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Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering PDF Download

Q.1 A closed thin-walled tube has thickness, t, mean enclosed area within the boundary of the centerline of tube's thickness, Am and shear stress, τ. Torsional moment of resistance T, of the section would be    [2019 : 1 Mark, Set-ll]
(a) 2τAmt
(b) 4τAmt
(c) τAmt
(d) 0.5τAmt
Ans.
(A)
Solution:
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
Shear stress, Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering

Q.2 A solid circular beam with radius of 0.25 m and length of 2 m is subjected to a twisting moment of 20 kNm about the z-axis at the free end, which is the only load acting as shown in the figure. The stress component τry at Point ‘ M ’ in the cross- section of the beam at a distance of 1 m from the fixed end is    [2018 : 1 Mark, Set-I]
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
(a) 0.0 MPa
(b) 0.51 MPa
(c) 0.815 MPa
(d) 2.0 MPa
Ans.
(A)
Solution:
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
The only non-zero stresses are Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering if θ is 900 then θ = y
Hence Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
= 16T/πd3 = 0.815 MPa
But in rest of the planes shear stresses are zero, hence, Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering

Q.3 A hollow circular shaft has an outer diameter of 100 mm and inner diameter of 50 mm. If the allowable shear stress is 125 MPa, the maximum torque (in kN-m) that the shaft can resist is _____.    [2017 : 2 Marks, Set-II]
Solution:

Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
⇒ T = 23 kNm

Q.4 A solid circular shaft of diameter d and length L is fixed at one end and free at the other end. A torque T is applied at the free end. The shear modulus of the material is G. The angle of twist at the free end is    [2010 : 1 Mark]
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
Ans.
(b)
Solution:
Angle of twist is given by,
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering
Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering 

The document Past Year Questions: Torsion of Shafts & Pressure Vessels | Solid Mechanics - Mechanical Engineering is a part of the Mechanical Engineering Course Solid Mechanics.
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FAQs on Past Year Questions: Torsion of Shafts & Pressure Vessels - Solid Mechanics - Mechanical Engineering

1. What is torsion in shafts and how does it affect their behavior?
Ans. Torsion in shafts refers to the twisting or rotational deformation experienced by a shaft due to the application of a torque. It can cause shear stress and shear strain within the shaft, leading to potential failure or damage. The behavior of a shaft under torsion depends on factors such as its material properties, dimensions, and the magnitude of the applied torque.
2. What are the main factors to consider when designing a pressure vessel?
Ans. When designing a pressure vessel, several factors must be taken into account. These include the vessel's intended purpose, the maximum operating pressure it will be subjected to, the material properties of the vessel and its components, the required safety factors, and any applicable regulations or standards. Additionally, considerations such as the vessel's geometry, wall thickness, and fabrication methods must be carefully evaluated to ensure structural integrity and reliability.
3. How can the torsional stress in a shaft be calculated?
Ans. The torsional stress in a shaft can be calculated using the formula: τ = (T * r) / J where τ is the torsional stress, T is the applied torque, r is the radius of the shaft, and J is the polar moment of inertia. The polar moment of inertia depends on the cross-sectional shape of the shaft and can be calculated using appropriate formulas for different geometries, such as circular, rectangular, or hollow shafts.
4. What are the different types of pressure vessels commonly used in industrial applications?
Ans. There are several types of pressure vessels commonly used in industrial applications, including: 1. Cylindrical vessels: These are the most common type, consisting of a cylindrical shell with hemispherical or dished ends. 2. Spherical vessels: These have a spherical shape and are often used for storing gases under high pressure. 3. Multilayer vessels: These vessels consist of multiple layers, typically with an outer layer made of a material with high strength and an inner layer capable of containing the substance being stored. 4. Composite vessels: These are made from a combination of different materials, such as metal and fiberglass, to achieve desired strength and weight characteristics. 5. Lined vessels: These have an inner lining made of a corrosion-resistant material to protect the vessel from the stored substance.
5. How can the hoop stress in a pressure vessel be calculated?
Ans. The hoop stress in a pressure vessel can be calculated using the formula: σ_h = (P * D) / (2 * t) where σ_h is the hoop stress, P is the internal pressure, D is the diameter of the vessel, and t is the wall thickness. This formula assumes that the vessel is thin-walled and that the hoop stress is uniformly distributed across the vessel's cross-section. It is important to note that this formula is applicable for cylindrical vessels with circular cross-sections and may differ for vessels with different geometries.
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