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DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET PDF Download

Section-II: 

Subjective Questions 

Trigonometry

Q1. Find the value of
(a) cos 120° 
(b) sin 240°
(c) tan (-60°) 
(d) cot 300° 
(e) tan 330° 
(f) cos (-60°) 
(g) sin (-150°) 
(h) cos (-120°) 
(e) tan 330° 
(f) cos (-60°)
(g) sin (-150°) 
(h) cos (-120°)

Ans.DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET

Solution:

 (a) Cos 120° = cos(180° – 60°) = – cos 60° = (since cos(180° – x) = – cos x)

Cos 120° = cos(90° + 30°) = – sin 30° = (we know that cos (90° + x) = -sin x)

(b) 
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET

(c) tan(-60°) = -tan 60°

= -√3

(d) cot300º = cot(360−60)º =−cot60º

cot300º=−1√3

(e) 




Q2. Find the value of 
(a) sec2θ - tan2θ 
(b) cosec2θ - cot2θ - 1 
(c) 2 sin 45°cos 45°
(d) 2sin 15°cos 45°

Ans.DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET


Calculus

Q3. Differentiate the following functions with respect to x 
(a) x4 + 3x2 - 2x 
(b) x2 cos x 
(c) (6x + 7 )4
(d) exx5

(e) (1 + x) / ex

Ans.

(a) 4x3 + 6x - 2
(b) 2x cosx - x2 sinx
(c) 24(6x + 7)3 
(d) 5exx4 + exx5 
(e) -xe-x



Q4. Integrate the following functions with respect to t
(a) ∫(3t2 - 2t)dt    
(b) ∫(4 cos t + t2) dt
(c) ∫(2t - 4)-4 dt

(d) ∫ dt / (6t - 1)

Ans.

(a) t3 - t2 + C
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET


Q5. Integrate the following functions
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET

Ans.

(a) 4

(b) (√3 - 1) / 2
(c) In (5/2)
(d) Zero
(e) - 1


Q6. Find maximum/minimum value of y in the functions given below
(a) y = 5 - (x - 1)2
(b) y = 4x2 - 4x + 7 
(c) y = x3 - 3x
(d) y = x3 - 6x2 + 9x+ 15
(e) v = (sin 2x - x),DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET

Ans.

(a) ymax = 5 at x = 1
(b) ymin = 6 at x = 1/2
(c) ymin = - 2 at x = 1 and ymax = 2 at x = - 1
(d) ymin = 15 at x = 3 and ymax = 19 at x = 1
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEETDC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET


Graphs

Q7. Draw the graphs corresponding to the equations 
(a) y = 4x 
(b) y = - 6x 
(c) y = x + 4 
(d) y = -2x + 4 
(e) y = 2x - 4 
(f) y = -4x - 6

Ans.

DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEETDC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEETDC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEETDC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET


Q8. For the graphs given below, write down their x-y equations
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET

Ans.

(a) y = x
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET
(d) y = - x + 2


Q9. For the equations given below, tell the nature of graphs.
(a) y = 2x2
(b) y = -4x2 +6
(c) y = 6e -4x
(d) y = 4 (1 - e -2x)
(e) y = 4/x
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET

Ans.

(a) parabola passing through origin
(b) parabola not passing through origin
(c) exponentially decreasing graph
(d) exponentially increasing graph
(e) Rectangular hyperbola in first and third quadrant
(f) Rectangular hyperbola in second and fourth quadrant


Q10. Value of y decreases exponentially from y = 10 to y = 6 Plot an x-y graph. 

Ans.

DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET


Q11. Value of y increases exponentially from y = -4 to y = +4. Plot an x- y graph.

Ans.

DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET


Q12. The graph shown in the figure is exponential. Write down the equation corresponding to the graph.

Ans.
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET

y = 4 + 8e -Kx Here, K is a positive constant


Q13. The graph shown in the figure is exponential. Write down the equation corresponding to the graph.

DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET

Ans.

y = - 4 + 10(1 - e-Kx)Here, K is positive constant


Significant Figures

Q14. Write down the number of significant figures in the following. 
(a) 6428 
(b) 62.00 m 
(c) 0.0628 cm 
(d) 1200 N

Ans.

(a) Four
(b) Four
(c) Three
(d) Four


Q15. Round off to four significant figures. 
(a) 45.689 
(b) 2.0082

Ans.

(a) 45.69
(b) 2.008


Q16. Add 6.75 x 103 cm and 4.52x 102 cm with due regards to significant figures.

Ans. 7.20 x 10cm


Q17. A thin wire has length of 21.7 cm and radius 0.46 mm. Calculate the volume of the wire to correct significant figures.

Ans. 0.14 cm3


Q18. A cube has a side of length of 2.342 m. Find volume and surface area in correct significant figures.

Ans. Area= 5.485 m2, volume= 12.85 m3


Q19. Find density when a mass of 9.23 kg occupies a volume of 1.1m3. Take care of significant figures.

Ans. Density = 8.4 kg/m3


Q20. Length, breadth and thickness of a rectangular slab are 4.234 m, 1.005 m and 2.01 cm respectively. Find surface area and volume to correct significant figures.

Ans. Area= 4.255 m2, volume = 8.55 m3


Q21. Solve with due regards to significant figures
(4.0 x 10-4 -2.5 x 10-6)

Ans. 4.0 x 10-4


Error Analysis

Q22. The refractive index (n) of glass is found to have the values 1.49, 1.50, 1.52,1.54 and 1.48. Calculate 
(a) the mean value of refractive index 
(b) absolute error is each measurement 
(c) fractional error and 
(d) percentage error

Ans.

(a) 1.51
(b) + 0.02,+ 0.01,- 0.01,- 0.03,+ 0.03
(c) ± 0.0132
(d) ± 1.32%


Q23. The radius of a sphere is measured to be (2.1 + 0.5)cm. Calculate its surface area with error limits.

Ans.

(55.4±26.4) cm2


Q24. Calculate focal length of a spherical mirror from the following observations. Object distance u = (50.1 + 0.5) cm and image distance v = (20.1 ± 0.2) cm.

Ans. (14.3 ± 0.4) cm


Q25. Find the percentage error in specific resistance given by DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEETwhere r is the radius having value (0.2+ 0.02)cm, R is the resistance of (60 ± 2) ohm and l is the length of (150 ± 0.1)cm.

Ans. 3.4%


Q26. A physical quantity ρ is related to four variables α, β, γ and η as 
DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET
The percentage errors of measurements in α, β, γ and η are 1%, 3%, 4% and 2% respectively. Find the percentage error in ρ.

Ans. 3%


Q27. The period of oscillation of a simple pendulum is DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET Length L is about 10 cm and is known to 1 mm accuracy. The period of oscillation is about 0.5 s. The time of 100 oscillations is measured with a wristwatch of 1 s time period. What is accuracy in the determination of g?

Ans. 5%


Vernier Callipers and Screw Gauge

Q28. 19 divisions on the main scale of a vernier callipers coincide with 20 divisions on the vernier scale. If each division on the main scale is of 1 cm, determine the least count of instrument.

Ans. 0.05 cm


Q29. The pitch of a screw gauge is 1 mm and there are 100 divisions on the circular scale. While measuring the diameter of a wire, the linear scale reads 1 mm and 47th division on the circular scale coincides with the reference line. The length of the wire is 5.6 cm. Find the curved surface area (in cm2) of the wire inappropriate number of significant figures.

Ans. 2.6 cm2


Q30. The edge of a cube is measured using vernier callipers. [9 divisions of the main scale are equal to 10 divisions of vernier scale and 1 main scale division is 1 mm]. The main scale division reading is 10 and 1 division of the vernier scale was found to be coinciding with the main scale. The mass of the cube is 2.736 g. Calculate the density in g/cm3 upto correct significant figures.

Ans. 2.66 g/cm3

The document DC Pandey Solutions: Basic Mathematics | Physics Class 11 - NEET is a part of the NEET Course Physics Class 11.
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FAQs on DC Pandey Solutions: Basic Mathematics - Physics Class 11 - NEET

1. What are the basic concepts covered in DC Pandey Solutions: Basic Mathematics?
Ans. The basic concepts covered in DC Pandey Solutions: Basic Mathematics include trigonometry, calculus, graphs, significant figures, error analysis, and the use of Vernier calipers and screw gauge.
2. How can DC Pandey Solutions: Basic Mathematics help improve understanding of mathematical concepts?
Ans. DC Pandey Solutions: Basic Mathematics provides detailed explanations and solutions to various mathematical problems, helping students to grasp complex concepts more effectively and improve their problem-solving skills.
3. What is the significance of significant figures in mathematical calculations according to DC Pandey Solutions: Basic Mathematics?
Ans. Significant figures are important in mathematical calculations as they indicate the precision of a measurement and help ensure that the final result is accurate and reliable. DC Pandey Solutions: Basic Mathematics emphasizes the proper use of significant figures in calculations.
4. How does DC Pandey Solutions: Basic Mathematics address error analysis in mathematical problems?
Ans. DC Pandey Solutions: Basic Mathematics includes discussions on error analysis, teaching students how to identify and analyze errors in mathematical calculations. This helps students to understand the sources of errors and improve the accuracy of their results.
5. In what ways can students benefit from studying trigonometry and calculus through DC Pandey Solutions: Basic Mathematics?
Ans. Studying trigonometry and calculus through DC Pandey Solutions: Basic Mathematics can help students develop a strong foundation in these fundamental mathematical concepts, which are essential for advanced studies in mathematics, physics, and engineering.
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