Class 8 Exam  >  Class 8 Notes  >  RD Sharma Solutions for Class 8 Mathematics  >  RD Sharma Solutions - Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics PDF Download

PAGE NO 9.11:

Question 1:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = 3x -10

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics= 3x -10

 or 2x + 5 = 9 x −30

or 9 x −2x = 5 + 30

or 7x = 35

or  x = 35/7

or  x = 5

Verification:L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = 15/3 = 5

R.H.S. = 15−10 = 5

∴ L.H.S. = R.H.S. for  x = 5.

PAGE NO 9.11:

Question 2:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 2a−16 = 3a−9

or 3a−2a = −16 + 9

or a = −7 

Verification:

L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = -5

R.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = -5
∴ L.H.S. = R.H.S. for a =  −-7

PAGE NO 9.11:

Question 3:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 77y + 22 = 30y−25

or 77y−30y = −25−22

or 47y = −47

or y = −47/47 = −1 

Verification:L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics
∴ L.H.S. = R.H.S. for y =  −-1

PAGE NO 9.11:

Question 4:

Solve each of the following equation and also check your result in each case:

x −2x + 2−16/3x + 5 = 3−7/2x 

ANSWER:

x −2x + 2−16/3x + 5 = 3−7/2x

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or −38 x + 42 = 18−21 x

or −21 x + 38 x = 42−18

or 17x = 24

or  x = 24/17

Check:L.H.S. = 24/17 − 2 × 24/17 + 7 − 16/3 × 24/17 = −33/17

R.H.S. = 3− 7/2 × 24/17 = −33/17

∴ L.H.S. = R.H.S. for  x   =  24/17

PAGE NO 9.11:

Question 5:

Solve each of the following equation and also check your result in each case:

1/2x + 7x −6 = 7x + 1/4

ANSWER:

1/2x + 7x −6 = 7x + 1/4

or 1/2x + 7x −7x = 1/4 + 6

or x/2 = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or  x/2 = 25/4

or  x = 25/2 

Check:L.H.S. = 12×25/2 + 7×25/2-6 = 35/14

R.H.S. = 7×25/2 + 1/4 = 35/14
∴ L.H.S. = R.H.S. for  x   =  25/2

PAGE NO 9.11:

Question 6:

Solve each of the following equation and also check your result in each case:

3/4 x + 4 x = 7/8 + 6 x −6

ANSWER:

3/4 x + 4 x = 7/8 + 6 x −6

or 3/4 x −2x = 7/8−6

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or−5 x/ 4 = −41/8

or −40 x = −16/4

or  x = −164/−40 = 41/10

Check:

L.H.S. = 3/4×41/10 + 4×41/10 = 123/40 + 164/10 = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. = 7/8 + 6×41/10 - 6 = 7/8 + 246/10 - 6 = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics
∴ L.H.S. = R.H.S. for  x   =  41/10

PAGE NO 9.11:

Question 7:

Solve each of the following equation and also check your result in each case:

7/2 x −5/2 x = 20/3x + 10

ANSWER:

7/2 x −5/2 x = 20/3x + 10

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 40 x + 60 = 6 x

or 34 x = −60

or  x = −60/34

= −30/17

Check:

L.H.S. = 7/2×−30/17−5/2× −30/17 = −30/17

R.H.S. = 20/3×−30/17 + 10 = −30/17

∴L.H.S. = R.H.S. for  x = −30/17

PAGE NO 9.11:

Question 8:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 18 x + 9 = 14 x −6

or 18 x −14 x = −6−9

or 4 x = −15

or  x = −15/4

Check: 

L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics
∴ L.H.S. = R.H.S. for  x   =  −15/4

PAGE NO 9.11:

Question 9:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 12a + 5 = 6a + 7

or 6a = 7−5

or a = 2/6 = 1/3

Check:

L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = -1/3 + 11/6 = 9/6 = 3/2

R.H.S. = 1/3 + 7/6 = 9/6 = 3/2
∴ L.H.S. = R.H.S. for a  =  1/3

PAGE NO 9.11:

Question 10:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 3x + 3 = 10−2x

or 5 x = 10−3

or  x = 7/5

Check:

L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. =Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics
∴ L.H.S. = R.H.S. for  x   =  7/5

PAGE NO 9.11:

Question 11:

Solve each of the following equation and also check your result in each case:
Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 4 x −8 = 3x + 6

or  x = 14

L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = 21/2-13/2 = 8/2 = 4

R.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics
∴ L.H.S. = R.H.S. for  x   =  14

PAGE NO 9.11:

Question 12:

Solve each of the following equation and also check your result in each case:
Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 85 x + 15 = 12x −36

or 73x = −51

or  x = −51/73 

Check:L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = -255/219 - 124292 = -5473

R.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics
∴ L.H.S. = R.H.S. for  x   =  −51/73

PAGE NO 9.11:

Question 13:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 7x −35 = −8 x + 40

or 15 x = 75

or  x = 75/15 = 5

Check:

L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics
 ∴ L.H.S. = R.H.S. for  x   = 5

PAGE NO 9.11:

Question 14:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 8−16 x = 98−7x

or −16 x + 7x = 98−8

or  x = −90/9

= −10 

Check:L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = 3-4 = -1

R.H.S. =Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics
∴ L.H.S. = R.H.S. for  x   =  −-10

PAGE NO 9.11:

Question 15:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 51 x + 45 = 504

or 51 x = 504−45

or  x = 459/51 = 9

Thus,  x = 9 is the solution of the given equation.

Check:Substituting  x = 9 in the given equation, we get:

L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics= 88/2−9 + 7/7 = 44−9 + 1 = 36

R.H.S. = 36

∴ L.H.S. = R.H.S. for  x = 9.

PAGE NO 9.11:

Question 16:

Solve each of the following equation and also check your result in each case:
 0.18(5 x  − 4) = 0.5 x   + 0.8

ANSWER:

0.18(5 x −4) = 0.5 x + 0.8

or 0.9 x −0.72 = 0.5 x + 0.8

or 0.9 x −0.5 x = 0.8 + 0.72

or 0.4 x = 1.52

or  x = 1.52/0.4

or  x = 3.8

Thus,  x = 3.8 is the solution of the given equation.

Check:Substituting  x = 3.8 in the given equation, we get:

L.H.S. = 0.18(5×3.8−4) = 0.18×15 = 2.7

R.H.S. = 0.5×3.8 + 0.8 = 2.7

∴ L.H.S. = R.H.S. for  x = 3.8.

PAGE NO 9.11:

Question 17:

Solve each of the following equation and also check your result in each case:

2/3x −3/2x = 1/12

ANSWER:

2/3x −3/2x = 1/12

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 6 x = −60

or  x = −60/6

or  x = −10

Thus,  x = −10 is the solution of the given equation.

Check:Substituting  x = −10 in the given equation, we get:

L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 MathematicsChapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. = 1/12

∴ L.H.S. = R.H.S. for  x = −10.

PAGE NO 9.11:

Question 18:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 61 x + 36 = 6(8 x + 19)  [Multiplying both sides by 108]

or 61 x + 36 = 48 x + 114

or 61 x −48 x = 114−36

or 13x = 78

or  x = 78/13

or  x = 6

Thus,  x = 6 is the solution of the given equation.

Check:Substituting  x = 6 in the given equation, we get:

L.H.S. =Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 MathematicsChapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

∴ L.H.S. = R.H.S. for  x = 6.

PAGE NO 9.12:

Question 19:

Solve each of the following equation and also check your result in each case: 

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics [Multiplying both sides by 3]

or 45−42x = 75−70 x   [After cross multiplication]

or 70 x −42x = 75−45

or 28 x = 30

or  x = 30/28

or  x = 15/14

Thus,  x = 15/14 is the solution of the given equation.

Check:Substituting  x = 15/14 in the given equation, we get:

L.H.S. =Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 MathematicsChapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

∴ L.H.S. = R.H.S. for  x = 15/14

PAGE NO 9.12:

Question 20:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 39 x + 23 = 62 [Multiplying both sides by 3]

or 39 x = 62−23

or  x = 39/39

or  x = 1

Thus,  x = 1 is the solution of the given equation.

Check:Substituting  x = 1 in the given equation, we get:

L.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

∴ L.H.S. = R.H.S. for  x = 1.

PAGE NO 9.12:

Question 21:

Solve each of the following equation and also check your result in each case:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 11 x −1 = 40  [Multiplying both sides by 12]

or 11 x = 40 + 1

or  x = 41/11

Thus,  x = 41/11 is the solution of the given equation.

Check:Substituting  x = 41/11 in the given equation, we get:

L.H.S. =Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 MathematicsChapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. = 10/3

∴ L.H.S. = R.H.S. for  x = 41/11

PAGE NO 9.12:

Question 22:

Solve each of the following equation and also check your result in each case:
Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics= x + 6.1 

ANSWER:

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics= x + 6.1

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or −0.4 + 2.71 = 0.7x + 4.27

or 0.7x = 2.71−0.4−4.27

or  x = −1.96/0.7 = −2.8

Thus,  x = −2.8 is the solution of the given equation.

Check:

Substituting  x = −2.8 in the given equation, we get:

L.H.S. =Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics= −4.571 + 7.871 = 3.3

R.H.S. = −2.8 + 6.1 = −3.3

∴ L.H.S. = R.H.S. for  x = −2.8

PAGE NO 9.12:

Question 23:

Solve each of the following equation and also check your result in each case:
 6.5 x + 
Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = 6.5 x + 13 + Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

ANSWER:

6.5 x + Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics = 6.5 x + 13 + Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

or 6.5 x −6.5 = 26 [After cross multiplication]

or 6.5 x = 26 + 6.5

or  x = 32.5/6.5 = 5

Thus,  x = 5 is the solution of the given equation.

Check:

Substituting  x = 5 in the given equation, we get:

L.H.S. = 6.5×5 + Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

R.H.S. = 6.5×5 + 13 + Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

∴ L.H.S. = R.H.S. for  x = 5.

PAGE NO 9.12:

Question 24:

Solve each of the following equation and also check your result in each case:
 (3x  − 8)(3x   + 2) − (4 x  − 11)(2x   + 1) = ( x  − 3)( x   + 7)

ANSWER:

(3x −8)(3x + 2)−(4 x −11)(2x + 1) = ( x −3)( x + 7)

or 9 x² + 6 x −24 x −16−8 x²−4 x + 22x + 11

= x² + 7x −3x −21

or  x²−5 = x² + 4 x −21

or 4 x = −5 + 21

or  x = 16/4 = 4

Thus,  x = 4 is the solution of the given equation.

Check:

Substituting  x = 4 in the given equation, we get:

L.H.S. = (3×4−8)(3×4 + 2)−(4×4−11)(2×4 + 1) = 4×14−5×9 = 11

R.H.S. = (4−3)(4 + 7) = 11

∴ L.H.S. = R.H.S. for  x = 4.

PAGE NO 9.12:

Question 25:

Solve each of the following equation and also check your result in each case:
 [(2x   + 3) + ( x   + 5)]2  + [(2x   + 3) − ( x   + 5)]2  = 10 x²  + 92

ANSWER:

[(2x + 3) + ( x + 5)]² + [(2x + 3)−( x + 5)]²

= 10 x² + 92

or (3x + 8)² + ( x −2)²

= 10 x² + 92

or 9 x² + 48 x + 64 + x²−4 x + 4

= 10 x² + 92           [ (a + b)² = a² + b² + 2ab  and (a−b)² = a² + b²−2ab ]

or 10 x²−10 x² + 44 x = 92−68

or  x = 24/44

or  x = 6/11

Thus,  x = 6/11 is the solution of the given equation.

Check:

Substituting  x = 6/11 in the given equation, we get:

L.H.S. = [(2 × 6/11 + 3) + (6/11 + 5)]2 + [(2 × 6/11 + 3)−(6/11 + 5)]2             

=   [(45/11) + (61/11)]2 + [(45/11)−(61/11)]2               

= (106/11)2 + (−16/11)2              

= 11492/121

R.H.S. = Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics

∴ L.H.S. = R.H.S. for  x = 6/11

The document Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions | RD Sharma Solutions for Class 8 Mathematics is a part of the Class 8 Course RD Sharma Solutions for Class 8 Mathematics.
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FAQs on Chapter 9 - Linear Equation in One Variable (Part - 2), Class 8, Maths RD Sharma Solutions - RD Sharma Solutions for Class 8 Mathematics

1. What is a linear equation in one variable?
Ans. A linear equation in one variable is an equation that can be written in the form ax + b = 0, where a and b are constants and x is the variable. The highest power of the variable in the equation is 1.
2. How do you solve a linear equation in one variable?
Ans. To solve a linear equation in one variable, follow these steps: 1. Simplify both sides of the equation, if possible. 2. Isolate the variable term on one side of the equation by performing inverse operations. 3. Solve for the variable by isolating it. 4. Check the solution by substituting it back into the original equation.
3. Can a linear equation have more than one solution?
Ans. No, a linear equation in one variable can have either one solution or no solution. If the equation is true for a particular value of the variable, it is said to have one solution. If the equation is not true for any value of the variable, it is said to have no solution.
4. What are the different methods to solve a linear equation in one variable?
Ans. There are three main methods to solve a linear equation in one variable: 1. Addition or subtraction method: In this method, the equation is solved by adding or subtracting the same value from both sides of the equation. 2. Multiplication or division method: In this method, the equation is solved by multiplying or dividing both sides of the equation by the same value. 3. Cross multiplication method: This method is used to solve equations involving fractions. The equation is solved by multiplying both sides of the equation by the product of the denominators.
5. How can linear equations be applied in real-life situations?
Ans. Linear equations have various applications in real-life situations, such as: 1. Finance: Linear equations can be used to calculate interest rates, loan payments, and investment returns. 2. Physics: Linear equations can be used to determine the speed, distance, and time in various physical phenomena. 3. Engineering: Linear equations are used in engineering calculations, such as determining the strength of materials or designing electrical circuits. 4. Economics: Linear equations are used in analyzing supply and demand, cost and revenue functions, and profit maximization. 5. Sports: Linear equations can be used to analyze sports statistics, such as calculating batting averages or shooting percentages.
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