reaction may as well proceed in two steps as in E1 reaction. The first step involves a fast and reversible removal of a proton from the β-carbon with the formation of a carbanion which then loses the leaving group in the second slow rate-determinig step.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

The overall rate of this reaction is thus dependent on the concentration of the conjugate base of the substrate (carbanion). Hence, this mechanism has been designated as E1 cB (Elilmination, Unimolecular from conjugate base).


To distinguish between E2 and E1cB mechanisms, deuterium exchange experiment was perfomed. for this 2-phenylethyl bromide was treated with sodium ethoxide in EtOD. This substrate was selected because the Ph group is expected to increase the acidity of the β-hydrogen and also to stabilize the carbanion to exist long enough for incorporation of deuterium in the starting material from the solvent EtOD.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

The reaction was interrupted before completion and analysed for deuterium content. No deuterium incorporation was found either in the substrate or in the styrene. Hence, no reversible carbanion was formed. The reaction followed E2 path. However, the E1cD mechanism does operate in substrates having strong electron-withdrawing groups, e.g., chlorine on β-carbon, and poor leaving groups, e.g., fluorine as in Cl2CH—CF3.

Orientation in elimination reactions: Substrates having alternative β-hydrogen give a mixture of olefins on elimination.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

To help in forecasting the major product of elimination (alkene), there are two empirical rules:

(i) Saytzev rule and (ii) Hofmann rule. 

(i) Saytzev Rule: The rule states that neutral substrates (alkyl halides, alkyl toluenesulphonates) lead predominantly depends wholly on the relative stabilities of the olefins. Therefore, Saytzev rule governs the orientation of E1 reaction.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

In suitable substrates the rearrangement of the carbocation before elimination may give different alkenes. For steric reasons the non-Saytzev product may be the major product in suitable substrates.


Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

The olefin obtained through path (b) is minor due to steric hindrance. In E2, it is suggested that the incipient olefinic bond formation in the transition state is being stabilized by the inductive effect of the alkyl groups, thereby lowering the energy of the transition state. Therefore, with the increasing number of alkyl groups there will be increasing stability of the transition state with progressive lowering of energy of the transition state.


Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

(ii) Hofmann Rule: When a quanternary ammonium hydroxide is strongly heated (<125°C) it decomposes to yield a tertiary amine, water and alkene.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

This is known as Hofmann elimination or β-elimination. The reaction involves abstraction of a proton from β-carbon with the simultaneous expulsion of the leaving group.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

When there are alternative β-hydrogens  inthe quaternary ammonium salts, a mixture of alkenes is formed. Hofmann rule states that in case of alternative β-hydrogens  in the charged substrates (quaternary ammonium and sulphonium salts), the least substituted alkene is predominantly formed.

Thus, 2-butylquaternary ammonium hydroxide undergoes Hofmann elimination to give 1-butene as the major product.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

To explain, it has been suggested that the strong electron-withdrawing effect of Me3N+  group makes the hydrogens of the β-carbons  more acidic for facile abstraction by the base and stabilizes the incipient carbanion formation in the transition state on gradual stretching of the βC — H  bond. In this particular compound with alternative β-hydrogens,and "β-hydrogens  are less acidic due to +1 effect of the adjacent methyl group. Hence, 'β-hydrogen which is relatively more acidic is removed to give predominantly I-butene.

Hofmann product increases on increasing in the base. Steric effect due to crowding in the leaving group or inthe substrate promotes Hofmann elimination.


In general the proton acidity and for that matter the inductive effect is the more important factor for Hofmann eilimination. Whatever be the conditions, that alkine is formed in which its double bond is conjugated with Ph or C=C groups, e.g.,


Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

MOLECULAR REARRANGEMENTS 

In most organic reactions the functional group of the substrate undergoes structural change without affecting the carbon skeleton of the molecule. There are however many other organic reactions in which atoms, groups (alkyl or aryl), double bonds or dunctional groups migrate within the molecule. The latter types of reactions are known as rearrangement reactions or molecular rearrangement. Thus, molecular rearrangement involves modification in the sequence of atoms or groups in a molecule resulting in a new structure. Migration of atoms or groups occurs from one atom to another (usually adjacent) within the same molecule by Whitmore, 1, 2-shift.


Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

The atom A is called the migration origin and the atom B is called the migration terminus. The shift of M from A to B is called 1, 2-shift. When M is hydrogen, alkyl or aryl group, it is called 1, 2-hydride shift, 1, 2-hydride shift, 1, 2alkyl shift or 1, 2-aryl shift respectively. The migration group may move with its bonding pair of electrons (anionotropic), without the bonding pair (cationotropic) or with a single electron (free radical). This means that rearrangement may take place through intermediates that are cations, anions or free radicals. A large number of molecular rearrangements involve anionotropic migration of a group to an adjacent atom with incomplete octet (i.e., electron-deficient). The rearrangement involving electron-deficient species are more common.

Rearrangement due to migration to electron-deficient atom (C, N, O)

During a reaction an electronegative group may depart with its bonding pair of electrons leaving behind an electrondeficient atom with six electrons. This results in the migration (1, 2-shift) of a group with its bonding pair from the adjacent atom tot he electron-deficient atom. The migrating group may be hydrogen, carbon, nitrogen, oxygen, sulphur or halogens.

The migrating group may either (i) detach from the migration origin and then form bond with the migration terminus (electron-deficient atom) or (ii) may remain partly bonded to both migration origin and terminus to form a bridged ion intermediate or transition state. The general mechanistic possibilities by 1, 2-shift are given below.

Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry | Organic Chemistry

When M is a hetero atom, besides crossover experiments there is stereochemical evidence that (29) is formed. The nonbonding electrons of the hetero atom are said to be involved in the neighbouring group participation in forming (29) since that of reaction is increased by anchimeric* assistance. Alkyl group or hydrogen has no non-bonding electrons. It is quite possible that those first leave the migration origin to form open ion and then form the bridged ion becuase the rearrangemennt do not show the increased rate expected from anchimeric assistance.

The corresponding rearrangements with radical and anion intermediates are seldom encountered because of unfavourable distribution of electrons in the molceular orbital encompassing the three atoms in the bridged ion. Rearrangements to electron-deficient carbon, nitrogen and oxygen will be separately studies.

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FAQs on Elimination Reactions and Molecular Rearrangement -Reaction Mechanism Chemistry - Organic Chemistry

1. What is an elimination reaction in chemistry?
Ans. An elimination reaction is a type of chemical reaction where a molecule loses atoms or functional groups from its structure, resulting in the formation of a double or triple bond. It involves the removal of one or more substituents from a molecule, leading to the formation of a new unsaturated compound.
2. How does an elimination reaction occur?
Ans. An elimination reaction can occur through two common mechanisms: E1 (unimolecular elimination) and E2 (bimolecular elimination). In an E1 reaction, the reaction proceeds in two steps: the formation of a carbocation intermediate followed by the elimination of a leaving group. In an E2 reaction, the elimination and deprotonation steps occur simultaneously, without the formation of a carbocation intermediate.
3. What are the possible products of an elimination reaction?
Ans. The possible products of an elimination reaction depend on the starting material and the reaction conditions. Generally, elimination reactions can result in the formation of alkenes or alkynes. For example, in the elimination of an alcohol, an alkene can be formed. Similarly, the elimination of a halide can lead to the formation of an alkene or alkyne.
4. Can an elimination reaction result in molecular rearrangement?
Ans. Yes, an elimination reaction can sometimes result in molecular rearrangement. This is known as a molecular rearrangement reaction. It occurs when the rearrangement of atoms or functional groups within a molecule takes place during the elimination process. Molecular rearrangements can lead to the formation of different isomeric products.
5. What are some examples of elimination reactions in organic chemistry?
Ans. Some examples of elimination reactions in organic chemistry include the dehydration of alcohols to form alkenes, the dehydrohalogenation of alkyl halides to form alkenes, and the elimination of hydrogen halides from alkyl halides to form alkynes. These reactions are commonly used in synthetic organic chemistry to create new carbon-carbon double or triple bonds.
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