Resistors, capacitors, and inductors—these are the three basic passive elements used in electrical circuits, either as individual devices or in combination. These elements are used as loads, delays, and current limiting devices. Capacitors are used as dc blocking devices, in level shifting, integrating, differentiating, filters, frequency determination, selection, and delay circuits. Inductive devices can be extended to cover analog meter movements, relays, audio to electrical conversion, electrical to audio conversion, and electromagnetic devices. They are also the basis for transformers and motors.
Passive components are extensively used in ac circuits for frequency selection, noise suppression, and so forth, and are always present as parasitic components, limiting signal response and introducing unwanted delays. These components also cause phase shift between voltages and currents, which has to be taken into account when evaluating the performance of ac circuits.(i) Voltage Step Input
Figure 3.1 (a) Input voltage transient to a circuit with resistance and capacitance, and (b) associated waveforms.
Figure 3.2 (a) Input voltage transient to a circuit with resistance and inductance, and (b) associated waveforms.
(ii) Time Constants
In an RC network when a step voltage is applied, as shown in Figure 3.1(a), the voltage across the capacitor is given by the equation [1]:
EC = E(1− e −t/RC) .........(3.1)
where EC is the voltage across the capacitor at any instant of time, E is the source voltage, t is the time (seconds) after the step is applied, R is in ohms and C is in farads.
Conversely, after the capacitor is fully charged, and the step input voltage is returned to zero, C discharges and the voltage across the capacitor is given by the equation:
EC = Ee−t/RC
Similar equations apply to the rise and fall of currents in the inductive circuit shown in Figure 3.2(a).
(ii) Sine Wave Inputs
When an ac sine wave is applied to C, L, and R circuits, as shown in Figure 3.3(a) the same phase shift between voltage and current occurs as when a step voltage is applied. Figure 3.3(b) shows the relationship between the input voltage, the current flowing and the voltage across C, L, and R as can be seen. In resistive elements, the current and voltage are in phase; in capacitive circuits, the current leads the voltage
Figure 3.3 (a) Series R, C, and L circuits, and (b) waveforms and phase relations in a series circuit.
by 90° (Figure 3.1); and in inductive circuits, the current lags the voltage by 90° (Figure 3.2).
Since the voltages and the currents are not in phase in capacitive and inductive ac circuits, these devices have impedance and not resistance. Impedance and resistance cannot be directly added. If a resistor, capacitor, and inductor are connected in series as shown in Figure 3.3(a), then the same current will flow through all three devices. However, the voltages in the capacitor and inductor are 180° out of phase and 90° out of phase with the voltage in the resistor, respectively, as shown in Figure 3.3(b). However, they can be combined using vectors to give:
E2 = V2R + (VL - VC)2 .......(3.5)
where E is the supply voltage, VR is the voltage across the resistor, VL is the voltage across the inductor, and VC is the voltage across the capacitor.
The vector addition of the voltages is shown in Figure 3.4. In Figure 3.4(a), the relations between VR, VL, and VC are given. VL and VC lie on the x-axis, with one positive and the other negative, since they are 180° out of phase. Since they have opposite signs, they can be subtracted to give the resulting VC − VL vector. VR lies at right angles (90°) on the y-axis. In Figure 3.4(b), the VC − VL and VR vectors are shown with the resulting E vector, which, from the trigonometry function, gives (3.5). The impedance (Z) of the ac circuit, as seen by the input is given by:
........(3.6)
where XC = 1/2πfC, which is the impedance to an ac frequency of f hertz by a capacitor C farads, and XL = 2πfL, which is the impedance to an ac frequency of f hertz by an inductance of L henries.
The current flowing in the circuit can be obtained from Ohm’s Law, as follows:
I = E/Z ............(3.7)
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