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Heat capacity and internal energy | Additional Documents & Tests for IIT JAM PDF Download

The goal in defining heat capacity is to relate changes in the internal energy to measured changes in the variables that characterize the states of the system. For a system consisting of a single pure substance, the only kind of work it can do is atmospheric work, and so the first law reduces to
dU = dQ − P dV.

Suppose now that U is regarded as being a function U(TV) of the independent pair of variables T and V. The differential quantity dU can always be expanded in terms of its partial derivatives according to
Heat capacity and internal energy | Additional Documents & Tests for IIT JAM

where the subscripts denote the quantity being held constant when calculating derivatives. Substituting this equation into dU = dQ − P dV then yields the general expression
Heat capacity and internal energy | Additional Documents & Tests for IIT JAM

for the path-dependent heat. The path can now be specified in terms of the independent variables T and V. For a temperature change at constant volume, dV = 0 and, by definition of heat capacity,
dQV = CV dT.
The above equation then gives immediately
Heat capacity and internal energy | Additional Documents & Tests for IIT JAM

for the heat capacity at constant volume, showing that the change in internal energy at constant volume is due entirely to the heat absorbed.
To find a corresponding expression for CP, one need only change the independent variables to T and P and substitute the expansion
Heat capacity and internal energy | Additional Documents & Tests for IIT JAM

for dV in equation and correspondingly for dU to obtain
Heat capacity and internal energy | Additional Documents & Tests for IIT JAM

For a temperature change at constant pressuredP = 0, and, by definition of heat capacity, dQ = CP dT, resulting in
Heat capacity and internal energy | Additional Documents & Tests for IIT JAM

The two additional terms beyond CV have a direct physical meaning. The term
Heat capacity and internal energy | Additional Documents & Tests for IIT JAM

Represents the additional atmospheric work that the system does as it undergoes thermal expansion at constant pressure, and the second term involving
Heat capacity and internal energy | Additional Documents & Tests for IIT JAM

represents the internal work that must be done to pull the system apart against the forces of attraction between the molecules of the substance (internal stickiness). Because there is no internal stickiness for an ideal gas, this term is zero, and, from the ideal gas law, the remaining partial derivative is
Heat capacity and internal energy | Additional Documents & Tests for IIT JAM

With these substitutions the equation for CP becomes simply
CP = CV + nR
or
cP = cV + R

for the molar specific heats. For example, for a monatomic ideal gas (such as helium), cV = 3R/2 and cP = 5R/2 to a good approximation. cVT represents the amount of translational kinetic energy possessed by the atoms of an ideal gas as they bounce around randomly inside their container. Diatomic molecules (such as oxygen) and polyatomic molecules (such as water) have additional rotational motions that also store thermal energy in their kinetic energy of rotation. Each additional degree of freedom contributes an additional amount R to cV. Because diatomic molecules can rotate about two axes and polyatomic molecules can rotate about three axes, the values of cV increase to 5R/2 and 3R respectively, and cP correspondingly increases to 7R/2 and 4R. (cV and cP increase still further at high temperatures because of vibrational degrees of freedom.) For a real gas such as water vapour, these values are only approximate, but they give the correct order of magnitude. For example, the correct values are cP = 37.468 joules per K (i.e., 4.5R) and cP − cV = 9.443 joules per K (i.e., 1.14R) for water vapour at 100 °C and 1 atmosphere pressure.

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