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3-Digit Numbers Class 2 Worksheet Maths
Q1: Fill in the Blanks
(a) The successor of 999 is 1000.
Ans. 999+1=1000 is the successor of the number 999.
(b) The largest number that can be made by using the digits 8, 4, 7 is 874.
Ans. The largest number that can be made by using the digits 8, 4, 7 is 874.
(c) The number name of the successor of 889 is Eight hundred ninety.
Ans. 889 + 1 = 890.
(d) The predecessor of 800 is 899.
Ans. 899 is the predecessor of 900. (900 - 1 = 899)
(e) The smallest number that can be made by using the digits 5, 6, 2 is 256.
Ans. The smallest number that can be made by using the digits 5, 6, 2 is 256.
(f) The largest two digit even number is 98.
Ans. The largest two-digit even number must end with an even digit. The largest two-digit number is 99, but since it is odd, the next largest two-digit number is 98, which is even.
Q2: Write True or False.
(a) 463 = 40 + 60 + 3
Ans. True
463 = 40 + 60 + 3
(b) 589 > 895
Ans. False
589 > 895
589 is smaller than 895.
(c) 30 tens = 3 hundreds
Ans. True
30 tens = 3 hundreds
30 tens has the same value as 300.
(d) 486 is the successor of 485
Ans. True
486 is the successor of 485
485 + 1 = 486
Q3: Multiple Choice Questions
(i) 586 is greater than
(a) 423
(b) 695
(c) 982
(a) 423
586 is greater than 423.
(ii) The place value of 7 in 478 is
(a) 7 tens
(b) 7 hundreds
(c) 7 ones
(a) 7 tens
The place value of 7 in 478 is 7 tens.
(iii) Even number between 467 and 469 is
(a) 466
(b) 465
(c) 468
(c) 468
Even number between 467 and 469 is 468
(iv)The place value of 7 in 478 is
(a) 7 tens
(b) 7 hundreds
(c) 7 ones
(a) 7 tens
The place value of 7 in 478 is 7 tens.
(v) I am a three-digit number. I have seven in my one’s place. The number present in my hundred’s place is four less than the number present in my one’s place. I have two in my ten's. Identify me.
(a) Three hundred and seventy-five.
(b) Three hundred and twenty-five.
(c) Three hundred and seventy-seven.
(d) Three hundred and twenty-seven.
(d) Three hundred and twenty-seven.
We need to find a three-digit number that follows these clues:
The one’s place has 7
- This means the last number is 7 ( _ _7 ).
The hundred’s place number is four less than the one’s place number
- The one’s place is 7.
- If we subtract 4 from 7:
7 - 4 = 3- So, the hundred’s place is 3 ( 3 _ 7 ).
The ten’s place has 2
- This means the middle number is 2 ( 3 2 7 ).
(vi) Which pumpkins have the largest and smallest number?
(a) B and E
(b) C and F
(c) F and A
(d) F and E
(a) B and E
The numbers are: 724, 734, 768, 769, 784, 786
The smallest number is 724, which is on Pumpkin B.
The biggest number is 786, which is on Pumpkin E.
The document 3-Digit Numbers Class 2 Worksheet Maths is a part of the Class 2 Course Mathematics for Class 2.
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FAQs on 3-Digit Numbers Class 2 Worksheet Maths
| 1. What are 3-digit numbers? |  |
| 2. How many 3-digit numbers are there in total? | |
Ans. There are a total of 900 3-digit numbers. This is because the first digit can be any number from 1 to 9 (excluding 0), and the second and third digits can be any number from 0 to 9.
| 3. How do you write a 3-digit number in expanded form? | |
Ans. To write a 3-digit number in expanded form, you break it down into the sum of its digit values. For example, the number 356 can be written as 300 + 50 + 6. Each digit is multiplied by its place value (100, 10, or 1) and then added together.
| 4. How many even 3-digit numbers are there? | |
Ans. There are a total of 450 even 3-digit numbers. This is because the last digit can only be an even number (0, 2, 4, 6, or 8), and the first digit can be any number from 1 to 9 (excluding 0). Therefore, there are 5 options for the last digit and 9 options for the first digit, resulting in 5 * 9 = 45 possibilities. Since the middle digit can be any number from 0 to 9, there are 10 options. So, the total number of even 3-digit numbers is 45 * 10 = 450.
| 5. How many prime 3-digit numbers are there? | |
Ans. There are a total of 143 prime 3-digit numbers. To determine if a number is prime, we need to check if it is divisible by any number other than 1 and itself. Since there are 900 3-digit numbers in total, we can start by eliminating numbers that end with 0, 2, 4, 5, 6, or 8, as these are divisible by 2 or 5. This leaves us with 450 numbers. Next, we can eliminate numbers where the sum of their digits is divisible by 3, as these are divisible by 3. This eliminates numbers such as 111, 114, 117, etc. After this step, we are left with 143 prime 3-digit numbers.
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