| Table of contents | |
| Mesh Analysis with Current Sources | |
| Practice Problems with Answers |

Overview: Nodal analysis (node-voltage method) is a systematic way to determine the voltage at circuit nodes with respect to a chosen reference node (ground) by applying KCL at the nodes and expressing the currents in terms of node voltages.
Once node voltages are known, voltage across any element and current through any element can be found by direct substitution into Ohm's law or the element V-I relation.
Problem statement: Find the nodal voltage at each node and current in each loop by nodal analysis.
Solution: We label nodes and circuit elements and then follow the nodal method.
The chosen reference node is the one labelled as Ground. There are three principal nodes in this circuit; node n1 is connected to a voltage source so its node voltage is known.
The KCL equation at node n2 equates currents through the branches connected to n2.
Known relation: v1 = Vs. (This is the node-voltage at n1 because the voltage source directly sets it.)
KCL at node n2: i1 = i2 + i3.



Using the expressions above and the known node-voltage v1, combine the relations to obtain the nodal equations.
…………… (4) Rewrite the expressions to form linear functions of the unknown node voltages v2 and v3.

KCL at node n3 gives the second equation.


Write both equations together in matrix form for unknowns v2 and v3.


Good practice when forming the matrix equations:

If the determinant of the coefficient matrix is non-zero, the set of simultaneous equations has a unique solution and node voltages can be obtained (Cramer's rule is referred to here as an illustration).


In Cramer's-rule notation, the unknown voltage VK is given by the ratio of the determinant with k-th column replaced by the source vector to the determinant of the coefficient matrix.


For this particular circuit the node voltages v2 and v3 are:


Floating voltage source: A voltage source that does not connect directly to the reference node is called a floating voltage source. It imposes a constraint between the two node voltages it connects.
The portion of the circuit that encloses the floating voltage source and the nodes it connects is treated as a supernode. Apply KCL to the supernode as you would for any node because charge conservation still holds for the closed surface enclosing the supernode.
Applying KCL to the supernode yields a current balance equation such as I1 = i2 + I3.

The voltage source provides a constraint between the node voltages forming the supernode. For example:
Constraint: V2 = v3 - v2.
Use the KCL equation for the supernode together with the voltage-source constraint to obtain a complete set of equations.


Problem statement: Determine the node voltages v1, v2 and v3 of the circuit shown.
Solution: The circuit contains a current source IS which provides a direct constraint on a branch current and, through Ohm's law, may set a related node voltage.
Begin by applying KCL to the relevant nodes and using Ohm's law where required.

The current source gives a direct expression for v3 in terms of IS and R3:
v3 = IS R3
Combine the KCL expression and the constraint provided by the current source to obtain the node-voltage equations.

Definition: A mesh is a loop in a planar circuit that does not contain any other loops within it. Mesh analysis (loop-current method) assigns mesh currents to independent meshes and applies KVL to each mesh to form simultaneous equations in the mesh currents.
Problem statement: Determine the mesh currents i1 and i2 for mesh 1 and mesh 2 in the circuit below.
Solution: The circuit contains three loops but only two meshes (inner loops). Assign mesh currents I1 and I2 clockwise.
The branch with R2 is shared by the two meshes, therefore its branch current equals I1 - I2 (depending on the chosen reference directions).
Apply KVL around mesh 1 (traverse in the direction of I1):
I1 R1 + (I1 - I2) R2 - VS = 0.
Apply KVL around mesh 2:
I2 (R3 + R4) + (I2 - I1) R2 = 0.
Rearrange to the standard simultaneous equation form:
I1 (R1 + R2) - I2 R2 = VS
-I1 R2 + I2 (R2 + R3 + R4) = 0

Solve the matrix equation for I1 and I2. Once mesh currents are known, branch currents follow from linear combinations of mesh currents.
For this circuit:
I1 = i1, i2 = I1 - I2, i3 = I2.
There are two common situations when current sources appear in mesh analysis:
Problem statement: Find the unknown mesh current I1 for the circuit shown.
Solution:
I2 is the mesh current through the mesh that contains the current source, therefore
I2 = IS.
Apply KVL around mesh 1, taking into account the shared branch currents:
I1 R1 + (I1 + IS) R2 = VS.
Solve the above algebraic equation for I1:

Q.1. Determine the currents in the given circuits with reference to the indicated direction?
Q.2. Determine the currents in the given circuits with reference to the indicated direction?
Answer: i1 = 3.31A, i2 = 1.68A, i3 = 1.63A, i4 = 0.627A, v2 = 8.39V, v3 = 6.51V
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