➢ Conduction
➢ Convection
➢ Radiation
Power, Here, σ is the Stefan’s constant.
➢ Temperature Gradient
➢ Coefficient of Thermal Conductivity
H depends upon following factors:
(a) Area of cross-section of rod: H ∝ A
(b) Temperature Gradient: H ∝-dθ/dx
(c) Nature of the material
So, H = -KA (dθ/dx)
Here K is called the coefficient of thermal conductivity of the material of rod. It depends upon the nature of material of rod.
(d) The total heat Q crossing from one cross-section to the other in time t.
Q = KA(θ1-θ2)t/l
Or K = Ql/A(θ1-θ2)t
Coefficient of thermal conductivity of the material of a rod is defined as the heat current (amount of heat flowing per second) flowing per unit area between two cross-section of the rod each of area 1m2 and separated 1m apart.
Dimension of K:
[K] = [M1L1T-3K-1]
Unit: C.G.S- cal cm-1s-1 ºC-1
S.I.: Wm-1K-1
➢ Thermal Conductance (σh)
σh= KA/l
σh= H/dθ
Unit- S.I- WK-1
➢ Thermal Resistance (RH)
Rh= 1/σH = l/KA = dθ/H
Units of RH: S.I – W-1K
➢ Analogy between Electricity and Heat
➢ Searle’s Method for K
➢ Ingen Hausz Experiment
Flow of a heat through a composite slab:
(a) Thermal Resistance in Series: Thermal resistance of the composite slab is equal to the sum of their individual thermal resistances.
(l1 +l2)/KA = (l1/K1A) + (l2/K2A)
Rcomb = Rh+Rh'
If l1=l2=l, then, K = 2K1K2/K1+K2Temperature of the interface:
θ0= [θ1Rh' + θ2Rh]/ [Rh+ Rh'] or θ0
= [θ1K1l2+ θ2 K2l1]/ [K1l2+ K2l1]
(b) Thermal resistance in parallel: Reciprocal of the combination thermal resistance is equal to the sum of the reciprocals of individual thermal resistances.
1/Rcomb = 1/Rh + 1/Rh
➢ Bolometer
➢ Absorptive Power (a)
➢ Reflecting Power (r)
➢ Transmitting Power (t)
t = Q3/Q
a + r + t = Q1/Q + Q2/Q + Q3/Q = [Q1+ Q2+ Q3]/Q = Q/Q = 1
➢ Radiant Emittance (E)
Unit: S.I-Jm-2s-1
C.G.S: erg cm-2s-1
➢ Energy Density
➢ Kirchhoff’s Law of Heat Radiation
➢ Wein’s Displacement Law
➢ Stefan’s Law
➢ Spectral Emissive Power
➢ Emissivity
➢ Rate of Loss of Heat
➢ Newton’s Law of Cooling
➢ Wein’s Radiation Law
➢ Solar Constant